I have another tricky Excel IF-Then formula that I need but I can’t figure out how to search for a solution online without knowing the correct terms to use.
What I’m trying to do is generate a result based off of 4 multiple options. This is similar to calculating someone's commission based on what price range they sell an item for.
Result =$1 for an item selling for $0-10.00
Result =$2 for an item selling between $10.01-12.50
Result =$3 for an item selling between $12.51-15.00
Result =$4 for an item selling $15.01 and up
Thanks for any help you can provide.
Let's say the selling price is in A2. We are starting from the bottom range of your pricing and using nested IF's to figure out which bucket the selling price is in. We will check if it is <= 10, if so then the result will be 1, if not then we will check if it is <= 12.50, if so then the result will be 2.. etc. Formula shown below.
=if(a2<=10,1,if(a2<=12.50,2,if(a2<=15,3,4)))
... or if the selling price was in A3,
=1+(a3>10)+(a3>12.5)+(a3>15)
A boolean TRUE is resolved as 1 when used in a maths operation like addition.
You need to use a capsuled if clause.
If is build up as following:
=if(condition, value if true, value if false)
Capsuled:
=if(condition1, value if true, if(condition2, value is true, if(...)))
The condition needs to resolve in a True/False Statement. For your case:
=if(price <= upperBound AND price >= lowerBound, commision, if(...))
If you arrange the conditions in the right order (from high to low) you do only need to type one bound per condition.
=if(price > 15, highestCommision, if(price > secondBound, Commision2, if(...)))
RESULT:
=if(A1 > 15, 4, if( A1 > 12.5, 3, if( A1 > 10, 2, 1 )))
Just for variety here is a version with vlookup:
VLOOKUP(E4,B3:C6,2,1)
and the table I used:
Corrected after Scott's comment and Jeeped's - cheers guys...
Use MATCH in its relative form. This will find where the number fits and return the relative location as a Long:
=MATCH(A1,{0,10.01,12.51,15.01})
Or if you have Office 365 Excel you can use IFS:
=IFS(A1<=10,1,A1<=12.5,2,A1<=15,3,A1>15,4)
Related
Good night,
I'm trying to think of a simple excel formula to allow me to get the codes of the most valuables drinks.
I don't wanna use PivotTable for this one.
Ex:
I want to retrieve, for MALIBU, the code 8991
For JAMESON, the code 6113 etc
I'm stuck here since I woke up haha
Thanks!
Try below formula for dynamic spill result-
=LET(x,UNIQUE(C2:C12),y,BYROW(x,LAMBDA(r,INDEX(SORT(FILTER(A2:B12,C2:C12=r),2,-1),1,1))),HSTACK(x,y))
Using MAX function to consider the scenario where more than one code for a given drink can have the maximum value. In cell E2 use the following formula:
=LET(rng, A2:C13, codes, INDEX(rng,,1), values, INDEX(rng,,2),
drinks, INDEX(rng,,3), drinksUx, UNIQUE(drinks),
maxValues, BYROW(drinksUx, LAMBDA(ux,
TEXTJOIN(",",,FILTER(codes, (drinks = ux)
* (values = MAX(FILTER(values, drinks=ux))))))),
HSTACK(drinksUx, maxValues)
)
Here is the output:
Note: Another code for HEINEKEN was added for testing purpose of more than one code with maximum value.
XMATCH can be used for the same purpose too, but it is a more verbose formula:
=LET(rng, A2:C13, codes, INDEX(rng,,1), values, INDEX(rng,,2),
drinks, INDEX(rng,,3),drinksUx, UNIQUE(drinks),
maxValues, BYROW(drinksUx, LAMBDA(ux, TEXTJOIN(",",,
LET(maxValue, MAX(FILTER(values, drinks = ux)),
FILTER(codes, ISNUMBER(XMATCH(drinks & values, ux & maxValue))))))),
HSTACK(drinksUx, maxValues)
)
I am trying to create a capacity tracker for my organisation whereby new starters are reflected at a reduced capacity throughout their induction. To do this I have an additional table next to the general capacity tracker that shows the start date vs the current date giving how many days the person has been working. This is then converted into 'months served' which is translated to a capacity adjustment. This adjustment is then used to divide their capacity by a set value per month, so 1 month served = an adjustment of 3 therefore their capacity is reduced to .3.
I am having some incorrect returns in my IF, AND statement which converts their days worked into months served. I am using the formula below, is there a better way to do this or could anyone spot the error in the formula? The first few statements are returning the correct answer but it goes wrong after 3 where the return '6+' when it should be 4.
=IF(
AJ38<30,
1,
IF(
AND(AJ38>30,AJ38<60),
2,
IF(
AND(AJ38>61,AJ38<90),
3,
IF(
AND(AJ38>91,AJ38<120),
4,
IF(
AND(AJ38>121,AJ38<150),
5,
IF(
AND(AJ38>151,AJ38<180),
6,
"6+"
)
)
)
)
)
)
I hope that makes sense, and thank you for your help!
I think I have solved this. I had not accounted for when a value returns the actual figure of say '90'. Each statement was between 2 figures and so if the figure landed on an a whole number it was not accounted for. I have adjusted the ranges to be from 1 figure down and it is now working. Working formula - =IF(AJ4<30,1,IF(AND(AJ4>29,AJ4<60),2,IF(AND(AJ4>59,AJ4<90),3,IF(AND(AJ4>89,AJ4<120),4,IF(AND(AJ4>119,AJ4<150),5,IF(AND(AJ4>149,AJ4<180),6,"6+"))))))
A few other possibilities:
Reduce the amount of layering by using IFS() instead of nested IF. Note: This works in Excel 2016 or newer.
=ifs(AJ4<30,1,
AND(AJ4>=30,AJ4<60),2,
AND(AJ4>=60,AJ4<90),3,
AND(AJ4>=90,AJ4<120),4,
AND(AJ4>=120,AJ4<150),5,
AND(AJ4>=150,AJ4<180),6,
TRUE,"6+")
Use integer division to do it mathematically.
=INT(AJ4/30)+1
If you need that "6+" in there, you'll have to use an IF statement:
=IF(AJ4<180,INT(AJ4/30)+1,"6+")
I am writing a series of queries to my workbook's data model to retrieve the number of documents by Category_Name which are greater than a certain numbers of days old (e.g. >=650).
Currently this formula (entered in celll C3) returns the correct number for a single Days Old value (=3).
=CUBEVALUE("ThisWorkbookDataModel",
"[Measures].[Count of Docs]",
"[EDD_Report].[Category_Name].&["&$B2&"]",
"[EDD_Report_10-01-18].[Days Old].[34]")
How do I return the number of documents for Days Old values >=650?
The worksheet looks like:
A B C
1 Date PL Count of Docs
2 10/1/2018 ALD 3
3 ...
UPDATE: As suggested in #ama 's answer below, the expression in step B did not work.
However, I created a subset of the Days Old values using
=CUBESET("ThisWorkbookDataModel",
"{[EDD_Report_10-01-18].[Days Old].[all].[650]:[EDD_Report_10-01-18].[Days Old].[All].[3647]}")
The cell containing this cubeset is referenced as the third Member_expression of the original CUBEVALUE formula. The limitation is now that the values for the beginning and end must be members of the Days Old set.
This is limiting, in that, I was hoping for a more general test for >=650 and there is no way to guarantee that specific values of Days Old will be in the query.
First time I hear about CUBE, so you got me curious and I did some digging. Definitely not an expert, but here is what I found:
MDX language should allow you to provide value ranges in the form of {[Table].[Field].[All].[LowerBound]:[Table].[Field].[All].[UpperBound]}.
A. Get the total number of entries:
D3 =CUBEVALUE("ThisWorkbookDataModel",
"[Measures].[Count of Docs]",
"[EDD_Report].[Category_Name].&["&$B2&"]"),
"{[EDD_Report_10-01-18].[Days Old].[All]")
B. Get the number of entries less than 650:
E3 =CUBEVALUE("ThisWorkbookDataModel",
"[Measures].[Count of Docs]",
"[EDD_Report].[Category_Name].&["&$B2&"]"),
"{[EDD_Report_10-01-18].[Days Old].[All].[0]:[EDD_Report_10-01-18].[Days Old].[All].[649]}")
Note I found something about using .[All].[650].lag(1)} but I think for it to work properly your data might need to be sorted?
C. Substract
C3 =D3-E3
Alternatively, go for the quick and dirty:
=CUBEVALUE("ThisWorkbookDataModel",
"[Measures].[Count of Docs]",
"[EDD_Report].[Category_Name].&["&$B2&"]"),
"{[EDD_Report_10-01-18].[Days Old].[All].[650]:[EDD_Report_10-01-18].[Days Old].[All].[99999]}")
Hope this helps and do let me know, I am still curious!
I have a scale, based on which I decide the value of the coefficient for the multiplication. The scale looks as following:
Which means that:
for Category1: when value>=1.000.000 then coef is 1, when value>=500.000 then coef is 0.8 and etc.
Same logic applies for Category2;
Then I have input data in the following format:
Company !MainCat|Sales Amount|
Company1|T1 | 6.500.000|
Company2|T2 | 70.000|
I need to find corresponding coefficient, ratio of the coeffitient and the value (=ratio*MaxCoef). Currently, I am finding coef the following way:
- for company1:
=IF(C8>=$D2;$D$1;IF(C8>=$E2;$E$1;IF(C8>=$F2;$F$1;IF(C8>=$G2;$G$1;IF(C8>=$H2;$H$1;IF(C8>=$I2;$I$1))))))
That is literally hardcoded and doesn't look good. Maybe there is a better way of doing ? Any suggestions?
Formula view:
You can COUNTIF(range, [criteria] < value) * 0.2 as your add 0.2 per coef stage.
To you data do: =COUNTIF(D2:H2, "<"&C8) * 0.2, count how many stages the value passes * the value per stage.
Your count if range needs to be until H2 as I2 is 0, so inferior to value and gets counted.
To combine the COUNTIF() with a dynamic search for the right category based on MainCat you can MATCH() the MainCat with Code which will give the row where the Code is located and utilize INDIRECT() to apply it as range.
=COUNTIF(INDIRECT("D"&MATCH(B8,B:B,0)&":H"&MATCH(B8,B:B,0)),"<"&C8)*0.2
MATCH(B8,B:B,0) - will match the value on B8 (lets say T1) and return the row 2.
INDIRECT("D"&MATCH(B8,B:B,0)&":H"&MATCH(B8,B:B,0) = INDIRECT("D"&2&":H"&2) - will turn the text into an actual range to be use by the COUNTIF().
Create a table ‚Mapping’ that contains two columns, ‚Category’ and ‚Coefficient‘, then use INDEX-MATCH on it as described in https://www.deskbright.com/excel/using-index-match/.
=INDEX(Mapping[Category]; MATCH([Coefficient]; Mapping[Coefficient]; -1))
This example assumes that you put this formula into a table that has a column named ‚Coefficient‘ with the input value to your multiple IFs.
The trick is that as a match_type argument, provide either -1 or 1, according to your needs.
You can do this in VBA. Write your own function which ends in something like that
=MyOwnScale(C8; B8; A2:I3)
The first parameter of your VBA-function is the value, the second the category and the third is the range with the thresholds. So you can move your cascading IF-loops in VBA-Code and you (and your users) see only a clean function call in the cell.
I've structured a formula that should spit out a numerical answer that is basically a simple sum formula with IF statements assigning numerical values to qualitative inputs. Apologies for the length, I am looking at a number of different factors.Formula is:
Cell F36 contains:
=IF(F32="Medium-High", 18, IF(F32="High", 24, SUM(F16, IF(F20="High",5,IF(F20="Medium-High",4,IF(F20="Medium",3,IF(F20="Low-medium",2,IF(F20="Low",1))))),IF(F24="High",5,IF(F24="Medium-High",4,IF(F24="Medium",3,IF(F24="Low-Medium",2,IF(F24="Low",1))))),IF(F28="High",5,IF(F28="Medium-High",4,IF(F28="Medium",3,IF(F28="Low-Medium",2,IF(F28="Low",1,IF(F28="N/A",0)))))),IF(F30="N/A",0,IF(F30="High",5,IF(F30="Medium-High",4,IF(F30="Medium",3,IF(F30="Low-Medium",2,IF(F30="Low",1)))))),IF(F32="High",5,IF(F32="Medium-High",4,IF(F32="Medium",3,IF(F32="Low-Medium",2,IF(F32="Low",1,IF(F32="N/A",0)))))))))
F16 - contains values from 1 to 5
F20, F24, F28, F30, F32 - Are dropdowns, where you choose a value: Low, Low-Medium, Medium, Medium-High, High;
Right now, based on a test input, where: F16 = 5, F20 = Low (1), F24= Medium-High (4), F28 = N/A (0), F30 = Medium (3), F32 = Medium (3) my output in F36 is 11, however doing simple adding, I should be at 5+1+4+0+3+3 = 16.
Where am I losing 5 points?
You can create a table allocating numerical output to each qualitative inputs and using vlookup to get your output. For example, for a table created on K19:L25, the following can be used:
=SUM(F16,VLOOKUP(F20,K19:L25,2,FALSE),VLOOKUP(F24,K19:L25,2,FALSE),VLOOKUP(F28,K19:L25,2,FALSE),VLOOKUP(F30,K19:L25,2,FALSE),VLOOKUP(F32,K19:L25,2,FALSE))
EDIT:
Tried your formula and it gives the correct result. Maybe your 5 in F16 is not a numerical value? You can test it by using
=ISNUMBER(F16)
and it should give a TRUE if it is a number.
Debug embedded IFs is just hell.
What you are doing is recode a 5 levels scale. You may use alternative solutions.
a. place the 5 text values (from "Low" to "High") somewhere in a sheet, say in T1:T5, even better, give this range a name
then you can retrieve the values you search with
MATCH(F20,$T$1:$T$5,0)
b. if it's suitable for your use, you may use combo boxes, presenting the 5 choices and giving the desired answer (from 1 to 5) in a linked cell.
(maybe not the answer, but I can't comment…)
(This should be a comment but I needed the formatting capabilities of an answer)
This is the current logic of your formula:
Check cell F32: "Medium-High" outputs 18, "High" outputs 24
If F32 is neither of those, then SUM the following:
F16
Lookup for F20, F24, F28, F30, and F32 where the lookup for each is:
"High" = 5
"Medium-High" = 4
"Medium" = 3
"Low-Medium" = 2
"Low" = 1
I find it strange that you first check cell F32 only to check it again later in the sum. Because this current logic produces incorrect results, we can't really advise how to fix it without sample data and expected results. My guess is you are summing too many lookups by including the F32 in there, but that's just speculation without data.