OS - Ubuntu 16.04
My goal is simple. There are multiple images in a folder say
A.jpg
A.jpeg
B.jpg
B.jpeg
C.jpg
I want the names of the jpg files who have a .jpeg copy. So in this case I want the names A.jpg and B.jpg. Note that I do not want C.jpg because it does not have a jpeg copy.
Next, I want to delete the .jpg files whose names I have. So in this case I want to delete A.jpg and B.jpg ONLY.
Is there a set of commands to do it ?
(I indented the file names because for some reason stackoverflow was telling me it is code.)
EDIT
Is there someway I could put those filenames in a txt file and then read from it to delete the required files?
You can try:
for file in *.jpeg; do echo ${file%.*}.jpg; done
If this is what you want, just replace 'echo' by 'rm'
(Edited) This way you won't see errors for non-existing files:
for file in *.jpeg; do [[ -f ${file%.*}.jpg ]] && rm ${file%.*}.jpg; done
This may be:
#!/bin/sh
JPG_LIST="*.jpg"
#JPG_LIST=$(cat JPG_filenames_to_test.txt)
for filename in $JPG_LIST; do
BASENAME="${filename%.*}"
echo -n "Basename '$BASENAME': "
if [ -e $BASENAME.jpg -a -e $BASENAME.jpeg ] ; then
echo "$BASENAME.jpeg found. Removing $BASENAME.jpg"
rm $BASENAME.jpg
else
echo "No $BASENAME.jpeg file found. Keeping original $BASENAME.jpg"
fi
done
Related
I have a folder with regular pictures, and another with resized ones.
The goal is to check if a picture is not resized, do the resizing and save in another folder.
I'm using an echo for simplicity, because I don't have the comparison working.
for file in ../regular/*.jpg;
do
img=`basename "$file"`
FILE=./resized/$img
if [ ! -f "$FILE" ]; then
echo "$img NOT RESIZED"
fi
done
This code just echoes NOT RESIZED for all the pictures in the regular folder i.e. it doesn't seem to make the comparison at all.
Where is my mistake?
for file in ../regular/*.jpg;
FILE=./resized/$img
Try to use absolute path, You can also add echo $FILE to see what scripts tries to verify
If this directory contains a huge amount of files, you can exceed command line length limit (usually ~4kb-32kb)
You are using quotas in basename command, why? If your images could contain spaces, you should use quotas also in "if" command, check script below
for file in ../regular/*.jpg;
do
img=$(basename "$file")
if [ ! -f "./resized/$img" ]; then
echo "$img NOT RESIZED"
fi
done
You should try to use diff command to compare directories:
diff -r "$PATH1" "$PATH2"
I am still a newbie in shell scripting and trying to come up with a simple code. Could anyone give me some direction here. Here is what I need.
Files in path 1: /tmp
100abcd
200efgh
300ijkl
Files in path2: /home/storage
backupfile_100abcd_str1
backupfile_100abcd_str2
backupfile_200efgh_str1
backupfile_200efgh_str2
backupfile_200efgh_str3
Now I need to delete file 300ijkl in /tmp as the corresponding backup file is not present in /home/storage. The /tmp file contains more than 300 files. I need to delete the files in /tmp for which the corresponding backup files are not present and the file names in /tmp will match file names in /home/storage or directories under /home/storage.
Appreciate your time and response.
You can also approach the deletion using grep as well. You can loop though the files in /tmp checking with ls piped to grep, and deleting if there is not a match:
#!/bin/bash
[ -z "$1" -o -z "$2" ] && { ## validate input
printf "error: insufficient input. Usage: %s tmpfiles storage\n" ${0//*\//}
exit 1
}
for i in "$1"/*; do
fn=${i##*/} ## strip path, leaving filename only
## if file in backup matches filename, skip rest of loop
ls "${2}"* | grep -q "$fn" &>/dev/null && continue
printf "removing %s\n" "$i"
# rm "$i" ## remove file
done
Note: the actual removal is commented out above, test and insure there are no unintended consequences before preforming the actual delete. Call it passing the path to tmp (without trailing /) as the first argument and with /home/storage as the second argument:
$ bash scriptname /path/to/tmp /home/storage
You can solve this by
making a list of the files in /home/storage
testing each filename in /tmp to see if it is in the list from /home/storage
Given the linux+shell tags, one might use bash:
make the list of files from /home/storage an associative array
make the subscript of the array the filename
Here is a sample script to illustrate ($1 and $2 are the parameters to pass to the script, i.e., /home/storage and /tmp):
#!/bin/bash
declare -A InTarget
while read path
do
name=${path##*/}
InTarget[$name]=$path
done < <(find $1 -type f)
while read path
do
name=${path##*/}
[[ -z ${InTarget[$name]} ]] && rm -f $path
done < <(find $2 -type f)
It uses two interesting shell features:
name=${path##*/} is a POSIX shell feature which allows the script to perform the basename function without an extra process (per filename). That makes the script faster.
done < <(find $2 -type f) is a bash feature which lets the script read the list of filenames from find without making the assignments to the array run in a subprocess. Here the reason for using the feature is that if the array is updated in a subprocess, it would have no effect on the array value in the script which is passed to the second loop.
For related discussion:
Extract File Basename Without Path and Extension in Bash
Bash Script: While-Loop Subshell Dilemma
I spent some really nice time on this today because I needed to delete files which have same name but different extensions, so if anyone is looking for a quick implementation, here you go:
#!/bin/bash
# We need some reference to files which we want to keep and not delete,
# let's assume you want to keep files in first folder with jpeg, so you
# need to map it into the desired file extension first.
FILES_TO_KEEP=`ls -1 ${2} | sed 's/\.pdf$/.jpeg/g'`
#iterate through files in first argument path
for file in ${1}/*; do
# In my case, I did not want to do anything with directories, so let's continue cycle when hitting one.
if [[ -d $file ]]; then
continue
fi
# let's omit path from the iterated file with baseline so we can compare it to the files we want to keep
NAME_WITHOUT_PATH=`basename $file`
# I use mac which is equal to having poor quality clts
# when it comes to operating with strings,
# this should be safe check to see if FILES_TO_KEEP contain NAME_WITHOUT_PATH
if [[ $FILES_TO_KEEP == *"$NAME_WITHOUT_PATH"* ]];then
echo "Not deleting: $NAME_WITHOUT_PATH"
else
# If it does not contain file from the other directory, remove it.
echo "deleting: $NAME_WITHOUT_PATH"
rm -rf $file
fi
done
Usage: sh deleteDifferentFiles.sh path/from/where path/source/of/truth
This should be a relatively straightforward problem but I haven't found any answers within stackoverflow. In a given directory, I have ~1000 files that are numbered (e.g. chem-0320.inp). I would like to cp the numbered file to a correspondingly numbered directory; all copied files will be renamed with the same name. I would like to do this for a specified numbered of files (#'s 300-500 for example).
For example, I would like to copy chem-0320.inp to a directory named 320 and rename it mech.dat.
Another example: copy chem-0430.inp to a directory named 430 and rename it mech.dat.
Thanks in advance for your help!
The following script would do the work for you
for file in *.inp
do
dir=$(echo $file | sed -r 's/[^0-9]+0([0-9]+).*/\1/g')
mv $file $dir/mech.dat
done
"cd" first to right dir. Subdirs will be created there.
#!/bin/bash
lo_limit=300
hi_limit=500
for file in ./*.inp
do
dir="${file//[^0-9]/}"
dir_cut="${dir:1:3}" # leading zero cut off
if [ $dir_cut -ge $lo_limit ] && [ $dir_cut -le $hi_limit ]; then
echo "$file $dir_cut"
mkdir -p "$dir_cut"
cp "$file" "$dir_cut"/mech.dat
fi
done
I want to delete all files from a folder that contain a not unique numerical string in the filename using linux terminal. E.g.:
werrt-110009.jpg => delete
asfff-110009.JPG => delete
asffa-123489.jpg => maintain
asffa-111122.JPG => maintain
Any suggestions?
I only now understand your question, I think. You want to remove all files that contain a numeric value that is not unique (in a particular folder). If a filename contains a value that is also found in another filename, you want to remove both files, right?
This is how I would do that (it may not be the fastest way):
# put all files in your folder in a list
# for array=(*) to work make sure you have enabled nullglob: shopt -s nullglob
array=(*)
delete=()
for elem in "${array[#]}"; do
# for each elem in your list extract the number
num_regex='([0-9]+)\.'
[[ "$elem" =~ $num_regex ]]
num="${BASH_REMATCH[1]}"
# use the extracted number to check if it is unique
dup_regex="[^0-9]($num)\..+?(\1)"
# if it is not unique, put the file in the files-to-delete list
if [[ "${array[#]}" =~ $dup_regex ]]; then
delete+=("$elem")
fi
done
# delete all found duplicates
for elem in "${delete[#]}"; do
rm "$elem"
done
In your example, array would be:
array=(werrt-110009.jpg asfff-110009.JPG asffa-123489.jpg asffa-111122.JPG)
And the result in delete would be:
delete=(werrt-110009.jpg asfff-110009.JPG)
Is this what you meant?
you can use the linux find command along with the -regex parameter and the -delete parameter
to do it in one command
Use "rm" command to delete all matching string files in directory
cd <path-to-directory>/ && rm *110009*
This command helps to delete all files with matching string and it doesn't depend on the position of string in file name.
I was mentioned rm command option as another option to delete files with matching string.
Below is the complete script to achieve your requirement,
#!/bin/sh -eu
#provide the destination fodler path
DEST_FOLDER_PATH="$1"
TEMP_BUILD_DIR="/tmp/$( date +%Y%m%d-%H%M%S)_clenup_duplicate_files"
#++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
clean_up()
{
if [ -d $TEMP_BUILD_DIR ]; then
rm -rf $TEMP_BUILD_DIR
fi
}
trap clean_up EXIT
[ ! -d $TEMP_BUILD_DIR ] && mkdir -p $TEMP_BUILD_DIR
TEMP_FILES_LIST_FILE="$TEMP_BUILD_DIR/folder_file_names.txt"
echo "$(ls $DEST_FOLDER_PATH)" > $TEMP_FILES_LIST_FILE
while read filename
do
#check files with number pattern
if [[ "$filename" =~ '([0-9]+)\.' ]]; then
#fetch the number to find files with similar number
matching_string="${BASH_REMATCH[1]}"
# use the extracted number to check if it is unique
#find the files count with matching_string
if [ $(ls -1 $DEST_FOLDER_PATH/*$matching_string* | wc -l) -gt 1 ]; then
rm $DEST_FOLDER_PATH/*$matching_string*
fi
fi
#reload remaining files in folder (this optimizes the loop and speeds up the operation
#(this helps lot when folder contains more files))
echo "$(ls $DEST_FOLDER_PATH)" > $TEMP_FILES_LIST_FILE
done < $TEMP_FILES_LIST_FILE
exit 0
How to execute this script,
Save this script into file as
path-to-script/delete_duplicate_files.sh (you can rename whatever
you want)
Make script executable
chmod +x {path-to-script}/delete_duplicate_files.sh
Execute script by providing directory path where duplicate
files(files with matching number pattern) needs to be deleted
{path-to-script}/delete_duplicate_files.sh "{path-to-directory}"
I have a folder that is full of .bak files and some other files also. I need to remove the extension of all .bak files in that folder. How do I make a command which will accept a folder name and then remove the extension of all .bak files in that folder ?
Thanks.
To remove a string from the end of a BASH variable, use the ${var%ending} syntax. It's one of a number of string manipulations available to you in BASH.
Use it like this:
# Run in the same directory as the files
for FILENAME in *.bak; do mv "$FILENAME" "${FILENAME%.bak}"; done
That works nicely as a one-liner, but you could also wrap it as a script to work in an arbitrary directory:
# If we're passed a parameter, cd into that directory. Otherwise, do nothing.
if [ -n "$1" ]; then
cd "$1"
fi
for FILENAME in *.bak; do mv "$FILENAME" "${FILENAME%.bak}"; done
Note that while quoting your variables is almost always a good practice, the for FILENAME in *.bak is still dangerous if any of your filenames might contain spaces. Read David W.'s answer for a more-robust solution, and this document for alternative solutions.
There are several ways to remove file suffixes:
In BASH and Kornshell, you can use the environment variable filtering. Search for ${parameter%word} in the BASH manpage for complete information. Basically, # is a left filter and % is a right filter. You can remember this because # is to the left of %.
If you use a double filter (i.e. ## or %%, you are trying to filter on the biggest match. If you have a single filter (i.e. # or %, you are trying to filter on the smallest match.
What matches is filtered out and you get the rest of the string:
file="this/is/my/file/name.txt"
echo ${file#*/} #Matches is "this/` and will print out "is/my/file/name.txt"
echo ${file##*/} #Matches "this/is/my/file/" and will print out "name.txt"
echo ${file%/*} #Matches "/name.txt" and will print out "/this/is/my/file"
echo ${file%%/*} #Matches "/is/my/file/name.txt" and will print out "this"
Notice this is a glob match and not a regular expression match!. If you want to remove a file suffix:
file_sans_ext=${file%.*}
The .* will match on the period and all characters after it. Since it is a single %, it will match on the smallest glob on the right side of the string. If the filter can't match anything, it the same as your original string.
You can verify a file suffix with something like this:
if [ "${file}" != "${file%.bak}" ]
then
echo "$file is a type '.bak' file"
else
echo "$file is not a type '.bak' file"
fi
Or you could do this:
file_suffix=$(file##*.}
echo "My file is a file '.$file_suffix'"
Note that this will remove the period of the file extension.
Next, we will loop:
find . -name "*.bak" -print0 | while read -d $'\0' file
do
echo "mv '$file' '${file%.bak}'"
done | tee find.out
The find command finds the files you specify. The -print0 separates out the names of the files with a NUL symbol -- which is one of the few characters not allowed in a file name. The -d $\0means that your input separators are NUL symbols. See how nicely thefind -print0andread -d $'\0'` together?
You should almost never use the for file in $(*.bak) method. This will fail if the files have any white space in the name.
Notice that this command doesn't actually move any files. Instead, it produces a find.out file with a list of all the file renames. You should always do something like this when you do commands that operate on massive amounts of files just to be sure everything is fine.
Once you've determined that all the commands in find.out are correct, you can run it like a shell script:
$ bash find.out
rename .bak '' *.bak
(rename is in the util-linux package)
Caveat: there is no error checking:
#!/bin/bash
cd "$1"
for i in *.bak ; do mv -f "$i" "${i%%.bak}" ; done
You can always use the find command to get all the subdirectories
for FILENAME in `find . -name "*.bak"`; do mv --force "$FILENAME" "${FILENAME%.bak}"; done