I've made a small program in Python that reads text files. However, I keep getting the FileNotFoundError, even though the file exists. The seemingly problematic code of my code looks like this:
fileEntered = False
while not fileEntered:
try:
fileName = input("Enter file name: ")
file = open(fileName, "r")
fileEntered = True
fileContents = file.readlines()
file.close()
except FileNotFoundError:
print("File not found. Please try again.")
When asked for the file, I enter randomtext.txt (which is located in the same folder as the program), but it keeps throwing the FileNotFoundError (it keeps printing the line in the except block).
Will be able to tell whether you are getting Win Error 2 or Win Error 3 when you are opening the file? If Win Error 2, then the problem may be related to your current working directory. That means, the scripting is looking into a different folder eventhough the file exists. If you are getting Win Error 3, then it is a different issue.
I've amended your code to get exact error code.
fileName = input("Enter file name: ")
file = open(fileName, "r")
fileContents = file.readlines()
print(fileContents)
file.close()
I am getting FileNotFoundError: [Errno 2] No such file or directory: '454544.txt' (when there is not file exists - Errno 2]. When I tried with full path or relative path, the script works fine. Please try and get the actual error so that you can progress. If the file exists in your current working directory, then the script will work properly. Please change the working directory to try.
Related
I`m creating a program that can read certain data from some txt files, the problem comes when I try to use the files inside subdirectories (the subdirectories are inside the main directory of the program. I'm using a for the option to find all the files and then create a new file with the info that I found. The main problem is that I can't read those files.
I tried using a for a function that creates a list of directories, files and roots, this works fine, but in the moment of running the file it says "it cannot be found txt file". The if not condition is made so the program excludes all.DS_Store files. I think the problem could be the way I open the file but im not sure
for root, directories, filenames in os.walk("Files_to_Insert"):
if not (filenames[-1] == ".DS_Store"):
lastFile = filenames[-1]
print lastFile
with open (lastFile, 'rt') as myfile:
IOError: [Errno 2] No such file or directory: txt
The mistake happens in the with open because it can`t find the file.
When I print I get all the txt files, but I can,t use them in the "with open"
A typical os.walk I use goes like this:
import os
for root, directories, filenames in os.walk("."):
for f in filenames:
if f.endswith(".DS_Store"):
continue
print(os.path.abspath(f))
with open (os.path.abspath(f), 'rt') as myfile:
I solve it by giving the path and the text file in separate strings:
for root, directories, filenames in os.walk("Files_to_Insert"):
if not(filenames[-1] == ".DS_Store"):
lastFile = filenames[-1]
# print (lastFile)
with open(str(root) + '/' + lastFile,'rt') as myfile:
I first noticed this problem a bit ago when I posted this thread. Essentially, I'm getting a very strange issue where Python "sees" files that don't actually exist in my file browser when working with files.
As in, if I open a file with an absolute path, modify and print the contents of it through Python, it will print exactly what it's supposed to. But when I try to open the same file through the same absolute path on my Windows file browser, the file is not updated with my modifications.
I experienced a similar issue recently as well - renaming files. Here's a simple script I wrote to replace all spaces in filenames with underscores.
rename.py:
import os
i = 0
path = "E:/sample_path/"
for filename in os.listdir(path):
src = path + filename
dst = path + filename.replace(" ", "_")
os.rename(src, dst)
i += 1
print(str(i) + " files processed.")
Upon doing some prints in Python, I can see that all the files in the directory are being renamed correctly but it just wasn't correctly updating when I actually viewed the directory. Both in the file browser and in using the dir command. Same with creating new files in Python, they exist in the eyes of Python, but they are nowhere to be found in Windows, even with hidden files being visible and all.
Now for the interesting part: This script works if I open the python editor in cmd and import it. So I know it's all correct, no syntax errors or anything - it's just a strange error occurring with Python.
For example, if I go into command prompt and type python rename.py it won't return any errors and will even output the correct results - x files processed. but it will not actually modify any "real" files.
But if I go into command prompt and type python to bring up the cmd editor, then type import rename it gives the correct output and updates all the files correctly. So for the time being this workaround helps, but it's a very strange issue and I have yet to see anyone else encounter it. It's almost like Python creates a temporary duplicate of the filesystem and is not completing it's sync back to Windows.
I've tried reinstalling Python several times, both x64 and x86 verisons and nothing has fixed it so far.
EDIT: Here's a simplified example illustrating my issue.
write.py:
f = open("newfile.txt", "w+")
f.write("hello new file")
f.close()
read.py:
f = open("newfile.txt", "r")
for l in f.readlines():
print(l)
If I run write.py, no errors are returned. But also no file named newfile.txt is visible in my current working directory. However, if I run read.py it prints hello new file. So clearly both of these are accessing the same invisible file somewhere.
I am trying to open 2 text files on PyCharm but it says file not found. Where do I put the files so they can be found?
I tried moving the files to the folder where all my PyCharm projects are kept but it didn't work.
dna = open('dna.txt', 'r')
dna.close()
dna_results = open("dnaresults.txt", "w")
dna_results.close()
Expected: I don't know honestly, for the text file to open on PyCharm so I can read it?
Actual: FileNotFoundError: [Errno 2] No such file or directory: 'dna.txt'
You need to pass the full path of the file in order to open it, for e.g. if the file is located at /home/john/dna.txt, you need to do.
dna = open('/home/john/dna.txt', 'r')
dna.close()
You can put your file anywhere you want, but you always need to pass the full path of the file in order to access it, otherwise the python interpreter doesn't know where to find it.
As an additional tidbit, if the dna.txt is located in the same folder as where the script is located, dna = open('dna.txt', 'r') will work
when trying to open a file using wit open .. getting error that file doesn't exist.
I am trying to parse some txt files , when working localy it works with no issue, but the issue started when I am trying to connect to a network folder. the strange this is that is does see the file , but says its not found .
The Path I referring is '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*' (this folder is full of txt files.
but I am still getting this error:
FileNotFoundError: [Errno 2] No such file or directory: 'Console_log_01-01-2019_08-17-56.txt'
as you see , it does see the needed file .
in order to get to this file I am parsing splitting the path the follwoing way :
readFile = name.split("/")[9].split("\\")[1]
because if I am looking on the list of my files I see them the following way :
['//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\Console_log_01-01-2019_08-17-56.txt',
after splitting I am getting :
Console_log_01-01-2019_08-17-56.txt
and still it says the file is not found.
def main():
lines =0
path = '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*'
files = glob.glob(path)
print ("files")
print ('\n')
print(files)
for name in glob.glob(path):
print (path)
readFile = name.split("/")[9].split("\\")[1]
print(readFile)
with open(readFile,"r") as file:
lines = file.readlines()
print (lines)
main()
files
['//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\\Console_log_01-01-2019_08-17-56.txt', '//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs\\Console_log_01-01-2019_08-18-29.txt']
Traceback (most recent call last):
//10.8.4.49/Projects/QASA_BR_TCL_Env_7.2.250/Utils/BR_Env/Call Generator/results/Console_Logs/*
Console_log_01-01-2019_08-17-56.txt
File "C:/Users/markp/.PyCharmEdu2018.3/config/scratches/scratch_3.py", line 19, in <module>
main()
File "C:/Users/markp/.PyCharmEdu2018.3/config/scratches/scratch_3.py", line 16, in main
with open(readFile,"r") as file:
FileNotFoundError: [Errno 2] No such file or directory: 'Console_log_01-01-2019_08-17-56.txt'
Process finished with exit code 1
When you are looking for the file you are looking in the entire path, however when you are opening the file, you are referencing it as if it was in the local path, either change the current working directory with
os.chdir(path)
before opening the file, or in the open statement use
open(os.path.join(path,filename))
I recommend the first approach if you have to open only one file in your program and second if you open multiple files at multiple directories.
In future better format your questions, stack overflow has multiple tools, use them, also you can see how your text looks, make sure to have a look at it before posting. Use the code brackets for your code, that will help whoever is trying to answer.
I'm working on a Python3 script where the code walks through directories and sub-directories to pull out all gzipped warc files.
I'd like to also add that the files are not in my home directory
file_path = os.path.join('/nappa7/pip73/Service')
walk_file(parallel_bulk, file_path)
Perhaps python is not looking where i think it's looking, nevertheless, here is my walk_file functions:
def walk_file(bulk, file_path):
warc = warcat.model.WARC()
try:
for (file_path,dirs,files) in os.walk(file_path):
for filenames in files:
if filenames.endswith('.warc.gz'):
warc.load(filenames)
except ValueError:
pass
When I replace the warc.load(filenames) with a print statement like so:
if filenames.endswith('.warc.gz'):
print(filenames)
The filenames are printed out onto the console as expected. Therefore, It leads me to believe that python was able to succesfully locate all warc.gz files. However, when i try the warc.load(filenames), i get:
FileNotFoundError: [Errno 2] No such file or directory: 'Sample.warc.gz'
I can certainly use some guidance.
Thank you.
So for anyone else who has a similar issue:
changing the code to this worked:
warc.load(os.path.join(file_path, filenames))
You need to use os.path.join(file_path, filenames) instead of just filenames.
Otherwise the operating system will look for the file in the current directory instead of file_path.
(And why is filenames plural when it refers to a single filename?)