I've been having trouble adding some features to my dashboard. My current formula is returning N/A (simple vloopup with MAX).
My Goal:
A person who has been a client for the most amount of days is the
favourite client
If two or more clients have been a client for the same amount of
days, pick the one higher up on the column, or pick one randomly (as long as it's not an error)
DATA:
A B
1 DAYS CLIENT
2 4 Josh
3 4 Sam
4 6 Aya
5 2 Zaptos
6 12 Goku
7 12 Gandalf
8 11 Tim
9
So the output should be Goku as he and Gandalf have been clients for the longest, but Goku is higher up in the column than Gandalf.
I would also be happy if the output was randomly selected between Goku and Gandalf.
Thanks.
=INDEX($B$2:$B$8,MATCH(MAX($A$2:$A$8),$A$2:$A$8,0))
This will return the first matching client - Goku in your example.
Shorter:
=VLOOKUP(MAX(A:A),A:B,2,0)
Related
I'm working with a data in which there are multiple sets of information in the same column. This is making it difficult to pick out the data I need as it always returns the first result. I am trying to find a way to ensure that the column result returned in a search is based on a different column's value. For example:
Name/Date
01/01/2022
02/01/2022
03/01/2022
04/01/2022
05/01/2022
Bob
1
7
2
6
1
Jane
1
7
9
3
1
Jimmy
8
7
5
4
2
Robin
1
2
9
6
2
Batman
4
7
6
6
8
06/01/2022
07/01/2022
08/01/2022
09/01/2022
10/01/2022
Bob
4
1
4
2
12
Jane
6
21
9
3
1
Jimmy
8
2
5
4
2
Robin
8
5
0
6
2
Batman
5
5
6
6
8
If I wanted to yield the number for Jane on 07/01/2022 (which is 21), is there any way of returning this? I've been able to use =MATCH to pull the correct column based on the date search criteria, but I cannot see a viable way of pulling for a particular person when their name appears multiple times in the same column. Attempting a lookup will return the first result for the name hit (so in the case of my Jane example, it would return row 3 instead of 9). I'm looking to be able to enter a name and a date, and it returns the result from that part of the array.
Is such a thing possible, please? If not, is there any workaround that may help to provide me the same result?
Thanks in advance for your assistance!
This is being attempting in Office 365.
Assuming:
ms365 (specifically access to the BETA-channel);
Equal intervals with the same names at the same postions;
Formula in I4:
=LET(X,WRAPCOLS(TOCOL(B1:F12,,1),6),SUM((A1:A6=I3)*FILTER(X,TAKE(X,1)=I2)))
Assuming your data starts in row 1
A1:F12 - data range
B17 - Jane
B18 - 07/01/2022
=LET(data,A1:F12,names,A1:A12,lookupname,B17,lookupdate,B18,INDEX(data,MIN(LET(rowlist,IF(names=lookupname,ROW(names),0),IF(rowlist>MAX(IF(data=lookupdate,ROW(data),0)),rowlist,""))),MAX(IF(data=lookupdate,COLUMN(data),0))))
Note, I have edited my original question to clarify my problem:
As the title suggests, I am looking for a way to combine the SUMPRODUCT functionalities with an INDEX and MATCH formula, but if a better approach exists to help solve the problem below I am also open to it.
In the below example, imagine that the tables are on different sheets. I have a report that has the sales of each ID in the rows and each month in the columns (first table). Unfortunately, the report only has IDs and not the region they belong to, but I do have a look up table which labels each ID with their respective region (second table):
A
B
C
D
1
ID
January
February
March
2
1
10
5
20
3
3
5
5
10
4
7
0
10
5
5
14
10
25
5
6
25
5
10
10
7
27
10
10
10
8
44
5
5
5
A
B
1
ID
Region
2
1
East
3
3
East
4
7
Central
5
14
Central
6
25
Central
7
27
West
8
44
West
My goal is to be able to aggregate the sales by region as per the result below. However I would only like to show sales data that belong to the month that is shown in cell D2.
Goal:
A
B
C
D
1
Region
Sales
February
2
East
10
3
Central
45
4
West
15
I have used the INDEX and MATCH combination to return a single value, but not sure how I can return multiple values with it and aggregate them at the same time. Any insight would be appreciated!
You may just use:
=SUMPRODUCT((Sheet1!B$1:D$1=D$1)*(Sheet1!H$2:H$8=A2),Sheet1!B2:D8)
Remember, SUMPRODUCT() could be quite heavy processing huge data, therefor to combine INDEX() and MATCH() is not a bad idea, but let's do it the other way around and nest the latter two into SUMPRODUCT() instead =):
=SUMPRODUCT(INDEX(Sheet1!B$2:D$8,0,MATCH(D$2,Sheet1!B$1:D$1,0))*(Sheet1!H$2:H$8=A2))
Another option using SUMIF+INDEX+MATCH function as in
In "Sheet2" B2, copied down :
=SUMIF(Sheet1!H:H,A2,INDEX(Sheet1!B$1:D$1,MATCH(D$2,Sheet1!B$1:D$1,0)))
I have a data-set with some names and months, sample:
Name Month
Max 2
Sally 5
Max 1
James 11
Richard 9
Sally 9
I then have a table as such:
Month
Name 1 2 3 4 5 6 7 8 9 10 11 12
Max
Sally
James
Richard
How do I create a formula that can enter "Yes", or "No" for each month based on the person's name? For example, Max would have months 2 and 1 displaying "Yes", all other months displaying "No".
I can't think of how to do this...using an INDEX/MATCH function I can pull up the first month for "Max", but it won't register the second time his name shows up (it just matches the order of his name with where his data lies in the array, doesn't consider duplicates).
Is there a way to do this?
Thanks.
Assuming a data setup like this:
In cell E3 and copied over and down is this formula:
=IF(COUNTIFS($A$2:$A$7,$D3,$B$2:$B$7,E$2),"Yes","No")
I have a number of clients in an excel spreadsheet (by client name), each associated with a particular item. For example
12345 1
12345 2
12345 2
23451 1
23451 3
55667 1
55667 2
89001 3
99999 1
99999 2
I need to count the number of distinctly different items for each client - in the above example, client 12345 has bought 3 items (output is 3); client 23451 has bought 2 items (output 2); client 89001 has bought one item (output 1). I'm sure it's a COUNT feature which looks to the previous column A and breaks/restarts the count if the client number changes, but I'm having a devil of a time doing it. Any help would be deeply appreciated.
Have you considered the SUM function instead? The COUNT function counts the amount of cells that are being used, the SUM adds up the integers within the cells.
Check out this link -> Here
Yes, or a better suggestion from David in the comments, the SumIf function.
Thanks David!
I am retired so I have a lot of free time on my hands so I like playing the greyhounds. Using Excel I attempted to help myself save time by sorting out two columns at a time (Post - B-SPD) etc, because you have to sort some low and some high. The columns not marked Post are formula columns =abs(a3) etc. but when I try to sort the Post columns will sort, but the column I try to sort with it does not sort and match the post number it is assigned to.
Can this be done or does the =ABS formula prevent it. Plus even using =ABS some of the number are negative but the -minus sign does not appear. I have tried everything using numbers, using currency, using general, but nothing works. One person sent me to control panel to the Clock, Language, and Region settings. go additional setting and set your negative setting there. But that would not let the -minus sign show up on negative numbers either.
Is any of the above even possible?
POST B-SPD POST A-SPD POST 8TH POST L-SPD POST A-FIN
1 31.43 1 31.84 1 0 1 3 1 5.83
2 31.43 2 31.67 2 35.14 2 0 2 4.67
3 31.79 3 31.9 3 59.11 3 6 3 5.67
4 31.32 4 31.73 4 65.5 4 3 4 3.83
5 31.47 5 31.68 5 29.71 5 4 5 3.33
6 31.76 6 32.18 6 100 6 9 6 5.01
7 31.48 7 31.99 7 41.13 7 1 7 5.67
8 31.69 8 31.99 8 75.79 8 6 8 4.83
LOW LOW HIGH HIGH LOW
The requirement is not clear but use of ABS should not cause sorting issues. =ABS (for absolute) function is to strip out minus signs (so seems to be working properly).
OP may be advised to delete all but one of the POST columns, select headers and data (not including 'LOW' or 'HIGH') and Insert > Tables - Table, check My table has headers, OK, then use the filter buttons to choose whether to Sort Smallest to Largest or Sort Largest to Smallest for whichever attribute is to be ordered (the other columns will 'follow suit'). The filter button will show which button is determining the ordering and whether ascending or descending (eg table below is sorted descending on '8TH'):