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How to import everything exported from a file with ES2015 syntax? Is there a wildcard?
(5 answers)
Closed 4 years ago.
Is there anyway not to write this:
import {replace_in_mtstr, tot_width, rationalize, eval_expression, ascii_to_latex, latex_to_ascii, getIndicesOf, cleanIndices, change_sign, exponentiate, multiply_grouped_nodes, flip_fraction, add_brackets, are_of_type, any_of_type, have_same_ancestors, have_same_type, have_same_text, have_single_factor, have_same_denom, are_same_terms, get_prev, get_next, get_all_next, has_op, parse_mtstr, parse_poly, prepare} from "./functions";
in ES6? These are all the exported functions in a different file. The closes thing I know is import * as object from 'file';. However, I want to have the functions available directly, not inside an object. Is this possible in ES6?
As the comments indicate, this is not possible.
Related
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Is it possible to access original function which has been overwritten in python [duplicate]
(3 answers)
Closed 4 months ago.
I'm doing maintenance on a huge file that follows like this
...stuff
def open(account):
...do stuff
...stuff
However I need to write a str to a txt, so I was gonna do the following
with open(filename,"a") as file:
file.write(mystr)
and this is calling the open(account) method, which is being used in a lot of classes, so renaming is not an option, how can I call the open method from the built-in functions from python and not the one with the same name?
You can do __builtins__.open().
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Const in JavaScript: when to use it and is it necessary?
(18 answers)
Closed 5 years ago.
I'm new to nodejs. I've been watching tutorials on Youtube and some use 'const' as opposed to 'var' which I'm familiar with in Javascript. I figured 'const' should mean constant and 'var'-variable. But I still don't get it. Why would you need to use 'const' instead of 'var'?
A similar question here:
Const in javascript? When to use it and is it necessary
If you are using ES6, you may want to look into using "let" vs "var". "let" is a safer choice as it is scoped and var is not. You can read more about that here:
https://medium.com/javascript-scene/javascript-es6-var-let-or-const-ba58b8dcde75#.xhhshyeaa
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Preferred method for viewing code generated by Template Haskell
(3 answers)
Closed 6 years ago.
I created Data with a help of Template Haskell. I use it from another program by $(code here).
So, can I convert Data to .hs file? I want to see the structure of Data.
One common way to do this is to write you normal Haskell code that uses the template Haskell and then feed GHC the option -ddump-splices and -ddump-to-file to have it output a file containing all of your original code but with the template Haskell expanded so you can see exactly what is being compiled.
Another option if you want to not see the full file is to use the pretty printer that comes with the template-haskell package. The module contains a number of helper functions for constructing a Doc which may then be rendered to a string with pprint :: Doc -> String and outputted using the IO features of the Q monad.
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Does groovy have an easy way to get a filename without the extension?
(10 answers)
Closed 7 years ago.
I'm wondering if there is a "Groovy" way to remove the file extension from a filename.
The current solution relies on the apache commons io package:
import org.apache.commons.io.FilenameUtils
String filename = '/tmp/hello-world.txt'
def fileWithoutExt = FilenameUtils.removeExtension(filename)
You can do something like this:
filename[0..<filename.lastIndexOf('.')]
To remove everything after the last . in the String.
Or the slightly prettier:
filename.take(filename.lastIndexOf('.'))
NB: if a file haven't an extension it will be not matched
May be overkill in this case but I tend to treat a lot of the commons classes as mixins
String.metaClass.mixin org.apache.commons.io.StringUtils
String.metaClass.mixin org.apache.commons.io.FilenameUtils
etc
This then allows you to
String filename = '/tmp/hello-world.txt'
def fileWithoutExt = filename.removeExtension()
Which ones I mixin depends on the requirements of the script but I tend to use this pattern a lot. It enables me to easily use methods I'm used to using without all the static class or import references.
This question already has answers here:
`export const` vs. `export default` in ES6
(6 answers)
Closed 7 years ago.
What is the difference between using
import { Devices } from '../models/devices';
and
import Devices from '../models/devices';
I haven't been able to google this one out yet.
I believe the first is a Named-Import and the second is a Default-Binding.
In simple English, I think the first one means "from all the stuff that was exported in ../models/devices, import only the Devices object". While the second one means "whatever is the default export of ../models/devices, import it as the name Devices.
See the standard. I must admit, though, I'm not 100% my interpretation is correct. That document was not written for mere humans to read, it seems... :/