Linq to Excel, get column names from CSV file - excel

I need to get the column headers of CSV files with LINQ to Excel
I use the code specified on https://github.com/paulyoder/LinqToExcel
This works perefectly for .XLSX files but not for CSV
//Select File
var book = new LinqToExcel.ExcelQueryFactory(link + #"\" + fileName);
//Select firtworkbook
var query = (from row in book.Worksheet(0) select row).ToList();
var workSheetName = book.GetWorksheetNames();
var columnNames = (from row in book.GetColumnNames(workSheetName.FirstOrDefault()) select row).ToList();
I also tried hardcoding the sheet name and calling the CSV sheet1
var columnNames = (from row in book.GetColumnNames("Sheet1") select row).ToList();
This breaks and gives me this error:
Message = "'54733658.csv' is not a valid worksheet name in file...
I double checked it is the correct path.
I then tried:(It takes worksheet name which is the same as file name - extention)
string extension = System.IO.Path.GetExtension(fileName);
string result = fileName.Substring(0, fileName.Length - extension.Length);
var colNames = book.GetColumnNames(result, "A1:F1").ToList();
This gives me the following error:
The Microsoft Jet database engine could not find the object '02119249$A1_Z1.txt'. Make sure the object exists and that you spell its name and the path name correctly.
I googled that error those results are not applicable.

I don't have enough time to figure out why I cant read the CSV column headers
For those of you who have the same issue:
Read the first line and make a list of strings, here is my method:
public List<string> ColumnNameGenerator(string FilePath)
{
string firstLine = "";
using (StreamReader reader = new StreamReader(FilePath))
{
firstLine = reader.ReadLine() ?? "";
}
return firstLine.Split(',').ToList();
}

Related

How do I convert the excel files into spreadsheet files without changing the existing excel files type in google drive folder?

In a google sheet, I managed to filter file name and file type and list all the particular files needed from a google drive folder based on the conditions into a spreadsheet. I am having an issue to convert the excel files into spreadsheet because I'm opening the selected files using "SpreadsheetApp.openById(id)" in another function() to get the data range from the specific files.
Based on the requirement set, I was been asked to convert the excel files into spreadsheet before getting the range data and export those data into another sheet.
Below are the codes that i created to list the file name and file type, so i believe that the file conversion method might need to be implemented here as well because it involves the file filtering process and these are the files need to be converted later on. Please correct me if I am wrong.
function getChildFiles(parentName, parent, sheet) {
var fileIter = parent.searchFiles("title contains 'completed'and title contains 'Verification
Visit Direct Suppliers'and mimeType='application/vnd.openxmlformats-
officedocument.spreadsheetml.sheet'");
var output = [];
var now = new Date();
var date = new Date();
var copy = new Date(date);
while (fileIter.hasNext()) {
var file = fileIter.next();
var fileName = file.getName();
var fileType = file.getMimeType();
var filecreatedate = file.getDateCreated();
var fileUpdate = file.getLastUpdated()
var path = parentName + ' |--> ' + fileName;
var fileID = file.getId();
var Url = 'https://drive.google.com/open?id=' + fileID;
output.push([fileID, fileName, path, Url,filecreatedate,fileUpdate,copy]);
Logger.log(fileType);}
if (output.length) {
var last_row = sheet.getLastRow();
sheet.getRange(last_row + 1, 1, output.length, 7).setValues(output);
SpreadsheetApp.flush();}
var childFolders = parent.getFolders();
while (childFolders.hasNext()) {
var childFolder = childFolders.next();
var childFolderName = childFolder.getName();
getChildFiles( parentName + ' |--> ' + childFolderName, childFolder, sheet);}}
So I'm trying to implement the file conversion method from excel file to spreadsheet, so that i can extract data from the excel file after the file successfully converted to spreadsheet.

Get Excel sheet names unsorted via delphi ADO [duplicate]

I'm using OleDb to read from an excel workbook with many sheets.
I need to read the sheet names, but I need them in the order they are defined in the spreadsheet; so If I have a file that looks like this;
|_____|_____|____|____|____|____|____|____|____|
|_____|_____|____|____|____|____|____|____|____|
|_____|_____|____|____|____|____|____|____|____|
\__GERMANY__/\__UK__/\__IRELAND__/
Then I need to get the dictionary
1="GERMANY",
2="UK",
3="IRELAND"
I've tried using OleDbConnection.GetOleDbSchemaTable(), and that gives me the list of names, but it alphabetically sorts them. The alpha-sort means I don't know which sheet number a particular name corresponds to. So I get;
GERMANY, IRELAND, UK
which has changed the order of UK and IRELAND.
The reason I need it to be sorted is that I have to let the user choose a range of data by name or index; they can ask for 'all the data from GERMANY to IRELAND' or 'data from sheet 1 to sheet 3'.
Any ideas would be greatly appreciated.
if I could use the office interop classes, this would be straightforward. Unfortunately, I can't because the interop classes don't work reliably in non-interactive environments such as windows services and ASP.NET sites, so I needed to use OLEDB.
Can you not just loop through the sheets from 0 to Count of names -1? that way you should get them in the correct order.
Edit
I noticed through the comments that there are a lot of concerns about using the Interop classes to retrieve the sheet names. Therefore here is an example using OLEDB to retrieve them:
/// <summary>
/// This method retrieves the excel sheet names from
/// an excel workbook.
/// </summary>
/// <param name="excelFile">The excel file.</param>
/// <returns>String[]</returns>
private String[] GetExcelSheetNames(string excelFile)
{
OleDbConnection objConn = null;
System.Data.DataTable dt = null;
try
{
// Connection String. Change the excel file to the file you
// will search.
String connString = "Provider=Microsoft.Jet.OLEDB.4.0;" +
"Data Source=" + excelFile + ";Extended Properties=Excel 8.0;";
// Create connection object by using the preceding connection string.
objConn = new OleDbConnection(connString);
// Open connection with the database.
objConn.Open();
// Get the data table containg the schema guid.
dt = objConn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);
if(dt == null)
{
return null;
}
String[] excelSheets = new String[dt.Rows.Count];
int i = 0;
// Add the sheet name to the string array.
foreach(DataRow row in dt.Rows)
{
excelSheets[i] = row["TABLE_NAME"].ToString();
i++;
}
// Loop through all of the sheets if you want too...
for(int j=0; j < excelSheets.Length; j++)
{
// Query each excel sheet.
}
return excelSheets;
}
catch(Exception ex)
{
return null;
}
finally
{
// Clean up.
if(objConn != null)
{
objConn.Close();
objConn.Dispose();
}
if(dt != null)
{
dt.Dispose();
}
}
}
Extracted from Article on the CodeProject.
Since above code do not cover procedures for extracting list of sheet name for Excel 2007,following code will be applicable for both Excel(97-2003) and Excel 2007 too:
public List<string> ListSheetInExcel(string filePath)
{
OleDbConnectionStringBuilder sbConnection = new OleDbConnectionStringBuilder();
String strExtendedProperties = String.Empty;
sbConnection.DataSource = filePath;
if (Path.GetExtension(filePath).Equals(".xls"))//for 97-03 Excel file
{
sbConnection.Provider = "Microsoft.Jet.OLEDB.4.0";
strExtendedProperties = "Excel 8.0;HDR=Yes;IMEX=1";//HDR=ColumnHeader,IMEX=InterMixed
}
else if (Path.GetExtension(filePath).Equals(".xlsx")) //for 2007 Excel file
{
sbConnection.Provider = "Microsoft.ACE.OLEDB.12.0";
strExtendedProperties = "Excel 12.0;HDR=Yes;IMEX=1";
}
sbConnection.Add("Extended Properties",strExtendedProperties);
List<string> listSheet = new List<string>();
using (OleDbConnection conn = new OleDbConnection(sbConnection.ToString()))
{
conn.Open();
DataTable dtSheet = conn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);
foreach (DataRow drSheet in dtSheet.Rows)
{
if (drSheet["TABLE_NAME"].ToString().Contains("$"))//checks whether row contains '_xlnm#_FilterDatabase' or sheet name(i.e. sheet name always ends with $ sign)
{
listSheet.Add(drSheet["TABLE_NAME"].ToString());
}
}
}
return listSheet;
}
Above function returns list of sheet in particular excel file for both excel type(97,2003,2007).
Can't find this in actual MSDN documentation, but a moderator in the forums said
I am afraid that OLEDB does not preserve the sheet order as they were in Excel
Excel Sheet Names in Sheet Order
Seems like this would be a common enough requirement that there would be a decent workaround.
This is short, fast, safe, and usable...
public static List<string> ToExcelsSheetList(string excelFilePath)
{
List<string> sheets = new List<string>();
using (OleDbConnection connection =
new OleDbConnection((excelFilePath.TrimEnd().ToLower().EndsWith("x"))
? "Provider=Microsoft.ACE.OLEDB.12.0;Data Source='" + excelFilePath + "';" + "Extended Properties='Excel 12.0 Xml;HDR=YES;'"
: "provider=Microsoft.Jet.OLEDB.4.0;Data Source='" + excelFilePath + "';Extended Properties=Excel 8.0;"))
{
connection.Open();
DataTable dt = connection.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, null);
foreach (DataRow drSheet in dt.Rows)
if (drSheet["TABLE_NAME"].ToString().Contains("$"))
{
string s = drSheet["TABLE_NAME"].ToString();
sheets.Add(s.StartsWith("'")?s.Substring(1, s.Length - 3): s.Substring(0, s.Length - 1));
}
connection.Close();
}
return sheets;
}
Another way:
a xls(x) file is just a collection of *.xml files stored in a *.zip container.
unzip the file "app.xml" in the folder docProps.
<?xml version="1.0" encoding="UTF-8" standalone="true"?>
-<Properties xmlns:vt="http://schemas.openxmlformats.org/officeDocument/2006/docPropsVTypes" xmlns="http://schemas.openxmlformats.org/officeDocument/2006/extended-properties">
<TotalTime>0</TotalTime>
<Application>Microsoft Excel</Application>
<DocSecurity>0</DocSecurity>
<ScaleCrop>false</ScaleCrop>
-<HeadingPairs>
-<vt:vector baseType="variant" size="2">
-<vt:variant>
<vt:lpstr>Arbeitsblätter</vt:lpstr>
</vt:variant>
-<vt:variant>
<vt:i4>4</vt:i4>
</vt:variant>
</vt:vector>
</HeadingPairs>
-<TitlesOfParts>
-<vt:vector baseType="lpstr" size="4">
<vt:lpstr>Tabelle3</vt:lpstr>
<vt:lpstr>Tabelle4</vt:lpstr>
<vt:lpstr>Tabelle1</vt:lpstr>
<vt:lpstr>Tabelle2</vt:lpstr>
</vt:vector>
</TitlesOfParts>
<Company/>
<LinksUpToDate>false</LinksUpToDate>
<SharedDoc>false</SharedDoc>
<HyperlinksChanged>false</HyperlinksChanged>
<AppVersion>14.0300</AppVersion>
</Properties>
The file is a german file (Arbeitsblätter = worksheets).
The table names (Tabelle3 etc) are in the correct order. You just need to read these tags;)
regards
I have created the below function using the information provided in the answer from #kraeppy (https://stackoverflow.com/a/19930386/2617732). This requires the .net framework v4.5 to be used and requires a reference to System.IO.Compression. This only works for xlsx files and not for the older xls files.
using System.IO.Compression;
using System.Xml;
using System.Xml.Linq;
static IEnumerable<string> GetWorksheetNamesOrdered(string fileName)
{
//open the excel file
using (FileStream data = new FileStream(fileName, FileMode.Open))
{
//unzip
ZipArchive archive = new ZipArchive(data);
//select the correct file from the archive
ZipArchiveEntry appxmlFile = archive.Entries.SingleOrDefault(e => e.FullName == "docProps/app.xml");
//read the xml
XDocument xdoc = XDocument.Load(appxmlFile.Open());
//find the titles element
XElement titlesElement = xdoc.Descendants().Where(e => e.Name.LocalName == "TitlesOfParts").Single();
//extract the worksheet names
return titlesElement
.Elements().Where(e => e.Name.LocalName == "vector").Single()
.Elements().Where(e => e.Name.LocalName == "lpstr")
.Select(e => e.Value);
}
}
I like the idea of #deathApril to name the sheets as 1_Germany, 2_UK, 3_IRELAND. I also got your issue to do this rename for hundreds of sheets. If you don't have a problem to rename the sheet name then you can use this macro to do it for you. It will take less than seconds to rename all sheet names. unfortunately ODBC, OLEDB return the sheet name order by asc. There is no replacement for that. You have to either use COM or rename your name to be in the order.
Sub Macro1()
'
' Macro1 Macro
'
'
Dim i As Integer
For i = 1 To Sheets.Count
Dim prefix As String
prefix = i
If Len(prefix) < 4 Then
prefix = "000"
ElseIf Len(prefix) < 3 Then
prefix = "00"
ElseIf Len(prefix) < 2 Then
prefix = "0"
End If
Dim sheetName As String
sheetName = Sheets(i).Name
Dim names
names = Split(sheetName, "-")
If (UBound(names) > 0) And IsNumeric(names(0)) Then
'do nothing
Else
Sheets(i).Name = prefix & i & "-" & Sheets(i).Name
End If
Next
End Sub
UPDATE:
After reading #SidHoland comment regarding BIFF an idea flashed. The following steps can be done through code. Don't know if you really want to do that to get the sheet names in the same order. Let me know if you need help to do this through code.
1. Consider XLSX as a zip file. Rename *.xlsx into *.zip
2. Unzip
3. Go to unzipped folder root and open /docprops/app.xml
4. This xml contains the sheet name in the same order of what you see.
5. Parse the xml and get the sheet names
UPDATE:
Another solution - NPOI might be helpful here
http://npoi.codeplex.com/
FileStream file = new FileStream(#"yourexcelfilename", FileMode.Open, FileAccess.Read);
HSSFWorkbook hssfworkbook = new HSSFWorkbook(file);
for (int i = 0; i < hssfworkbook.NumberOfSheets; i++)
{
Console.WriteLine(hssfworkbook.GetSheetName(i));
}
file.Close();
This solution works for xls. I didn't try xlsx.
Thanks,
Esen
This worked for me. Stolen from here: How do you get the name of the first page of an excel workbook?
object opt = System.Reflection.Missing.Value;
Excel.Application app = new Microsoft.Office.Interop.Excel.Application();
Excel.Workbook workbook = app.Workbooks.Open(WorkBookToOpen,
opt, opt, opt, opt, opt, opt, opt,
opt, opt, opt, opt, opt, opt, opt);
Excel.Worksheet worksheet = workbook.Worksheets[1] as Microsoft.Office.Interop.Excel.Worksheet;
string firstSheetName = worksheet.Name;
Try this. Here is the code to get the sheet names in order.
private Dictionary<int, string> GetExcelSheetNames(string fileName)
{
Excel.Application _excel = null;
Excel.Workbook _workBook = null;
Dictionary<int, string> excelSheets = new Dictionary<int, string>();
try
{
object missing = Type.Missing;
object readOnly = true;
Excel.XlFileFormat.xlWorkbookNormal
_excel = new Excel.ApplicationClass();
_excel.Visible = false;
_workBook = _excel.Workbooks.Open(fileName, 0, readOnly, 5, missing,
missing, true, Excel.XlPlatform.xlWindows, "\\t", false, false, 0, true, true, missing);
if (_workBook != null)
{
int index = 0;
foreach (Excel.Worksheet sheet in _workBook.Sheets)
{
// Can get sheet names in order they are in workbook
excelSheets.Add(++index, sheet.Name);
}
}
}
catch (Exception e)
{
return null;
}
finally
{
if (_excel != null)
{
if (_workBook != null)
_workBook.Close(false, Type.Missing, Type.Missing);
_excel.Application.Quit();
}
_excel = null;
_workBook = null;
}
return excelSheets;
}
As per MSDN, In a case of spreadsheets inside of Excel it might not work because Excel files are not real databases. So you will be not able to get the sheets name in order of their visualization in workbook.
Code to get sheets name as per their visual appearance using interop:
Add reference to Microsoft Excel 12.0 Object Library.
Following code will give the sheets name in the actual order stored in workbook, not the sorted name.
Sample Code:
using Microsoft.Office.Interop.Excel;
string filename = "C:\\romil.xlsx";
object missing = System.Reflection.Missing.Value;
Microsoft.Office.Interop.Excel.Application excel = new Microsoft.Office.Interop.Excel.Application();
Microsoft.Office.Interop.Excel.Workbook wb =excel.Workbooks.Open(filename, missing, missing, missing, missing,missing, missing, missing, missing, missing, missing, missing, missing, missing, missing);
ArrayList sheetname = new ArrayList();
foreach (Microsoft.Office.Interop.Excel.Worksheet sheet in wb.Sheets)
{
sheetname.Add(sheet.Name);
}
I don't see any documentation that says the order in app.xml is guaranteed to be the order of the sheets. It PROBABLY is, but not according to the OOXML specification.
The workbook.xml file, on the other hand, includes the sheetId attribute, which does determine the sequence - from 1 to the number of sheets. This is according to the OOXML specification. workbook.xml is described as the place where the sequence of the sheets is kept.
So reading workbook.xml after it is extracted form the XLSX would be my recommendation. NOT app.xml. Instead of docProps/app.xml, use xl/workbook.xml and look at the element, as shown here -
`
<workbook xmlns="http://schemas.openxmlformats.org/spreadsheetml/2006/main" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships">
<fileVersion appName="xl" lastEdited="5" lowestEdited="5" rupBuild="9303" />
<workbookPr defaultThemeVersion="124226" />
- <bookViews>
<workbookView xWindow="120" yWindow="135" windowWidth="19035" windowHeight="8445" />
</bookViews>
- <sheets>
<sheet name="By song" sheetId="1" r:id="rId1" />
<sheet name="By actors" sheetId="2" r:id="rId2" />
<sheet name="By pit" sheetId="3" r:id="rId3" />
</sheets>
- <definedNames>
<definedName name="_xlnm._FilterDatabase" localSheetId="0" hidden="1">'By song'!$A$1:$O$59</definedName>
</definedNames>
<calcPr calcId="145621" />
</workbook>
`

EPPlus DataField with PercentOfTotal

I'm usingg EPPlus to create a pivot table in excel but I wish show data as percent of the total in one my DataFields, how can I do that?
public static void createTableMotivo(Worksheet ws, ExcelRangeBase range)
{
const string FORMATCURRENCY = "#,###;[Red](#,###)";
ExcelWorksheet worksheet = ws.EPPlusSheet;
//The pivot table
ExcelPivotTable pivotTable = worksheet.PivotTables.Add(worksheet.Cells["B12"], range, "pivot_table1");
//The label row field
pivotTable.RowFields.Add(pivotTable.Fields["FIELD1"]);
pivotTable.DataOnRows = false;
pivotTable.ShowCalcMember = true;
//The data fields
ExcelPivotTableDataField fieldSum = pivotTable.DataFields.Add(pivotTable.Fields["FIELD2"]);
fieldSum.Name = "Quantidade de Faturas";
fieldSum.Function = DataFieldFunctions.Sum;
fieldSum.Format = FORMATCURRENCY;
ExcelPivotTableDataField fieldPercent = pivotTable.DataFields.Add(pivotTable.Fields["FIELD2"]);
fieldPercent.Name = "%";
fieldPercent.Function = DataFieldFunctions.None;
fieldPercent.Format = "0.00%";
pivotTable.PageFields.Add(pivotTable.Fields["FIELD3"]);
pivotTable.PageFields.Add(pivotTable.Fields["FIELD4"]);
}
I am trying to do something similar. The only way I can get it this to work is by manipulating the xml of the Excel file.
This was interesting in itself - I can't remember where I saw that you can rename .xlsx to .zip and then just view all of the xml files inside that zip.
In my case, I first set "Show Values As" to "% of Grand Total" on the pivot table of the actual Excel file. Then after changing the file extention from .xlsx to .zip and extracting, there was a pivotTable3.xml file that had:
<dataFields count="2">
<dataField name="Number of Orders" fld="10" subtotal="count"/>
<dataField name="Percent of Total" fld="10" subtotal="count" showDataAs="percentOfTotal" numFmtId="10"/>
</dataFields>
The goal is to get showDataAs="percentOfTotal" in the dataField element whose name is "Percent of Total".
I tried to use an xpath expression to get the dataField element, but it returns null:
pivotTable.PivotTableXml.SelectSingleNode("//dataField[name='Percent of Total']")
So I had to fall back to walking down the xml:
pivotTable.DataFields[1].Format = "#0.00%";
pivotTable.DataFields[1].Function = DataFieldFunctions.Count;
pivotTable.DataFields[1].Name = "Percent of Total";
foreach (XmlElement documentElementChild in pivotTable.PivotTableXml.DocumentElement.ChildNodes)
{
if (documentElementChild.Name.Equals("dataFields"))
{
foreach (XmlElement dataFieldChild in documentElementChild.ChildNodes)
{
foreach (XmlAttribute attribute in dataFieldChild.Attributes)
{
if (attribute.Value.Equals("Percent of Total"))
{
// found our dataField element; add the attribute
dataFieldChild.SetAttribute("showDataAs", "percentOfTotal");
break;
}
}
}
}
}

Node.js append a row to xlsx file

I'm just trying to figure out how to append a single row to an xlsx file. For example, append array = [1 2 3 4 5] to the first empty row using columns 1,2,3,4,5. Ideally I'd start with an empty .xlsx file, and repeatedly rerun this program, which appends a new row to the file each time it is ran.
I'm attempting to use exceljs, but any test writes I try to do to a file say corrupted when I attempt to open them.
edited code (still not working):
var Excel = require('exceljs');
var workbook = new Excel.Workbook();
var sheet = workbook.addWorksheet('rssi');
file = 'testfile.xlsx'
var array = [1,2,3,4,5]
sheet.addRow(array)
workbook.xlsx.writeFile(file)
.then(function() {
console.log('Array added and file saved.')
});
Output is zero bytes and cannot be opened by Microsoft Excel. Says, "The file format or file extension is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file."
Basically, you was trying to add the row in method which was called after file write. Try this example:
var workbook = new Excel.Workbook();
file = 'testfile.xlsx'
var array = [1,2,3,4,5]
var sheet = workbook.addWorksheet('rssi');
sheet.addRow(array)
workbook.xlsx.writeFile(file)
.then(function() {
console.log('Array added and then file saved.')
});
But it add only one row at a time
var spread_sheet = require('spread_sheet');
var row = "1,2,Jack,Pirate";
var filePath = '/home/Pranjal/Desktop/test.xlsx';
var sheetName = "Sheet1";
spread_sheet.addRow(row,filePath,sheetName,function(err,result){
console.log(err,result)
})
Add row to spreadsheet:-
I also stuck with the same functionality issue, so I used 'spread_sheet' module.
It worked for me

Input/Export data through MS Excel into OATS Scripts

When trying to get the Input the data from the Excel Sheet while working with OATS tool, it always gets into the catch block of the function. The below is the script written. Please help us resolve this issue.
public String getInputfromExcel(int argColumnNumber,int argRowNumber)throws Exception
{
String inputExcelName = dataPath+".xlsx";
String cellContent = "12";
try
{
Workbook workbook = Workbook.getWorkbook(new File(inputExcelName));
Sheet sheet = workbook.getSheet(0);
Cell a1 = sheet.getCell(argColumnNumber, argRowNumber);
cellContent = (a1.getContents()).toString();
System.out.println(cellContent.toString());
workbook.close();
}
catch (Exception e)
{
addReport("Getting Input From Excel", "Fail","Exception while reading value from excel sheet");
}
return cellContent;
}
Axel has brought up the point. On a further note, if I remember correctly, the function sheet.getCell(arg1, arg2) has first argument as rowNumber and 2nd as columnNumber (both the values are 0 based index).
Its old quetion....but just posting answer it might be helpful for someone needy.
In Oracle Application Testing Suite. NO NEED of external JARs to read/write data.
You can enable DataTable module in the tool
Complete explanation given here, http://www.testinghive.com/how-to-read-write-excel-in-oats/
//Define Sheet name to be read, and provide comma seperated to read multiple sheets
String sheetName = "Sheet1";
//Mention excel sheet path
String strFile= "C:\\Demo\\test.xls";
//Defined array list to add Sheets to read
List sheetList = new ArrayList();
sheetList.add(sheetName);
// Iports Sheet1
datatable.importSheets(strFile, sheetList, true, true);
//get rowcount
info("Total rows :"+datatable.getRowCount());
int rowcount=datatable.getRowCount();
//Loop to read all rows
for (int i=0;i<rowcount;i++)
{
//Set current row fromw here you need to start reading, in this case start from first row
datatable.setCurrentRow(sheetName, i);
String strCompany=(String) datatable.getValue(sheetName,i,"Company");
String strEmpFName=(String) datatable.getValue(sheetName,i,"FirstName");
String strEmpLName=(String) datatable.getValue(sheetName,i,"LastName");
String strEmpID=(String) datatable.getValue(sheetName,i,"EmpID");
String strLocation=(String) datatable.getValue(sheetName,i,"Location");
//prints first name and last name
System.out.println("First Name : "+strEmpFName+", Last Name : "+strEmpLName);
//Sets ACTIVE column in excel sheet to Y
String strActive="Y";
datatable.setValue(sheetName, i, datatable.getColumn(sheetName, datatable.getColumnIndex("Active")), strActive);
}
//Updates sheet with updated values ie ACTIVE column sets to Y
datatable.exportToExcel("C:\\Demo\\test1.xlsx");

Resources