Match right to left not working - excel

So what's happening. I have a planned lot number and production lot number
In K5 I have the planned lot number as F31807010902
The production lot number FRD 03201807010902 is on another sheet with all the production lot numbers called Prod Time.
What I am to trying to do a wildcard search so that F31807010902 turns into *1807010902 and search for that in the 'Prod Time Sheet' so I can pull the corresponding date.
The 'Prod Time' sheet is layed out as
Prod Date-----Run Time-----Prod Lot#-----Qty
Solution 1 Tried
=INDEX('Prod Time'!A4:D4000,MATCH("*"&MID(K5,3,10),'Prod Time'!A4:D4000&"",0))
Solution 2 Tried
=VLOOKUP("*"&MID(K5,3,10),CHOOSE({1,2},'Prod Time'!A4:4000,'Prod Time'!A4:D4000),1,0)
Is there something wrong with my arguments or do I have to take a completely different approach?

Match only wants a single column or a single row, not a two dimensional range. Use the range in which you want to search the value.
=INDEX('Prod Time'!A4:A4000,MATCH("*"&MID(K5,3,10),'Prod Time'!C4:C4000&"",0))
And this is an array formula meaning it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting Edit mode

Related

Excel Formula Slow

is there anything i can do to further improve performance of this formula ?
=IF($A3<>"",IF(Jan!$E6<>"",LET(d_patt,IF(Jan!$E6<>"",VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(Jan!$B6<>"",Jan!$B6,0)&IF(Jan!$C6<>"",Jan!$C6,0)&IF(Jan!$D6<>"",Jan!$D6,0),""),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&IF(LEFT(d_patt,3)="OVT",d_patt,"OVT000")&IF(LEFT(d_patt,3)="SSI",d_patt,"SSI000")&IF(LEFT(d_patt,3)="SSO",d_patt,"SSO000")&IF(LEFT(d_patt,3)="SDS",d_patt,"SDS000")&IF(LEFT(d_patt,3)="HOL",d_patt,"HOL000")&IF(LEFT(d_patt,3)="LID",d_patt,"LID000")&IF(LEFT(d_patt,3)="UNP",d_patt,"UNP000")&IF(LEFT(d_patt,3)="FLD",d_patt,"FLD000")&IF(LEFT(d_patt,3)="MAT",d_patt,"MAT000")&IF(LEFT(d_patt,3)="LIS",d_patt,"LIS000")&IF(LEFT(d_patt,3)="CBR",d_patt,"CBR000")&IF(LEFT(d_patt,3)="ABS",d_patt,"ABS000")),"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000"),"")
i have this on a sheet for each day of the year x 400 people so 146k+ times. this is therefor taken up 80% of the sheet load time.
The sheet basically gets shift patters from Teams, check if there is any holidays, overtime etc from the relevant month tab and relevant cell for the day, and then will generate a code like below.
ROT080OVT000SSI000SSO000SDS234HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000
i have so far managed to make this faster by using the LET function, but not show if its possible to make any further improvements.
if you need an example file i can send this or upload somewhere, not sure if that is possible via stackoverflow or a preferred site to upload to.
Thanks
The following is a shortened version of your formula to reduce the complexity of computations.
Instead of building the 'OVT000SSI000...' string one piece after another while always checking if the first 3 characters of 'd_patt' match the current piece, we can set the whole string with '000's as default and only replace the section that matches 'd_patt' (see highlighted elements in screenshot below)
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&IF(LEN(Jan!$B6)>0,Jan!$B6,0)&IF(LEN(Jan!$C6)>0,Jan!$C6,0)&IF(LEN(Jan!$D6)>0,Jan!$D6,0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)
If $B6, $C6 and $D6 can only be either empty or a numerical number, in other words, if they are never a letter or special character, the 'd_patt' function can be further shortened as follows:
Which results in the full formula:
=IF(LEN($A3)>0,"ROT"&IF(LEN(Teams!$BHR4)>0,MID(Teams!$BHR4,MOD(NETWORKDAYS.INTL(Teams!$C4,I$2,"0000000")-1,LEN(Teams!$BHR4)/3)*3+1,3),"000")&LET(default,"OVT000SSI000SSO000SDS000HOL000LID000UNP000FLD000MAT000LIS000CBR000ABS000",d_patt,VLOOKUP(Jan!$E6,SETTINGS!$A$12:$B$27,2,FALSE)&(Jan!$B6+0)&(Jan!$C6+0)&(Jan!$D6+0),IF(LEN(d_patt)>0,REPLACE(default,SEARCH(LEFT(d_patt,3),default),6,d_patt),default)),“”)

Index with double Match returns incorrect closest values

I have an planning exported to Excel which looks like the following (tab ' Data'):
Each production line has a number of people working on it. Now is my goal to show how many people are working on a line per minute. We plan per product group, and several product groups combined form waht a line has to do per minute.
To get the production per minute I created the following (tab 'Conversie'):
=INDEX(Data!$H$2:$H$157;MATCH($N$1&A4;Data!$B$2:$B$157&Data!$C$2:$C$157;1))
In the example it works correct. However, the formula doesn't seem to always return the correct "Artikelomschrijving"(H) every time. I get incorrect return values when I extend this formula to other product groups.
I read that the data needs to be sorted ascending cause I use match_type 1. When I do that I get the right returns for some product groups, but the given example suddenly returns incorrect values.
I can't sort both column C and A in ascending order for the formulas to always return correct items. Can you help me to get past this hurdle?
After a little bit of google translate work, if I'm understanding your question correctly, you need to find the "Item Description" (H) of the record where the "Line" (B) = the value in N1 and the time is between the start and end times.
This is an array formula, you have to confirm it with Ctrl+Shift+Enter
=INDEX(Data!$H$2:$H$157,MATCH(1,(Data!$B$2:$B$157=$N$1)*(Data!$C$2:$C$157<$A2)*(Data!$D$2:$D$157>=$A2),0))
OR with semicolon syntax:
=INDEX(Data!$H$2:$H$157;MATCH(1;(Data!$B$2:$B$157=$N$1)*(Data!$C$2:$C$157<$A2)*(Data!$D$2:$D$157>=$A2);0))
I found the solution, thank you for pointing me in the right direction Valon Miller. This is the formula I fixed it with:
=ALS.FOUT(INDEX(Data!$H$2:$H$154;MATCH(1;(Conversie!L$1=Data!$B$2:$B$154)*((Conversie!$A32>=Data!$C$2:$C$154)*(Conversie!$A32<=Data!$D$2:$D$154));0));"")

automatic rota system based on special conditions

I am trying to create system for assigning tasks to a team using existing sequence. I have four separate columns:
Column A – Indicates the given sequence of operators
Column B – Indicates number of current tasks per operator (imported from another file by vlookup)
Column C – Indicates the name of the operator that was assigned to the last task (imported from another file by vlookup)
Column D – Indicates whether any of the operators are currently on holiday (check/uncheck check box (TRUE/FALSE logic)
I would like to automate the system so that the next operator that is due to receive tasks is displayed, however the operator must not have more than 4 tasks already assigned to him/her and must be present (not on holiday).
The selection process must repeat taking into consolidation the given sequence until the name is selected, hence if the last name in the sequence is not the exact match the system must start with the first name in the sequence.
Could someone be able to figure this out please as I am completely stock.
Currently, I have the following, column with the following =IF(B2<=4,A2,"N/A") and another column with the following =IF(E2=FALSE,F2,"N/A"). And one more column with =INDEX(SQESequence,MATCH(C2,SQESequence,0)+1,1), however that is not fully automated.
I think that I understand your problem / question and have come up with a solution. A more elegant formula solution may exist, will play with it more if I have time.
{=IFERROR(INDEX(INDIRECT("A"&MATCH(C2,A2:A5)+1&":A5"),MATCH(1,(INDIRECT("A"&MATCH(C2,A2:A5)+1&":A5")<>$C$2)*(INDIRECT("B"&MATCH(C2,A2:A5)+1&":B5")<4)*(INDIRECT("D"&MATCH(C2,A2:A5)+1&":D5")=FALSE),0)),INDEX($A$2:$A$5,MATCH(1,($A$2:$A$5<>$C$2)*($B$2:$B$5<4)*($D$2:$D$5=FALSE),0)))}
Enter CTRL SHIFT ENTER to set as an array formula, each function then returns an array of values rather than just a single value. You know you have set as an array formula when you see the { } 's
They say that a picture is worth 1000 words....so here are three!

Excel small mistake in function

I'm having a small problem with my formula in excel. I got a long list with IDs from different people numbered from 1 to 20535 for which I want to calculate the portfolio return. One ID has multiple lines so the ID is repeated over multiple lines depending on their number of investments.
This is the formula (it's working perfectly except for the bold)
=IF(B3=1;SUMIF($B$2:$B$357553;V3;$D$2:$D$357553);B4=B3+1)+IF(B3=1;SUMIF($G$2:$G$187396;V3;$I$2:$I$187396);B4=B3+1)+IF(B3=1;SUMIF($M$2:$M$544950;V3;$O$2:$O$544950);B4=B3+1)+IF(B3=1;SUMIF($R$2:$R$131523;V3;$T$2:$T$131523);B4=B3+1)
The only mistake is the part in bold. Once I get to the second person (so the second ID) it stops as the condition is not met anymore. How can I make it run past the first person? So untill ID 20535.
Thanks in advance!
Since you just want the TRUE part of the IF each time, just remove the IF and use the SUMIFs:
=SUMIF($B$2:$B$357553;V2;$D$2:$D$357553)+SUMIF($G$2:$G$187396;V2;$I$2:$I$187396‌​)+SUMIF($M$2:$M$544950;V2;$O$2:$O$544950)+SUMIF($R$2:$R$131523;V2;$T$2:$T$131523)‌​
Put the above in row 2 and copy down. That should do it.

How to search for a partial and an absolute in excel to get an answer?

I have a worksheet, in where I need a search that does more than one query. The problem I am running into is this:
On the workbook there are two tabs, the first is Jobs, the second is OOR. In OOR there are multiple columns empty, Order Qty., Orig Promise Date, and Shop Order.
Now I know there are duplicates, and this is fine, what I am looking at now is to use Column B in OOR is a refrence. So in this case use B3 as the refrence point. which is a partial number of 48900421 Rev 2. What I want to do is this, use two refrence points.
I want to look up B3 in OOR, and use two points of refrence to gurantee the correct job is refrenced. Those two columns to refrence is in Jobs. The first is Column B which will always equal Dakota Systems, Inc., and the other will reference Column C, but this is where I don't know what to do here, I since C3 in OOR only shows 48900421, it will never find 48900421 Rev 2I thought about using something like this:
=IFERROR(INDEX(Jobs!$E:$E,MATCH(1,INDEX((OOR!$C:$C=$B3)*(Jobs!$C:$C="Dakota Systems, Inc."),1),0)),"")
But for some reason I am getting a blank when I don't think I should be. I'm loosing my sanity this late in the week, can someone help?
https://dl.dropbox.com/u/3327208/Excel/twosearches.xlsx
You don't seem to be referencing the right columns....and also you need a zero in the second INDEX function, not a 1
Try this version in in OOR!I3 copied down, using ISNUMBER(FIND to find your part number within other text:
=IFERROR(INDEX(Jobs!E$3:E$1000,MATCH(1,INDEX(ISNUMBER(FIND(B3,Jobs!C$3:C$1000))*(Jobs!B$3:B$1000="Dakota Systems, Inc."),0),0)),"")
format in required date format
Revised re comment below:
=IFERROR(INDEX(Jobs!E$3:E$1000,MATCH(1,INDEX(ISNUMBER(FIND(B3,Jobs!C$3:C$1000))*(Jobs!B$3:B$1000="Dakota Systems, Inc.")*(Jobs!A$3:A$1000=M3),0),0)),"")

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