when trying to open a file using wit open .. getting error that file doesn't exist.
I am trying to parse some txt files , when working localy it works with no issue, but the issue started when I am trying to connect to a network folder. the strange this is that is does see the file , but says its not found .
The Path I referring is '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*' (this folder is full of txt files.
but I am still getting this error:
FileNotFoundError: [Errno 2] No such file or directory: 'Console_log_01-01-2019_08-17-56.txt'
as you see , it does see the needed file .
in order to get to this file I am parsing splitting the path the follwoing way :
readFile = name.split("/")[9].split("\\")[1]
because if I am looking on the list of my files I see them the following way :
['//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\Console_log_01-01-2019_08-17-56.txt',
after splitting I am getting :
Console_log_01-01-2019_08-17-56.txt
and still it says the file is not found.
def main():
lines =0
path = '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*'
files = glob.glob(path)
print ("files")
print ('\n')
print(files)
for name in glob.glob(path):
print (path)
readFile = name.split("/")[9].split("\\")[1]
print(readFile)
with open(readFile,"r") as file:
lines = file.readlines()
print (lines)
main()
files
['//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\\Console_log_01-01-2019_08-17-56.txt', '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\\Console_log_01-01-2019_08-18-29.txt']
Traceback (most recent call last):
//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*
Console_log_01-01-2019_08-17-56.txt
File "C:/Users/markp/.PyCharmEdu2018.3/config/scratches/scratch_3.py", line 19, in <module>
main()
File "C:/Users/markp/.PyCharmEdu2018.3/config/scratches/scratch_3.py", line 16, in main
with open(readFile,"r") as file:
FileNotFoundError: [Errno 2] No such file or directory: 'Console_log_01-01-2019_08-17-56.txt'
Process finished with exit code 1
When you are looking for the file you are looking in the entire path, however when you are opening the file, you are referencing it as if it was in the local path, either change the current working directory with
os.chdir(path)
before opening the file, or in the open statement use
open(os.path.join(path,filename))
I recommend the first approach if you have to open only one file in your program and second if you open multiple files at multiple directories.
In future better format your questions, stack overflow has multiple tools, use them, also you can see how your text looks, make sure to have a look at it before posting. Use the code brackets for your code, that will help whoever is trying to answer.
Related
The txt file is saved in the exact same folder as my code but when I run it I get that traceback. I right clicked saved file directly to folder but when run the code vs studio. I am very new to code sorry for the basic question.
file = open('regex_sum_1114202.txt', 'r')
Traceback:
Traceback (most recent call last):
File "c:\Users\EM2750\Desktop\py4e\ex_11\ex_11.py", line 2, in <module>
file = open('regex_sum_1114202.txt', 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'regex_sum_1114202.txt'
screen shot of traceback
Try file = open('./regex_sum_1114202.txt', 'r') instead.
This explicitly specifies that Python should look for the file in the current directory by providing the relative path. Think of the point as a shorthand for the current working directory. So if the current working directory is the directory where the script and the file is, that should work.
Use forward slashes (/) instead of backslashes (\). Backslashes are the default directory separator on Windows, but here they make problems because they are interpreted as escape sequences by Python. Alternatively, you can use two backslashes after another as directory separator: \\.
You can also try to specify the full path before the filename: file = open('c:/Users/EM2750/Desktop/py4e/ex_11/regex_sum_1114202.txt', 'r'). The downside is of course that the path wouldn't be correct anymore if you'd move the file.
I`m creating a program that can read certain data from some txt files, the problem comes when I try to use the files inside subdirectories (the subdirectories are inside the main directory of the program. I'm using a for the option to find all the files and then create a new file with the info that I found. The main problem is that I can't read those files.
I tried using a for a function that creates a list of directories, files and roots, this works fine, but in the moment of running the file it says "it cannot be found txt file". The if not condition is made so the program excludes all.DS_Store files. I think the problem could be the way I open the file but im not sure
for root, directories, filenames in os.walk("Files_to_Insert"):
if not (filenames[-1] == ".DS_Store"):
lastFile = filenames[-1]
print lastFile
with open (lastFile, 'rt') as myfile:
IOError: [Errno 2] No such file or directory: txt
The mistake happens in the with open because it can`t find the file.
When I print I get all the txt files, but I can,t use them in the "with open"
A typical os.walk I use goes like this:
import os
for root, directories, filenames in os.walk("."):
for f in filenames:
if f.endswith(".DS_Store"):
continue
print(os.path.abspath(f))
with open (os.path.abspath(f), 'rt') as myfile:
I solve it by giving the path and the text file in separate strings:
for root, directories, filenames in os.walk("Files_to_Insert"):
if not(filenames[-1] == ".DS_Store"):
lastFile = filenames[-1]
# print (lastFile)
with open(str(root) + '/' + lastFile,'rt') as myfile:
I am trying to open 2 text files on PyCharm but it says file not found. Where do I put the files so they can be found?
I tried moving the files to the folder where all my PyCharm projects are kept but it didn't work.
dna = open('dna.txt', 'r')
dna.close()
dna_results = open("dnaresults.txt", "w")
dna_results.close()
Expected: I don't know honestly, for the text file to open on PyCharm so I can read it?
Actual: FileNotFoundError: [Errno 2] No such file or directory: 'dna.txt'
You need to pass the full path of the file in order to open it, for e.g. if the file is located at /home/john/dna.txt, you need to do.
dna = open('/home/john/dna.txt', 'r')
dna.close()
You can put your file anywhere you want, but you always need to pass the full path of the file in order to access it, otherwise the python interpreter doesn't know where to find it.
As an additional tidbit, if the dna.txt is located in the same folder as where the script is located, dna = open('dna.txt', 'r') will work
I am trying to get code to read from a .txt file, the file itself is within another file called driving_dataset. The files exist and it should be able to find the .txt file but it won't and I cannot tell what I am doing wrong..
I have triple checked for any spelling errors
#read data.txt
with open("driving_dataset/data.txt") as f:
for line in f:
xs.append("driving_dataset/" + line.split()[0])
It should be directed through driving_dataset folder to the data.txt file but it does not pick it up. and gives me the error
with open("driving_dataset/data.txt","r") as f:
FileNotFoundError: [Errno 2] No such file or directory: 'driving_dataset/data.txt'
I've made a small program in Python that reads text files. However, I keep getting the FileNotFoundError, even though the file exists. The seemingly problematic code of my code looks like this:
fileEntered = False
while not fileEntered:
try:
fileName = input("Enter file name: ")
file = open(fileName, "r")
fileEntered = True
fileContents = file.readlines()
file.close()
except FileNotFoundError:
print("File not found. Please try again.")
When asked for the file, I enter randomtext.txt (which is located in the same folder as the program), but it keeps throwing the FileNotFoundError (it keeps printing the line in the except block).
Will be able to tell whether you are getting Win Error 2 or Win Error 3 when you are opening the file? If Win Error 2, then the problem may be related to your current working directory. That means, the scripting is looking into a different folder eventhough the file exists. If you are getting Win Error 3, then it is a different issue.
I've amended your code to get exact error code.
fileName = input("Enter file name: ")
file = open(fileName, "r")
fileContents = file.readlines()
print(fileContents)
file.close()
I am getting FileNotFoundError: [Errno 2] No such file or directory: '454544.txt' (when there is not file exists - Errno 2]. When I tried with full path or relative path, the script works fine. Please try and get the actual error so that you can progress. If the file exists in your current working directory, then the script will work properly. Please change the working directory to try.