I want to know how I can search for a specific word in a .txt file using Python3.
If the word 'pizza' is included in the .txt file, then it should (e.g.) import another python program.
You can iterate through each line in the file with a 'for' loop and check to see if the string is in the line:
f = open('file.txt', 'r')
for line in f:
if 'pizza' in line:
# do whatever you want here
print("Found it!")
else:
pass
Related
I have a text file with file paths:
path1
path2
path3
...
path100000000
I have my python script app.py that should run on each file (path1, path2 ...)
Please advise what is the best way to do it?
Should I just get it as argument, and then:
with open(input_file, "r") as f:
lines = f.readlines()
for line in lines:
main_function(line)
Yes that should work, except readlines() doesn't remove newline characters.
with open(input_file, "r") as f:
lines = f.readlines()
for line in lines:
main_function(line.strip())
**Note: The above code assumes the file is in the same directory as the python script file.
You are using context managers. Hence, place the code inside the context.
So according to your comment,
If you want to pass filename where you will read the file contents in the main_function, then the above code will work.
If you want to read the file and then pass the file contents, then you will have to modify the above code to first read the content and then pass it to the function
with open(input_file, "r") as f:
lines = f.readlines()
for line in lines:
main_function(open(line.strip(), "r").read())
**Note: the above function will read the whole file as a single string (text)
I have a text file say storyfile.txt
Content in storyfile.txt is as
'Twas brillig, and the slithy toves
Did gyre and gimble in the wabe;
All mimsy were the borogoves,
And the mome raths outgrabe
I have another file- hashfile.txt that contains some words separated by comma(,)
Content of hashfile.txt is:
All,mimsy,were,the,borogoves,raths,outgrabe
My objective
My objective is to
1. Read hashfile.txt
2. Insert Hashtag on each of the comma separated word
3. Read storyfile.txt . Search for same words as in hashtag.txt and add hashtag on these words.
4. Update storyfile.txt with words that are hash-tagged
My Python code so far
import in_place
hashfile = open('hashfile.txt', 'w+')
n1 = hashfile.read().rstrip('\n')
print(n1)
checkWords = n1.split(',')
print(checkWords)
repWords = ["#"+i for i in checkWords]
print(repWords)
hashfile.close()
with in_place.InPlace('storyfile.txt') as file:
for line in file:
for check, rep in zip(checkWords, repWords):
line = line.replace(check, rep)
file.write(line)
The output
can be seen here
https://dpaste.de/Yp35
Why is this kind of output is coming?
Why the last sentence has no newlines in it?
Where I am wrong?
The output
attached image
The current working code for single text
import in_place
with in_place.InPlace('somefile.txt') as file:
for line in file:
line = line.replace('mome', 'testZ')
file.write(line)
Look if this helps. This fulfills the objective that you mentioned, though I have not used the in_place module.
hash_list = []
with open("hashfile.txt", 'r') as f:
for i in f.readlines():
for j in i.split(","):
hash_list.append(j.strip())
with open("storyfile.txt", "r") as f:
for i in f.readlines():
for j in hash_list:
i = i.replace(j, "#"+j)
print(i)
Let me know if you require further clarification on the same.
I have been searching a large directory of text files for files that match a list of words. How do I have python output the word from the list that matches?
This is what I have so far. It writes the file name every time one of the words from the list is found. I want to add the matching word to the line with the file name so I have the file name and 1 matched word each time. How do I do that?
ngwrds= ['words'...]
for filename in os.listdir(os.getcwd()):
with open(filename, 'r') as searchfile:
for line in searchfile:
if any(x in line for x in ngwrds):
with open("keyword.txt", 'a') as out:
out.write(filename + '\n')
The input is a long text file a line might read like this:
The company reported depreciation of $1.20.
The if one of the search words from the list was depreciation then the output file would look like this:
filename depreciation
Thank you.
I am not sure what out is and I can't run your code from where I am but you could try something like this:
ngwrds= ['words'...]
for filename in os.listdir(os.getcwd()):
with open(filename, 'r') as searchfile:
for line in searchfile:
line = line.strip().split(" ")
for word in line:
if word in ngwrds:
out.write(filename + " " + word)
strip gets rid of whitespace on either end of line. split returns a list of the words in line.
I have approximately 160,000 text files in a directory. My first objective is to create a list of files that contain at least one item from a list of about 50 keywords. My current code is
import os
ngwrds= [list of words]
for filename in os.listdir(os.getcwd()):
with open(filename, 'r') as searchfile:
for line in searchfile:
if any(x in line for x in ngwrds):
with open("keyword.txt", 'a') as out:
out.write(filename + '\n')
Which works but sends out duplicate filenames. Ideally what I would like is for the loop to stop once it hits the first keyword, write the file name to 'keyword.txt', and move on to the next file in the directory. Any thoughts on how to do this?
A more in depth answer to #strubbly's comment, you would simply add a break in the 2nd for loop
with open(filename, 'r') as searchfile:
for line in searchfile:
if any(x in line for x in ngwrds):
with open("keyword.txt", 'a') as out:
out.write(filename + '\n')
break
What does the break do? from the python3 docs:
The break statement, like in C, breaks out of the smallest enclosing for or while loop.
for more information on break go to the control flow documentation :https://docs.python.org/3/tutorial/controlflow.html
Can you explain what is going on in this code? I don't seem to understand
how you can open the file and read it line by line instead of all of the sentences at the same time in a for loop. Thanks
Let's say I have these sentences in a document file:
cat:dog:mice
cat1:dog1:mice1
cat2:dog2:mice2
cat3:dog3:mice3
Here is the code:
from sys import argv
filename = input("Please enter the name of a file: ")
f = open(filename,'r')
d1ct = dict()
print("Number of times each animal visited each station:")
print("Animal Id Station 1 Station 2")
for line in f:
if '\n' == line[-1]:
line = line[:-1]
(AnimalId, Timestamp, StationId,) = line.split(':')
key = (AnimalId,StationId,)
if key not in d1ct:
d1ct[key] = 0
d1ct[key] += 1
The magic is at:
for line in f:
if '\n' == line[-1]:
line = line[:-1]
Python file objects are special in that they can be iterated over in a for loop. On each iteration, it retrieves the next line of the file. Because it includes the last character in the line, which could be a newline, it's often useful to check and remove the last character.
As Moshe wrote, open file objects can be iterated. Only, they are not of the file type in Python 3.x (as they were in Python 2.x). If the file object is opened in text mode, then the unit of iteration is one text line including the \n.
You can use line = line.rstrip() to remove the \n plus the trailing withespaces.
If you want to read the content of the file at once (into a multiline string), you can use content = f.read().
There is a minor bug in the code. The open file should always be closed. I means to use f.close() after the for loop. Or you can wrap the open to the newer with construct that will close the file for you -- I suggest to get used to the later approach.