Should I make subVIs in preallocated VI as preallocated too in LabVIEW? - execution

I have got a VI which execution type is set to be as preallocated clone reentrant.
In the VI i have several SubVIs. Should I set the execution type of SubVIs the same as in the main VI?
Thank you

Setting a VI to be reentrant doesn't automatically make its subVIs reentrant - if it did, this would break some of the use cases for non-reentrant VIs, such as serialising access to single resources or maintaining stored state data between calls. So to decide whether a subVI needs to be reentrant, you just have to consider the same issues as you did when deciding whether the parent VI needed to be reentrant.
I found a good summary of the considerations in this post by GregR on the LAVA forum, which still holds true as far as I can see (fully reentrant was the older LabVIEW term for preallocated clone reentrant):
Any VI that maintains state needs to be either non-reentrant or fully
reentrant depending on its requirements for that state.
If there are any VIs that truly can't be called at the same time, those should
stay non-reentrant. This could be things like configuration dialogs or file modification. Non-reentrant VIs are one of the easiest ways to serialize access to single instance resources.
Any VI that is part
of a performance critical code path probably should be made fully reentrant. This avoids synchronization points between multiple parallel instances of performance critical code or non-performance critical code getting in the way of performance critical code.
Beyond that you can start to favor non-reentrant or shared reentrant to reduce memory usage.
[...] VIs that always execute quickly can be considered for leaving as non-reentrant. Keep in mind that there is a difference between a VI that always executes quickly and one that typically executes quickly. Anything that does asynchronous communication (networking, queues, ...) should be considered slow, because it could take longer than expected.
Making VIs that are called from a lot of places shared reentrant instead of fully reentrant will slightly increase execution time but can greatly
reduce the number of instances required and thus memory usage.

Related

Does a variable only read by one thread, read and written by another, need synchronization?

Motive:
I am just learning the fundamentals of multithreading, not close to finishing them, but I'd like to ask a question this early in my learning journey to guide me toward the topics most relevant to my project I 'm working on.
Main:
a. If a process has two threads, one that edits a set of variables, the other only reads said variables and never edits their values; Then do we need any sort of synchronization for guaranteeing the validity of the read values by the reading thread?
b. Is it possible for the OS scheduling these two threads to cause the reading-thread to read a variable in a memory location in the exact same moment while the writing-thread is writing into the same memory location, or that's just a hardware/bus situation will never be allowed happen and a software designer should never care about that? What if the variable is a large struct instead of a little int or char?
a. If a process has two threads, one that edits a set of variables, the other only reads said variables and never edits their values; Then do we need any sort of synchronization for guaranteeing the validity of the read values by the reading thread?
In general, yes. Otherwise, the thread editing the value could change the value only locally so that the other thread will never see the value change. This can happens because of compilers (that could use registers to read/store variables) but also because of the hardware (regarding the cache coherence mechanism used on the target platform). Generally, locks, atomic variables and memory barriers are used to perform such synchronizations.
b. Is it possible for the OS scheduling these two threads to cause the reading-thread to read a variable in a memory location in the exact same moment while the writing-thread is writing into the same memory location, or that's just a hardware/bus situation will never be allowed happen and a software designer should never care about that? What if the variable is a large struct instead of a little int or char?
In general, there is no guarantee that accesses are done atomically. Theoretically, two cores executing each one a thread can load/store the same variable at the same time (but often not in practice). It is very dependent of the target platform.
For processor having (coherent) caches (ie. all modern mainstream processors) cache lines (ie. chunks of typically 64 or 128 bytes) have a huge impact on the implicit synchronization between threads. This is a complex topic, but you can first read more about cache coherence in order to understand how the memory hierarchy works on modern platforms.
The cache coherence protocol prevent two load/store being done exactly at the same time in the same cache line. If the variable cross multiple cache lines, then there is no protection.
On widespread x86/x86-64 platforms, variables having primitive types of <= 8 bytes can be modified atomically (because the bus support that as well as the DRAM and the cache) assuming the address is correctly aligned (it does not cross cache lines). However, this does not means all such accesses are atomic. You need to specify this to the compiler/interpreter/etc. so it produces/executes the correct instructions. Note that there is also an extension for 16-bytes atomics. There is also an instruction set extension for the support of transactional memory. For wider types (or possibly composite ones) you likely need a lock or an atomic state to control the atomicity of the access to the target variable.

Guaranteed CPU cache update after a certain time

Let's say I have a variable var located somewhere in memory and that an arbitrary number of processors/threads could read and modify it at any given time. But it's guaranteed that at least n seconds will have elapsed between a processor modifying var and any other one reading var. Is it possible to be certain that, if time in seconds is n, there's a value for n that guarantees that the processor reading var will read the updated value?
If your concern really is Cache coherence you should generally be safe 1.
Specifically, however, you may be not.
Cache coherence is usually handled by the hardware2 without the help of the software.
However this is very implementation specific: NUMA may be non cache-coherent, a Compute Shader may need specific built-in functions, IA32e and ARM generally hide cache coherence from the programmer.
To answer you question directly: No, you have no guarantees whatsoever.
The point is that cache coherence is something you deal with in clustered and parallel non uniform architectures.
While in this situations the programming model is inherently multi-threading, the two concepts3 are separated and what really should bug you is how to properly handle multi-threading, specifically synchronization and memory order.
Your question seems to suggest a simple case, where the readers are executed long after the writer is done.
If this property is really enforced you don't need any synchronization nor memory barrier. Beware however that sleep functions don't qualify as a valid enforcement.
If you instead need to synchronize (and so to order the memory accesses) then you need to use language specific constructs, for example volatile in C# and Java, atomics in C and C++ or specific instructions in assembly.
You may need to implement Critical sections too.
If you actually need to manually control the cache coherence for your architecture, than you have to check the specifications of interest (usually datasheets and formal papers) because there is no uniform way to deal with it and the compiler should provide some intrinsic or the runtime should provide a library.
So to add something to the direct answer above: No, you have no guarantees whatsoever, but when an usual CPU, in an usual architecture, need that data, it will be able to use the most updated one anyway. So you don't need to worry about that aspect.
Please note the use of the words common and that
1 For example if you use an Intel/AMD/ARM CPU, don't even think about cache coherence.
2 Either the CPU itself, a local monitor, a system monitor or a specific device.
3 Multi-threading and cache-coherence.
The cache will tend to get flushed on operating system tick interrupts when it goes into the scheduler to see if there's a different task to run.
However, as operating systems get smarter with things such as tickless NoHz and as CPU core counts go up, this gets less and less likely, and you shouldn't count on it.
Supercomputer clusters may not task switch for minutes at a time because they're using customized operating system code that doesn't interrupt the running jobs, ever. Compute jobs are assigned to a core from 1-7 with no interrupts and all of the other work runs on core-0.
There are two concepts mixed in you question: software synchronization and hardware coherency. Hardware coherency is talked by Margaret already so I won't cover it here.
Software Synchronization
x86 provides guarantee that quadword access would be carried out atomically if aligned on 64-bit boundary. But this guarantees that other processor won't read partial result (e.g. [32bit New]<32bit Old> weird mixture). It does not guarantee a hard time deadline before which another processor would see the newly assigned value. Let another thread wait for some time is not quite an elegant solution because first the two threads need to have the same starting time synchronized. So, if you need such guarantee, you need conditional variable to make sure another thread should wait.
https://en.wikipedia.org/wiki/Monitor_(synchronization)
In a word, use conditional variable if you need a sequencing effect and use locks/transactional memory, etc. to protect variable longer than quadword or not 64bit aligned.
Btw, here is an useful material for cache coherency if you are interested.
http://www.cs.cmu.edu/afs/cs/academic/class/15418-s12/www/lectures/10_coherence.pdf

Deciding the critical section of kernel code

Hi I am writing kernel code which intends to do process scheduling and multi-threaded execution. I've studied about locking mechanisms and their functionality. Is there a thumb rule regarding what sort of data structure in critical section should be protected by locking (mutex/semaphores/spinlocks)?
I know that where ever there is chance of concurrency in part of code, we require lock. But how do we decide, what if we miss and test cases don't catch them. Earlier I wrote code for system calls and file systems where I never cared about taking locks.
Is there a thumb rule regarding what sort of data structure in critical section should be protected by locking?
Any object (global variable, field of the structure object, etc.), accessed concurrently when one access is write access requires some locking discipline for access.
But how do we decide, what if we miss and test cases don't catch them?
Good practice is appropriate comment for every declaration of variable, structure, or structure field, which requires locking discipline for access. Anyone, who uses this variable, reads this comment and writes corresponded code for access. Kernel core and modules tend to follow this strategy.
As for testing, common testing rarely reveals concurrency issues because of their low probability. When testing kernel modules, I would advice to use Kernel Strider, which attempts to prove correctness of concurrent memory accesses or RaceHound, which increases probability of concurrent issues and checks them.
It is always safe to grab a lock for the duration of any code that accesses any shared data, but this is slow since it means only one thread at a time can run significant chunks of code.
Depending on the data in question though, there may be shortcuts that are safe and fast. If it is a simple integer ( and by integer I mean the native word size of the CPU, i.e. not a 64 bit on a 32 bit cpu ), then you may not need to do any locking: if one thread tries to write to the integer, and the other reads it at the same time, the reader will either get the old value, or the new value, never a mix of the two. If the reader doesn't care that he got the old value, then there is no need for a lock.
If however, you are updating two integers together, and it would be bad for the reader to get the new value for one and the old value for the other, then you need a lock. Another example is if the thread is incrementing the integer. That normally involves a read, add, and write. If one reads the old value, then the other manages to read, add, and write the new value, then the first thread adds and writes the new value, both believe they have incremented the variable, but instead of being incremented twice, it was only incremented once. This needs either a lock, or the use of an atomic increment primitive to ensure that the read/modify/write cycle can not be interrupted. There are also atomic test-and-set primitives so you can read a value, do some math on it, then try to write it back, but the write only succeeds if it still holds the original value. That is, if another thread changed it since the time you read it, the test-and-set will fail, then you can discard your new value and start over with a read of the value the other thread set and try to test-and-set it again.
Pointers are really just integers, so if you set up a data structure then store a pointer to it where another thread can find it, you don't need a lock as long as you set up the structure fully before you store its address in the pointer. Another thread reading the pointer ( it will need to make sure to read the pointer only once, i.e. by storing it in a local variable then using only that to refer to the structure from then on ) will either see the new structure, or the old one, but never an intermediate state. If most threads only read the structure via the pointer, and any that want to write do so either with a lock, or an atomic test-and-set of the pointer, this is sufficient. Any time you want to modify any member of the structure though, you have to copy it to a new one, change the new one, then update the pointer. This is essentially how the kernel's RCU ( read, copy, update ) mechanism works.
Ideally, you must enumerate all the resources available in your system , the related threads and communication, sharing mechanism during design. Determination of the following for every resource and maintaining a proper check list whenever change is made can be of great help :
The duration for which the resource will be busy (Utilization of resource) & type of lock
Amount of tasks queued upon that particular resource (Load) & priority
Type of communication, sharing mechanism related to resource
Error conditions related to resource
If possible, it is better to have a flow diagram depicting the resources, utilization, locks, load, communication/sharing mechanism and errors.
This process can help you in determining the missing scenarios/unknowns, critical sections and also in identification of bottlenecks.
On top of the above process, you may also need certain tools that can help you in testing / further analysis to rule out hidden problems if any :
Helgrind - a Valgrind tool for detecting synchronisation errors.
This can help in identifying data races/synchronization issues due
to improper locking, the lock ordering that can cause deadlocks and
also improper POSIX thread API usage that can have later impacts.
Refer : http://valgrind.org/docs/manual/hg-manual.html
Locksmith - For determining common lock errors that may arise during
runtime or that may cause deadlocks.
ThreadSanitizer - For detecting race condtion. Shall display all accesses & locks involved for all accesses.
Sparse can help to lists the locks acquired and released by a function and also identification of issues such as mixing of pointers to user address space and pointers to kernel address space.
Lockdep - For debugging of locks
iotop - For determining the current I/O usage by processes or threads on the system by monitoring the I/O usage information output by the kernel.
LTTng - For tracing race conditions and interrupt cascades possible. (A successor to LTT - Combination of kprobes, tracepoint and perf functionalities)
Ftrace - A Linux kernel internal tracer for analysing /debugging latency and performance related issues.
lsof and fuser can be handy in determining the processes having lock and the kind of locks.
Profiling can help in determining where exactly the time is being spent by the kernel. This can be done with tools like perf, Oprofile.
The strace can intercept/record system calls that are called by a process and also the signals that are received by a process. It shall show the order of events and all the return/resumption paths of calls.

Perl ithreads :shared variables - multiprocessor kernel threads - visibility

perlthrtut excerpt:
Note that a shared variable guarantees that if two or more threads try
to modify it at the same time, the internal state of the variable will
not become corrupted. However, there are no guarantees beyond this, as
explained in the next section.
Working on Linux supporting multiprocessor kernel threads.
Is there a guarantee that all threads will see the updated shared variable value ?
Consulting the perlthrtut doc as stated above there is no such guarantee.
Now the question: What can be done programmatically to guarantee that?
You ask
Is there a guarantee that all threads will see the updated shared variable value ?
Yes. :shared is that guarantee. The value will be safely and consistently and freshly updated.
The problem is simply that, without other synchronization, you don't know the order of these updates.
Consulting the perlthrtut doc as stated above there is no such guarantee.
You didn't read far enough. :)
The very next section in perlthrtut explains the kind of pitfalls you do face with perl threads: data races, which is to say, application logic races concerning shared data. Again, the shared data will be consistent and fresh and immune to corruption from (more-or-less) atomic perl opcodes. However, the high-level perl operations you perform on that shared data are not guaranteed to be atomic. $shared_var++, for instance, might be more than one atomic operation.
(If I may hazard a guess, you are perhaps thinking too much about other languages' lower level threading interfaces with their cache inconsistencies, torn words, reordered instructions, and lions and tigers and bears. Perl's model takes care of those low-level concerns for you.)
Using :shared on a variable causes all threads to reference it in the same physical memory address, so it doesn't matter which processor/core/hyper-thread they happen to be executing in. The perlthrtut talk of guarantees is in reference to race conditions, and in short, that you need to take into account that shared variables can be modified by any thread at any time. If this is a problem you'll need to make use of synchronization functions (e.g. lock() and cond_wait()) to control access.
You seem to be confused as to what :shared does. It makes it so a variable is shared by all threads.
A variable is indeed guaranteed to have the value it has, no matter which thread accesses it. It's a tautology, so nothing can be done to programmatically guarantee that.

Usage of registers by the compiler in multithreaded program

It is a general question but:
In a multithreaded program, is it safe for the compiler to use registers to temporarily store global variables?
I think its not, since storing global variables in registers may change saved values
for other threads.
And how about using registers to store local variables defined within a function?
I think it is ok,since no other thread will be able to get these variables.
Please correct me if im wrong.
Thank you!
Things are much more complicated than you think they are.
Even if the compiler stores a value to memory, the CPU generally does not immediately push the data out to RAM. It stores it in a cache (and some systems have 2 or 3 levels of caches between the processor and the memory).
To make things worse, the order of instructions that the compiler decides, may not be what actually gets executed as many processors can reorder instructions (and even sub-parts of instructions) in their own pipelines.
In general, in a multithreaded environment you should personally take care to never access (either read or write) the same memory from two separate threads unless one of the following is true:
you are using one of several special atomic operations that ensure proper synchronization.
you have used one of several synchronization operations to "reserve" access to shared data and then to "relinquish" it. These do include the required memory barriers that also guarantee the data is what it's supposed to be.
You may want to read http://en.wikipedia.org/wiki/Memory_ordering#Memory_barrier_types and http://en.wikipedia.org/wiki/Memory_barrier
If you are ready for a little headache and want to see how complicated things can actually get, here is your evening lecture Memory Barriers: a Hardware View for Software Hackers.
'Safe' is not really the right word to use. Many higher level languages (eg. C) do not have a threading model and so the language specification says nothing about mutli-threaded interactions.
If you are not using any kind of locking primitives then you have no guarantees what so ever about how the different threads interact. So the compiler is within its rights to use registers for global variables.
Even if you are using locking the behaviour can still be tricky: if you read a variable, then grab a lock and then read the variable again the compiler still has no way of knowing if it has to read the variable from memory again, or can use the earlier value it stored in a register.
In C/C++ declaring a variable as volatile will force the compiler to always reload the variable from memory and solve this particular instance.
There are also 'Interlocked*' primitives on most systems that have guaranteed atomicity semantics which can be used to ensure certain operations are threadsafe. Locking primitives are typically built on these low level operations.
In a multithreaded program, you have one of two cases: if it's running on a uniprocessor (single core, single CPU), then switching between threads is handled like switching between processes (although it's not quite as much work since the threads operate in the same virtual memory space) - all registers of one thread are saved during the transition to another thread, so using registers for whatever purpose is fine. This is the job of the context switch routines that the OS uses, and the register set is considered part of a threads (or processes) context. If you have a multiprocessor system - either multiple CPUs or multiple cores on a single CPU - each processor has its own distinct set of registers, so again, using registers for storing things is fine. On top of that, of course, context switching on a particular CPU will save the registers of the old thread/process before switching to the new one, so everything is preserved.
That said, on some architectures and/or with some OSes, there might be specific exceptions to that, because certain registers are reserved by the ABI for specific uses by the OS or by the libraries that provide an interface to the OS, but your compiler(s) generally have that type of knowledge of your platform built in. You need to be aware of them, though, if you're doing inline assembly or certain other "low-level" things...

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