So I have a double loop that for some reason always skips to my outer loop for some reason. The loop goes from:
For j = lastColumn To 6 Step (-1)
to:
Next i
every single time. However, in my data set there's a mixed variety of data which should be captured in my if statement and count the data.
Any ideas? Maybe I formatted the macro wrongly.
Sub CheckDates()
Dim count As Integer
Dim i As Integer
Dim j As Integer
Sheets(1).Select
lastrow = ActiveSheet.Cells(Rows.count, "B").End(xlUp).Row
'have to keep data in a table for this to actually work as it ctrls+left to the table, which will end where the very last text of any row is
lastColumn = ActiveSheet.Cells(1, Columns.count).End(xlToLeft).Column
count = 0
i = 3
j = lastColumn
For i = 3 To lastrow
For j = lastColumn To 6 Step (-1)
If Sheet1.Cells(i, j) < Sheet2.Cells(1, 1) And Sheet1.Cells(i, j - 1) = "Reçu" Then
count = count + 1
GoTo NextIteration
End If
Next j
NextIteration:
Next i
Sheet2.Cells(1, 7) = count
Sheets(2).Select
'Runs the DeleteSAC Macro
Call DeleteSAC
End Sub
I don't quite follow what you're doing, but try this instead. Notice the Exit For. This should produce the result you're looking for, without the For-Next counter variables getting confused.
For i = 3 To lastrow
For j = lastColumn To 6 Step (-1)
If Sheet1.Cells(i, j) < Sheet2.Cells(1, 1) And Sheet1.Cells(i, j - 1) = "Reçu" Then
count = count + 1
Exit For
End If
Next j
Next i
Simplification
Use Long for rows, and Integer for columns.
When you write With Sheet1, everywhere where you should write Sheet1, e.g. Sheet1.Range(whatever)... you can write just .Range(whatever) instead, until you close with End With.
The Exit For exits only the For Loop where it is in. So it does exactly what you are doing with your Goto line, but you are using a line more.
When you use Sheet1 or Sheet2 etc. you are actually using code names so you can change the names in the tab and the code will still run.
Counting backwards is usually used when you delete row by row so there is no need to do so since you are only counting.
Option Explicit
Sub CheckDates()
Dim dataCount As Long
Dim i As Long
Dim j As Integer
Dim lastrow As Long
With Sheet1
lastrow = .Cells(.Rows.count, "B").End(xlUp).Row
'have to keep data in a table for this to actually work as it ctrls+left
'to the table, which will end where the very last text of any row is
lastColumn = .Cells(1, .Columns.count).End(xlToLeft).Column
For i = 3 To lastrow
For j = 6 To lastColumn
If .Cells(i, j) < Sheet2.Cells(1, 1) And .Cells(i, j - 1) = "Reçu" Then
dataCount = dataCount + 1
Exit For
End If
Next
Next
End With
With Sheet2
.Cells(1, 7) = dataCount
.Select
End With
'Runs the DeleteSAC Macro
DeleteSAC
End Sub
Related
I have a table with information in column A and an appropriate value in column B. I want to write a macro that inserts a new row for each "Person" in dependence of the value in column B and copies the original information into that row, which for example means that in the end there are 5 rows with "Person A", 2 rows for "Person B" etc.
original table:
result:
My first approach looks like that. It doesn't work.
Dim i, j, k As Integer
For i = Range("A" & Range("A:A").Rows.Count).End(xlUp).Row To 1 Step -1
For j = 1 To Range("B" & i)
Rows(i).Select
Selection.Insert Shift:=xlDown
k = k + j
Range(Cells(k, 1), Cells(k, 2)).Copy Destination:=Range("A" & i)
Next j
Next i
This would work for you, changing the number of inserts based on value in column B:
Option Explicit
Sub test()
With Sheets(1)
Dim lastRow As Long: lastRow = .Cells(.Rows.Count, 1).End(xlUp).Row
Dim i As Long
For i = lastRow To 1 Step -1
If IsNumeric(.Cells(i, 2).Value) = True Then
Dim numberOfInserts As Long
numberOfInserts = .Cells(i, 2).Value - 1
If numberOfInserts > 0 Then
Dim insertCount As Long
For insertCount = 1 To numberOfInserts
.Rows(i).Copy
.Rows(i).Insert
Next insertCount
End If
End If
Next i
End With
End Sub
First we check that you're dealing with numbers. Second you have a single line already, so number -1, then that this number is >0. Lastly, you insert via a loop which does the counting for you.
Test data:
Output after running:
Your index calculation is messed up. Use the debugger, step thru the code (F8) and notice what happens:
a) Your Select/Insert-construct creates a new row above the row you want to copy, not below.
b) Your calculation of index k fails: You are not initializing k, so it starts with value 0. Than you add j (1..3) to k, resulting in values 1, 3, 6, and copy data from that line.
I would suggest you take a different approach: Copy the original data into an array and then loop over that array. This avoids multiple Select, Copy and Insert statements (that are slow) and allow to copy the data from top to bottom.
Sub copy()
Dim rowCount As Long
Dim data As Variant
With ActiveSheet ' Replace with the sheet you want to work with
' Copy the current table into array
rowCount = .Cells(.Rows.Count, 1).End(xlUp).row
data = .Range(.Cells(1, 1), .Cells(rowCount, 2))
Dim oldRow As Long, newRow As Long
newRow = 1
' Loop over old data
For oldRow = 1 To rowCount
Dim repeatCount As Long
repeatCount = Val(data(oldRow, 2)) ' We want to have so many occurrences of the row
if repeatCount <= 0 Then repeatCount=1
Dim col As Long
' Create "repeatCount" rows of data (copy column by column)
For col = 1 To 2
.Cells(newRow, col).Resize(repeatCount, 1) = data(oldRow, col)
Next col
newRow = newRow + repeatCount
Next
End With
End Sub
I am trying to do a "for each" sub in VBA, comparing two pairs of rows and the values in each cell to one another. For example row 2 is compared with row 3, row 4 is compared with row 5 etc. I need the code to highlight the differences in each cell for each of the comparisons. This is what I have so far and I cannot seem to get it to work. Any thought?
Sub testing_2()
Dim rw_2 As Range, rw_1 As Range, decisions As String
decisions = MsgBox("Check accuracy?", vbYesNo)
If decisions = vbYes Then
For Each rw_1 In Worksheets("worksheet").Rows
For Each rw_2 In Worksheets("worksheet").Rows
If Not StrComp(rw_1.row Mod 2 = 0, rw_2.row Mod 2 = 1, vbBinaryCompare) = 0 Then
Range(rw_1.row Mod 2 = 0, rw_2.row Mod 2 = 1).Interior.ColorIndex = 6
End If
Next rw_2
Next rw_1
Else: End If
End Sub
Thank you!
Basically, I am looking at each row, two at a time, and highlighting the different values between them.
One loop to to loop the rows stepping 2 rows at a time and another loop to loop the columns
Sub testing_2()
decisions = MsgBox("Check accuracy?", vbYesNo)
If decisions = vbYes Then
With Worksheets("Sheet4") ' change to your sheet
Dim lstRw As Long
lstRw = .Cells(.Rows.Count, 1).End(xlUp).Row
Dim lstClm As Long
lstClm = .Cells(1, Columns.Count).End(xlToLeft).Column
Dim i As Long
For i = 2 To lstRw Step 2
Dim j As Long
For j = 2 To lstClm
If .Cells(i, j) <> .Cells(i + 1, j) Then
.Range(.Cells(i, j), .Cells(i + 1, j)).Interior.ColorIndex = 6
End If
Next j
Next i
End With
End If
End Sub
I would like to make every set of eight rows move into columns in Excel for example here is a set with every four rows broken into columns:
From this:
To this:
I've tried this code in VBA which I've seen in a previous question found on https://superuser.com/questions/583595/move-every-7-columns-into-new-row-in-excel
Dim i As Integer, j As Integer, cl As Range
Dim myarray(100, 6) As Integer 'I don't know what your data is. Mine is integer data
'Change 100 to however many rows you have in your original data, divided by seven, round up
'remember arrays start at zero, so 6 really is 7
If MsgBox("Is your entire data selected?", vbYesNo, "Data selected?") <> vbYes Then
MsgBox ("First select all your data")
End If
'Read data into array
For Each cl In Selection.Cells
Debug.Print cl.Value
myarray(i, j) = cl.Value
If j = 6 Then
i = i + 1
j = 0
Else
j = j + 1
End If
Next
'Now paste the array for your data into a new worksheet
Worksheets.Add
Range(Cells(1, 1), Cells(101, 7)) = myarray
End Sub
However, it only seems to work with integers and not data that has both numbers and letters if I am understanding correctly.
I get an error:
Run-time error '13':
Type mismatch
This should do it
Sub movedata()
Dim rowcounter, colcounter, rowcounter2 As Long
colcounter = 3
rowcounter2 = 1
For rowcounter = 1 To Cells(Cells.Rows.Count, 1).End(xlUp).Row
If Cells(rowcounter, 1).Value2 <> "" Then
Cells(rowcounter2, colcounter).Value2 = Cells(rowcounter, 1).Value2
colcounter = colcounter + 1
Else
rowcounter2 = rowcounter2 + 1
colcounter = 3
End If
Next rowcounter
End Sub
So you basically want to transpose the used range of a given sheet? This code may
Option Explicit
Sub transpose()
Dim a As Integer, x As Integer
a = 1 + Cells(1, 1).End(xlToRight).Column
ActiveSheet.UsedRange.Copy
Cells(1, a).Select
Selection.PasteSpecial Paste:=xlPasteAll, transpose:=True
Cells(1, 1).Select
For x = 1 To (a - 1)
Columns(1).Delete
Next x
End Sub
It works as follows:
- find the last used column and define "a" as this columnnumber + 1
- Copy the used range (where your data is)
- transpose into cells(1,a)
- select cells(1,1)
- delete this column (a-1) times
Is this what you are looking for?
I am trying to figure out some code here, I have looked on a few sites now, including here and it almost works but it is most likely my datasheet that is causing the issue.
This: Search for two values and copy everything in between in a loop
and this: I need code to copy between two rows and paste into the another sheet with our giving any values?
Would probably work, however the first value cannot be found. Let me explain.
I have an exported report from a website, it groups the totals with a name (value 1) and then the word totals for: (word 2).
What I need it to do is only copy and paste where value 1 is met , and value 2 will always be "totals for:".
Problem is with this loop is that there are blanks between each group of data, so it finds the first "totals for:" but cannot find my first value because it is between about 20 blank cells. (19 groups of data - with a blank row between each group).
How can i retro fix the above codes so that it keeps going down the rows, regardless of blanks to find the first value, then find the second value. Copy that range to a new sheet, and repeat this with a new value 1?
Sub MoveRows()
Dim rownum As Integer
Dim colnum As Integer
Dim startrow As Integer
Dim endrow As Integer
rownum = 1
colnum = 1
With ActiveWorkbook.Worksheets("Sheet1")
Do
If .Cells(rownum, 1).Value = "LIFEC - Supp Life - Ch" Then
startrow = rownum
End If
rownum = rownum + 1
Loop Until .Cells(rownum, 1).Value = "Totals for:"
endrow = rownum
ActiveWorkbook.Worksheets("Sheet1").Range(startrow & ":" & endrow).Copy
End With
ActiveWorkbook.Worksheets("Sheet2").Paste
End Sub
Sub Star123()
Dim rownum As Long
Dim colnum As Long
Dim startrow As Long
Dim endrow As Long
Dim lastrow As Long
rownum = 1
colnum = 1
lastrow = Worksheets("Sheet1").Range("A65536").End(xlUp).Row
With ActiveWorkbook.Worksheets("Sheet1").Range("A1:A" & lastrow)
For rownum = 1 To lastrow
Do
If .Cells(rownum, 1).Value = "LIFEC - Supp Life - Ch" Then
startrow = rownum
End If
rownum = rownum + 1
If (rownum > lastrow) Then Exit For
Loop Until .Cells(rownum, 1).Value = "Totals for:"
endrow = rownum
rownum = rownum + 1
Worksheets("Sheet1").Range(startrow & ":" & endrow).Copy
Sheets("Sheet2").Select
Range("A1").Select
ActiveSheet.Paste
Next rownum
End With
End Sub
I attached the codes that almost work, but cannot find my first value.
You can use Find method which looks something like:
Dim s As Range, e As Range
With Sheet1 'or this can be any other sheet where you search
Set r = .Range("A:A").Find("Whatever you want found")
If Not r Is Nothing Then
Set e = .Range("A:A").Find("The other end", r)
If Not e Is Nothing Then
.Range(r, e).EntireRow.Copy Sheet2.Range("A1") 'or to whatever sheet
End If
End If
End With
You can then have this in a loop which replaces the strings you want found. HTH.
I'm trying to delete all rows with cell values non equivalent to one of the values from array Ar(). When I put logical operator NOT loop goes infinite for some reason (excel freezes). In opposite it works flawlessly, in case if I would want to delete rows containing values from array.
The problem is on line:
If Not .Cells(i, 10).Value = Ar(j) Then
My code:
Sub Tims()
Dim LastRow As Long, LR As Long
Dim i As Long, j As Long
Dim t As Integer
Dim Ar() As String
Worksheets("Start").Activate
t = Count("a", Range("A3:A14"))
LR = Range("I3:I10").End(xlDown).Row
Worksheets("Master").Activate
Sheets("Master").Range("A100:A" & 100 + LR - 3).Value = Sheets("start").Range("I3:I" & LR).Value
With Worksheets("Master")
For j = 1 To LR - 2
ReDim Preserve Ar(j)
Ar(j) = Cells(99 + j, 1)
Next j
End With
With Worksheets("Master")
LastRow = .Cells(.Rows.Count, "B").End(xlUp).Row
End With
Worksheets("Master").Activate
For j = 1 To LR - 2
For i = 1 To LastRow
With Worksheets("Master")
If Not .Cells(i, 10).Value = Ar(j) Then
.Cells(i, 10).EntireRow.Delete
i = i - 1
End If
End With
Next i
Next j
End Sub
The line causing the infinite loop is this one:
i = i - 1
Get rid of it, and replace this
For i = 1 To LastRow
with this
For i = LastRow To 1 Step -1
I see why you tried i = i - 1 in order to avoid skipping a row each time a row is deleted. But that doesn't work: if a row gets deleted, then it is replaced by an empty row at the bottom of your table, and eventually you reach it. This empty row obviously does not contain any of the values in your array Ar(j), so it gets deleted and replaced by another empty row, which then gets deleted and replaced by another empty row, ad infinitum.
You could have figured this out yourself had you stepped through your code in debug mode.
Instead, just iterate from the bottom up using Step -1.