Hi I'm trying to write a basic function that prints the contents from a textfile. The code I used is:
def open_my_file(input_file):
in_file = open(input_file, "r")
contents = in_file.read()
file.close()
word_list = contents.split(',')
print(word_list)
when I try running the program, it says syntax error.
Can someone help, please?
You use in_file when you open & read, but file when you close. That wouldn't be a syntax error, though.
When you're opening the file you're declaring the file with the name in_file, when you close the file you're saying file.close(), because you haven't declared any variable with the name file the python program gives you an SyntaxError.
Change file.close() to in_file.close()
Related
I am a beginner, learning programming using python 3.7. I am running a basic program to read content of a file after writing on it. But the print function won't print out the content of the file on the terminal. Can you please correct what mistake I am making here:
spam = input("What file would you like to open. Type the name below\n>>>")
# for the file name I type example.txt
work = open(spam, "r+")
work.write(input("Now write something on the file here\n>>"))
x = work.read()
print(x)
work.close()
After the write() completes, the file's object index needs to be moved to the beginning of the file
add work.seek(0) before the read() operation
spam = input("What file would you like to open. Type the name below\n>>>")
# for the file name I type example.txt
work = open(spam, "r+")
work.write(input("Now write something on the file here\n>>"))
work.seek(0)
x = work.read()
print(x)
work.close()
You can't actually read your spam variable since it is not a file.
Instead:
work = open("NewFile.txt", "w")
work.write(spam)
work.close()
I have to do this Coding Challenge on python 3.5.2.
So far here is my code:
file = open("holiday text",'r')
contents = file.read
print(contents)
file.close()
This should do the trick. Note that if the text file isn't in the same folder as the python (eg C:/Python35-32) you should specify the whole path, except if it's for some online challenge where you just provide the text file.
file = open("holiday text.txt",'r')
contents = file.read()
file.close()
print(contents)
Another way is to use the with statement which automatically opens/closes the file appropriately, like so:
with open("holiday text.txt",'r') as file:
contents = file.read()
print(contents)
If it helped, please press the arrow button for accepted answer.
import os,sys
import time
from colorama import Fore,Back,Style,init
init(autoreset=True)
appdata_path = os.path.join(os.getenv("APPDATA"), os.pardir)
subpath = "Local/sieosp/filesav2292.sav"
f = open(os.path.join(appdata_path, subpath), "r+")
lines=f.readlines()
a1=int (lines[116])
a2=int (lines[120])
a3=int (lines[124])
b4=int (lines[128])
c5=int (lines[132])
d6=int (lines[136])
e7=int (lines[140])
d8=int (lines[144])
d9=int (lines[148])
d10=int (lines[152])
d11=int (lines[156])
d12=int (lines[160])
total=int (a1+a2+a3+b4+c5+d6+e7+d8+d9+d10+d11+d12)
if (total)==(12):
print("You already own every character")
else:
with f:
userinputvalue=int (input("Type 1 if you want to unlock every character,or 0 if you would like to close this \n"))
if(userinputvalue)==1:
lines[156]=f.write("1\n")
lines[116]=f.write("1\n")
lines[120]=f.write("1\n")
lines[124]=f.write("1\n")
lines[128]=f.write("1\n")
lines[132]=f.write("1\n")
lines[136]=f.write("1\n")
lines[140]=f.write("1\n")
lines[144]=f.write("1\n")
lines[148]=f.write("1\n")
lines[152]=f.write("1\n")
lines[160]=f.write("1\n")
else:
print("Closing")
time.sleep(1)
So this should work,right? Don't know why f.write doesn't write 1 to my file. am i using it very wrong? Searched around google for some more info but I didnt understand a thing :/ tried to use f.write as f.readlines but no luck. thanks
It looks like you dont open the file in write mode, only in read mode.
f = open(os.path.join(appdata_path, subpath), "r+")
Change the "r" to a "w"
You have opened the file with "r+", so the file is even writable, the problem is that if you open a file with "r+" you have to manage the pointer in the file, otherwise the string will be append at the end.
In order to manage it you have to use the function f.seek(offset, from_what) like described here Input and Output.
For example in this code I change only the first line of the file:
f = open("File/Path/file.txt", "r+")
f.seek(0,0)
f.write("something")
f.close()
You also use line[N] = f.write("something"), careful to use it in this way, because it returns the number of characters wrote, not the characters wrote ;)
I try to do the following,
file = open('test.txt', 'w+')
item = "hello"
file.write(item)
print(file)
When I run this program I get the following output,
<_io.TextIOWrapper name='test.txt' mode='w+' encoding='cp1252'>
Is there a way to open and then write in the file and then save it so I can use that new file somewhere else? Even though I have something written in the file, I still get this output.
f = open("file.txt",'r+')
lines = f.readlines()
f.writelines(lines)
f.close()
Im trying to compare a users input with a .txt file but they never equal. The .txt contains the number 12. When I check to see what the .txt is it prints out as
<_io.TextIOWrapper name='text.txt' encoding='cp1252'>
my code is
import vlc
a = input("test ")
rflist = open("text.txt", "r")
print(a)
print(rflist)
if rflist == a:
p = vlc.MediaPlayer('What Sarah Said.mp3')
p.play()
else:
print('no')
so am i doing something wrong with my open() or is it something else entirely
To print the contents of the file instead of the file object, try
print(rflist.read())
instead of
print(rflist)
A file object is not the text contained in the file itself, but rather a wrapper object that facilitates operations on the file, like reading its contents or closing it.
rflist.read() or f.readline() is correct.
Read the documentation section 7.2
Dive Into Python is a fantastic book to start Python. take a look at it and you can not put it down.