I recently got into python3.x and want to have a script where a random number is generated and stored in a variable, the user has to input a number and the script then checks if the number is greater or smaller (or the same) than the generated number and answers accordingly.
So far I got
import random
n = random.randint(1, 101)
a = input("Please enter your number: ")
while not(int(a) == n):
if(int(a) > n)
print("Your number is smaller."):
elif(int(a) < n)
print("Your number is greater."):
But in this code I get "Invalid Syntax in line 5", the first if. How do I get rid of that? Also, how do I loop the whole while-block until the number is correct?
You are missing a colon on line 5 and you have colons on like 6 and 8.
You should read up on a python tutorial somewhere on how the python syntax works, but in general colons are used to denote a new indented block, so whenever you write indented code, it should be preceeded by a colon
Try this: Actually you left colon in if and elif at last.
import random
n = random.randint(1, 101)
a = input("Please enter your number: ")
while not(int(a) == n):
if(int(a) > n):
print("Your number is smaller.")
elif(int(a) < n):
print("Your number is greater.")
Related
I am new to python and Jupyter Notebook
The objective of the code I am writing is to request the user to introduce 10 different integers. The program is supposed to return the highest odd number introduced previously by the user.
My code is as followws:
i=1
c=1
y=1
while i<=10:
c=int(input('Enter an integer number: '))
if c%2==0:
print('The number is even')
elif c> y
y=c
print('y')
i=i+1
My loop is running over and over again, and I don't get a solution.
I guess the code is well written. It must be a slight detail I am not seeing.
Any help would be much appreciated!
You have elif c > y, you should just need to add a colon there so it's elif c > y:
Yup.
i=1
c=1
y=1
while i<=10:
c=int(input('Enter an integer number: ')) # This line was off
if c%2==0:
print('The number is even')
elif c> y: # Need also ':'
y=c
print('y')
i=i+1
You can right this in a much compact fashion like so.
Start by asking for 10 numbers in a single line, separated by a space. Then split the string by , into a list of numbers and exit the code if exactly 10 numbers are not provided.
numbers_str = input("Input 10 integers separated by a comma(,) >>> ")
numbers = [int(number.strip()) for number in numbers_str.split(',')]
if len(numbers) != 10:
print("You didn't enter 10 numbers! try again")
exit()
A bad run of the code above might be
Input 10 integers separated by a comma(,) >>> 1,2,3,4
You didn't enter 10 numbers! try again
Assuming 10 integers are provided, loop through the elements, considering only odd numbers and updating highest odd number as you go.
largest = None
for number in numbers:
if number % 2 != 0 and (not largest or number > largest):
largest = number
Finally, check if the largest number is None, which means we didn't have any odd numbers, so provide the user that information, otherwise display the largest odd number
if largest is None:
print("You didn't enter any odd numbers")
else:
print("Your largest odd number was:", largest)
Possible outputs are
Input 10 integers separated by a comma(,) >>> 1,2,3,4,5,6,7,8,9,10
Your largest odd number was: 9
Input 10 integers separated by a comma(,) >>> 2,4,6,8,2,4,6,8,2,4
You didn't enter any odd numbers
I am very new to programming, please advise me if my code is correct.
I am trying to write a program that repeatedly prompts a user for integer numbers until the user enters 'done'. Once 'done' is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore the number.
largest = None
smallest = None
while True:
num = input("Enter a number: ")
if num == 'done':
break
try:
fnum = float(num)
except:
print("Invalid input")
continue
lst = []
numbers = int(input('How many numbers: '))
for n in range(numbers):
lst.append(num)
print("Maximum element in the list is :", max(lst), "\nMinimum element in the list is :", min(lst))
Your code is almost correct, there are just a couple things you need to change:
lst = []
while True:
user_input = input('Enter a number: ')
if user_input == 'done':
break
try:
lst.append(int(user_input))
except ValueError:
print('Invalid input')
if lst:
print('max: %d\nmin: %d' % (max(lst), min(lst)))
Also, since you said you're new to programming, I'll explain what I did, and why.
First, there's no need to set largest and smallest to None at the beginning. I actually never even put those values in variables because we only need them to print them out.
All your code is then identical up to the try/except block. Here, I try to convert the user input into an integer and append it to the list all at once. If any of this fails, print Invalid input. My except section is a little different: it says except ValueError. This means "only run the following code if a ValueError occurs". It is always a good idea to be specific when catching errors because except by itself will catch all errors, including ones we don't expect and will want to see if something goes wrong.
We do not want to use a continue here because continue means "skip the rest of the code and continue to the next loop iteration". We don't want to skip anything here.
Now let's talk about this block of code:
numbers = int(input('How many numbers: '))
for n in range(numbers):
lst.append(num)
From your explanation, there is no need to get more input from the user, so none of this code is needed. It is also always a good idea to put int(input()) in a try/except block because if the user inputs something other than a number, int(input()) will error out.
And lastly, the print statement:
print('max: %d\nmin: %d' % (max(lst), min(lst)))
In python, you can use the "string formatting operator", the percent (%) sign to put data into strings. You can use %d to fill in numbers, %s to fill in strings. Here is the full list of characters to put after the percent if you scroll down a bit. It also does a good job of explaining it, but here are some examples:
print('number %d' % 11)
x = 'world'
print('Hello, %s!' % x)
user_list = []
while True:
user_input = int(input())
if user_input < 0:
break
user_list.append(user_input)
print(min(user_list), max(user_list))
Question:
The hand is displayed.
The user may input a word or a single period (the string ".")
to indicate they're done playing
Invalid words are rejected, and a message is displayed asking
the user to choose another word until they enter a valid word or "."
When a valid word is entered, it uses up letters from the hand.
After every valid word: the score for that word is displayed,
the remaining letters in the hand are displayed, and the user
is asked to input another word.
The sum of the word scores is displayed when the hand finishes.
The hand finishes when there are no more unused letters or the user inputs a "."
hand: dictionary (string -> int)
wordList: list of lowercase strings
I am trying to write a code for my Python programming online course. However, I am getting an error :
ERROR: Failed to display hand correctly - be sure 'Current Hand' and the display of the hand are on the same line!
Here is my code :
def playHand(hand, wordList, n):
total = 0
while True:
print("\nCurrent Hand:",)
displayHand(hand)
entered = input('Enter word, or a "." to indicate that you are finished: ')
if entered == '.':
print ("Goodbye! Total score: " + str(total) +" points.")
break
if isValidWord(entered, hand, wordList) == False:
print ("Invalid word, please try again.")
else:
total += getWordScore(entered, n)
print (str(entered), "earned", getWordScore(entered,n), "points. Total:", str(total))
hand = updateHand(hand, entered)
if calculateHandlen(hand) == 0:
print ("\nRun out of letters. Total score: " + str(total) +" points.")
break
The answer is in your code already:
def displayHand(hand):
for letter in hand.keys():
for j in range(hand[letter]):
print(letter,end=" ") # print all on the same line
print() # print an empty line
Use end=" " in your print statement!!
New to programming. How to count and print iterations(attempts) I had on guessing the random number?` Let's say, I guessed the number from 3-rd attempt.
import random
from time import sleep
str = ("Guess the number between 1 to 100")
print(str.center(80))
sleep(2)
number = random.randint(0, 100)
user_input = []
while user_input != number:
while True:
try:
user_input = int(input("\nEnter a number: "))
if user_input > 100:
print("You exceeded the input parameter, but anyways,")
elif user_input < 0:
print("You exceeded the input parameter, but anyways,")
break
except ValueError:
print("Not valid")
if number > user_input:
print("The number is greater that that you entered ")
elif number < user_input:
print("The number is smaller than that you entered ")
else:
print("Congratulation. You made it!")
There are two questions being asked. First, how do you count the number of iterations? A simple way to do that is by creating a counter variable that increments (increases by 1) every time the while loop runs. Second, how do you print that number? Python has a number of ways to construct strings. One easy way is to simply add two strings together (i.e. concatenate them).
Here's an example:
counter = 0
while your_condition_here:
counter += 1 # Same as counter = counter + 1
### Your code here ###
print('Number of iterations: ' + str(counter))
The value printed will be the number of times the while loop ran. However, you will have to explicitly convert anything that isn't already a string into a string for the concatenation to work.
You can also use formatted strings to construct your print message, which frees you from having to do the conversion to string explicitly, and may help with readability as well. Here is an example:
print('The while loop ran {} times'.format(counter))
Calling the format function on a string allows you replace each instance of {} within the string with an argument.
Edit: Changed to reassignment operator
This is from Ken Lambert's "Fundamentals of Python":
{
sum=0
while True:
data = input('enter a number or just enter to quit: ')
if data == "":
break
number = float(data)
sum += number
print("the sum is", sum)
}
error message:
data = input('enter a number or just enter to quit: ')
File "<string>", line 0
^
SyntaxError: unexpected EOF while parsing
Process finished with exit code 1
Use raw_input rather than input. The description of input begins with:
Equivalent to eval(raw_input(prompt))
You're getting an error because eval("") reports a syntax error, because there's no expression there; it gets EOF immediately.
On the other hand, the description of raw_input says:
The function then reads a line from input, converts it to a string (stripping a trailing newline), and returns that.
Since you want the string that the user typed, rather than the evaluation of an expression, this is the function you should use.
The error you provided is because you used input, which tries to execute the text from stdin as python code https://docs.python.org/2/library/functions.html#input. I've provided some fixes below.
sum=0
while True:
data = raw_input('enter a number or just enter to quit: ')
if len(data) < 1:
break
number = float(data)
sum += number
print("the sum is %f" % sum)
I found that you have a syntax problem with your code. If you want to to put data in a variable you should use that:
variable = raw_input("Please enter ____")
Therefore you should replace line 4 to:
data = raw_input('enter a number or just enter to quit: ')