https://www.sec.gov/Archives/edgar/data/1383094/000119312518268345/0001193125-18-268345.txt
The part I'm unsure how to read can be found by using ctrl+f on the following characters: M_]C_X0QQ17AI9#
This is the start of a section I am not familiar with, which contains a long block of text characters with each row starting with "M".
Thanks for your help!
The character sequence you see there is an encoded JPEG picture. You can recognize this by checking the starting character sequence - that is:
begin 644 g61300267.jpg
Related
some time ago i found this weird character that i can t put it here because it doesn't work but i have images of it. It looks like a space character in the begin but it isn't.
When i google it i get this here and some random character in the search bar. Also i can't find it in the Unicode/ASCII library of characters
Does anyone what this character is and it's purpose?
Based on your Google search string, you have a long series of the character U+3164, the "Hangul Filler." Hangul is the Korean alphabet.
I am trying to search for multiple strings in a text log alltogether with the following pattern:
s(n)KEY: some data
s(n)Measurement: some data
s(n)Units: some data
Where s(n) is the number of spaces that varies. KEY will change at every iteration in the loop as it comes from the .ini file. As an example see the following snippet the of log:
WHITE On Axis Lum_010 OPTICAL_TEST_01 some.seq
WHITE On Axis Lum_010 Failed
Bezel1 Luminance-Light Source: Passed
Measurement: 148.41
Units: fc
WHITE On Axis Lum_010: Failed
Measurement: 197.5
Units: fL
In this case, I only want to detect when the key (WHITE On Axis Lum_010) appears along with Measurement and I don't want to detect if it appears anywhere else in the log. My ultimate goal is to get the measurement and unit data from file.
Any help will be greatly appreciated. Thank you, Rav.
I'd do it similar to Salome, using regular expressions. Since those are a little tricky, I have a test VI for them:
The RegEx is:
^\s{2}(.*?):\s*(\S*)\n\s*Measurement:\s*(\S*)\n\s*Units:\s*(\S*)
and means:
^ Find a beginning of a line
\s{2} followed by exactly two whitespaces
(.*?) followed by multible characters
: followed by a ':'
\s* followed by several whitespaces
(\S*) followed by several non-whitespaces
\n followed by a newLine
\s* followed by several whitespaces
Measurement: followed by this string
\s* followed by several whitespaces
(\S*) followed by several non-whitespaces
\n followed by a newLine
... and the same for the 'Unit'
The parentheses denote groups, and allow to easily collect the interesting parts of the string.
The RegEx string might need more tuning if the format of the data is not as expected, but this is a starting point.
To find more data in your string, put this in a while loop and use a shift register to feed the offset past match into the offset of the next iteration, and stop if it's =-1.
It's easier to search through and to implement.
LabVIEW also has VIs to create and manage JSONs.
Alternatively, you could use Regular Expressions in a while-loop to look if it exists in your log, maybe something like this:
WHITE On Axis Lum_010:(\s)*((Failed)|(Pass))\n(\s)+Measurement:(\s)*[0-9]*((\.)[0-9]*){0,1}\n(\s)*Units:\s*\w*
Then you can split the string or pick lines and take the information.
But I would not recommend that, as it is impractical to change and not useful if you want to use the code for other keys.
I hope it helps you :)
HotKey: Shift+Ctrl+F
Correct result:
Error results,
you can find the results just show as '<binary>'.I've searched this problem in google,but get nothing,
Here is log text.
Thanks for anyone give suggestion
The file most likely contains non UTF-8 encoded characters, binary characters or the content encoding cannot be guessed. Thus, it is not reliable to show search result summary.
need convert control characters
java -jar replacecontrol.jar *filepath*
replacecontrol.jar
From Sublimetext Forum
In general, if a file contains any ASCII characters < 32,
except 0x3, 0x9, 0xa, 0xc or 0xd, then it’s considered binary
Reading that I searched [\x00-\x09] and found a \x02
Then deleted that character; Problem disappeared
Next step would have been [\x0B-\x1F] as x0A is newline
But I did not need it
u can use regexp [^[:print:]\t\r\n] to replace all text, then u can find your result without binary.
Can someone please help in adding a command for enter in a .txt file to emulate enter.
Example:
12345enter548793enter.....
where an entry will be a number followed by enter to next field where the next number will be inserted etc.. so it will look like this:
12345
548793
etc...
There is a difference between an enter and a return (-- old skool typewriter stuff - check Wikipedia on that).
One is a carriage return and one is a line feed; the ASCII codes for those are 10 and 13, I'd say test and find out which one (if not both) you'll need.
Normally (in like C++,C#,etc) you'd post \r\n --> 10 13
Just add newlines in the file?
12345
548793
etc...
The script that is reading in your txt file should already recognize whichever EOL character the text editor used. Many scripting languages automatically understand the various EOLs when reading from a filehandle. If yours doesn't, you may have to compose a regex that looks for the most common ones.
I was just wondering if anyone could help out with how to do the following using vi.
I have a text file and it might contain something like
start of text file:
--something1.something2--
--anotherThing1.something2--
end of text file:
If I want to take this line and convert it by way of searching for anything matching the first occurrence of [A-Za-z0-9] copy that to the buffer then append it on the same line to before the first occurrent of --
start of text file:
--something1.something2.something1--
--anotherThing1.something2.anotherThing1--
end of text file:
Is there a single VI command to do this?
Cheers
Ben
:%s/--\([a-zA-Z0-9]*\).\(.*\)--/--\1.\2.\1--/gc
or without asking confirmation for every replace:
:%s/--\([a-zA-Z0-9]*\).\(.*\)--/--\1.\2.\1--/g
will produce:
--something1.something2.something1--
--anotherThing1.something2.anotherThing1--
from:
--something1.something2--
--anotherThing1.something2--
This is if you want to copy the first word after '--' up to first '.' and append '.' and word found before the last '--'.
Using vim.
RE COMMENTS:
Someone mentioned that it will not work when there are multiple words and so on.
I tested it on the following:
start of text file:
--something1.something2.something3.something4.something5.something6--
--anotherThing1.something2.anotherThing3.anotherThing4.anotherThing5--
end of text file:
after replace with the above expression:
start of text file:
--something1.something2.something3.something4.something5.something6.something1--
--anotherThing1.something2.anotherThing3.anotherThing4.anotherThing5.anotherThing1--
end of text file:
Try this:
%s:\([A-Za-z0-9]\+\)\(\..\+\)--:\1\2.\1--:g
Holy crap, in the time it took me to login to post that answer, you posted it and already got a comment!
%s/--\(\w*\)\.\(.*\)--/--\1.\2.\1--/g
--ab1.cd2..yz99-- -> --ab1.cd2..yz99.ab1--
Building on stefanB's solution but using negated character classes and the "very magic" setting, I arrive at the following substitution command:
:%s/\v--([^.]+)\.(.*)--/--\1.\2.\1--/
Depending on the exact requirements (what are allowed characters for "something1" and "anotherThing1") this might or might not be more correct.
One more thing to consider: all solutions posted so far assume that there is only one occurance of the "--text.someOtherText-- pattern per line. If this is not the case, the (.*) part of the pattern would have to be adjusted and the /g modifier is required.