I'm trying to build a simple formula: if the cell on the same row as current cell, but column J is either =1 or empty, then the result is 1, else 0.
The part about =1 works, the part about="" does not for some reason.
Here is my formula:
=IF(OR("J"&ROW()=1,"J"&ROW()=""),1,0)
Can anyone help me find out why "J"&ROW()="" returns false, even if it is clearly true? The "J"&ROW()=1 returns true if the target cell is 1.
Another thing i tested is "J"&ROW()=j50, where 50 is the actual row number, and this also returned false, which does not make any sense to me.
You need either INDIRECT to turn the string into a cell reference
=IF(OR(INDIRECT("J"&ROW())=1,INDIRECT("J"&ROW())=""),1,0)
or use INDEX (as INDIRECT is volatile)
=IF(OR(INDEX(J:J,ROW())=1,INDEX(J:J,ROW())=""),1,0)
In this specific case it makes sense to make use of RC notation. A formula would look like this:
=IF(OR(RC10=1;RC10="");1;0)
Related
I have the following formula to make a unique list from column plant in table 15:
{=IFERROR(INDEX(Tabel15[Plant];MATCH(0;COUNTIF(Analyses!$Q$2:$Q2;Tabel15[Plant]);0));"")}
This formula is working, but when there is just 1 value in column plant the formula gives a value of 0. This is wrong because it should return the value.
Does anyone know how I can adapt this formula to make it work?
I wanted to change it to this:
{=IF(COUNTA(Tabel15[plant])>0;INDEX(Tabel15[Plant];MATCH(0;COUNTIF(Analyses!$Q$2:$Q2;Tabel15[Plant]);0));Kopie - datablad$G$2)}
But it doesn't work either.
Good mock example. Try and see if this works:
The formula counts the unique cells against another list. The unique list expects to take the first row, no matter what. It also expects you to have more than one value in your duplicate list. If it doesn't you can't compare since it expect duplicates and it throws an error, #N/A. This is mask as blank cell since it's wrapped in IFERROR:
"Unique formula" = IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF($Q$1:Q2,Tabel15[Plant]), 0)),"")
To solve this we check how many values it exist in our duplicate list:
=IF(COUNTA(Tabel15[Plant])>1,... "Unique formula" ... ,Tabel15[Plant]) //***//
This will give us this result.
Then you probably don't want duplicates...
So we need to check if previous rows contain any of the values the formula would return.
The VLOOKUP formula do that for us, and as lookup value we use the formula above //***// and lookup range will be our current column: $Q$1:Q2. NOTICE this is a dynamic range so Q2 is relative reference (no $).
=IF(ISERROR(VLOOKUP(IF(COUNTA(Tabel15[Plant])>1,IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF($Q$1:Q2,Tabel15[Plant]), 0)),""),Tabel15[Plant]),$Q$1:Q2,1,FALSE))
So the Final result we need to apply is this in Cell Q3:
=IF(ISERROR(VLOOKUP(IF(COUNTA(Tabel15[Plant])>1,IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF(Analyses!$Q$1:Q2,Tabel15[Plant]), 0)),""),Tabel15[Plant]),Analyses!$Q$1:Q2,1,FALSE)),IF(COUNTA(Tabel15[Plant])>1,IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF(Analyses!$Q$1:Q2,Tabel15[Plant]), 0)),""),Tabel15[Plant]),"")
The macro error can be ignored by:
If Not IsError(Sheets("Hulpblad").Range("B6").Value) Then
t = Sheets("Hulpblad").Range("B6").Value
'Code...
End If
there is no problem in your formula, it is just telling that there are blanks in the range, 0 means blank. the formula is treating the blank as a value and also considering it in the unique value calculations.
If you want to remove 0 you can just insert an if over your formula to remove it. like
=if(formula = 0, "", formula)
or in orignal form
=IF( (IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF(Analyses!$Q$2:$Q2,Tabel15[Plant]),0)),""))=0,"",IFERROR(INDEX(Tabel15[Plant],MATCH(0,COUNTIF(Analyses!$Q$2:$Q2,Tabel15[Plant]),0)),""))
or go in the cell formatting and change the format to display 0 as a dash.
sometimes blank is also used as error checking, you can apply such formulae as well to check how many are blank, maybe that would someday be used to check any data entry problems.
I am using the formula:
=(Cost!C8)
to get values from another sheet using named ranges. I want this to only show a value if there is a value in the corresponding cell of the other sheet, however, this formula returns a value of 0 even if the cell on the other sheet is empty. How can I make it so that the formula returns nothing (is blank) when the cell it refers to is empty?
Invoice
There are a number of ways to prevent zero's from showing when you refer to a blank cell.
The easiest if probably an IF statement. If your formula is:
=(Cost!C8)
...use:
=IF(Cost!C8="","",Cost!C8)
Similarly you could show a default value, or a label like <No Data> with a variation:
=IF(Cost!C8="","<No Data>",Cost!C8)
Note that Cost!C8 is not a Named Range; it's a cell reference, referring to another worksheet.
More Information:
Office Support : Create conditional formulas
TechRepublic : Three ways to hide zero values in an Excel sheet
Use,
=Cost!C8&""
'alternate for Qty
=TEXT(Cost!C8, "[<>0]0;;;")
'alternate for currency
=TEXT(Cost!C8, "[<>0]$ 0.00;;;")
'alternate for text items
=TEXT(Cost!C8, ";;;#")
Granted, this actually converts your true numbers to text-that-looks-like-a-number and that is generally a practice to be avoided but they will be converted back to true numbers through any maths operation like addition or multiplication.
A blank cell is considered numeric by nature. This can be tested with =ISNUMBER(<blank_cell>). The closest thing to a blank number is zero so you are returning those as the value of the blank cells you are linking to.
Use ISBLANK with IF
=IF(ISBLANK(Cost!C8),"",Cost!C8)
If you just want it to not be visible, you might consider using conditional formatting to make the text color white when the cell is equal to 0. This way the actual value remains 0 so it won't break downstream formulas.
A nice, slightly simpler, alternative is to concatenate the named range with an empty string.
=MyRange --> 0
=""&MyRange --> ""
This is equivalent to TEXT(MyRange) more concise than IF(ISBLANK(MyRange), "", MyRange)
In my excel file, I am trying to determine if a set of numbers is greater than the value of another cell.
I have written out an IF statement that only works sometimes depending on the range of the set of numbers. I have been able to replicate the problem but can't understand what is going wrong. I have included an example of my problem.
"B4" is equal to 2
"'Data Sheet'!A1:A10" is a set of 10 numbers from 1 to 10 inclusive.
My first statement (seen below) is working fine:
=IF(B4>'Data Sheet'!A1:A10,"Pass", "Fail")
which returns Fail, as expected.
However, when I change the statement to:
=IF(B4>'Data Sheet'!A6:A10,"Pass", "Fail")
It returns "#VALUE!".
Why does the range of values in the IF statement make a difference to whether it works or not?
Your formula is an array formula, and it is probably due to serendipity that your first formula is returning what you expect as an answer.
When you enter it into a cell as a non-array formula, which is what you are doing, it will return the value from the column A range that is in the same row as the formula.
Had you entered the first formula in Row 1, it would have returned "Pass" since it would be comparing B4 with A1.
If it is not in a row corresponding to a row in the range, it will return #VALUE.
If you confirm the formula as an array formula, by holding down ctrl + shift while hitting enter, then the formula will return an array of Pass;Fail depending on the relationship of B4 to each of the values in A1:A10. (or A6:A10). The visible value in a single cell will be the result of the first comparison.
So you will need to properly evaluate the array, in order to return whatever it is you want from the formula.
I'm not sure of exactly what you want.
If you want to determine if B4 is greater than any of the numbers in A1:A10, then try (entered normally):
If(B4 > MAX(A1:A10),"Pass","Fail")
If you want something else as a result, you will need to be more specific.
I've searched for an answer for this for awhile now but haven't had any luck. It's a bit difficult to put into words, so please let me know if anything's unclear.
What I want is a way to perform conditional statements on two columns. When both conditions are true, I want to return the value from a third column that is in the same row as where these conditions were met. So if the conditions are true in D5 and C5, I want to return the value from Q5 into the cell with the formula. The conditional statements are easy enough but I haven't figured out the last step yet.
If I use the following formula, I get 1 in the cell with the formula, which is right.
=IF(AND('Stata Output'!D2:D6='Backcheck schedule and results'!C2, 'Stata Output'!C2:C6=1),1,0)
However, replacing 1 in the formula with the range of cells that I want to pull the value from gives me a zero every time, which I know is wrong. For this latter formula I'm using:
=IF(AND('Stata Output'!D2:D6='Backcheck schedule and results'!C2, 'Stata Output'!C2:C6=1),'Stata Output'!Q2:Q5,0)
Any ideas on where I'm messing up?
Thanks!
Give this a shot - I'm sure there is a simpler way but it seems to get the job done (make sure to enter as an array formula with Control+Shift+Enter):
=INDEX('Stata Output'!$D$2:$Q$6,MATCH(1,(--('Stata Output'!$C$2:$C$6=1)*--('Stata Output'!$D$2:$D$6="Backcheck schedule and results")),0),14)
What this does is take your entire table as the range (first argument to INDEX, then uses MATCH to find the row where both of your conditions are met (in this case, column C must be 1 and the corresponding value in column D must be Backcheck schedule and results). You then search the resulting array for 1 (which indicates the match) and return column 14 (which represents column Q in our table). You can continue to add filters inside the MATCH() function as needed.
Note that this will match only the first 'hit'.
Looks like AND isn't working correctly in array formulas, so I would use this:
=IF(('Stata Output'!D2:D6='Backcheck schedule and results'!C2)*('Stata Output'!C2:C6=1)=1,'Stata Output'!Q2:Q5,0)
This will give you a new results column, that will be filled from the Q2:Q6 column for every matching row.
To use it, you should select all of the results column, input the formula and then use CTRL+SHIFT+ENTER.
Just make sure to use use ranges of the same size.
Try the following formula:
=LOOKUP(2,1/('Stata Output'!D2:D6='Backcheck schedule and results'!C2)/('Stata Output'!C2:C6=1),'Stata Output'!Q2:Q5)
If there is more than one row where both conditions are satisfied, this formula will return the col Q value from the last of those.
In Excel we have the VLOOKUP function that looks for a value in a column in a table and then returns a value from a given column in that table if it finds something. If it doesn't, it produces an error.
Is there a function that just returns true or false depending on if the value was found in a column or not?
You could wrap your VLOOKUP() in an IFERROR()
Edit: before Excel 2007, use =IF(ISERROR()...)
You still have to wrap it in an ISERROR, but you could use MATCH() instead of VLOOKUP():
Returns the relative position of an
item in an array that matches a
specified value in a specified order.
Use MATCH instead of one of the LOOKUP
functions when you need the position
of an item in a range instead of the
item itself.
Here's a complete example, assuming you're looking for the word "key" in a range of cells:
=IF(ISERROR(MATCH("key",A5:A16,FALSE)),"missing","found")
The FALSE is necessary to force an exact match, otherwise it will look for the closest value.
Just use a COUNTIF ! Much faster to write and calculate than the other suggestions.
EDIT:
Say you cell A1 should be 1 if the value of B1 is found in column C and otherwise it should be 2. How would you do that?
I would say if the value of B1 is found in column C, then A1 will be positive, otherwise it will be 0. Thats easily done with formula: =COUNTIF($C$1:$C$15,B1), which means: count the cells in range C1:C15 which are equal to B1.
You can combine COUNTIF with VLOOKUP and IF, and that's MUCH faster than using 2 lookups + ISNA. IF(COUNTIF(..)>0,LOOKUP(..),"Not found")
A bit of Googling will bring you tons of examples.
We've always used an
if(iserror(vlookup,"n/a",vlookup))
Excel 2007 introduced IfError which allows you to do the vlookup and add output in case of error, but that doesn't help you with 2003...
You can use:
=IF(ISERROR(VLOOKUP(lookup value,table array,column no,FALSE)),"FALSE","TRUE")
ISNA is the best function to use. I just did. I wanted all cells whose value was NOT in an array to conditionally format to a certain color.
=ISNA(VLOOKUP($A2,Sheet1!$A:$D,2,FALSE))