I have a text as 00:02:02:22 where the syntax is hh:mm:ss:ff (hours:minutes:seconds:frames)
I have tried changing the format to time so that I can calculate the difference between two values but I keep getting #VALUE.
I would like the answer in decimal places as 2.43 seconds...
The decimal value is frames which divided by 24. So e.g.
So the difference between 00:02:02:22 and 00:02:05:18 would be 2.83 seconds
There are a number of frame codes:
Film (24 frames per second)
PAL (25 fps)
NTSC (29.97 fps)
NTSC Drop-Frame
Digital Video (30 fps)
50 fps
60 fps
Assuming yours is the first.
With data in A1 like:
11:11:11:10
In another cell enter:
=LEFT(A1,2)/24+MID(A1,4,2)/(24*60)+MID(A1,7,2)/(24*60*60)+RIGHT(A1,2)/(24*60*60*24)
and format this cell as:
[ss].00
Once the values are converted to true times, values can be subtracted and the differences formatted as you like.
Related
I am trying to find duration for time where wave height is under 3m and time period is between 5:00am and 6:00pm. Trying to find this duration for a month of tidal data.
I have raw data for wave height and timestamps when it is high and low.
eg.
Timestamp Wave_Height
1/01/2022 3:16 0.68
1/01/2022 9:37 6.62
1/01/2022 16:14 1.07
1/01/2022 21:54 5.37
2/01/2022 4:06 0.59
etc…
So far I have got linear interpolation to find points where wave height=3. I am struggling to get a function to find the durations for my limits on time.
Included a picture to explain
Graph of wave data over time
The timestamps occur over different days in the month so difference between times must consider the changed dates in some cases(see rev 2 errors ####### where errors occur for changing of dates)
rev 2 error
The following should work. I have added some columns to avoid complicated formulas.
interpolate when the wave_height = 3 (column G)
add column H which is True when wave_height increases and False if it decreases (at the time in column G):
so cell H6 = F7<3 gives TRUE
add column E to limit the time window to 5:00-18:00.
E7 is =IF(D7<$G$2;$G$2;IF(D7>$H$2;$H$2;D7))
Added column I to calculate the time during wich wave_height < 3. The sum of that column is what you need.
I8 is =H8*(G8-E7)+NOT(H8)*(D8-G8)
I need to check if a time of collection is within allowed time window or not.
For e.g.
A B C
1 10.36 10.30 1 min out of +/- 5 minutes window
2 10.24 10.30 1 min out of +/- 5 minutes window
A1 here time of collection of data, and B1 is the scheduled time. The acceptable window or range for this is +/- 5 minutes out of window. In this case the time of collection is 1 min out of +/- 5 minutes window. Similar example is shown in row 2. How can i get C1 to show the message as above which can account for + 5 minutes and - 5 minutes scenarios?.
Thanks in advance.
=IF(ABS(A1-B1)>(5/1440),"Problem!","OK")
5/1440 is 5 minutes (1440 minutes in a full day)
Use this formula¹ in C1 and fill down as necessary,
=ROUND(MAX((ABS(A1-B1)-0.05)*100, 0), 0)
Use the following custom number format on column C,
0 \mi\n out of ± 5 \mi\nut\e wi\n\dow
The advantages of a custom number format is that the numbers remain numbers and are available for future calculations (e.g. SUM, AVERAGE, etc) while displaying the text you wish to show. Note the right-alignment in the cells indicating true numbers.
¹ This formula depends on the time values being mixed numbers and not true time. If the time values are true time with a non-EN-US number format then additional maths may have to be applied to the formula.
I have a list of times in a column [Logtime]:
11:45:44PM
07:05:05PM
I'd like to create a measure that returns the total number of hours after 6:30PM. So given the above times:
5.5
0.58
HoursAfter:=[logtime] -6:30PM doesn't work.
Hour[logtime] - hour(18.5) also doesn't work
EDIT:
timevalue([logtime]) - timevalue("05:00:00") works but it returns a datetime ala
12/30/1899 5:17:16PM
I need to convert the time 5:17:16 into decimal hours i.e. 5.26, how can I do this?
There may be a slightly more elegant way, but I was able to create a calculated column that does what you want as follows,
HoursAfter = DATEDIFF(TIMEVALUE("6:30 PM"), Times[LogTime], SECOND) / 3600
This takes the time difference between 6:30 PM and your LogTime in units of seconds and then converts it to hours by dividing by 60*60 = 3600.
Edit: A simpler formula can be written as follows,
HoursAfter = 24 * (Times[LogTime] - TIMEVALUE("6:30 PM"))
(Multiply by 24 since the datetime values are stored in units of days.)
timevalue([logtime]) - timevalue("05:00:00")
I got wind speed data in excel table like this:
(wind speed) (wind direction)
Year|month|day|00:00|06:00|12:00|18:00||00:00|06:00|12:00|18:00||X|
1966|01|01|5|12|6|8||60|360|270|50||X|
goal is to get in each day wind directin at wich was the max wind speed, for example: in firs jan. 1966 the max wind speed was 12 m/s at 06:00 and directon at the same time was 360. I need that 360 in next (X) column. If there is equal max wind speed in several observaton times then is no mater which of those directions put in at next column.
Is it poseble do it in MS excel? If someone can help me it would be so great!
Assuming the wind speed columns are D-G and the directions H-K then put the following formula in your column where the 'X' is (for row 2; copy it down the other rows)
=LOOKUP(MAX(D2:G2);D2:G2;H2:K2)
I have a certain value of time(10:00:00:00) and I have 1000 samples in excel for one minuit till
(10:00:01:00) which means every time interval to every sample is 0.06 second.
How could add 0.06 second to 10:00:00:00 incrementally till reach to 10:00:01:00 in excel
10:00:00:00 AM
10:00:00:06
10:00:00:12
10:00:00:18
:
:
10:00:59:54
10:00:01:00
hint: I need the formula of time in milliseconds due to big data samples for 24 hours and every hour has 1000 samples which means 24000 samples.
Say that:
Cell A1 contains start time: 10:00:00.00 AM
Cell Z1 contains constant: 00:00.06
Cell A2 will be: =A1+$Z$1
Then you can drag down A2...