I am a beginner, learning programming using python 3.7. I am running a basic program to read content of a file after writing on it. But the print function won't print out the content of the file on the terminal. Can you please correct what mistake I am making here:
spam = input("What file would you like to open. Type the name below\n>>>")
# for the file name I type example.txt
work = open(spam, "r+")
work.write(input("Now write something on the file here\n>>"))
x = work.read()
print(x)
work.close()
After the write() completes, the file's object index needs to be moved to the beginning of the file
add work.seek(0) before the read() operation
spam = input("What file would you like to open. Type the name below\n>>>")
# for the file name I type example.txt
work = open(spam, "r+")
work.write(input("Now write something on the file here\n>>"))
work.seek(0)
x = work.read()
print(x)
work.close()
You can't actually read your spam variable since it is not a file.
Instead:
work = open("NewFile.txt", "w")
work.write(spam)
work.close()
Related
How can I pass a excel/csv file as a function parameter?
I have wrote a piece of code to copy content from one excel file to another excel file. Now I want to define it as a function so I just have to mention file name from which I want to transfer data to my existing file.
Thanks a lot in advance.
I am very new to Python Programming, and looking forward to learn a lot.
def feed_input_file(InputFile):
InputFile = "D:\\Python_Projects\\ABC.xlsx" #(I am passing Input file at the moment but I don't wanna pass it here)
#( Here I am trying to call my function parameter value)
Workbook1 = xl.load_workbook(feed_input_file(InputFile))
............
Still not quite sure what you are trying to do but if you want to create a function that will take a filename as an argument you could try something along the lines of:
def processFile(fn:str):
#Reads in the contents of file specified by fn
content = ''
with open(fn, 'a') as f:
data = f.read()
#Do something with data here to create content
return content
Then in your main part of the script
for filename in listofFiles:
fle_out = processFile(filename
#Do something here with file contents
I have to do this Coding Challenge on python 3.5.2.
So far here is my code:
file = open("holiday text",'r')
contents = file.read
print(contents)
file.close()
This should do the trick. Note that if the text file isn't in the same folder as the python (eg C:/Python35-32) you should specify the whole path, except if it's for some online challenge where you just provide the text file.
file = open("holiday text.txt",'r')
contents = file.read()
file.close()
print(contents)
Another way is to use the with statement which automatically opens/closes the file appropriately, like so:
with open("holiday text.txt",'r') as file:
contents = file.read()
print(contents)
If it helped, please press the arrow button for accepted answer.
So I am completely new to Python and can't figure out what's wrong with my code.
I need to write a program that asks for the name of the existing text file and then of the other one, that doesn't necessarily need to exist. The task of the program is to take content of the first file, convert it to upper-case letters and paste to the second file. Then it should return the number of symbols used in the file(s).
The code is:
file1 = input("The name of the first text file: ")
file2 = input("The name of the second file: ")
f = open(file1)
file1content = f.read()
f.close
f2 = open(file2, "w")
file2content = f2.write(file1content.upper())
f2.close
print("There is ", len(str(file2content)), "symbols in the second file.")
I created two text files to check whether Python performs the operations correctly. Turns out the length of the file(s) is incorrect as there were 18 symbols in my file(s) and Python showed there were 2.
Could you please help me with this one?
Issues I see with your code:
close is a method, so you need to use the () operator otherwise f.close does not do what your think.
It is usually preferred in any case to use the with form of opening a file -- then it is close automatically at the end.
the write method does not return anything, so file2content = f2.write(file1content.upper()) is None
There is no reason the read the entire file contents in; just loop over each line if it is a text file.
(Not tested) but I would write your program like this:
file1 = input("The name of the first text file: ")
file2 = input("The name of the second file: ")
chars=0
with open(file1) as f, open(file2, 'w') as f2:
for line in f:
f2.write(line.upper())
chars+=len(line)
print("There are ", chars, "symbols in the second file.")
input() does not do what you expect, use raw_input() instead.
Hi I'm trying to write a basic function that prints the contents from a textfile. The code I used is:
def open_my_file(input_file):
in_file = open(input_file, "r")
contents = in_file.read()
file.close()
word_list = contents.split(',')
print(word_list)
when I try running the program, it says syntax error.
Can someone help, please?
You use in_file when you open & read, but file when you close. That wouldn't be a syntax error, though.
When you're opening the file you're declaring the file with the name in_file, when you close the file you're saying file.close(), because you haven't declared any variable with the name file the python program gives you an SyntaxError.
Change file.close() to in_file.close()
Im trying to compare a users input with a .txt file but they never equal. The .txt contains the number 12. When I check to see what the .txt is it prints out as
<_io.TextIOWrapper name='text.txt' encoding='cp1252'>
my code is
import vlc
a = input("test ")
rflist = open("text.txt", "r")
print(a)
print(rflist)
if rflist == a:
p = vlc.MediaPlayer('What Sarah Said.mp3')
p.play()
else:
print('no')
so am i doing something wrong with my open() or is it something else entirely
To print the contents of the file instead of the file object, try
print(rflist.read())
instead of
print(rflist)
A file object is not the text contained in the file itself, but rather a wrapper object that facilitates operations on the file, like reading its contents or closing it.
rflist.read() or f.readline() is correct.
Read the documentation section 7.2
Dive Into Python is a fantastic book to start Python. take a look at it and you can not put it down.