I am running below script:-
#!/bin/bash
threshold="20"
i=2
result=`df -kh |grep -v “Filesystem” | awk ‘{ print $5 }’ | sed ‘s/%//g’`
for percent in $result; do
if ((percent > threshold))
then
partition=`df -kh | head -$i | tail -1| awk ‘{print $1}’`
echo “$partition at $(hostname -f) is ${percent}% full”
fi
let i=$i+1
done
But I get the following error:
awk: ‘{
awk: ^ invalid char '▒' in expression
sed: -e expression #1, char 1: unknown command: `▒'
Please help me to resolve this.
What awk does not work? (your script does work fine on my Ubuntu)
This line:
result=`df -kh |grep -v "Filesystem" | awk '{ print $5 }' | sed 's/%//g'`
could be changed to:
result=$(df -kh | awk '!/Filesystem/ {print $5+0}')
Avoid using old and outdated backtics if parentheses works like this: var=$(code...)
This:
partition=`df -kh | head -$i | tail -1| awk '{print $1}'`
could be changed to:
partition=$(df -kh | awk -v line="$i" 'NR==line {print $1}')
This
let i=$i+1
could be change to:
((i++))
This would then give some like this:
#!/bin/bash
threshold="20"
i=2
result=$(df -kh | awk '!/Filesystem/ {print $5+0}')
for percent in $result; do
if ((percent > threshold))
then
partition=$(df -kh | awk -v line="$i" 'NR==line {print $1}')
echo "$partition at $(hostname -f) is ${percent}% full"
fi
((i++))
done
You're using ‘ for a single quote not '. Try re-encoding your file with an editor.
You got the answer to your syntax error, now re-write the whole script as just:
#!/bin/bash
df -kh |
awk -v t=20 -v h="$(hostname -f)" '(NR>1)&&($5+0>t){printf "%s at %s is %s full\n",$1,h,$5}'
Related
I have a linux script for selecting the node.
For example:
4
40*r13n15:40*r10n61:40*r11n18:40*r09n15
The correct result should be:
r13n15
r10n61
r11n18
r09n15
My linux script content is like:
hostNum=`bjobs -X -o "nexec_host" $1 | grep -v NEXEC`
hostSer=`bjobs -X -o "exec_host" $1 | grep -v EXEC`
echo $hostNum
echo $hostSer
for i in `seq 1 $hostNum`
do
echo $hostSer | awk -F ':' '{print '$i'}' | awk -F '*' '{print $2}'
done
But unlucky, I got nothing about node information.
I have tried:
echo $hostSer | awk -F ':' '{print "'$i'"}' | awk -F '*' '{print $2}'
and
echo $hostSer | awk -F ':' '{print '"$i"'}' | awk -F '*' '{print $2}'
But there are wrong. Who can give me a help?
One more awk:
$ echo "$variable" | awk 'NR%2==0' RS='[*:\n]'
r13n15
r10n61
r11n18
r09n15
By setting the record separtor(RS) to *:\n , the string is broken into individual tokens, after which you can just print every 2nd line(NR%2==0).
You can use multiple separators in awk. Please try below:
h='40*r13n15:40*r10n61:40*r11n18:40*r09n15'
echo "$h"| awk -F '[:*]' '{ for (i=2;i<=NF;i+=2) print $i }'
**edited to make it generic based on the comment from RavinderSingh13.
I have a task which asks to write a script which displays all partitions formatted with a specific file system, given as parameter.
I have written the script but when i run it it displays '0'. What am i doing wrong?
This is my code:
#!/bin/bash
n=sudo parted -l | tail -n +8 | awk '{print $5}' | wc | awk '{print $2}'
m=sudo parted -l | tail -n +8 | awk '{print $5}'
q=sudo parted -l | tail -n +8
for i in $n; do
if [ "[ $m | sed -n ip ]" = "$1" ]; then
echo "$q | sed -n ip"
fi
done
Different approach from yours, but does it do what you need?
lsblk -f | awk '$0 ~ fs {print $NF}' fs=ext2
Below you seen my real code, I suppose it can be simplified to
$ echo 123456789012 | awk '{print $1}'
123456789012
Question
How can I get awk to add colons, it outputs 12:34:56:78:90:12 instead?
grep -v '^#' $hosts | grep -E '[0-9A-F]{12}\b' | grep -v 000000000000 | awk '{
print "host "$5" {"
print " option host-name \""$5"\";"
print " hardware ethernet "$3";"
print " fixed-address "$1";"
print "}"
print ""
}' > /etc/dhcp/reservations.conf
another way
$ echo 123456789012 | fold -w2 | paste -sd:
12:34:56:78:90:12
here is a different gawk version
$ echo 123456789012 | awk -v FPAT='..' -v OFS=':' '{$1=$1}1'
12:34:56:78:90:12
One more:
echo 0123456789ab | awk '{gsub(/..\B/,"&:")}1'
another way is to make use of gawk's FIELDWIDTHS
awk -v FIELDWIDTHS='2 2 2 2 2 2' -v OFS=":" '1+($1=$1)'
Could you please try following.
echo 123456789012 | awk '{gsub(/../,"&:");sub(/:$/,"")} 1'
I'm monitoring from an actively written to file:
My current solution is:
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | grep -q -e "enterpriseID:"
if [ $? = 0 ]
then
((ws_trans++))
fi
echo $LINE | grep -q -e "sc_ID:"
if [ $? = 0 ]
then
((sc_trans++))
fi
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
However when attempting to do this with AWK I don't get the output - the $ws_trans and $sc_trans remains 0
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | awk '/enterpriseID:/ {++ws_trans} END {print | ws_trans}'
echo $LINE | awk '/sc_ID:/ {++sc_trans} END {print | sc_trans}'
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
Attempting to do this to reduce load. I understand that AWK doesn't deal with bash variables, and it can get quite confusing, but the only reference I found is a non tail application of AWK.
How can I assign the AWK Variable to the bash ws_trans and sc_trans? Is there a better solution? (There are other search terms being monitored.)
You need to pass the variables using the option -v, for example:
$ var=0
$ printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} {print awk_var}'
To set the variable "back" you could use declare, for example:
$ declare $(printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} END {print "var=" awk_var}')
$ echo $var
$ 10
Your script could be rewritten like this:
ws_trans=0
sc_trans=0
tail -F /var/log/system.log |
while read LINE
do
declare $(echo $LINE | awk -v ws=${ws_trans} '/enterpriseID:/ {++ws} END {print "ws_trans="ws}')
declare $(echo $LINE | awk -v sc=${sc_trans} '/sc_ID:/ {++sc} END {print "sc_trans="sc}')
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
I have a command that is giving me the output:
/home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611
I need the output to be:
ea66574ff0daad6d0406f67e4571ee08 counted-file.xml
The closest I got was:
$ echo /home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611 | awk '{ printf "%s", $1 }; END { printf "\n" }'
/home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08
I'm not familiar with awk but I believe this is the command I want to use, any one have any ideas?
Or just a sed oneliner:
echo /home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611 \
| sed -E 's/.*:(.*\.xml).*/\1/'
$ echo "/home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611" |
cut -d: -f2 |
cut -d. -f1-2
ea66574ff0daad6d0406f67e4571ee08 counted-file.xml
Note that this relies on the dot . being present as in counted-file.xml.
$ awk -F[:.] -v OFS="." '{print $2,$3}' <<< "/home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611"
ea66574ff0daad6d0406f67e4571ee08 counted-file.xml
not sure if this is ok for you:
sed 's/^.*:\(.*\)\.[^.]*$/\1/'
with your example:
kent$ echo "/home/konnor/md5sums:ea66574ff0daad6d0406f67e4571ee08 counted-file.xml.20131003-083611"|sed 's/^.*:\(.*\)\.[^.]*$/\1/'
ea66574ff0daad6d0406f67e4571ee08 counted-file.xml
this grep line works too:
grep -Po ':\K.*(?=\..*?$)'