disable SublimeREPL backslash highlights - sublimetext3

When running SublimeRepl with python, I have noticed that it always highlights some backslash + characters. I am not sure why this, any suggestion into why this is going on and how to disable this ?
side note
My search led me to ANSII escape code/color code, or even syntax highlighting. are these relevant ? I am not sure since I don't know much about these topics

In python unless an 'r' or 'R' prefix is present, every character after '\' is interpreted as an escape sequence.And the ones that are highlighted here are not valid escape sequences. \a is not highlighted here in the same fashion because it is a valid escape sequence.
\a ASCII Bell (BEL)
If you want to use a backslash inside a string, you should use double slashes(\\) like this,
>>> print("c:\\my_main\\asdf\\xsdf")

Related

How to fine-tune Macros after having recorded it through recording in Vim?

Specific question
Description
After recording the desired action to registrar o, I pasted the whole macro to my ~/.vimrc and assigned it as follows (directly pasting the mappings are not displayed properly)
Expected behavior
I would like to use this macro to get myself a new "comment line" that leads a new section of script, formatted such that the name of the section is centered. After populating the "section title", I would like to enter insert mode in a new line.
In the following screen-record, I have tested both #o and #p$ on the word "time". The second attempt with#p` worked as desired.
The problem (on Windows machine specifically)
As you see, the #o mapping gets me junk phrases which had been part of my definition for the macro. Does this have to do with the ^M operator? And, how can I fix the #o mapping, which uses * to populate the line?
The two mapping worked just fine on Linux system. (Don't know why, as I have recorded and pasted the macro-definition on Windows machine.) This also does not appear to be a problem on Mac with MacVim.
Generalized question
Is there a way to properly substitute the ^M operator (for <CR>, or "Enter"-key)?
Is there a way to properly substitute the ^[ operator (for <ESC>, or the "Escape"-key)?
Is there a systematic list of mappings from these weird representation of keystrokes, as recorded by the "recording" function through q.
Solution
Substitute the ^M marks in the macro-definition with \r. And, substitute ^[ to be \x1b, for the ESC key. The mappings are fixed as follows:
let #o = ":center\ri\r\x1bkV:s/ /\*/g\rJx50A\*\x1b80d|o"
let #p = ":center\ri\r\x1bkV:s/ /\"/g\rJx50A\"\x1b80d|o"
Complete list of key-codes/mappings? Approach 1: through hex code.
Thanks to Zbynek Vyskovsky, the picture is clear. For whatever key one may think of, Vim takes its ASCII value at the "face value". (The trick is to use a escape clause starting with \x, where x serves as the leader key/string/character connecting to the hex values.) Thus, the correspondence list (incomplete yet), goes as follows:
Enter --- \x0d --- \r
ESC --- \x1b --- \e
Solution native to Vim
By chance, :help expr-quote gives the following list of special characters. This shall serve as the definite answer to the original question in general form.
string *string* *String* *expr-string* *E114*
------
"string" string constant *expr-quote*
Note that double quotes are used.
A string constant accepts these special characters:
\... three-digit octal number (e.g., "\316")
\.. two-digit octal number (must be followed by non-digit)
\. one-digit octal number (must be followed by non-digit)
\x.. byte specified with two hex numbers (e.g., "\x1f")
\x. byte specified with one hex number (must be followed by non-hex char)
\X.. same as \x..
\X. same as \x.
\u.... character specified with up to 4 hex numbers, stored according to the
current value of 'encoding' (e.g., "\u02a4")
\U.... same as \u but allows up to 8 hex numbers.
\b backspace <BS>
\e escape <Esc>
\f formfeed <FF>
\n newline <NL>
\r return <CR>
\t tab <Tab>
\\ backslash
\" double quote
\<xxx> Special key named "xxx". e.g. "\<C-W>" for CTRL-W. This is for use
in mappings, the 0x80 byte is escaped.
To use the double quote character it must be escaped: "<M-\">".
Don't use <Char-xxxx> to get a utf-8 character, use \uxxxx as
mentioned above.
Note that "\xff" is stored as the byte 255, which may be invalid in some
encodings. Use "\u00ff" to store character 255 according to the current value
of 'encoding'.
Note that "\000" and "\x00" force the end of the string.
As you use assigning to register using vim expression language, it's definitely possible in platform independent way. The strings in vim expressions understand the standard escape sequences, therefore it's best to replace ^M with \r and Esc with \x1b:
let #o = ":center\riSomeInsertedString\x1b"
There is no list of of special characters to be translated as far as I know but you can simply take all control characters (ASCII below 32) and translate them to corresponding escape sequence "\xHexValue" where HexValue is the value of the character. Even \r (or ^M) can be translated to \x0d as its ASCII value is 13 (0x0d hex).

How do I remove the last six characters of every line in Vim?

I have the following characters being repeated at the end of every line:
^[[00m
How can I remove them from each line using the Vim editor?
When I give the command :%s/^[[00m//g, it doesn't work.
You could use :%s/.\{6}$// to literally delete 6 characters off the end of each line.
The : starts ex mode which lets you execute a command. % is a range that specifies that this command should operate on the whole file. The s stands for substitute and is followed by a pattern and replace string in the format s/pattern/replacement/. Our pattern in this case is .\{6}$ which means match any character (.) exactly 6 times (\{6}) followed by the end of the line ($) and replace it with our replacement string, which is nothing. Therefore, as I said above, this matches the last 6 characters of every line and replaces them with nothing.
I would use the global command.
Try this:
:g/$/norm $xxxxxx
or even:
:g/$/norm $5Xx
I think the key to this problem is to keep it generic and not specific to the characters you are trying to delete. That way the technique you learn will be applicable to many other situations.
Assuming this is an ANSI escape sequence, the ^[ stands for a single <Esc> character. You have to enter it by pressing Ctrl + V (or Ctrl + Q) on many Windows Vim installations), followed by Esc. Notice how this is then highlighted in a slightly different color, too.
It's easy enough to replace the last six characters of every line being agnostic to what those characters are, but it leaves considerable room for error so I wouldn't recommend it. Also, if ^[ is an escape character, you're really looking for five characters.
Escape code
Using ga on the character ^[ you can determine whether it's an escape code, in which case the status bar would display
<^[> 27, Hex 1b, Octal 033
Assuming it is, you can replace everything using
:%s/\%x1b\[00m$//gc
With \%x1b coming from the hex value above. Note also that you have to escape the bracket ([) because it's a reserved character in Vim regex. $ makes sure it occurs at the end of a line, and the /gc flags will make it global and confirm each replacement (you can press a to replace all).
Not escape code
It's a simple matter of escaping then. You can use either of the two below:
:%s/\^\[\[00m$//gc
:%s/\V^[[00m\$//gc
If they are all aligning, you can do a visual-block selection and delete it then.
Otherwise, if you have a sequence unknown how to input, you can visually select it by pressing v, then mark and yank it y (per default into register "). Then you type :%s/<C-R>"//g to delete it.
Note:
<C-R>" puts the content of register " at the cursor position.
If you yanked it into another register, say "ay (yank to register a - the piglatin yank, as I call it) and forgot where you put it, you can look at the contents of your registers with :reg.
<C-R> is Vim speak for Ctrl+R
This seems to work fine when the line is more than 5 chars long:
:perldo $_ = substr $_, 0, -5
but when the line is 5 or less chars long it does nothing.
Maybe there is a easy way in perl to delete the last 5 chars of a string, but I don't really know it:)
Use this to delete:
:%s/^[[00m//gc

Vim Search/replace: what do I need to escape?

I'm trying to search and replace $data['user'] for $data['sessionUser'].
However, no matter what search string I use, I always get a "pattern not found" as the result of it.
So, what would be the correct search string? Do I need to escape any of these characters?
:%s/$data['user']/$data['sessionUser']/g
:%s/\$data\[\'user\'\]/$data['sessionUser']/g
I did not test this, but I guess it should work.
Here's a list of all special search characters you need to escape in Vim: `^$.*[~)+/
There's nothing wrong with with the answers given, but you can do this:
:%s/$data\['\zsuser\ze']/sessionUser/g
\zs and \ze can be used to delimit the part of the match that is affected by the replacement.
You don't need to escape the $ since it's the at the start of the pattern and can't match an EOL here. And you don't need to escape the ] since it doesn't have a matching starting [. However there's certainly no harm in escaping these characters if you can't remember all the rules. See :help pattern.txt for the full details, but don't try to digest it all in one go!
If you want to get fancy, you can do:
:%s/$data\['\zsuser\ze']/session\u&/g
& refers to the entire matched text (delimited by \zs and \ze if present), so it becomes 'user' in this case. The \u when used in a replacement string makes the next character upper-case. I hope this helps.
Search and replace in vim is almost identical to sed, so use the same escapes as you would with that:
:%s/\$data\['user'\]/$data['session']/g
Note that you only really need to escape special characters in the search part (the part between the first set of //s). The only character you need to escape in the replace part is the escape character \ itself (which you're not using here).
The [ char has a meaning in regex. It stands for character ranges. The $ char has a meaning too. It stands for end-line anchor. So you have to escape a lot of things. I suggest you to try a little plugin like this or this one and use a visual search.

How to search and replace an unprintable character

I've a file that was exported from Word and it replaced all quotes with strange unicode characters which aren't correctly displayed in vim.
So now I want those characters to be replaced with quotes, but I don't know how to enter this character in
:%s/???/'/g
The characters look like this: ~U ~R. But of course I can't just mark them with mouse and paste in the command.
You can try setting the encoding type and see if it fixes the visalizations of those characters:
:set encoding=utf-8
then you can use them directly. Alternatively, you can place your cursor on the unprintable character and hit ga, it will show the decimal/hex/octal code of that character, then you can substitute it with:
:%s/\%xYY/substitute/g
where YY is the hex code of the char, if it's multibyte:
:%s/\%uYYYY/substitute/g
for details:
:help character-classes
Note that you can search and match with \%xff or \%uabcd but will be unable to substitute with it.
I usually:
delete the character with: x
undo my change with: u
do the substitute thanks to c_CTRL-R: :%s/^R"/'/g
you can also filter it by using the tr command
for example replacing the hex a0 which stems from MacOs cut-and-paste
can be replaced with a whitespace as follows (\240 being the octal representation of hex a0)
:.,$!tr "\240" " "

vim regexps from the perl's point of view: which special characters to escape with backslash

Imagine, we have to construct a regexp in vi/vim. Which special characters we have to escape with backslash?
By special characters I mean the following chars: {}|()-[]+*.^$?
Seems like we have to escape: {|()+?
And leave as is: }^$*.[]-
Thanks.
p.s. AFAIK, we have no '?' character in vi/vim but '=' instead which should be also escaped by backslash.
I think the Vim documentation on magic characters will give you a definitive list.
In vim:
:help magic
I think the simplest way, that will work regardless of vim's magic setting, is
let re = '\V' . escape(fixed_string, '\')
\V disables magic entirely from that point onward in the RE. This means that anything not preceded by a single backslash (well, technically by an odd number of backslashes) is a normal character. Since we escape any backslashes in the fixed string, there can be no magic characters contained in it.
Remember that with \V in effect, you have to backslash-prefix any RE meta-characters. So if you're looking for a line that entirely consists of the fixed string, you would
let full_line_re = '\V\^' . escape(fixed_string, '\') . '\$'
Also keep in mind that vim's ignorecase and smartcase settings will affect RE behaviour. The \C (case-sensitive) and \c (case-insensitive) switches work the same way as \V: they will override those settings for the part of any regexp which follows them.

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