When I add the script snippet "exit 0" in profile, I can not ssh to this linux system any more.
How to fix it.
The actual answer is that you can ssh to that machine, however when doing an ssh it reads your profile where it reads directly exit 0 so it cleanly terminates your ssh session.
If you do something like :
ssh user#machine
Then ssh will try to invoke a login-shell. Assuming your default shell is bash, then you find the following in man bash:
When bash is invoked as an interactive login shell, or as a non-interactive shell with the --login option, it first reads and executes commands from the file /etc/profile, if that file exists. After reading that file, it
looks for ~/.bash_profile, ~/.bash_login, and ~/.profile, in that order, and reads and executes commands from the first one that exists and is readable.
So since you have an exit statement in one of those files, your ssh session will terminate immediately.
how to solve it: remove the exit statement.
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I have a command that runs fine if I ssh to a machine and run it, but fails when I try to run it using a remote ssh command like :
ssh user#IP <command>
Comparing the output of "env" using both methods resutls in different environments. When I manually login to the machine and run env, I get much more environment variables then when I run :
ssh user#IP "env"
Any idea why ?
There are different types of shells. The SSH command execution shell is a non-interactive shell, whereas your normal shell is either a login shell or an interactive shell. Description follows, from man bash:
A login shell is one whose first character of argument
zero is a -, or one started with the --login option.
An interactive shell is one started without non-option
arguments and without the -c option whose standard input
and error are both connected to terminals (as determined
by isatty(3)), or one started with the -i option. PS1 is
set and $- includes i if bash is interactive, allowing a
shell script or a startup file to test this state.
The following paragraphs describe how bash executes its
startup files. If any of the files exist but cannot be
read, bash reports an error. Tildes are expanded in file
names as described below under Tilde Expansion in the
EXPANSION section.
When bash is invoked as an interactive login shell, or as
a non-interactive shell with the --login option, it first
reads and executes commands from the file /etc/profile, if
that file exists. After reading that file, it looks for
~/.bash_profile, ~/.bash_login, and ~/.profile, in that
order, and reads and executes commands from the first one
that exists and is readable. The --noprofile option may
be used when the shell is started to inhibit this behav
ior.
When a login shell exits, bash reads and executes commands
from the file ~/.bash_logout, if it exists.
When an interactive shell that is not a login shell is
started, bash reads and executes commands from ~/.bashrc,
if that file exists. This may be inhibited by using the
--norc option. The --rcfile file option will force bash
to read and execute commands from file instead of
~/.bashrc.
When bash is started non-interactively, to run a shell
script, for example, it looks for the variable BASH_ENV in
the environment, expands its value if it appears there,
and uses the expanded value as the name of a file to read
and execute. Bash behaves as if the following command
were executed:
if [ -n "$BASH_ENV" ]; then . "$BASH_ENV"; fi
but the value of the PATH variable is not used to search
for the file name.
How about sourcing the profile before running the command?
ssh user#host "source /etc/profile; /path/script.sh"
You might find it best to change that to ~/.bash_profile, ~/.bashrc, or whatever.
(As here (linuxquestions.org))
Shell environment does not load when running remote ssh command. You can edit ssh environment file:
vi ~/.ssh/environment
Its format is:
VAR1=VALUE1
VAR2=VALUE2
Also, check sshd configuration for PermitUserEnvironment=yes option.
I had similar issue, but in the end I found out that ~/.bashrc was all I needed.
However, in Ubuntu, I had to comment the line that stops processing ~/.bashrc :
#If not running interactively, don't do anything
[ -z "$PS1" ] && return
I found an easy resolution for this issue was to add
source /etc/profile
to the top of the script.sh file I was trying to run on the target system.
On the systems here, this caused the environmental variables which were needed by script.sh to be configured as if running from a login shell.
In one of the prior responses it was suggested that ~/.bashr_profile etc... be used.
I didn't spend much time on this but, the problem with this is if you ssh to a different user on the target system than the shell on the source system from which you log in it appeared to me that this causes the source system user name to be used for the ~.
Just export the environment variables you want above the check for a non-interactive shell in ~/.bashrc.
I was assigned an account for log in to a remote server, and I want to change my default shell.
I tried chsh command but it says: chsh: "/public/home/{my_id}/bin/zsh" is not listed in /etc/shells.
If you don't have permission to install zsh system wide, a quick fix is to append exec ~/bin/zsh -l to ~/.bash_profile (if bash is the current shell), or an equivalent rc file for the current login shell.
zsh -l starts zsh as a login shell.
exec COMMAND replaces the current process with COMMAND, so you'll only have to type exit (or press ctrl+d) once.
~/.bash_profile is executed when bash starts as a login shell, you can still run command bash normally.
Depending what is in ~/.bash_profile (or equivalent), you may wish to avoid executing its other contents, by putting exec ~/bin/zsh -l at the start of the file (not the end), and copy/port anything important over to the zsh equivalent, $ZDOTDIR/.zprofile.
I might also do export SHELL="$HOME/bin/zsh", although I'm unsure of the full effects of setting SHELL differently to that specified for your user in /etc/passwd, to a shell not in /etc/shells, and to a shell binary in your home path.
First check all the shells available on your linux system
cat /etc/shells
Use chsh command line utility for changing a login shell with the -s or –shell option like this.
# chsh --shell /bin/sh tecmint
i have a question related to connecting via ssh with "system()" function in perl.
in my perl script i want to connect via ssh to another ip, run a command and return its value or redirect result value to a file.
system ("su - anotherUSer ; ssh someUsername#someIpAddress");
(i change my username so that i am not asked for a password)
when i execute this only line it changes the username correctly but not connects via ssh. In other words, the second part of the system call is not done (or is done but not reflected on the terminal).
If i enter mannualy to the server where this script executes and run this two commands, i can run them without errors.
When i run "exit" command to logout my anotherUser user an error raises:
(ssh: "username"."ip": node name or service name not known)
I also tested it escaping '#' and '.'
system ("su - anotherUSer ; ssh someUsername\#number\.number\.number\.number");
in this case when i run the "exit" command, it askes for the password(Remember that i swiched users so that password could be ommited).
I hope you understand my problem.
Thanks!!!
You're telling the wrong shell to execute ssh.
You spawn a shell and ask it to execute two commands, su and ssh. It first spawns su, which launches another shell. You didn't tell this new shell to do anything, so it waits for input. When it finally exits, the first shell executes the second command, ssh.
Use:
system("su -c 'ssh someUsername#someIpAddress' - anotherUSer");
But that's nasty! Why not just set up a key for the current user instead of becoming anottherUSer to use theirs?
I read some following script when looking for script to run Appium with Jenkins
#!/bin/bash --login
killall -9 "iPhone Simulator" &> /dev/null
killall -9 node &> /dev/null
killall -9 instruments &> /dev/null
...
I don't understand why the first line of the script needs to pass a --login option here. I have read the man page but still have some confusions.
What I get from the man page is that passing --login to make the script be called as login shell instead of interactive shell. interactive shell is the shell that users can interact with the shell, like input something with keyboard. But what is login shell? I checked the man page that it said login shell would load ~/.bash_profile, but if open the terminal through Mac OSX's Terminal.app, it also loads the ~/.bash_profile and I am able to interactive with the shell,right? So, the shell I open is both login shell and interactive shell?
The main difference is that a login shell executes your profile when it starts. From the man page:
When bash is invoked as an interactive login shell, or as a non-interactive shell with the --login option, it first reads and
executes commands from the file /etc/profile, if that file exists. After reading that file, it looks for ~/.bash_profile,
~/.bash_login, and ~/.profile, in that order, and reads and executes commands from the first one that exists and is readable.
The --noprofile option may be used when the shell is started to inhibit this behavior.
When a login shell exits, bash reads and executes commands from the file ~/.bash_logout, if it exists.
If I open a shell into a machine with: putty -load session_name and then execute a command to add a job to a Grid queue on a linux system (qsub -cwd -b hostname), everything works fine.
But if I add the command to a text file, and then do putty -load session_name -m file.txt, I get qsub: command not found
If I back out and simplify the text file to be only the command hostname and use the -m option, it also works fine.
If I use the Connection->SSH->Remote command, and do something similar as the -m command, I get the same results as from the command line.
I'm very much a novice at linux systems, and this seems like it should be a simple fix to tell something that 'qsub' exists somewhere. Either that or there are some restrictions on these remote access things...
Edit:
Ok, so the initial question was how to run it--and I figured that out (add an absolute path), but there are other environment variable issues as well. It appears that qsub requires the SGE_ROOT variable to be set, but that isn't set for the remote commands window either.
So, a better question is, how do I get the putty remote commands shell (using -m) to open with the same properties and setup as a manual command line shell?
qsub is on your path when you log in interactively, but in the non-interactive shell it is not. Give the full path in the script, or set PATH in the script, and you ought to fix your problem.
It seems you need to run your command in the context of an interactive session, but the sshd protocol doesn't directly do that. So try invoking the command indirectly through /bin/sh.
/bin/sh -i -c "qsub -cwd -b hostname"
The -i makes the shell initialize itself like an interactive one, so it will load all the environment variables in your .profile or .bashrc that are loaded in a real interactive shell. The -c provides a command to run within that interactive shell.
You shouldn't have to explicitly set any paths this way since it works in an interactive session.