Searching a specific file system in bash - linux

I have a task which asks to write a script which displays all partitions formatted with a specific file system, given as parameter.
I have written the script but when i run it it displays '0'. What am i doing wrong?
This is my code:
#!/bin/bash
n=sudo parted -l | tail -n +8 | awk '{print $5}' | wc | awk '{print $2}'
m=sudo parted -l | tail -n +8 | awk '{print $5}'
q=sudo parted -l | tail -n +8
for i in $n; do
if [ "[ $m | sed -n ip ]" = "$1" ]; then
echo "$q | sed -n ip"
fi
done

Different approach from yours, but does it do what you need?
lsblk -f | awk '$0 ~ fs {print $NF}' fs=ext2

Related

Awk: parse node names out of "40*r13n15:40*r10n61:40*r11n18:40*r09n15"

I have a linux script for selecting the node.
For example:
4
40*r13n15:40*r10n61:40*r11n18:40*r09n15
The correct result should be:
r13n15
r10n61
r11n18
r09n15
My linux script content is like:
hostNum=`bjobs -X -o "nexec_host" $1 | grep -v NEXEC`
hostSer=`bjobs -X -o "exec_host" $1 | grep -v EXEC`
echo $hostNum
echo $hostSer
for i in `seq 1 $hostNum`
do
echo $hostSer | awk -F ':' '{print '$i'}' | awk -F '*' '{print $2}'
done
But unlucky, I got nothing about node information.
I have tried:
echo $hostSer | awk -F ':' '{print "'$i'"}' | awk -F '*' '{print $2}'
and
echo $hostSer | awk -F ':' '{print '"$i"'}' | awk -F '*' '{print $2}'
But there are wrong. Who can give me a help?
One more awk:
$ echo "$variable" | awk 'NR%2==0' RS='[*:\n]'
r13n15
r10n61
r11n18
r09n15
By setting the record separtor(RS) to *:\n , the string is broken into individual tokens, after which you can just print every 2nd line(NR%2==0).
You can use multiple separators in awk. Please try below:
h='40*r13n15:40*r10n61:40*r11n18:40*r09n15'
echo "$h"| awk -F '[:*]' '{ for (i=2;i<=NF;i+=2) print $i }'
**edited to make it generic based on the comment from RavinderSingh13.

How to direct linux bash script output to one line per host

I'd like to change my script(s) so that the command output is separated by a comma and is all on one line per host. Any ideas on how I can achieve this:
1st Script:
#!/bin/bash
for i in `cat ~/hostnames.txt`
do
ssh -q $i 'bash -s' < server_info.sh
done
2nd Script (server_info.sh):
#!/bin/bash
echo -n "Name: "
uname -n
echo -n "CPUs: "
cat /proc/cpuinfo* | grep processor | wc -l
echo -n "Memory (kb): "
cat /proc/meminfo | grep MemTotal: | awk '{print $2}'
echo -n "Current Kernel: "
uname -a | awk '{print $3}'
echo -n "IP: "
hostname -i
echo -e
Changing your 1st script:
#!/bin/bash
for i in cat ~/hostnames.txt
do
ssh -q $i 'bash -s' < server_info.sh
done | awk -v RS= '{$1=$1}1'
Note: Your server_info.sh can be a lot more optimized.For example:
cat /proc/meminfo | grep MemTotal: | awk '{print $2}'
could be changed to:
awk '/MemTotal:/{print $2}' /proc/meminfo

Echo result from Linux file with dynamic filename

I have a tomcat server I am trying to get a list of info on for a project. I need to get the results from /etc/default/tomcat file. However some of my servers are tomcat6 and some are tomcat7 so hardcoding the filename is not going to work.
How would I dynamically insert the filename in this batch script.
#!/bin/bash
echo Server Name: `hostname`
echo CPU: `top -b -n1 | grep "Cpu(s)" | awk '{print $2 + $4}'`
FREE_DATA=`free -m | grep Mem`
CURRENT=`echo $FREE_DATA | cut -f3 -d' '`
TOTAL=`echo $FREE_DATA | cut -f2 -d' '`
echo Internal IP : `ifconfig eth0 2>/dev/null|awk '/inet addr:/ {print $2}'|sed 's/addr://'`
echo OS Memory: `cat /proc/meminfo | grep MemTotal | awk '{ print $2 }'`
echo Operating System: `uname -mrs`
***echo Tomcat Memory: `cat /etc/default/tomcat6 | grep Xmx | awk '{ print $5}'`***
Your last command can be simplified to single awk like this:
awk '/Xmx/{print "Tomcat Memory:", $5}' "$tomcatFile"
Pass "$tomcatFile" whatever tomcat filename from ver6 or ver7.
You can get output from both tomcat files in same command using:
awk '/Xmx/{print "Tomcat Memory:", $5}' /etc/default/tomcat[67]

Shell command with operator followed by pipes

I want a one line command to grab the most recent restart date from JBoss restart logs. I'm currently using the following, which works
ls -rt $JBOSS_HOME/log/ser* |
xargs grep -ih "Incomplete\s*Deploy" |
awk '{print $1" "$2}' | tail -n 1
Now, I want to add an echo if the grep fails to match anything, i.e.:
ls -rt $JBOSS_HOME/log/ser* |
xargs grep -ih "Incomplete\s*Deploy" ||
echo 'NO RESTART' |
awk '{print $1" "$2}' |
tail -n 1
The problem here is that it seems that the OR operator now causes anything following to go with the failed case. How do I specify that I want to OR (echo) to be printed only when the grep fails? When the grep succeeds it should work like the first command I posted.
Use { to group the terms:
ls -rt $JBOSS_HOME/log/ser* |
xargs grep -ih "Incomplete\s*Deploy" && {
awk '{print $1" "$2}' |
tail -n 1
} ||
echo 'NO RESTART'
or as one line:
ls -rt $JBOSS_HOME/log/ser* | xargs grep -ih "Incomplete\s*Deploy" && { awk '{print $1" "$2}' | tail -n 1; } || echo 'NO RESTART'
No additional subshell required.
You can group commands within a pipe by using parentheses:
ls -rt $JBOSS_HOME/log/ser* | ( xargs grep -ih "Incomplete\s*Deploy" || echo 'NO RESTART' ) | awk '{print $1" "$2}' | tail -n 1
This makes the commands in the parentheses run in a subshell, which from the standpoint of the pipe, makes them work as a single command, i.e. they'll take the input and either print the grep match or 'NO RESTART', and then that will be fed into awk.
res=$(ls -rt $JBOSS_HOME/log/ser* | xargs grep -ih "Incomplete\s*Deploy" | awk '{print $1" "$2}' | tail -n 1)
echo "${res:-NO RESTART}"
Also note that this is not safe for filenames with spaces/etc.

Getting error while running script to find disk space

I am running below script:-
#!/bin/bash
threshold="20"
i=2
result=`df -kh |grep -v “Filesystem” | awk ‘{ print $5 }’ | sed ‘s/%//g’`
for percent in $result; do
if ((percent > threshold))
then
partition=`df -kh | head -$i | tail -1| awk ‘{print $1}’`
echo “$partition at $(hostname -f) is ${percent}% full”
fi
let i=$i+1
done
But I get the following error:
awk: ‘{
awk: ^ invalid char '▒' in expression
sed: -e expression #1, char 1: unknown command: `▒'
Please help me to resolve this.
What awk does not work? (your script does work fine on my Ubuntu)
This line:
result=`df -kh |grep -v "Filesystem" | awk '{ print $5 }' | sed 's/%//g'`
could be changed to:
result=$(df -kh | awk '!/Filesystem/ {print $5+0}')
Avoid using old and outdated backtics if parentheses works like this: var=$(code...)
This:
partition=`df -kh | head -$i | tail -1| awk '{print $1}'`
could be changed to:
partition=$(df -kh | awk -v line="$i" 'NR==line {print $1}')
This
let i=$i+1
could be change to:
((i++))
This would then give some like this:
#!/bin/bash
threshold="20"
i=2
result=$(df -kh | awk '!/Filesystem/ {print $5+0}')
for percent in $result; do
if ((percent > threshold))
then
partition=$(df -kh | awk -v line="$i" 'NR==line {print $1}')
echo "$partition at $(hostname -f) is ${percent}% full"
fi
((i++))
done
You're using ‘ for a single quote not '. Try re-encoding your file with an editor.
You got the answer to your syntax error, now re-write the whole script as just:
#!/bin/bash
df -kh |
awk -v t=20 -v h="$(hostname -f)" '(NR>1)&&($5+0>t){printf "%s at %s is %s full\n",$1,h,$5}'

Resources