awk sum of selected values in column - linux

Question

I want to sum selected values in column in awk. Second column is time. I want to add values from 4th column in each second.
Input:
1 0.1 2 1 3
2 0.3 2 2 3
4 0.6 2 3 3
2 1.1 2 4 3
5 1.3 2 5 3
6 2.2 2 6 3
7 2.7 2 7 3
8 3.6 2 8 3
9 3.9 2 1 3
10 4.1 2 1 3
Expected output (we have 5 seconds):
6
9
13
9
1
EDIT:
Here is my code but i have no idea how can it works dynamic.
awk '$2>x && $2<=y (sum+=$4) END {print sum}' filename
where x - start time, y - end time. It works only for static values, it means that now I can obtain result only for one selected second.

Answer 1

Try the following awk program
BEGIN {
total = 0
secondEnd = 1
}
{
if($2 < secondEnd) {
total += $4
next
}
while($2 > secondEnd) {
print(total)
total = 0
secondEnd++
}
total = $4
}
END {
print(total)
}

Answer 2

EDIT: As per OP's request adding a code which will accept any field provided to it as a awk variable.
awk -v col1="2" -F"[ .]" '$col1 == prev+1{print sum;sum=prev=""} {sum+=$NF;prev=$col1} END{if(prev && sum){print sum}}' Input_file
OR(a non-one liner form of solution here)
awk -v col1="2" -F"[ .]" '
$col1 == prev+1{
print sum;
sum=prev=""
}
{
sum+=$NF;
prev=$col1
}
END{
if(prev && sum){
print sum}
}' Input_file
In case you are passing a bash variable to awk variable then do following.
column=2 ##Shell variable
awk -v col1="$column" -F"[ .]" '$col1 == prev+1{print sum;sum=prev=""} {sum+=$NF;prev=$col1} END{if(prev && sum){print sum}}' Input_file
Could you please try following and let me know if this helps you(considering that your actual Input_file is same as shown sample here).
awk -F"[ .]" '$2 == prev+1{print sum;sum=prev=""} {sum+=$NF;prev=$2} END{if(prev && sum){print sum}}' Input_file
Adding a non-one liner form of solution too now.
awk -F"[ .]" '
$2 == prev+1{
print sum;
sum=prev=""
}
{
sum+=$NF;
prev=$2
}
END{
if(prev && sum){
print sum}
}' Input_file