I am an occasional Excel user and stuck how to create a dynamic range.
After looking up a text in a table, how can I calculate the range next to this cell, up to the next empty row? Not using VBA.
Thanks for your help.
In H4, formula copied down :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):C$1000,MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):B$1000,0)),"")
Should you want a dynamic range,
Change C$1000 to INDEX(C:C,MATCH(9.9E+307,B:B)
and
Change B$1000 to INDEX(B:B,MATCH(9.9E+307,B:B))
Then
The H4 copied down formula become :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):INDEX(C:C,MATCH(9.9E+307,B:B)),MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):INDEX(B:B,MATCH(9.9E+307,B:B)),0)),"")
Edit :
As per Ron Rosenfeld's comment, "should B11 change to 24 and G4 change to 24"
The "Source Table" set up in Excel Table type for dynamic range growing purpose
and
The H4 formula change to :
=IFERROR(LOOKUP(9^9,Table1[price]/(LOOKUP(ROW(Table1[texture]),ROW(Table1[texture])/(Table1[texture]<>""),Table1[texture])=F4)/(Table1[length]=G4)),"")
Combining the Index() and Match() functions usually works well when using two conditions. However, you will need to fill out the entire column A with the "texture" list in order for the below formula to work.
=INDEX(<P1>, MATCH(TRUE, (<T1>=<T2>) + (<L1>=<L2>) > 1,0))
Where <P1> is your entire price column (ex. C2:C15)
Where <T1> is your entire texture column (ex. A2:A15)
Where <T2> is your texture lookup value cell
Where <L1> is your entire length column (ex. B2:B15)
Where <L2> is your length lookup value cell
Let's say that you input your texture value into cell F3, and your length value into cell F4. With the remaining columns remaining as they are in your image, you would use the following formula:
=INDEX(C2:C15, MATCH(TRUE, (A2:A15=F3) + (B2:B15=F4) > 1,0))
Now last time I had to use Index/Match I thought I had to place the formula into an array. However, the above seems to work without it.
If you notice that it's not working as expected, you can place into an array formula by clicking the cell that contains the formula, then clicking the formula box at the top. While in the formula box, simultaneously press Ctrl + Shift + Return. This should then place curly brackets around your entire formula if done properly, as such:
If you have O365 with the SEQUENCE function, you can use, for price:
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2}),2,FALSE))
explanation:
get starting row:
MATCH(F4,$A:$A,0)
ending row will be the first blank row after the starting row:
MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)
Construct the relevant array:
INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2})
The above might reduce (with wavy) to:
index(b:c,{9,10,11},{1,2}
Then it's just a matter of applying the VLOOKUP
A more understandable, but longer with more operations, formula available in O365 makes use of LET. The advantage is that one can use names which indicate what each section of the formula does.
For example:
=IF(G4="","",LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,
arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),price,XLOOKUP(G4,INDEX(arr,0,1),INDEX(arr,0,2)),price))
Or, using VLOOKUP
=IF(G4="","",VLOOKUP(G4,LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),arr),2,FALSE))
Finally, for earlier versions of Excel, you can use this whopper where we replace the SEQUENCE function with a construct like: ROW(INDEX(A:A,firstRow):INDEX(A:A,lastRow))
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,ROW(INDEX($A:$A,MATCH(F4,$A:$A,0)):INDEX($A:$A,MATCH(F4,$A:$A,0)+MATCH(TRUE,INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX($B:$B,ROWS($B:$B))="",0)-2)),{1,2}),2,FALSE))
In excel, I am trying to obtain the average of a range of numbers in a single column with a fixed start row (B4) and a variable end row (which is the value of Cell C2 minus 1 with the match function) I am using the following formula in Excel that works perfectly:
=AVERAGE(B4:INDIRECT(CONCATENATE("B",MATCH((C2-1),A:A,0))))
HOWEVER, I will need to copy and paste this formula into other columns, so the "B" will need to change to a "G" and so on. The new column letter will always be +5 from the previous column, and -3 from the column the cell formula is stored in. I want Excel to auto-populate the change in column letter, but CONCATENATE only works with text. I tried to use the offset function in place of the CONCATENATE "B" argument (see below), but I think INDIRECT might require text as well and/or I'm using the offset function incorrectly.
AVERAGE(B4:INDIRECT((OFFSET(5,-3,0)) & MATCH((C2-1),A:A,0))))
Does anyone have any ideas for a fix?
Use INDEX:
=AVERAGE(B4:INDEX(B:B,MATCH((C2-1),A:A,0)))
I am trying to find how to get an excel formula to get a cell's relative reference into a cell.
A formula that would be like =getcellreference(B2) and then has B2 as the output.
Nothing complicated but i could not find a simple solution.
You can use CELL():
=CELL("address",B2)
For formatting to literally show B2 instead of the absolute reference, you can do:
=SUBSTITUTE(CELL("address",B2),"$","")
If all you are trying to do is output a cell reference that you manually input, then all you need to do is:
="B2"
or
B2 (no equals sign)
You can use the ADDRESS function to obtain the address of a cell in a worksheet, given specified row and column numbers
ADDRESS(row_num, column_num, [abs_num], [a1], [sheet_text])
So for cell B2, you will need to put =ADDRESS(2,2) where the first 2 stands for the row number and 2nd is for column B.
I have this formula in excel, to return a row number:
=MATCH(INDIRECT(ADDRESS(ROW(),4)),DayOffRequests!$A$1:$A$100,0)
and it works just fine.
I would like to make a new name (DAYS_OFF_ROW) and assign it to this formula.
Here's what I did in the name manager:
But when I write this into a cell: =DAYS_OFF_ROW it says #VALUE! whereas when I write the same formula into the cell, it gives me the row number I am looking for.
Why is does it say #VALUE! and not the row number like the formula does?
First off Row() returns the row on which the cell resides. If you put Row() in indirect you will get an error since there is no cell for which Excel can find a Row(). So right off the bat, your formula is nonsense for a named range.
Second, even if there was some magic way for Excel to know which Row() you cared about here, Match doesn't return a range. Just a position in an array like "5" or "50". When you use a formula to define a named range, the result of the formula MUST be a range. So you could do another Indirect like =Indirect("A" & Match(foo,bar)) or something so that the result out of your formula actually refers to a range in your sheet.
It works if i set the name to this formula: =MATCH(!$D1,DayOffRequests!$A$1:$A$100,0)
Of course i have to be in field A1 when setting the name. Now its reference the fourth column and whichever row i am in.
I have the following formula
=IFERROR(IF(FIND(OFFSET($B$2,1,0),$A3,1),VLOOKUP(OFFSET($B$2,1,0),'Keyword list'!B2:E316533,2,FALSE),""),"n/a")
which looks up a value associated with a word if the word is found and otherwise returns "n/a". I have included the OFFSET() function with the hope of making it so that when I move the formula to another column, say from column B to column C, the reference is not still $B$2, and not C2, but B3. Effectively I am trying to make it so that when the formula is dragged across the reference row changes instead of the column, and when I drag down the reference remains fixed at $B$2, $B$3 and so on. Is it possible to use the offset function to do this? Is there a clear mistake I've made in trying to apply it to the above formula? Thanks!
You could maybe try the following?
=IFERROR(IF(FIND(OFFSET($B$2,COLUMNS($A:A)-1,0),$A3,1),
VLOOKUP(OFFSET($B$2,COLUMNS($A:A)-1,0),'Keyword list'!$B$2:$E$31,2,FALSE),""),
"n/a")
I made a google spreadsheet so that you can try to drag the formula across.
The limitation of that formula is that it will rely on the column of the formula, and it cannot be dragged towards the left in Excel, since that will cause the reference COLUMNS($A:A) to go COLUMNS(#REF!). It can be put in any column then dragged to the right.
This is untested, but I think it does what you want, i.e., shift the reference down one row, for each column you drag to the right. It uses the COLUMNS function anchored at B in one half and relative in another:
=IFERROR(IF(FIND(OFFSET($B$2,COLUMNS($B:B),1),$A3,1),VLOOKUP(OFFSET($B$2,COLUMNS($B:B),1),'Keyword list'!B2:E316533,2,FALSE),""),"n/a")
I'd go with using INDIRECT to build a reference out of a computed string.
INDIRECT("B"&(2+COLUMN(<current cell>)-COLUMN($B$1)))
This way your reference gets calculated dependent from the offset to column B:
In cell D2 the referenced cell is "B"&(2+COLUMN(D2)-COLUMN($B$1)) = "B"&(2+4-2) = "B4"
In cell D3 the reference does not change, as only columns are taken into account.
Same for cell E2: "B"&(2+COLUMN(E2)-COLUMN($B$1)) = "B"&(2+5-2) = "B5"
If your calculation is that fixed, you could even only do with COLUMN(E2) as 2 and COLUMN(B1) cancel each other out: INDIRECT("B"&COLUMN(<current cell>)))