enter image description hereI need a little help with VBA to perform the Sumif function.
I have a file and need to extract from sheet2: Using the normal formulas, the function is thus:enter image description here SUMIF (Sheet2! B: B; Sheet1! A: A; Sheet2! C: C)
However, I want them in VBA, can give this small force :)
I've tried a few things, but it always returns zero. Then follow the criteria to get help with new ideas
Your worksheet formula is using 'implicit reference' for the Sheet1!A:A criteria. Normally, you would use,
=SUMIF(Sheet2!B:B; Sheet1!A2; Sheet2!C:C)
... in Sheet1!C2 (or any other cell) and fill down for Sheet1!A3, Sheet1!A4, etc. as the criteria. There is no 'implicit reference' because you are explicitly referencing one specific cell in Sheet1's column A. By using,
=SUMIF(Sheet2!B:B; Sheet1!A:A; Sheet2!C:C)
... as a standard formula you are implicitly referencing the cell in column A which is in the same worksheet row as the formula. When the formula is in row 5, Sheet1!A5 is referenced as the criteria; when it is in row 99, Sheet1!A99 becomes the criteria.
The concept of 'implicit reference' (aka 'inferred reference') can be easily demonstrated with this simple exercise.
Put 5, 10, 15, ... 40, 45, 50 into cells A1:A10.
In any unused column to the right, pick a row between 1 and 10 and put in the formula,
=a:a
The result will be the value from column A in whatever row you put the formula into.
Without a cell (in VBA known as Application.Caller) to provide the implicit or inferred row, the formula becomes confused as to what cell in column A to implicitly reference. Using the simplified example provided above, VBA has no row reference to determine how to resolve A:A to a single cell reference. My best guess in that it is trying to reference either Sheet1!A1 or Sheet1!A1048576 as the criteria.
Hope I've explained that concept sufficiently. Comments welcomed and I'll try to respond.
Related
How do I find either the cell address or preferably the row and column of the value 119, or any other number in the table below?
The table does not contain row or column titles, only the numbers as shown.
I am looking for a worksheet solution (formula) and not a VBA solution.
An Array Formula
This is an array formula and it has to be entered with control shift enter i.e. hold control shift and then press enter.
=MAX(IF(A1:J34=119,ROW(A1:J34)-ROW(A1)+1))
Remarks:
The value is searched by column i.e. A1, A2, ... B1, B2 ... i.e. if you had another 119 in cell D1 the result would still be 2, and if you had a 119 in cell c1 then the result would be
1.
For a column version just replace ROW with COLUMN:
=MAX(IF(A1:J34=119,COLUMN(A1:J34)-COLUMN(A1)+1))
Well, clunky and you can expand it, but it does work:
Row is separate to column but you could put them together in one cell, does depend on how you want to use the results, but you did not specify that so I have done this...
You could use a choose() function or a lookup table with vlookup() to change the column result to a letter...
Please try:
=MOD((K1-50),34)+1&" | "&1+(INT((K1-50)/34))
where K1 is your selected value.
Returns R | C. (Data in A1:J34 is not required.)
Below is a general purpose answer based on VBasic2008's answer.
I modified the formulas to utilize defined names so that the cell references do not have to be hard coded in the formulas. This way both the data table and row / column formulas can be relocated to anywhere on the spreadsheet. It works for both numerical AND text based data.
I also included the =ADDRESS() function to return the absolute reference of the look up value.
For illustration purposes, a step by step example for Data Set 1 is shown replacing the hard coded cell references with defined names.
The Data Set 2 section is the simplified version just using one defined for each the row and column look up value.
You can download an example spreadsheet here: Look_Up_a_Value_in_a_Table.xls
Thanks to all of you: Solar Mike, VBasic2008, and pnuts
Click on the image to enlarge.
I was wondering why the formula I did won't go to the next column over. I did place the $ sign to stay in the same row, but not on the column, thinking it will go to the next column over. Is there any suggestions as to why this is doing this?
The following is the formula I inputted into the spreadsheet:
=(INDIRECT("BHR8732A2!P$16"))*$S283
Because you have " " around the sheet and cell reference BHR8732A2!P$16, it's going to be treated as a text string, not a cell reference. It's not going to change when you copy across.
If you want to just multiply the value in column S by the value in row 16, you'd write it as ='BHR8732A2'!P$16*$S283.
If you want to multiply the value in column S by the value in another cell whose address is in row 16, you'd write it as =INDIRECT('BHR8732A2'!P$16)*$S283.
Using a text string inside the Indirect is kind of the 'worst of both worlds', where you're just feeding the cell reference directly into the Indirect, which is unnecessary.
I'm not sure why the whole BHR8732A2!P$16 has quotes. Excel does not seem to recognise the P$16 part as a cell reference for me.
Try this: =(INDIRECT('BHR8732A2'!P$16))*$S283
I would like to create a table with products and formulas on a sheet (Sheet2). For different products, different formulas apply.
I would like to retrieve the formula from that table but use the row numbers from the row in Sheet1
How do I enter a formula which is evaluated with the correct row numbers from Sheet1.
I have a UDF eval that can evaluate a text string:
=eval(vlookup(Product;Table;2;false)
The formula retrieved from the Table should use the row number of the actual row that the eval() is on.
I tried the following:
="D"&ROW(Sheet2!$A16)&"/G"&ROW(Sheet2!$A16)&"/F"&ROW(Sheet2!$A16)&"*5"
This retrieves the formula but the eval() does not calculate the result.
In your example, product is located on Sheet2 in the 16th row of the first column of table. If you want the 16th row on the worksheet, you can use the MATCH function on a full column reference, discarding the structured references of the ListObject table or you can use MATCH on the structured table reference and compensate for the 'position within' table by adjusting by the table header row.
That's probably confusing so here is an example.
To find the actual row-on-the-worksheet where bcd resides you would use one of these formulas.
=MATCH("bcd", Sheet2!B:B, 0)
=MATCH("bcd", Table2[a], 0)+ROW(Table2[#Headers])
The first simply returns row 6 on the worksheet. The second returns 2 since bcd is in the second row of the ListObject's .DataBodyRange property and this is adjusted by the row that the .HeaderRowRange property is in; e.g. 2 + 4 = 6.
Now that everything is clear, all you need to do is use the result from one of those formulas as the row_number parameter in an INDEX function.
=INDEX(D:D, MATCH("bcd", Sheet2!B:B, 0))/
INDEX(G:G, MATCH("bcd", Sheet2!B:B, 0))/
INDEX(F:F, MATCH("bcd", Sheet2!B:B, 0))*5
'or,
=INDEX(D:D, MATCH("bcd", Table2[a], 0)+ROW(Table2[#Headers]))/
INDEX(G:G, MATCH("bcd", Table2[a], 0)+ROW(Table2[#Headers]))/
INDEX(F:F, MATCH("bcd", Table2[a], 0)+ROW(Table2[#Headers]))*5
Your own formula could have worked with a series of INDIRECT functions that convert constructed strings to actual cell references. However, INDIRECT is considered volatile and best avoided if possible.
=INDIRECT("D"&ROW(Sheet2!$A6))/INDIRECT("G"&ROW(Sheet2!$A6))/INDIRECT("F"&ROW(Sheet2!$A6))*5
This solution is based on the capability of Excel to reference the cells in R1C1 style. In order to use it, you will have to go to File -> Options -> "Formulas" tab, and check the box "R1C1 reference style" in "Working with Formulas" group.
In addition, your eval() function will have to be able to evaluate such kind of formulas.
Once, all of these is done, you only have to retrieve the formula.
In order to make the things clear, I will focus on an example.
The table below is the contents of Sheet1 (the "Database" of products).
The column "Formula" contains the relevant formula:
for apple: RC[-2]+RC[-1]
for banan: RC[-2]*RC[-1]
for lemon: RC[-2]/RC[-1]
The table below is the contents of Sheet2:
The column "Formula" here contains the formula, retrieved from Sheet1. The formula of the column "Formula" is as follows:
=FORMULATEXT(INDEX(Sheet1!R2C1:R4C4,MATCH(RC[-3],Sheet1!R2C1:R4C1,0),4))
The description of each of the functions, used here (formulatext, index and match) can be found in Excel help.
As it can be seen, the retrieved formula, represented in R1C1 style is correct in context of Sheet2, were the products are arranged differently, and may appear more than once. The only remaining work to do is to apply the eval() function, after it was adapted to evaluate R1C1-style referenced formulas.
I hope it helps.
I have been working on an attendance sheet and trying to make the monthly reports automatic. I have asked my previous question on the same issue and got the idea to accomplish the task.
But now I have stuck at one place. I have this below formula:
=COUNTIFS(C5:C27,">0", E5:E27,"G", F5:F27,"CAT1")
The value in cell "C" in the above is coming from the below formula (in cell "C")
=IF((COUNTIF(G5:AK5,"p"))>0,1,0)
I had to add this extra column ("C") only to supply input to my fist formula. My question is - "Can we merge the IF function inside the COUNTIFS to get the result in one go and to eliminate the use of an extra column (column C)"?
To perform these cell reference acrobatics you will likely need to switch to an array formula. Array formulas chew up calculation cycles logarithmically so it is good practise to narrow the referenced ranges to a minimum. A 'helper' column such as you've used in column C can generally reduce calculation cycles and make a worksheet more 'user friendly'.
A COUNTIFS function requires that the ranges being examined are not only the same size but also the same shape. Looking at G5:AK5 is not the same as looking at E5:E35 even though they contain the same number of cells¹.
In the sample data below, you formula is in A1 and uses the 'helper column' C. My array formula is in A2 and does not consider column C ahough it incorporated the logic.
The array formula in A2 is:
=SUM(IF(E5:E27 = "G", IF(F5:F27 = "CAT1", SIGN(COUNTIFS(OFFSET($G$5, ROW($1:$23)-1, 1, 1, 31), $I2)))))
Array formulas need to be finalized with Ctrl+Shift+Enter↵. Once entered into the first cell correctly, they can be filled or copied down or right just like any other formula.
¹Some functions not only accept but welcome cell ranges that are the same number of calls but transposed. Offsetting or staggering the ranges is also an option if the cell ranges are the same size. In difficult cases the TRANSPOSE function can be helpful.
Currently I have a huge formula in my excel sheet:
=SUM(SUMIF(INDIRECT(A9&"!$F:$F"),"working";INDIRECT(A9&"!$B:$B"))+SUMIF(INDIRECT(A9&"!$F:$F");"Open";INDIRECT(A9&"!$B:$B"))+SUMIF(INDIRECT(A9&"!$F:$F");"internal",INDIRECT(A9&"!$B:$B"))+(SUMIF(INDIRECT(A9&"!$F:$F"),"finished";INDIRECT(A9&"!$AP:$AP"))))
In A9 is the name of the excel sheet that the formula has to use. So for example in A3 there's '20140612', so it has to use the excel sheet with the name '20140612'. Furthermore it sums up some values depending on some conditions.
My question is: I would like to direct the columns in the other sheets by their headlines, not their positions in the sheet. So for example le column AP doesn't always has to be in the position AP, but has always the headline 'Points'.
Can you think of an adaption of the formula that can direct the column by their headline?
I though of the MATCH formula. But I'm not to sure where I have to put this in.
I think the simplest answer would be to use named ranges within your sheet. In this way you could name a range (currently in column AP) as 'Points', change your formula to use 'Points' instead of '$AP:$AP' & if you move your points data about the formulas would be unchanged.
If you are planning to keep changing your header row values then you could use HLOOKUP to match up the header column probably in conjunction with MATCH & INDEX.
To answer your question about the usage of MATCH(), it's worth thinking of it as half of a VLOOKUP() or HLOOKUP(), i.e. it's the bit that finds the row or column containing the value you're searching for, then you can use INDEX() to get that row / column from a range you specify.
So, if you know that one of your column headings is "Points", then you could find it by using:
=MATCH("Points", A1:Z1, FALSE)
...which would return 10 if "Points" were the heading of column J for example. If you wanted to then use that column for a lookup, you can use OFFSET() to define that column as a range to use for a lookup, so let's say I wanted to find the text "foo" in the "Points" column, I could use:
=MATCH("foo", OFFSET(A1:Z1000, 0, MATCH("Points", A1:Z1, FALSE) - 1, 1000, 1), false)
... which uses the column index I found before as an input to OFFSET() in order to dynamically reference J1:J1000 and then search for "foo" in that column.
For your example in the question, rather than A1:Z1000 you could use a call to INDIRECT() that would return the entire range of interest from your source sheet.