I am trying to create an IF statement in Excel, in order to group some data into 3 distinct variables. For the purpose of this attempt, I simply want to classify words into people names.
Now, the screenshot shows a simplified version of what I am trying to do, as I am unable to post photos of the full data for security reasons.
As the shot shows, the brackets before F7 and after Joe are in red, but am very confused why. Any help would be appreciated.
Thomas
Excel colour codes brackets when in Edit / Enter mode, to make it easier to identify matching pairs.
You can do it like this:
=IF(ISNUMBER(MATCH(F7,{"Tom","Ed","Joe"},0)),"names","Not names")
Your formula wasn't correct because you didn't have logical values in OR() and the red color was due to Excel pair coloring - not because of error.
To make your formula work as is it would look like:
=IF(OR(F7="Tom",F7="Ed",F7="Joe"),"names","Not names")
Related
I am trying to fill the sell price column in an Excel spreadsheet with the increased values in colors based on the round up columns value (1 to 50 green, 50 to 100 blue, 100 to 150 yellow, 150+ pink).
I've opted for the percentage table because some items can be sold for a lot more than what I have purchased them for, so that's just for my benefit. I am open to any other suggestions and I am new to this whole business thing.
I was using IF in my formula which would work great for using one percentage increase in the formula:
=IF($E27<50,ROUNDUP(I$27,-1))
If I try to enter a second argument like
=IF(OR($E28<50,ROUNDUP(I$28,-1)OR($E28>50,<100,ROUNDUP(J$28,-1))))
I will get an error.
I'm probably using the formulas wrong, I've tried "AND" and a couple other formulas, but I can't find anyone else trying to achieve the same or similar.
So something like this:
=IF($E28<50,ROUNDUP(I$28,-1),IF($E28>50,ROUNDUP(J$28,-1),"Error"))
But not sure what the <100 was for.
Although the problem is not completely clear, I understand that you want to add a formula with nested if statements.
I will recommend you to try nested ifs in parts.
=IF($E27<50,ROUNDUP(I$27,-1),"First if condition is false")
If everything is working as per the requirement then edit that text in the formula to add another if statement.
=IF($E27<50,ROUNDUP(I$27,-1),IF(OR(condition 1, condition 2,more conditions),"value if true","value if false"))
In the second argument provided by you, the arguments of the OR function has not been properly provided. Ensure that all the arguments of an OR function are conditions separated by a comma.
$E28<50 This is a condition so it's ok.
But other arguments are not making sense.
Also, using OR multiple times inside the first OR arguments is not clear.
It would be beneficial if you could provide the basic table and mention the requirement clearly.
I'm trying to clean up job title data using the formula below:
=IF(OR(ISNUMBER(SEARCH({"admin","reception","account","finance","HR","public","sales","customer","creative","IT","human"},A1))),"",A1)
It should work by eliminating job titles with any of the texts specified in the quotes above. However, I've encountered an issue where it doesn't. In a case where the job title is Quantity Surveyor, the title contains none of the specified texts but Excel seems to reflect it as such. What am I not doing right here?
Quantity Surveyor Example
To extract the information you are looking for, this is the formula you want to use:
=IFERROR(IF(OR(ISNUMBER(SEARCH({"admin","reception","account","finance","HR","public","sales","customer","creative","human"},A1)),NOT(SEARCH("Quantity",A1))),"",A1),"")
Using countif you don't need to check for errors if they occur:
=IF(OR(COUNTIF(A1,{"admin","reception","account","finance","HR","public","sales","customer","creative","human"}))+COUNTIF(A1,"<>Quantity"),"",A1)
Select the part of formula of search, and then press F9. You will find the match result of 6, where it has original value of 'IT', it means Quantity, has IT.
I really donot know why there is negative vote as not useful.
Here is the formula to solve your problem
=IFERROR(LOOKUP(1,0/FIND({"admin","reception","account","finance","HR","public","sales","customer","creative","IT","human"},A1)),A1)
Of course, it is better to define a range instead of hard code {}, like below
=IFERROR(LOOKUP(1,0/FIND($J$2:$J$7,A2),$K$2:$K$7),A2)
I am trying to extract the text to the right of a character pattern of form -201*-*- in excel (I also tried using Access, but the issue persists).
For example, in the text:
EP-005-FI6-2012-1-124-000000-1
I want to extract the number 124; the following formula works:
=LEFT(RIGHT(C1,SEARCH("-201*-*-",C1)+1),3)
124
However, when i apply the exact same formula to extract169 from the text below:
NAATS-MG-D6-2017-1-169-070000-1
The formula returns a completely different result:
=LEFT(RIGHT(C540495,SEARCH("-201*-*-",C540495)+1),3)
-16
The pattern is the same, but the results is completely differnt.
My dataset is too big to go row by row fixing the issue...
Seems to be a simple problem, but i can't get this working...
Any thoughts?
Thank you
Your RIGHT() is wrong. Use:
=LEFT(MID(C1,SEARCH("-201?-?-",C1)+8,9999),3)
Good afternoon, I'm stuck with a small problem of formulas in excel:
I have a table in another sheet and I have to perform the following operations:
1. number of units sold in Bogota.
2. number of units sold in different cities to Bogota.
I'm trying to use the formula:
=SUMIF(DATOS!$G$4:$G$146;"BOGOTA";DATOS!$H$4:$H$146)
For the first requirement works, but at the moment of using it to know which city is different from Bogota, I do not know how to do it; try to use the <> operator but I get an error and placing the formula as follows:
=SUMIF(DATOS!$G$4:$G$146;NOT("BOGOTA");DATOS!$H$4:$H$146)
do not add the data (Summation gives 0). Someone has an idea of the problem.
I believe you have to put quotes "like this" around the entire logical statement ""<>BOGOTA"
It can be used like this:
=SUMIF(DATOS!$G$4:$G$146;"<>BOGOTA")
Hope this helps
I have a large spreadsheet with column data like:
ABC:1:I.0
ABC:1:I.1
ABC:1:I.2
ABC:1:I.3
ABC:2:I.0
ABC:2:I.1
ABC:2:I.2
ABC:2:I.3
ABC:3:I.0
ABC:3:I.2
ABC:3:I.3
ABC:4:I.0
ABC:4:I.1
ABC:4:I.2
ABC:4:I.3
ABC:5:I.0
ABC:5:I.1
ABC:5:I.2
ABC:5:I.3
ETC.
I need to replace the above with the following:
ABC:I.Data[1].0
ABC:I.Data[1].1
ABC:I.Data[1].2
ABC:I.Data[1].3
ABC:I.Data[2].0
ABC:I.Data[2].1
ABC:I.Data[2].2
ABC:I.Data[2].3
ABC:I.Data[3].0
ABC:I.Data[3].2
ABC:I.Data[3].3
ABC:I.Data[4].0
ABC:I.Data[4].1
ABC:I.Data[4].2
ABC:I.Data[4].3
ABC:I.Data[5].0
ABC:I.Data[5].1
ABC:I.Data[5].2
ABC:I.Data[5].3
ETC.
Here is a sample of the data, most of the data follows a similar format with the exception of the naming "ABC", which can vary in size, so it might be "ABCD" and also with the exception of the letter "I", it can be "O" as well. Also, some might be missing some values such as ABC:3:I.1 which is missing from the data. I am not too familiar with excel formulas or VBA code. Does anyone know how to do this? I have no preference on which method it has to be done in as I don't mind learning some VBA code if someone provides me with a VBA solution.
I was thinking of using some sort of loop along with some conditional statements.
Thanks!
Please try:
=LEFT(F11,FIND(":",F11))&MID(F11,FIND(":",F11,6)+1,1)&".Data["&MID(F11,FIND(":",F11,2)+1,1)&"]."&RIGHT(F11,1)
copied down to suit, assuming placed in Row11 and your data is in ColumnF starting in Row11.
Curiosities:
When this A was first posted it attempted to address only the tabulated example input and output. I temporarily deleted that version while addressing that what was in the table as ABC might at times be ABCD and that what was I might at times be O.
OP has posted an answer that I edited to make no visible change but which shows as the deletion of two characters. A copy of the OP’s formula exhibited a syntax error prior to my edit.
OP suggested an edit to my answer but this was rejected by the review process. As it happens, I think the edit suggestion was incorrect.
I have edited my answer again to include these ‘curiosities’ and to match the cell reference used by the OP in his answer.
=LEFT(A1,SEARCH(":",A1)) & MID(A1, SEARCH(".",A1)-1, 2) &
"Data[" & MID(A1,SEARCH(":",A1)+1,1) & "]" & RIGHT(A1,2)
With the help of pnuts I was able to come up with my own solution:
=LEFT(F11,LEN(F11)-5)&MID(F11,LEN(F11)-2,2)&"Data["&MID(F11,LEN(F11)-4,1)&"]"&RIGHT(F11,2)
My solution works based on the fact that the length of the last six values in the string ABC:1:I:0 will always be the same in size for all the data I have, hence you see LEN(F11)-some number in my code. The only part of the string that changes in size is the first part, in this case ABC which can also be ABCDEF, etc.
If you'd like to use formulas rather than VBA, an easy option is to split the data into 4 columns, using the Text To Columns option - first split using the colon as a delimiter, then using a full-stop / period as a delimiter.
Once you have 4 columns of data (one for each block), you can use the Concatenate function to join them and add in the extra characters: =CONCATENATE(A1,":",C1,".","Data[",B1,"].",D1)
This should still work if you have extra / alternative characters (eg ABCD instead of ABC), as long as you have the same delimiters, but obviously you'd need to test to make sure.