This question already has answers here:
Const in JavaScript: when to use it and is it necessary?
(18 answers)
Closed 5 years ago.
I'm new to nodejs. I've been watching tutorials on Youtube and some use 'const' as opposed to 'var' which I'm familiar with in Javascript. I figured 'const' should mean constant and 'var'-variable. But I still don't get it. Why would you need to use 'const' instead of 'var'?
A similar question here:
Const in javascript? When to use it and is it necessary
If you are using ES6, you may want to look into using "let" vs "var". "let" is a safer choice as it is scoped and var is not. You can read more about that here:
https://medium.com/javascript-scene/javascript-es6-var-let-or-const-ba58b8dcde75#.xhhshyeaa
Related
This question already has answers here:
Is it possible to access original function which has been overwritten in python [duplicate]
(3 answers)
Closed 4 months ago.
I'm doing maintenance on a huge file that follows like this
...stuff
def open(account):
...do stuff
...stuff
However I need to write a str to a txt, so I was gonna do the following
with open(filename,"a") as file:
file.write(mystr)
and this is calling the open(account) method, which is being used in a lot of classes, so renaming is not an option, how can I call the open method from the built-in functions from python and not the one with the same name?
You can do __builtins__.open().
This question already has answers here:
How do I do a case-insensitive string comparison?
(15 answers)
Closed 7 months ago.
I’m new with Python. Just One question.
I try to create a mini quizz game and i want avoid this :
Answer = Input(« « « Who sing : « Thriller » ? » » »)
If answer == « Michael Jackson »:
Print(« Good. »)
Else:
Print(« Wrong. »)
The problem is that if the user answer «michael jackson », the code run with wrong.
How can i fixed that?
Thanks
The way that this is usually done is to just turn all the input to lowercase. This can be done with the .lower() method on the input string. The corrector answer would then be "michael jackson".
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How to import everything exported from a file with ES2015 syntax? Is there a wildcard?
(5 answers)
Closed 4 years ago.
Is there anyway not to write this:
import {replace_in_mtstr, tot_width, rationalize, eval_expression, ascii_to_latex, latex_to_ascii, getIndicesOf, cleanIndices, change_sign, exponentiate, multiply_grouped_nodes, flip_fraction, add_brackets, are_of_type, any_of_type, have_same_ancestors, have_same_type, have_same_text, have_single_factor, have_same_denom, are_same_terms, get_prev, get_next, get_all_next, has_op, parse_mtstr, parse_poly, prepare} from "./functions";
in ES6? These are all the exported functions in a different file. The closes thing I know is import * as object from 'file';. However, I want to have the functions available directly, not inside an object. Is this possible in ES6?
As the comments indicate, this is not possible.
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How to use string.replace() in python 3.x
(9 answers)
Closed 5 years ago.
I am trying to write a program that replaces every 'a' for '&'.I am currently stumped and was wondering if someone could write it for me to get an idea of what it would look like. Thanks.
strw = "kabhi kabhi mery dil main khyaal aata hy"
print (strw.replace("a", "&"))
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Annoying PHP error: “Strict Standards: Only variables should be passed by reference in”
I have this line of code,
$extension=end(explode(".", $srcName));
when I fun my function I get
PHP Strict Standards: Only variables should be passed by reference in
I am not sure how to solve this
The function end() requires a variable to be passed-by-reference and passing the return-value of a function doesn't acheive this. You'll need to use two lines to accomplish this:
$exploded = explode(".", $srcName);
$extension = end($exploded);
If you're simply trying to get a file-extension, you could also use substr() and strrpos() to do it in one line:
$extension = substr($srcName, strrpos($srcName, '.'));
Or, if you know the number of .'s that appear in the string, say it's only 1, you can use list() (but this won't work if there is a dynamic number of .'s:
list(,$extension) = explode('.', $srcName);