I have a certain value of time(10:00:00:00) and I have 1000 samples in excel for one minuit till
(10:00:01:00) which means every time interval to every sample is 0.06 second.
How could add 0.06 second to 10:00:00:00 incrementally till reach to 10:00:01:00 in excel
10:00:00:00 AM
10:00:00:06
10:00:00:12
10:00:00:18
:
:
10:00:59:54
10:00:01:00
hint: I need the formula of time in milliseconds due to big data samples for 24 hours and every hour has 1000 samples which means 24000 samples.
Say that:
Cell A1 contains start time: 10:00:00.00 AM
Cell Z1 contains constant: 00:00.06
Cell A2 will be: =A1+$Z$1
Then you can drag down A2...
Related
I want to convert numbers (that represent seconds) into HH:MM:SS format (like shown in pic..) but don't want to split them.. I want to format it using some formula or
If you just want to display the 715 seconds as hours:minutes:seconds, you will need a helper column that you use just for display.
You can create it either as in your example screenshot, or using a formula:
=TEXT(B2/86400,"[hh]:mm:ss")
Note the brackets around hh. That keeps the hours from rolling over every 24 and displays total hours correctly for instances where seconds > 86,400.
There's no way I know of to have 715 displayed as the associated hours:minutes:seconds in the same cell.
You can use a formula like this to convert 715 to HH:MM:SS:
=TEXT(FLOOR((A1-FLOOR(A1/86400,1)*86400)/3600, 1), "00:") & text(floor((A1 - floor(A1/3600,1)*3600)/60, 1),"00:") & text(A1 - floor(A1/3600,1)*3600 - floor((A1 - floor(A1/3600,1)*3600)/60, 1)*60,"00")
Let's break it down.
Get hours
A1 is seconds
There are 86400 seconds in a day
FLOOR(A1/86400, 1) gives us the floor of days
Multiply that by 86400 will give us seconds in those days FLOOR(A1/86400,1)*86400
Remove those many seconds from A1 and you get seconds remaining in the fraction of the last day A1- FLOOR(A1/86400,1)*86400
Divide those remaining seconds with 3600 to get hours FLOOR((A1- FLOOR(A1/86400,1)*86400 )/3600, 1)
Use TEXT function to format it to 2 digits and a colon at the end TEXT(FLOOR((A1- FLOOR(A1/86400,1)*86400 )/3600, 1), "00:")
Then, find remaining minutes and format it.
Then, take remaining seconds and format it.
Alternate method
Assume that your seconds are in column A6.
In B6, we will put Whole Days =FLOOR(A6/86400, 1)
In C6, we will put remaining seconds =A6-B6*86400
In D6, we will put Whole Hours =FLOOR(C6/3600,1)
In E6, we will put remaining seconds =C6-D6*3600
In F6, we will put Whole Minutes =FLOOR(E6/60, 1)
In G6, we will put remaining seconds =E6-F6*60
In H6, we'll format Hours, Minutes and Seconds =TEXT(D6,"00:") & TEXT(F6,"00:") & TEXT(G6,"00")
I need to check if a time of collection is within allowed time window or not.
For e.g.
A B C
1 10.36 10.30 1 min out of +/- 5 minutes window
2 10.24 10.30 1 min out of +/- 5 minutes window
A1 here time of collection of data, and B1 is the scheduled time. The acceptable window or range for this is +/- 5 minutes out of window. In this case the time of collection is 1 min out of +/- 5 minutes window. Similar example is shown in row 2. How can i get C1 to show the message as above which can account for + 5 minutes and - 5 minutes scenarios?.
Thanks in advance.
=IF(ABS(A1-B1)>(5/1440),"Problem!","OK")
5/1440 is 5 minutes (1440 minutes in a full day)
Use this formula¹ in C1 and fill down as necessary,
=ROUND(MAX((ABS(A1-B1)-0.05)*100, 0), 0)
Use the following custom number format on column C,
0 \mi\n out of ± 5 \mi\nut\e wi\n\dow
The advantages of a custom number format is that the numbers remain numbers and are available for future calculations (e.g. SUM, AVERAGE, etc) while displaying the text you wish to show. Note the right-alignment in the cells indicating true numbers.
¹ This formula depends on the time values being mixed numbers and not true time. If the time values are true time with a non-EN-US number format then additional maths may have to be applied to the formula.
I have an excel sheet with times in one column and temperatures in another. I'm trying to work out a formula that will find a certain temperature and measure how long it remained at that temperature.
11:25:29 AM 69.3°C
11:26:29 AM 69.6°C
11:27:29 AM 69.8°C
11:28:29 AM 70.0°C
11:29:29 AM 70.2°C
11:35:29 AM 70.8°C
11:36:29 AM 70.3°C
11:37:29 AM 69.5°C
11:38:29 AM 68.5°C
11:39:29 AM 67.5°C
12:39:29 PM 66.3°C
1:39:29 PM 52.1°C
2:39:29 PM 12.1°C
3:39:29 PM 5.0°C
In this example, I would like to find when it hit 70.0°C and how long it stayed above 70.0°C.
This is a bit of a tough problem because you might have multiple occasions where you go above 70 degrees. In that case, do you want the total time spent above 70 in the entire dataset, or do you want the total time spent above 70 consecutively? And then, how are you determining which of these potential multiple nonconsecutive periods you are talking about?
That said, you can try this. If column A is your datetime, and column B is your temp reading, specify another cell as your temperature reference value ($D$1 here), and in column C starting in row 2 do this:
=(A2-A1)*IF(B2>=$D$1,1,0)
and then copy that all the way down. What that does is it calculates the time difference between measurements and then if the temperature at that time is greater than your reference, it multiplies it by 1, otherwise it multiplies by 0. Because a date/time in Excel is really just a number, what you get is an interval of a day between measurements in each cell of column C. In other words, .25 = 6 hours.
Now that you have that data in column C, you are free to further parse it. You can use a simple SUM(C:C) formula in a cell, or you can go back and sum up individual ranges. I hope this helps.
I have tried every which way to format cells to subtract the result from time for instance the formula in the cell = 11(this is 11 minutes) I want to take that result minus 8:00:00 to give me 7:49:00 but it doesn't work the result is ####### no matter how big I make the cell. And if I format the cells with the formula to custom [m]:ss then the value changes.
Sample of the Worksheet:
I want Y2 = X3-W3 in a time format.
So, if A1=11
Then in some other cell, (B1 in this example): =TIME(,A1,)
Then subtract from the cell with 8:00:00. (If it's C1...:)
=C1-B1
That will give you the time you want.
Info: The main thing is that you have to tell Excel that your cell with the "11" in it, is minutes. By using the =TIME(,A1,) you will get the value of: 12:11 am. (If you keep it in Date format.) 12:11 am could also be viewed as: 0 Hours, 11 minutes, 0 seconds. And now that it knows, you should be able to subtract.
Try this:
=TIME(HOUR(X3),MINUTE(X3)-W3,SECOND(X3))
The ######### is because you have a negative time. Becuase Excel reads time as decimals of 24 hours, 8:00:00 is .3333 and if you subtract 11 from that you get -10.6666 and date/time can not be negative.
a) So I have a huge folder of .csv data with a column about time duration where the cells are 'x min y sec' (e.g. 15 min 29 sec) or 'x hrs y min z sec' (e.g. 1 hrs 48 min 28 sec). The cells are formatted by text.
I want to batch change them to the number of seconds, but I have no idea where to start. I can't get the data in another format.
I thought about somehow using 'hrs', 'min' or 'sec' as delimiters, but I don't know how to move from there. I also thought about using ' ' as delimiters, but then the first column is filled with either hours or minutes depending on the time duration.
I also thought about using PostgreSQL's SELECT EXTRACT(EPOCH FROM INTERVAL '5 days 3 hours'), but I haven't been able to work out how to use this on a column from a table.
b) Is there a better way to change this time format 'Fri Mar 14 11:29:27 EST 2014' to epoch time? Right now I'm thinking of using macros in Excel to get rid of 'Fri' and 'EST', then put the columns back together, then use the to_timestamp function in PostgreSQL.
In Excel if you have data in only those 2 formats and starting from A2 you can use this formula in B2 copied down to get the number of seconds:
=IFERROR(LEFT(A2,FIND("hrs",A2)-1)*3600,0)+SUM(MID(0&A2,FIND({"min","sec"},0&A2)-3,2)*{60,1})
It finds the relevant text then gets the number in front for each and multiplies by the relevant number to get seconds
You can do:
SELECT EXTRACT(EPOCH FROM column_name::interval)
FROM my_table;
The interval can use the regular time units (like hour), abbreviations thereof (hr) and plurals (hours). I am not sure about a combination of plural and abbreviation (hrs) though. If that does not work, UPDATE the column and replace() the sub-string "hrs" to "hours".
If you want to save the number of seconds in your table, then you convert the above statement into an UPDATE statement:
UPDATE my_table SET seconds_column = extract(epoch FROM column_name::interval);
I would split with space as the delimiter, then examine the second column. If it contains the string "hrs", then your seconds answer is:
3600 * column 1 + 60 * column 3 + column 5
Otherwise it is:
60 * column 1 + column 3