=O27&" "&IF(D27<>"",VLOOKUP(D27,성취기준1반!$B$4:$C$19,2)&" ","")&IF(E27<>"",VLOOKUP(E27,성취기준1반!$E$4:$F$19,2)&" ","")&IF(F27<>"",VLOOKUP(F27,성취기준1반!$H$4:$I$19,2)&" ","")&IF(G27<>"",VLOOKUP(G27,성취기준1반!$K$4:$L$19,2)&" ","")&IF(H27<>"",VLOOKUP(H27,성취기준1반!$N$4:$O$33,2)&" ","")&IF(I27<>"",VLOOKUP(I27,성취기준1반!$Q$4:$R$33,2)&" ","")&IF(J27<>"",VLOOKUP(J27,성취기준1반!$T$4:$U$33,2)&" ","")&IF(K27<>"",VLOOKUP(K27,성취기준1반!$W$4:$X$33,2)&" ","")&IF(L27<>"",VLOOKUP(L27,성취기준1반!$Z$4:$AA$33,2)&" ","")&IF(M27<>"",VLOOKUP(M27,성취기준1반!$AC$4:$AD$19,2)&" ","")&P27
this is working code
=O28&" "&IF(D28<>"",VLOOKUP(D28,성취기준1반!$B$4:$C$19,2)&" ","")&IF(E28<>"",VLOOKUP(E28,성취기준1반!$E$4:$F$19,2)&" ","")&IF(F28<>"",VLOOKUP(F28,성취기준1반!$H$4:$I$19,2)&" ","")&IF(G28<>"",VLOOKUP(G28,성취기준1반!$K$4:$L$19,2)&" ","")&IF(H28<>"",VLOOKUP(H28,성취기준1반!$N$4:$O$33,2)&" ","")&IF(I28<>"",VLOOKUP(I28,성취기준1반!$Q$4:$R$33,2)&" ","")&IF(J28<>"",VLOOKUP(J28,성취기준1반!$T$4:$U$33,2)&" ","")&IF(K28<>"",VLOOKUP(K28,성취기준1반!$W$4:$X$33,2)&" ","")&IF(L28<>"",VLOOKUP(L28,성취기준1반!$Z$4:$AA$33,2)&" ","")&IF(M28<>"",VLOOKUP(M28,성취기준1반!$AC$4:$AD$19,2)&" ","")&P28
this is doesn't workin code.
Why doesn't it work?
This is not an answer in terms of a solution, but an answer in terms of the method you could employ to find and solve the issue. Mainly because you have not provided a working verifiable example, data or detail of the actual error.
First I would remove the vlookups and replace them with the expected results - if that then functions as it should then each of the vlookups needs to be tested, if not then check the detail of the function.
Appreciate if you can assist by explaining.. "why this doesn't work?" part. It is an error message or the the expected value is _ but I got _ instead.. (:
One thing I noticed is that you don't define what will be the outcome if D28 is "". If you don't define it, it'll return 'FALSE' value instead of a String/text.
In your IF() function, you only say IF(d28<>"",<DisplayValueFrom성취기준1반>) it should be IF(d28<>"",<DisplayValueFrom성취기준1반>,<DisplaySomeThingElse>)
Related
While trying to help the author of this other question, I bumped (again) into the situation that I would like the following Excel function:
=IFERROR(value, value_if_error, value_if_no_error)
In other words, I'm looking for an IFERROR() function with an else-clause.
The issue is: it can in theory be done as follows:
=IF(IFERROR(function(),error_value),value_if_error,value_if_no_error)
But what if error_value is a possible outcome of function()? That would make it impossible to use IFERROR(): e.g. function() returns a string, which can be anything, also an empty string, but it might also generate an error.
Edit: some clarification
Let me give an example:
=IFERROR(B3, "weird")
In "B3", there is a function, which returns a string, but even in case the value of this string is "weird", this is ok. How can I distinguish the erroneous case and the case where "weird" is a normal correct result?
As an image says more than a thousand words:
Next to IFERROR(), there also is the ISERROR() function, which can be used as an input for an IF()-clause:
=IF(ISERROR(value),value_if_error,value_if_no_error)
This might be a simple fix I'm unsure. I have the following formula which I would like to be able to drag up and down =IF(C311>B311,IF(C310>B310,IF(B309>C309,IF(C312>B312,2,1),0),0),0)
I'm guessing AND can be implemented in some way but I'm not sure. The logic behind my goal is if C311>B311 AND C310>B310 AND B309>C309 then check to see if C312>B312 if it is then put a 2 else put a 1. Perhaps there is another solution as well I'm not thinking of.
Try this: =IF(AND(C311>B311,C310>B310,B309>C309),IF(C312>B312,2,1),"")
Last argument I left it as "" but replace it to whatever you need.
Just another approach-
=IF((C311>B311)*(C310>B310)*(B309>C309),IF(C312>B312,2,1),"")
Highly likely this is a syntax error, but it's not throwing any errors.
=IF(ISERROR(MATCH(MID(Z2,28,6),$AF$1:$AG1,0)),"Mismatch","Included")
I have Z2, Z2 contains the following text:
"Revenue account for invoice P13930."
Or something like that, so the Mid function is suppoused to match that code, P13930, and not if it is within the specified cells (Here, AF1 and AG1)
I tried copying the whole text, or even just the code to AF1 and AG1, but it never writes a match. What's wrong with it?
Based it on my prototype:
=IF(ISERROR(MATCH($AE1,$AF1:$AG$1,0)),"Mismatch","Included")
Which does happen to work.
EDIT: I forgot to mention, I was wondering how to include the following scenarios:
Sometimes the code would look like this: P13930. and other times like this: P13930A. I'm not sure how to consider these as my knowledge is limited to Mid , Left , and Right. And as Jordan Mentioned, MATCH would be out of the picture given these variations.
If AF1 and AG1 contain codes like P13930A, you can use a wild card to match them like this
=IF(ISERROR(MATCH(MID(Z2,29,6)&"*",$AF$1:$AG1,0)),"Mismatch","Included")
Could you please specify your question:
First which we can advice, is to correct mid function argument:
=IF(ISERROR(MATCH(MID(Z2,29,6),$AF$1:$AG1,0)),"Mismatch","Included")
MID(Z2,29,6) - will give you result P13930
and then you want to find this code in some area, don't you? for example in the area AF1:AG1.
Please specify the result which you want to see in the cell AF2:
(a) code P13930; (b) INCLUDED - if area AF1:AG1 includes code P13930; (c) MISMATCHED - if area AF1:AG1 does NOT include code P13930 and etc.
I have found several sites that talk about work arounds but they all talk about doing some kind of mathematical equation, so this is the nested if's I am trying to fix.
=IF((COUNTIF($A$137:$A$146,$C173)=1), 9203, IF((COUNTIF($A$161:$A$196,$C173)=1), 9202, IF((COUNTIF($A$199:$A$228,$C173)=1),9216, IF((COUNTIF($A$231:$A$255,$C173)=1),9222, IF((COUNTIF($A$258:$A$295,$C173)=1),9202, IF((COUNTIF($A$199:$A$228,$C173)=1),9216, IF((COUNTIF($A$298:$A$312,$C173)=1),9203, IF((COUNTIF($A$327:$A$361,$C173)=1),9202, IF((COUNTIF(A364:A383,$C173)=1),9219, Error)))))))))
Any tips?
The problem is in the last word Error. It's not a valid name in Excel. Replace for example with "Error"
I'm using a function in vbscript which returns a variant array of strings.
JobIDs = objDoc.ConnectedSubmit(objServer)
The problem is I can't get the Job ID values from that array, as vbscript doesn't handle typed variables. It just gives a type mismatch when I attempt to do ANYTHING with the JobIDs array. I found some promising information here, but when I used the conversion function:
Set objConverter = CreateObject("ADS.ArrayConvert")
ConvertedJobIDs = objConverter.CStrArray(JobIDs())
It is giving me the same type mismatch error. Am I missing something obvious here? This is, apparently, an official microsoft solution, so I'm not sure why it seems to have the same problem, namely, not being able to actually do anything with a string array in the first place. I've seen the first part of my question answered in many places, all pointing to the MS solution, but I have yet to see any follow up reports of someone successfully using that solution.
I'm not sure if I understand why it doesn't work, so this answer might not be very helpful. I would have thought that something like this might work (following on from your previous question I'm assuming you're trying to get the cancellation to work):
For Each id In JobIDs
WScript.Echo id
YourJob = YourOutgoingFaxQueue.GetJob(id)
YourJob.Cancel()
Next
This behavior is by design, VBScript can't do anything with a non-variant array, there was a KB article from Microsoft that explained this but it is not on-line anymore:
Q165967 - PRB: Script Error Occurs When Referencing Non-variant Array
An archived copy of the article can be found at:
https://ftp.zx.net.nz/pub/archive/ftp.microsoft.com/MISC/KB/en-us/165/967.HTM