This is my code when.
I am hitting put API it is executing middleware 3 times but it should execute for put API only.
app.use('/api/user', MiddlewareFun);
app.get('/api/user', (req, res) => {
//do something
});
app.use('/api/user', MiddlewareFun);
app.post('/api/user', (req, res) => {
//do something
});
app.use('/api/user', MiddlewareFun);
app.put('/api/user', (req, res) => {
//do something
});
please don't say use like this.
app.put('/api/user', MiddlewareFun, (req, res) => {
//do something
});
Well, it's happening, because you've made it to. If you want the middleware, to be executed at only selected method, you have to specify it. For example:
Instead of doing:
app.use('/api/user', MiddlewareFun)
app.put('/api/user', (req, res) => {
//do something
})
replace use method with put. As you'd bind regular route:
app.put('/api/user', MiddlewareFun)
app.put('/api/user', (req, res) => {
//do something
})
Also, one more thing. You don't have to duplicate your middleware call before every route declaration. If you want to apply a middleware to your whole router, you can use .use() (as you did), or .all(); which will result in the same behavior.
The middlewares in Express are binded to app or to router.
The solution to yuur problem is to check the method of the request object at the middleware
let MiddlewareFun = function (req, res, next) {
if (req.method === 'PUT') {
// do something
}
next()
}
app.use('/api/user', MiddlewareFun);
The answer is, You need to write express middleware which is part of your app or router. You can write as many middlewares you want, but in your case you just need it only once and here is the implementation of that.
const MiddlewareFun = function(req, res, next) {
// req is object which consist of information about request made.
// From req object you can get method name which is called.
if(req.method.toLowerString() === 'put') {
// your logic goes here
}
next();
}
app.use('/api/user', MiddlewareFun);
app.get('/api/user', (req, res) => {
//do something
});
app.post('/api/user', (req, res) => {
//do something
});
app.put('/api/user', (req, res) => {
//do something
});
Related
I'm trying to understand how to use an application-level middleware (or at least usually used like this) like cookie-parser on route-level and conditionally.
I tried something like:
const myMiddleware = (req, res, next) => {
if (myCondition) {
return cookieParser();
} else {
next();
}
}
app.use('/admin', myMiddleware, (req, res) => {
res.sendStatus(401)
})
But it's not working, the request will be just stuck.
Is this possible?
Traditional cookie-parser implementation:
app.use(cookieParser())
cookieParser() returns a middleware function, i.e. a function that takes in req, res, next as arguments. You just have to pass it the arguments:
const cookieParserMiddleware = cookieParser();
const myMiddleware = (req, res, next) => {
if (myCondition) {
return cookieParserMiddleware(req, res, next);
}
next();
};
app.use("/admin", myMiddleware, (req, res) => {
res.sendStatus(401);
});
Notice that I'm creating the cookieParser middleware outside myMiddleware - technically we could also just do return cookieParser()(req, res, next) but recreating the same middleware again and again on every request would be wasteful.
I've also removed the else since the if block returns from the function (guard clause).
I am using express with a pattern like this :
app = express();
router = express.Router();
router.use((req, res, next) => {
console.log("my middleware before");
next();
});
router.get('/foo', (req, res, next) => {
console.log("My route");
res.send("<h1>Hello</h1>")
next();
});
router.use((req, res, next) => {
console.log("my middleware after");
});
app.use("/", router);
app.get("*", (req, res, next) => {
console.log("page not found");
throw new Error("Not Found");
});
app.use((err, req, res, next) => {
console.log("Error occure");
res.send("<h1>Error</h1>");
});
app.listen(3000);
When I request '/foo' I would like to have
> my middleware before
> My route
> my middleware after
<h1>Hello</h1>
And when I request anything else :
> page not found
> Error occure
<h1>Error</h1>
But the page not found route is executed in each case, even if route '/foo' is done.
How can I get it working ?
When I run your code, I do not get the output you show, so something about your real code is apparently different than what you show in your question.
I do get a slightly confusing output and that happens because the browser sends both the /foo request and a /favicon.ico request. When I run it, the /foo request generates the desired output. The /favicon.ico request generates some middleware output and then gets stuck in the router.
If you filter out the /favicon.ico route (so that it doesn't confuse things) by adding this as the first route:
app.get("/favicon.ico", (req, res) => {
res.sendStatus(404);
});
Then, I get exactly this output in the server logs when I request /foo:
my middleware before
My route
my middleware after
Which is exactly what you asked for.
There is, however, a general problem with this:
router.use((req, res, next) => {
console.log("my middleware after");
});
Because it will catch and hang any legit requests that haven't yet had a response sent. You can't really code it that way unless you only don't call next() if a response has already been sent.
As a bit of a hack, you could do this:
router.use((req, res, next) => {
console.log("my middleware after");
// if response hasn't yet been sent, continue routing
if (!res.headersSent) {
next();
}
});
But, there is probably a better way to solve whatever problem you're actually trying to solve. If, in the future, you describe your real problem rather than a problem you have with your solution, then you allow people to offer a wider range of solutions to your real problem including things you haven't even thought of to try. As your question is written right now, we're stuck down the solution path you followed and don't know what the original problem was. That is, by the way, referred to as an XY Problem.
Do this
app = express();
router = express.Router();
router.use((req, res, next) => {
console.log("my middleware before");
next();
});
router.get('/foo', (req, res, next) => {
// use locals to record the fact we have a match
res.locals.hasMatch = true
console.log("My route");
res.send("<h1>Hello</h1>")
next();
});
router.use((req, res, next) => {
console.log("my middleware after");
});
app.use("/", router);
app.get("*", (req, res, next) => {
console.log("page not found");
throw new Error("Not Found");
});
app.use((err, req, res, next) => {
// check locals to see if we have a match
if (!res.locals.hasMatch) {
console.log("Error occure");
res.send("<h1>Error</h1>");
}
});
app.listen(3000);
You can utilize middlewares and even nest them.
You can implement it like this:
Middlewares
const before = (req, res, next) => {
console.log("my middleware before");
next(); // Supply next() so that it will proceed to the next call,
// in our case, since this is supplied inside the router /foo, after this runs, it will proceed to the next middleware
};
const after = (req, res, next) => {
console.log("my middleware after");
};
Route
// Supply "before" middleware on 2nd argument to run it first when this route is called
router.get('/foo', before, (req, res, next) => {
console.log("My route");
res.send("<h1>Hello</h1>");
next(); // Call next() to proceed to the next middleware, or in "after" middleware
}, after); // Supply the "after" middleware
Once ran, it will proceed with this desired result sequence:
> my middleware before
> My route
> my middleware after
Unmatched Routes Handler
Instead of this
app.get("*", (req, res, next) => {
console.log("page not found");
throw new Error("Not Found");
});
You can implement it like this instead, this is after your app.use("/", router); -- This will handle your unmatched routes:
Sources:
https://stackoverflow.com/a/44540743/6891406
https://stackoverflow.com/a/16637812/6891406
app.use((req, res, next) => {
console.log("page not found");
res.json({ error: 'Page not Found' })
});
I am using NodeJS, Express and Handlebars (template engine) to build a web application. Currently I'm trying to automatically redirect users whenever they enter an URL that does not exist (or whenever they might not have access to it).
The following returns the index page:
router.get('/', (req, res) => {
res.render('index/index');
});
But how do I make something like this:
router.get('/:ThisCouldBeAnything', (req, res) => {
res.render('errors/404');
});
The following example is from Github:
Say that I enter this URL:
https://github.com/thispagedoesnotexist
It automatically returns a 404. How do I implement this in my application?
Thanks in advance.
Use a middleware just after all route handlers to catch non existing routes:
app.get('/some/route', function (req, res) {
...
});
app.post('/some/other/route', function (req, res) {
...
});
...
// middleware to catch non-existing routes
app.use( function(req, res, next) {
// you can do what ever you want here
// for example rendering a page with '404 Not Found'
res.status(404)
res.render('error', { error: 'Not Found'});
});
After all your other routes you can add:
app.get('*', (req, res) => {
res.render('errors/404');
});
Alternately, you can use a middleware function after all your other middleware and routes.
app.use((req, res) => {
res.render('errors/404');
});
So you might end up with something that looks like:
//body-parser, cookie-parser, and other middleware etc up here
//routes
app.get('/route1', (req, res) => {
res.render('route1');
});
app.get('/route2', (req, res) => {
res.render('route2');
});
//404 handling as absolute last thing
//You can use middleware
app.use((req, res) => {
res.render('errors/404');
});
//Or a catch-all route
app.get('*', (req, res) => {
res.render('errors/404');
});
I see that you have express tagged. All you have to do is include a default handler that includes
res.status(404).render('404template')
For example
app.get('*', (req, res,next) => {
res.status(404).render('error.ejs')
});
I want to do something like this. I want to use different middleware if there is or isn't a certain query string.
app.get("/test?aaa=*", function (req, res) {
res.send("query string aaa found");
});
app.get("/test", middleware, function (req, res) {
res.send("no query string");
});
However, I failed. Can anyone help me? Thanks.
EDIT: I only need to add the middleware, I dont care what the value of the query string is
If your intention is to run the same route handler and call the middleware depending on whether the query string matches, you can use some sort of wrapping middleware:
var skipIfQuery = function(middleware) {
return function(req, res, next) {
if (req.query.aaa) return next();
return middleware(req, res, next);
};
};
app.get("/test", skipIfQuery(middleware), function (req, res) {
res.send(...);
});
If you want to have two route handlers, you could use this:
var matchQueryString = function(req, res, next) {
return next(req.query.aaa ? null : 'route');
};
app.get("/test", matchQueryString, function (req, res) {
res.send("query string aaa found");
});
app.get("/test", middleware, function (req, res) {
res.send("no query string");
});
(these obviously aren't very generic solutions, but it's just to give an idea on how to solve this)
You can do this:
app.get("/test", middleware, function (req, res) {
res.send("no query string");
});
middleware = function(req, res, next) {
if(!req.query.yourQuery) return next();
//middleware logic when query present
}
I'm relatively new to Express, and I'm looking for a way to make routes more reusable. In my app, I will have quite a few routes that can be passed to a generic handler, but will have different templates.
Example:
app.get('/about', function(req, res) {
res.render('about.html');
});
app.get('/', function(req, res) {
res.render('home.html');
});
While this example is contrite, I have 30+ such routes. What I would like to be able to do is something like this:
app.get('/about', generic.render('about.html'));
or otherwise somehow pass the template name to the function that returns res.render Is this possible in Express? All of my attempts to work around this result in variables being undefined.
I would prefer to not do something like this, tightly coupling my route parameters and template names:
app.get('/:template', function(req, res) {
res.render(req.params.template + '.html');
});
You could just make a a simple middleware that does this for you. Example:
function simpleRender(file, opts) {
opts || (opts = {});
return function(req, res) {
res.render(file, opts);
};
}
Then just use it like:
app.get('/about', simpleRender('about.html'));
app.get('/', simpleRender('home.html'));
This is how I do it:
const handler = (req, res, template) => {
res.render(template)
}
app.get('/about', (req, res) => {
handler(req, res, 'about.html')
})
This is a best practice for me
app.get('/:template',(req, res, next) => {
res.locals = `${template}.html`;
next();
},
renderMethod
);
function renderMethod(req, res){
res.render(res.locals)
}