I'm trying to play sound files (.wav) with pygame but when I start it I never hear anything.
This is the code:
import pygame
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("desert_rustle.wav")
sounda.play()
I also tried using channels but the result is the same
For me (on Windows 7, Python 2.7, PyGame 1.9) I actually have to remove the pygame.init() call to make it work or if the pygame.init() stays to create at least a screen in pygame.
My example:
import time, sys
from pygame import mixer
# pygame.init()
mixer.init()
sound = mixer.Sound(sys.argv[1])
sound.play()
time.sleep(5)
sounda.play() returns an object which is necessary for playing the sound. With it you can also find out if the sound is still playing:
channela = sounda.play()
while channela.get_busy():
pygame.time.delay(100)
I had no sound from playing mixer.Sound, but it started to work after i created the window, this is a minimal example, just change your filename, run and press UP key to play:
WAVFILE = 'tom14.wav'
import pygame
from pygame import *
import sys
mixer.pre_init(frequency=44100, size=-16, channels=2, buffer=4096)
pygame.init()
print pygame.mixer.get_init()
screen=pygame.display.set_mode((400,400),0,32)
while True:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == KEYDOWN:
if event.key==K_ESCAPE:
pygame.quit()
sys.exit()
elif event.key==K_UP:
s = pygame.mixer.Sound(WAVFILE)
ch = s.play()
while ch.get_busy():
pygame.time.delay(100)
pygame.display.update()
What you need to do is something like this:
import pygame
import time
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("desert_rustle.wav")
sounda.play()
time.sleep (20)
The reason I told the program to sleep is because I wanted a way to keep it running without typing lots of code. I had the same problem and the sound didn't play because the program closed immediately after trying to play the music.
In case you want the program to actually do something just type all the necessary code but make sure it will last long enough for the sound to fully play.
import pygame, time
pygame.mixer.init()
pygame.init()
sounda= pygame.mixer.Sound("beep.wav")
sounda.play()
pygame.init() goes after mixer.init(). It worked for me.
I had the same problem under windows 7. In my case I wasn't running the code as Administrator. Don't ask me why, but opening a command line as administrator fixed it for me.
I think what you need is pygame.mixer.music:
import pygame.mixer
from time import sleep
pygame.mixer.init()
pygame.mixer.music.load(open("\windows\media\chimes.wav","rb"))
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
sleep(1)
print "done"
You missed to wait for the sound to finish. Your application will start playing the sound but will exit immediately.
If you want to play a single wav file, you have to initialize the module and create a pygame.mixer.Sound() object from the file. Invoke play() to start playing the file. Finally, you have to wait for the file to play.
Use get_length() to get the length of the sound in seconds and wait for the sound to finish:
(The argument to pygame.time.wait() is in milliseconds)
import pygame
pygame.mixer.init()
sounda = pygame.mixer.Sound('desert_rustle.wav')
sounda.play()
pygame.time.wait(int(sounda.get_length() * 1000))
Alternatively you can use pygame.mixer.get_busy to test if a sound is being mixed. Query the status of the mixer continuously in a loop.
In the loop, you need to delay the time by either pygame.time.delay or pygame.time.Clock.tick. In addition, you need to handle the events in the application loop. See pygame.event.get() respectively pygame.event.pump():
For each frame of your game, you will need to make some sort of call to the event queue. This ensures your program can internally interact with the rest of the operating system.
import pygame
pygame.init()
pygame.mixer.init()
sounda = pygame.mixer.Sound('desert_rustle.wav')
sounda.play()
while pygame.mixer.get_busy():
pygame.time.delay(10)
pygame.event.poll()
Your code plays desert_rustle.wav quite fine on my machine (Mac OSX 10.5, Python 2.6.4, pygame 1.9.1). What OS and Python and pygame releases are you using? Can you hear the .wav OK by other means (e.g. open on a Mac's terminal or start on a Windows console followed by the filename/path to the .wav file) to guarante the file is not damaged? It's hard to debug your specific problem (which is not with the code you give) without being able to reproduce it and without having all of these crucial details.
Just try to re-save your wav file to make sure its frequency info. Or you can record a sound to make sure its frequency,bits,size and channels.(I use this method to solve this problem)
I've had something like this happen. Maybe you have the same problem? Try using an absolute path:
import pygame
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("/absolute_path/desert_rustle.wav")
sounda.play()
Where abslute_path is obviously replaced with your actual absolute path ;)
good luck.
import pygame
pygame.init()
sound = pygame.mixer.Sound("desert_rustle.wav")
pygame.mixer.Sound.play(sound)
This will work on python 3
5 years late answer but I hope I can help someone.. :-)
Firstly, you dont need the "pygame.init()"-line.
Secondly, make a loop and play the sound inside that, or else pygame.mixer will start, and stop playing again immediately.
I got this code to work fine on my Raspberry pi with Raspbian OS.
Note that I used a while-loop that continues to loop the sound forver.
import pygame.mixer
pygame.mixer.init()
sounda = pygame.mixer.Sound("desert_rustle.wav")
while True:
sounda.play()
Just try:
import pygame.mixer
from time import sleep
pygame.mixer.init()
pygame.mixer.music.load(open("\windows\media\chimes.wav","rb"))
print ""
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
sleep(1)
print "done"
This should work. You just need to add print ""and the sound will have
had time to load its self.
Many of the posts are running all of this at toplevel, which is why the sound may seem to close. The final method will return while the sound is playing, which closes the program/terminal/process (depending on how called).
What you will eventually want is a probably a class that can call either single time playback or a looping function (both will be called, and will play over each other) for background music and single sound effects.
Here is pattern, that uses a different event loop / run context other than Pygame itself, (I am using tkinter root level object and its init method, you will have to look this up for your own use case) once you have either the Pygame.init() runtime or some other, you can call these methods from your own logic, unless you are exiting the entire runtime, each file playback (either single use or looping)
this code covers the init for ONLY mixer (you need to figure our your root context and where the individual calls should be made for playback, at least 1 level inside root context to be able to rely on the main event loop preventing premature exit of sound files, YOU SHOULD NOT NEED TIME.SLEEP() AT ALL (very anti-pattern here).... ALSO whatever context calls the looping forever bg_music, it will probably be some 'level' or 'scene' or similar in your game/app context, when passing from one 'scene' to the next you will probably want to immediately replace the bg_music with the file for next 'scene', and if you need the fine-grained control stopping the sound_effect objects that are set to play once (or N times)....
from pygame import mixer
bg_music = mixer.Channel(0)
sound_effects = mixer.Channel(1)
call either of these from WITHIN your inner logic loops
effect1 = mixer.Sound('Sound_Effects/'+visid+'.ogg')
sound_effects.play(effect1, 0)
sound1 = mixer.sound('path to ogg or wav file')
bg_music.play(sound1, -1) # play object on this channel, looping forever (-1)
do this:
import pygame
pygame.mixer.init()
pygame.mixer.music.load("desert_rustle.wav")
pygame.mixer.music.play(0)
I think that your problem is that the file is a WAV file.
It worked for me with an MP3. This will probably work on python 3.6.
So far I have a GUI but right now I'm having a problem on how to change the window upon usb insertion. I tried pyudev for monitoring devices but whenever I add it in my GUI code, it doesn't run even though these codes worked when separated. Also I want to list the files in the GUI so that the user can select which file to print. Thank you in Advance! :)
This is my code for detection of usb devices.
import pyudev
context = pyudev.Context()
monitor = pyudev.Monitor.from_netlink(context)
monitor.filter_by(subsystem='usb')
for device in iter(monitor.poll, None):
if device.action == 'add':
print('{} connected'.format(device))
if device.action == 'remove':
print('{} removed' .format(device))
I'm using Python 3.5 and Pyglet 1.2.4 on OS X 10.11.5. I am very new to this setup.
I am trying to see if I can use event handling to capture keystrokes (without echoing them to the screen) and return them to the main program one at a time by separate invocations of the pyglet.app.run method. In other words I am trying to use Piglet event handling as if it were a callable function for this purpose.
Below is my test program. It sets up the Pyglet event mechanism and then calls it four times. It works as desired but causes the system messages shown below.
import pyglet
from pyglet.window import key
event_loop = pyglet.app.EventLoop()
window = pyglet.window.Window(width=400, height=300, caption="TestWindow")
#window.event
def on_draw():
window.clear()
#window.event
def on_key_press(symbol, modifiers):
global key_pressed
if symbol == key.A:
key_pressed = "a"
else:
key_pressed = 'unknown'
pyglet.app.exit()
# Main Program
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
print("Quitting NOW!")
Here is the output with blank lines inserted for readability. The first message is different and appears even if I comment out the four calls to piglet.app.run. The double release messages do not occur after every call to event handling and do not appear in a consistent manner from one test run to the next.
/Library/Frameworks/Python.framework/Versions/3.5/bin/python3.5 "/Users/home/PycharmProjects/Test Event Handling/.idea/Test Event Handling 03B.py"
2016-07-28 16:49:59.401 Python[11419:4185158]ApplePersistenceIgnoreState: Existing state will not be touched. New state will be written to /var/folders/8q/bhzsqtz900s742c17gkj_y740000gr/T/org.python.python.savedState
a
2016-07-28 16:50:02.841 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
2016-07-28 16:50:03.848 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
a
a
2016-07-28 16:50:04.632 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
a
Quitting NOW!
Process finished with exit code 0
Basic question: Why is this happening and what can I do about it?
Alternate question: Is there a better way to detect and get a users keystrokes without echoing them to the screen. I will be using Python and Pyglet for graphics so I was trying this using Pyglet's event handling.
Try to play with this simple example. It uses the built-in pyglet event handler to send the key pressed to a function that can then handle it. It shows that pyglet.app itself is the loop. You don't need to create any other.
#!/usr/bin/env python
import pyglet
class Win(pyglet.window.Window):
def __init__(self):
super(Win, self).__init__()
def on_draw(self):
self.clear()
# display your output here....
def on_key_press(self, symbol, modifiers):
if symbol== pyglet.window.key.ESCAPE:
exit(0)
else:
self.do_something(symbol)
# etc....
def do_something(symbol):
print symbol
# here you can test the input and then redraw
window = Win()
pyglet.app.run()
I have written this code to take a picture when it detects motion however when I run the code it prints 'picture taken' but does not save the picture.
I know my camera works as I tested it in LX terminal with the raspistill command. I have also tried changing the path for the file to be saved.
If you can see where i have been going wrong an answer would be greatly appreciated.
Thanks
import RPi.GPIO as GPIO
import time
import picamera
GPIO.setmode(GPIO.BCM)
GPIO.setup(4, GPIO.IN, GPIO.PUD_DOWN)
cam = picamera.PiCamera()
time.sleep(1)
if GPIO.input(4):
cam.capture('/home/pi/Eaglecam/surveillance.jpg')
print('picture taken')
Try putting the print statement in the scope of if GPIO.input(4) to see if you have successfully received the signal from the camera.
Might not be the cause but you should close the camera after you're done with it. Use camera.close() or initialize the camera using with picamera.PiCamera() as camera:
an example from its documentaion:
import time
import picamera
with picamera.PiCamera() as camera:
camera.resolution = (1024, 768)
camera.start_preview()
# Camera warm-up time
time.sleep(2)
camera.capture('foo.jpg')
I was wondering is there any way to get a custom sound to play as soon as a message dialog box comes up? my only restriction is that I can only use wxPython for this, for arguments sake lets call the sound file 'music.wav' Here is my code so far (ignore the stuff about playing with text, that was me creating a dummy GUI for it to load):
import wx
import time
import winsound, sys
class ButtonTest(wx.Frame):
def __init__(self,parent,id):
wx.Frame.__init__(self,None,id,'Button/Text test frame',size=(800,500))
panel=wx.Panel(self)
button=wx.Button(panel, label='Exit', pos=(200,50), size=(-1,-1))
self.Bind(wx.EVT_BUTTON, self.closer, button)
self.Bind(wx.EVT_CLOSE, self.wincloser)
ape=wx.StaticText(panel, -1, 'This text is STATIC', (200,80))
ape.SetFont(wx.Font(25, wx.SWISS, wx.ITALIC, wx.BOLD, True,'Times New Roman'))
def beep(sound):
winsound.PlaySound('%s.wav'%sound, winsound.SND_FILENAME)
#wx.FutureCall(1000, beep('C:\Users\Chris\Desktop\music'))
box=wx.MessageDialog(None,'Is this a good test?','Query:',wx.ICON_ERROR)
answer=box.ShowModal()
box.Destroy
beep('C:\Users\Chris\Desktop\music')
def closer(self,event):
self.Close(True)
def wincloser(self,event):
self.Destroy()
if __name__=='__main__':
app=wx.PySimpleApp()
frame=ButtonTest(None,id=-1)
frame.Show()
app.MainLoop()
For Windows, there's winsound, which is built in to Python. Otherwise, you'll need an external library like pyAudio or Snack Sound. See also Play a Sound with Python