formula unique character from first char in cell text - excel

have any idea for create unique character from cell in excel?
example :
i have string in cell
A1 = "lorem lipsum bla bla"
and A2 with formula generate char from A1 like "LLBB"; just get first char


with Office 365 Excel you can use CONCAT() in an array formula:
=UPPER(CONCAT(LEFT(TRIM(MID(SUBSTITUTE(A1," ",REPT(" ",99)),(ROW(1:20)-1)*99+1,99)))))
Being an array formula it must be confirmed with Ctrl+Shift+Enter instead of Enter when exiting edit mode. If done correctly Excel will put {} around the formula.
Replace the 20 with the max number of words it can be.


Try this small User Defined Function:
Public Function fLetter(rng As Range) As String
Dim a
For Each a In Split(rng.Value, " ")
fLetter = fLetter & UCase(Left(a, 1))
Next a
End Function

Related

Check if cell contains other characters than a-z; 0-9

I am searching for a way in excel to check a cell for other characters than the alphabet a-z, numbers 0-9 and the character "-"
In column "A" I have a list of product names like
A1: samsung-s7-black
A2: apple-phone-6-silver
A3: huawei-p9-limited-edition!
In column "B" I would like to get the following info
B1:
B2:
B3: !
Basically I am looking for a "negative" search in which i don't define which characters are not allowed but more which characters are allowed in my cell and output the characters that do not match. If this could be done without VBA even better.

If you have Office 365 / Excel 2016, you can use the TEXTJOIN function in an array formula:
B1: =TEXTJOIN("",TRUE,IF((CODE(MID(A3,seq,1))>=97)*(CODE(MID(A3,seq,1))<=122)+(CODE(MID(A3,seq,1))=45)+ISNUMBER(--MID(A3,seq,1))=1,"",MID(A3,seq,1)))
Since this is an array formula, you need to "confirm" it by holding down ctrl + shift while hitting enter. If you do this correctly, Excel will place braces {...} around the formula as observed in the formula bar
seq is a Name'd formula that refers to:
=ROW(INDEX(Sheet1!$1:$65535,1,1):INDEX(Sheet1!$1:$65535,LEN(INDIRECT("RC[-1]",FALSE)),1))
Note that we use the RC version of INDIRECT so the formula needs to be placed in the adjacent column of the string being tested.
Oh, and if you have mixed case in your actual data, replace A1 in the formula with =LOWER(A1)
=TEXTJOIN("",TRUE,IF((CODE(MID(LOWER(A1),seq,1))>=97)*(CODE(MID(LOWER(A1),seq,1))<=122)+(CODE(MID(LOWER(A1),seq,1))=45)+ISNUMBER(--MID(LOWER(A1),seq,1))=1,"",MID(LOWER(A1),seq,1)))
If you do not have the TEXTJOIN function, you could do a nested SUBSTITUTE or use a VBA solution.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(LOWER(A1),"a",""),"b",""),"c",""),"d",""),"e",""),"f",""),"g",""),"h",""),"i",""),"j",""),"k",""),"l",""),"m",""),"n",""),"o",""),"p",""),"q",""),"r",""),"s",""),"t",""),"u",""),"v",""),"w",""),"x",""),"y",""),"z",""),"0",""),"1",""),"2",""),"3",""),"4",""),"5",""),"6",""),"7",""),"8",""),"9",""),"-","")

Here's a VBA solution. Put this in a workbook module, and you can call with =remove_alphanumeric(A1)
Function remove_alphanumeric(InputString As String) As String
Dim i As Integer, strLen As Integer
Dim tmp_str As String, final As String
final = ""
i = 1
strLen = Len(InputString)
For i = 1 To strLen
tmp_str = Mid(InputString, i, 1)
If InStr(1, "abcdefghijklmnopqrstuvwxyz0123456789-", tmp_str) = 0 Then final = final + tmp_str
Next
remove_alphanumeric = final
End Function

Excel Macro to Trim a cell value

I have to Trim a cell value thru macro. I have a cell where I am getting a value like "20170411 675432". Here you can see there a space in between 1 and 6. I want to remove that space so that I can get the field value as "20170411675432"
Thanks

Try this:
Function trimacelll(cellalue As Variant)
trimacelll = Replace(CStr(cellalue), " ", "")
End Function

Posting this as you have asked for a formula,
=SUBSTITUTE(A1," ","")
A1 should contain the value

Split text into different columns from the right

I have a string of alpha-numeric text that is in one cell of Excel, using v2016. the text is similar to: ECN 6120 012 MMR 12195 201481
I have used variants of the "search" and "find" and "trim" to get the 1st, 2nd, 3rd, and last groups of text into individual cells.
I need to get the second to last group of numbers but it needs to be grabbed from the right because the 'MMR' sometimes is not present.
Any ideas?

With data in A1, in B1 enter:
=TRIM(MID(SUBSTITUTE($A1," ",REPT(" ",999)),COLUMNS($A:A)*999-998,999))
and copy across:

You could use a UDF to do this.
In VBE, create a new module and drop this code in:
Function strtok(strIn As String, strDelim As String, intToken As Integer) As String
strtok = Split(strIn, strDelim)(intToken - 1)
End Function
You can use this on your sheet then by using formula:
=strtok(A1, " ", 4)
To get the 4th word in that cell.

Extract the last substring from a cell

I have names in a column. I need to split just the last names from that column into another column.
The last name is delimited by a space from the right side.
The contents in cell A2 = Alistair Stevens and I entered the formula in cell B2 (I need 'Stevens' in cell B2)
I tried using the following formulas:
=RIGHT(A2,FIND(" ",A2,1)-1)
=RIGHT(A2,FIND(" ",A2))
Both these formulas work for this cell but when I fill it down / copy and paste it for the cells below it doesn't work. I get the wrong values!!
A3 -> David Mckenzie
B3 -> Mckenzie

This works, even when there are middle names:
=MID(A2,FIND(CHAR(1),SUBSTITUTE(A2," ",CHAR(1),LEN(A2)-LEN(SUBSTITUTE(A2," ",""))))+1,LEN(A2))
If you want everything BUT the last name, check out this answer.
If there are trailing spaces in your names, then you may want to remove them by replacing all instances of A2 by TRIM(A2) in the above formula.
Note that it is only by pure chance that your first formula =RIGHT(A2,FIND(" ",A2,1)-1) kind of works for Alistair Stevens. This is because "Alistair" and " Stevens" happen to contain the same number of characters (if you count the leading space in " Stevens").

The answer provided by #Jean provides a working but obscure solution (although it doesn't handle trailing spaces)
As an alternative consider a vba user defined function (UDF)
Function RightWord(r As Range) As Variant
Dim s As String
s = Trim(r.Value)
RightWord = Mid(s, InStrRev(s, " ") + 1)
End Function
Use in sheet as
=RightWord(A2)

Try this function in Excel:
Public Shared Function SPLITTEXT(Text As String, SplitAt As String, ReturnZeroBasedIndex As Integer) As String
Dim s() As String = Split(Text, SplitAt)
If ReturnZeroBasedIndex <= s.Count - 1 Then
Return s(ReturnZeroBasedIndex)
Else
Return ""
End If
End Function
You use it like this:
First Name (A1) | Last Name (A2)
Value in cell A1 = Michael Zomparelli
I want the last name in column A2.
=SPLITTEXT(A1, " ", 1)
The last param is the zero-based index you want to return. So if you split on the space char then index 0 = Michael and index 1 = Zomparelli
The above function is a .Net function, but can easily be converted to VBA.

If you want to get the second to last word in a text, you can use this macro as a function in your spreadsheet:
Public Function Get2ndText(S As String) As String
Dim sArr() As String
Dim i As Integer
sArr = Split(S, " ")
'get the next to the last string
i = UBound(sArr) - 1
Get2ndText = sArr(i)
End Function
Then in your spreadsheet B1 as the text:
CURRENT OWNER 915 BROADWAY ST HOUSTON TX 77012-2126
in B2 your formula would be:
=Get2ndText(B1)
The result would be
TX

Simpler would be:
=TRIM(RIGHT(SUBSTITUTE(TRIM(A2)," ",REPT(" ",99)),99))
You can use A2 in place of TRIM(A2) if you are sure that your data doesn't contain any unwanted spaces.
Based on concept explained by Rick Rothstein:
http://www.excelfox.com/forum/showthread.php/333-Get-Field-from-Delimited-Text-String
Sorry for being necroposter!

Right(A1, Len(A1)-Find("(asterisk)",Substitute(A1, "(space)","(asterisk)",Len(A1)-Len(Substitute(A1,"(space)", "(no space)")))))
Try this. Hope it works.

Try this:
=RIGHT(TRIM(A2),LEN(TRIM(A2))-FIND(" ",TRIM(A2)))
I was able to copy/paste the formula and it worked fine.
Here is a list of Excel text functions (which worked in May 2011, and but is subject to being broken the next time Microsoft changes their website). :-(
You can use a multiple-stage-nested IF() functions to handle middle names or initials, titles, etc. if you expect them. Excel formulas do not support looping, so there are some limits to what you can do.

RIGHT return whatever number of characters in the second parameter from the right of the first parameter. So, you want the total length of your column A - subtract the index. which is therefore:
=RIGHT(A2, LEN(A2)-FIND(" ", A2, 1))
And you should consider using TRIM(A2) everywhere it appears...

Try this:
Right(RC[-1],Len(RC[-1])-InStrRev(RC[-1]," "))

excel: how do i break up cell contents into CODE

There is a code function that returns ASCII for every letter.
I would like to use it in a way that it will break up a cell a1 = "some string"
Into it's ASCII codes:
Something like this: "23423423434634"
Sorry I don't know the exact ASCII of that but you get my point.
please note that i would like to do this specifically with a formula and NOT with VBA

One way is to use a Byte Array to give Unicode number pairs for each character:
Sub ByteArray()
Dim aByte() As Byte
Dim str1 As String<
Dim j As Long
str1 = "ABC"
aByte = str1
For j = LBound(aByte) To UBound(aByte)
MsgBox aByte(j)
Next j
End Sub

Write an Excel User Defined Function.
Pseudocode for the function is below:
string returnValue;
for each ( char c in string)
returnValue = returnValue + Chr(char)
return returnValue
You can call the UDF as part of an excell formula eg
=StringToASCIICodeValues(A1)
Formula Version
You could do it manually with excel builtin formula's by (excel doesn't have a for-loop function for formulae)
A1="some string"
A2="=MID($A$1,COLUMN(A2),1)"
Drag the formula in cell A2 to the right. Drag to K2 for some string example.
A3="=CODE(A2)"
Drag the formula in cell A3 to the right. Drag to K3 for some string example.
A4="=A3"
B4="=CONCATENATE(A4,B3)"
Drag the formula in cell B4 to the right. Drag to Cell K4 for some string example.
The right most column with a value on row 4 contains the final value. For some string it will return: 11511110910132115116114105110103 in cell K4

string someText = "some string";
CharEnumerator ce = someText.GetEnumerator();
int counter = 0;
while (ce.MoveNext())
{
char letter = someText[counter];
//Call the function to get the ascii
GetAsciiValue(letter);
//Do something
counter++;
}
May be this might help you.
Regards, J'Sinh

Although it's ugly, if your strings are not too long you can do it with a long formula which converts each character and then joins them back together.
For example this formula can handle strings which are up to 20 characters in length (creating hex ascii codes):
=if(len(A1)>=1,DEC2HEX(CODE(MID(A1,1,1))),"")&
if(len(A1)>=2,DEC2HEX(CODE(MID(A1,2,1))),"")&
if(len(A1)>=3,DEC2HEX(CODE(MID(A1,3,1))),"")&
if(len(A1)>=4,DEC2HEX(CODE(MID(A1,4,1))),"")&
if(len(A1)>=5,DEC2HEX(CODE(MID(A1,5,1))),"")&
if(len(A1)>=6,DEC2HEX(CODE(MID(A1,6,1))),"")&
if(len(A1)>=7,DEC2HEX(CODE(MID(A1,7,1))),"")&
if(len(A1)>=8,DEC2HEX(CODE(MID(A1,8,1))),"")&
if(len(A1)>=9,DEC2HEX(CODE(MID(A1,9,1))),"")&
if(len(A1)>=10,DEC2HEX(CODE(MID(A1,10,1))),"")&
if(len(A1)>=11,DEC2HEX(CODE(MID(A1,11,1))),"")&
if(len(A1)>=12,DEC2HEX(CODE(MID(A1,12,1))),"")&
if(len(A1)>=13,DEC2HEX(CODE(MID(A1,13,1))),"")&
if(len(A1)>=14,DEC2HEX(CODE(MID(A1,14,1))),"")&
if(len(A1)>=15,DEC2HEX(CODE(MID(A1,15,1))),"")&
if(len(A1)>=16,DEC2HEX(CODE(MID(A1,16,1))),"")&
if(len(A1)>=17,DEC2HEX(CODE(MID(A1,17,1))),"")&
if(len(A1)>=18,DEC2HEX(CODE(MID(A1,18,1))),"")&
if(len(A1)>=19,DEC2HEX(CODE(MID(A1,19,1))),"")&
if(len(A1)>=20,DEC2HEX(CODE(MID(A1,20,1))),"")
For longer strings you could repeat this pattern, although you'd be limited by the maximum formula length allowed by Excel, which seems to be 8,192 characters.

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