There is a code function that returns ASCII for every letter.
I would like to use it in a way that it will break up a cell a1 = "some string"
Into it's ASCII codes:
Something like this: "23423423434634"
Sorry I don't know the exact ASCII of that but you get my point.
please note that i would like to do this specifically with a formula and NOT with VBA
One way is to use a Byte Array to give Unicode number pairs for each character:
Sub ByteArray()
Dim aByte() As Byte
Dim str1 As String<
Dim j As Long
str1 = "ABC"
aByte = str1
For j = LBound(aByte) To UBound(aByte)
MsgBox aByte(j)
Next j
End Sub
Write an Excel User Defined Function.
Pseudocode for the function is below:
string returnValue;
for each ( char c in string)
returnValue = returnValue + Chr(char)
return returnValue
You can call the UDF as part of an excell formula eg
=StringToASCIICodeValues(A1)
Formula Version
You could do it manually with excel builtin formula's by (excel doesn't have a for-loop function for formulae)
A1="some string"
A2="=MID($A$1,COLUMN(A2),1)"
Drag the formula in cell A2 to the right. Drag to K2 for some string example.
A3="=CODE(A2)"
Drag the formula in cell A3 to the right. Drag to K3 for some string example.
A4="=A3"
B4="=CONCATENATE(A4,B3)"
Drag the formula in cell B4 to the right. Drag to Cell K4 for some string example.
The right most column with a value on row 4 contains the final value. For some string it will return: 11511110910132115116114105110103 in cell K4
string someText = "some string";
CharEnumerator ce = someText.GetEnumerator();
int counter = 0;
while (ce.MoveNext())
{
char letter = someText[counter];
//Call the function to get the ascii
GetAsciiValue(letter);
//Do something
counter++;
}
May be this might help you.
Regards, J'Sinh
Although it's ugly, if your strings are not too long you can do it with a long formula which converts each character and then joins them back together.
For example this formula can handle strings which are up to 20 characters in length (creating hex ascii codes):
=if(len(A1)>=1,DEC2HEX(CODE(MID(A1,1,1))),"")&
if(len(A1)>=2,DEC2HEX(CODE(MID(A1,2,1))),"")&
if(len(A1)>=3,DEC2HEX(CODE(MID(A1,3,1))),"")&
if(len(A1)>=4,DEC2HEX(CODE(MID(A1,4,1))),"")&
if(len(A1)>=5,DEC2HEX(CODE(MID(A1,5,1))),"")&
if(len(A1)>=6,DEC2HEX(CODE(MID(A1,6,1))),"")&
if(len(A1)>=7,DEC2HEX(CODE(MID(A1,7,1))),"")&
if(len(A1)>=8,DEC2HEX(CODE(MID(A1,8,1))),"")&
if(len(A1)>=9,DEC2HEX(CODE(MID(A1,9,1))),"")&
if(len(A1)>=10,DEC2HEX(CODE(MID(A1,10,1))),"")&
if(len(A1)>=11,DEC2HEX(CODE(MID(A1,11,1))),"")&
if(len(A1)>=12,DEC2HEX(CODE(MID(A1,12,1))),"")&
if(len(A1)>=13,DEC2HEX(CODE(MID(A1,13,1))),"")&
if(len(A1)>=14,DEC2HEX(CODE(MID(A1,14,1))),"")&
if(len(A1)>=15,DEC2HEX(CODE(MID(A1,15,1))),"")&
if(len(A1)>=16,DEC2HEX(CODE(MID(A1,16,1))),"")&
if(len(A1)>=17,DEC2HEX(CODE(MID(A1,17,1))),"")&
if(len(A1)>=18,DEC2HEX(CODE(MID(A1,18,1))),"")&
if(len(A1)>=19,DEC2HEX(CODE(MID(A1,19,1))),"")&
if(len(A1)>=20,DEC2HEX(CODE(MID(A1,20,1))),"")
For longer strings you could repeat this pattern, although you'd be limited by the maximum formula length allowed by Excel, which seems to be 8,192 characters.
Related
I am searching for a way in excel to check a cell for other characters than the alphabet a-z, numbers 0-9 and the character "-"
In column "A" I have a list of product names like
A1: samsung-s7-black
A2: apple-phone-6-silver
A3: huawei-p9-limited-edition!
In column "B" I would like to get the following info
B1:
B2:
B3: !
Basically I am looking for a "negative" search in which i don't define which characters are not allowed but more which characters are allowed in my cell and output the characters that do not match. If this could be done without VBA even better.
If you have Office 365 / Excel 2016, you can use the TEXTJOIN function in an array formula:
B1: =TEXTJOIN("",TRUE,IF((CODE(MID(A3,seq,1))>=97)*(CODE(MID(A3,seq,1))<=122)+(CODE(MID(A3,seq,1))=45)+ISNUMBER(--MID(A3,seq,1))=1,"",MID(A3,seq,1)))
Since this is an array formula, you need to "confirm" it by holding down ctrl + shift while hitting enter. If you do this correctly, Excel will place braces {...} around the formula as observed in the formula bar
seq is a Name'd formula that refers to:
=ROW(INDEX(Sheet1!$1:$65535,1,1):INDEX(Sheet1!$1:$65535,LEN(INDIRECT("RC[-1]",FALSE)),1))
Note that we use the RC version of INDIRECT so the formula needs to be placed in the adjacent column of the string being tested.
Oh, and if you have mixed case in your actual data, replace A1 in the formula with =LOWER(A1)
=TEXTJOIN("",TRUE,IF((CODE(MID(LOWER(A1),seq,1))>=97)*(CODE(MID(LOWER(A1),seq,1))<=122)+(CODE(MID(LOWER(A1),seq,1))=45)+ISNUMBER(--MID(LOWER(A1),seq,1))=1,"",MID(LOWER(A1),seq,1)))
If you do not have the TEXTJOIN function, you could do a nested SUBSTITUTE or use a VBA solution.
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(LOWER(A1),"a",""),"b",""),"c",""),"d",""),"e",""),"f",""),"g",""),"h",""),"i",""),"j",""),"k",""),"l",""),"m",""),"n",""),"o",""),"p",""),"q",""),"r",""),"s",""),"t",""),"u",""),"v",""),"w",""),"x",""),"y",""),"z",""),"0",""),"1",""),"2",""),"3",""),"4",""),"5",""),"6",""),"7",""),"8",""),"9",""),"-","")
Here's a VBA solution. Put this in a workbook module, and you can call with =remove_alphanumeric(A1)
Function remove_alphanumeric(InputString As String) As String
Dim i As Integer, strLen As Integer
Dim tmp_str As String, final As String
final = ""
i = 1
strLen = Len(InputString)
For i = 1 To strLen
tmp_str = Mid(InputString, i, 1)
If InStr(1, "abcdefghijklmnopqrstuvwxyz0123456789-", tmp_str) = 0 Then final = final + tmp_str
Next
remove_alphanumeric = final
End Function
have any idea for create unique character from cell in excel?
example :
i have string in cell
A1 = "lorem lipsum bla bla"
and A2 with formula generate char from A1 like "LLBB"; just get first char
with Office 365 Excel you can use CONCAT() in an array formula:
=UPPER(CONCAT(LEFT(TRIM(MID(SUBSTITUTE(A1," ",REPT(" ",99)),(ROW(1:20)-1)*99+1,99)))))
Being an array formula it must be confirmed with Ctrl+Shift+Enter instead of Enter when exiting edit mode. If done correctly Excel will put {} around the formula.
Replace the 20 with the max number of words it can be.
Try this small User Defined Function:
Public Function fLetter(rng As Range) As String
Dim a
For Each a In Split(rng.Value, " ")
fLetter = fLetter & UCase(Left(a, 1))
Next a
End Function
I have two text cells in Excel as shown below which contains strings (A1 and A2), I am trying to remove A2 cell characters from A1 cell string and store the result in A3.
I have tried using few functions like SEARCH(), TEXT(), RIGHT() .. but couldnt achieve what I would need as result.
I could do this easily using any programming language (Python, C, etc.,) - just need a loop and couple of string functions. But couldn't figure out the way to get the same using Excel Formula.
Any thoughts how can we get this?
Doing this via a UDF would be pretty straightforward. Basically just loop through the ins character by character and use replace() to swap the character out with nothing;
Function textSubtract(startString As String, subtractString As String) As String
'Function to subtract characters in one string from another string
'Loop through every character in subtractString
Dim charCounter As Integer
For charCounter = 1 To Len(subtractString)
'Replace out the character in startString
startString = Replace(startString, Mid(subtractString, charCounter, 1), "")
Next charCounter
'Return
textSubtract = startString
End Function
Then you can call it like:
In B2 enter:
=MID($A$2,COLUMN()-1,1)
and copy across (this isolates the characters). In B3 enter:
=SUBSTITUTE($A$1,B2,"")
In C3 enter:
=SUBSTITUTE(B3,C2,"")
and copy across (this removes each character):
Looking for some suggestions to tweak/enhance the formula I have created, to extract the number from a string.
Have the below sample text in a Cell A1:
Based on the invnum:-1234567 The calculation is based on 123.33*3.00
Wrote the below formula in B1
=VALUE(LEFT(MID(A1,FIND("invnum:-",A1)+7,LEN((A1))),7)
the Result given is -1234567
However, the length of the reference number on my source file is variable, Looking to extract only the number following the word invnum:-
Looking to include this formula in a macro, so trying to keep it simple any ideas/suggestions please?
Try this Function:
Function findNumber(inPtStr As String) As Double
Dim strArr() As String
Dim i As Long
inPtStr = Replace(inPtStr, ":", " ")
strArr = Split(inPtStr)
For i = LBound(strArr) To UBound(strArr)
If IsNumeric(strArr(i)) Then
findNumber = --strArr(i)
Exit Function
End If
Next i
End Function
Then you can call it from a regular sub.
If you want a formula then:
=--TRIM(MID(SUBSTITUTE(A1," ",REPT(" ",99)),FIND("invnum:",SUBSTITUTE(A1," ",REPT(" ",99)))+7,99))
Let's get crazy and step through this...
Start with the intermediate indexes you need to find, such as the start, end, and length of the numeric string. Once you have those, just carefully reassemble your formula:
I have names in a column. I need to split just the last names from that column into another column.
The last name is delimited by a space from the right side.
The contents in cell A2 = Alistair Stevens and I entered the formula in cell B2 (I need 'Stevens' in cell B2)
I tried using the following formulas:
=RIGHT(A2,FIND(" ",A2,1)-1)
=RIGHT(A2,FIND(" ",A2))
Both these formulas work for this cell but when I fill it down / copy and paste it for the cells below it doesn't work. I get the wrong values!!
A3 -> David Mckenzie
B3 -> Mckenzie
This works, even when there are middle names:
=MID(A2,FIND(CHAR(1),SUBSTITUTE(A2," ",CHAR(1),LEN(A2)-LEN(SUBSTITUTE(A2," ",""))))+1,LEN(A2))
If you want everything BUT the last name, check out this answer.
If there are trailing spaces in your names, then you may want to remove them by replacing all instances of A2 by TRIM(A2) in the above formula.
Note that it is only by pure chance that your first formula =RIGHT(A2,FIND(" ",A2,1)-1) kind of works for Alistair Stevens. This is because "Alistair" and " Stevens" happen to contain the same number of characters (if you count the leading space in " Stevens").
The answer provided by #Jean provides a working but obscure solution (although it doesn't handle trailing spaces)
As an alternative consider a vba user defined function (UDF)
Function RightWord(r As Range) As Variant
Dim s As String
s = Trim(r.Value)
RightWord = Mid(s, InStrRev(s, " ") + 1)
End Function
Use in sheet as
=RightWord(A2)
Try this function in Excel:
Public Shared Function SPLITTEXT(Text As String, SplitAt As String, ReturnZeroBasedIndex As Integer) As String
Dim s() As String = Split(Text, SplitAt)
If ReturnZeroBasedIndex <= s.Count - 1 Then
Return s(ReturnZeroBasedIndex)
Else
Return ""
End If
End Function
You use it like this:
First Name (A1) | Last Name (A2)
Value in cell A1 = Michael Zomparelli
I want the last name in column A2.
=SPLITTEXT(A1, " ", 1)
The last param is the zero-based index you want to return. So if you split on the space char then index 0 = Michael and index 1 = Zomparelli
The above function is a .Net function, but can easily be converted to VBA.
If you want to get the second to last word in a text, you can use this macro as a function in your spreadsheet:
Public Function Get2ndText(S As String) As String
Dim sArr() As String
Dim i As Integer
sArr = Split(S, " ")
'get the next to the last string
i = UBound(sArr) - 1
Get2ndText = sArr(i)
End Function
Then in your spreadsheet B1 as the text:
CURRENT OWNER 915 BROADWAY ST HOUSTON TX 77012-2126
in B2 your formula would be:
=Get2ndText(B1)
The result would be
TX
Simpler would be:
=TRIM(RIGHT(SUBSTITUTE(TRIM(A2)," ",REPT(" ",99)),99))
You can use A2 in place of TRIM(A2) if you are sure that your data doesn't contain any unwanted spaces.
Based on concept explained by Rick Rothstein:
http://www.excelfox.com/forum/showthread.php/333-Get-Field-from-Delimited-Text-String
Sorry for being necroposter!
Right(A1, Len(A1)-Find("(asterisk)",Substitute(A1, "(space)","(asterisk)",Len(A1)-Len(Substitute(A1,"(space)", "(no space)")))))
Try this. Hope it works.
Try this:
=RIGHT(TRIM(A2),LEN(TRIM(A2))-FIND(" ",TRIM(A2)))
I was able to copy/paste the formula and it worked fine.
Here is a list of Excel text functions (which worked in May 2011, and but is subject to being broken the next time Microsoft changes their website). :-(
You can use a multiple-stage-nested IF() functions to handle middle names or initials, titles, etc. if you expect them. Excel formulas do not support looping, so there are some limits to what you can do.
RIGHT return whatever number of characters in the second parameter from the right of the first parameter. So, you want the total length of your column A - subtract the index. which is therefore:
=RIGHT(A2, LEN(A2)-FIND(" ", A2, 1))
And you should consider using TRIM(A2) everywhere it appears...
Try this:
Right(RC[-1],Len(RC[-1])-InStrRev(RC[-1]," "))