I'm trying to run a bash script 10 minutes after my system startup and on every reboot. I was planning to the #reboot of crontab, but I'm not sure of two things
Whether it will run on the first system start or only on reboot.
How to delay the run by 10 minutes after the reboot.
What expression would suit my situation the best? Please note that I can't run 'at' or system timer to accomplish this as both are not accessible to us. I'm working on the RHEL 7..
I would just sleep 600 at the beginning of your reboot script. Sure, there's probably a more "expert" way of doing it, but it'll work.
I think your question may be more appropriate on the Unix and Linux stack exchange, because I found two answers over there which directly address your question:
https://unix.stackexchange.com/questions/57852/crontab-job-start-1-min-after-reboot
Basically you can always just add sleep 600 to the beginning of your cronjob invocation.
As to whether you should be running a cronjob vs an init script:
https://unix.stackexchange.com/questions/188042/running-a-script-during-booting-startup-init-d-vs-cron-reboot
There are a handful of subtle differences, but basically, your cron #reboot will run each time the system starts and may be more easy to manage as a non-root user.
rc-local.service would be better for your needs on a EL7 system.
systemctl status rc-local.service
● rc-local.service - /etc/rc.d/rc.local Compatibility
Loaded: loaded (/usr/lib/systemd/system/rc-local.service; static; vendor preset: disabled)
Active: inactive (dead)
You need to put your script that can run with any amount of delay inside the file, /etc/rc.d/rc.local, e.g.,
sleep 600 && /usr/local/bin/myscript.sh
OR you can put delay inside the script.
# Give exe permission to the local script as well as `rc.local`
chmod a+x /usr/local/bin/myscript.sh
chmod a+x /etc/rc.d/rc.local
# Enable the service. Note the service name has a `-` compared `.` in the file.
systemctl enable rc-local.service
Related
I have a discord bot running on a raspberry pi that i need to restart every day, I'm trying to do this through crontab but with no luck.
It manages to kill the active screen processes but never starts an instance, not that I can see with "screen -ls" and I can tell that it doesn't create one that I can't see as the bot itself does not come online.
Here is the script:
#!/bin/bash
sudo pkill screen
sleep 2
screen -dmS discordBot
sleep 2
screen -S "discordBot" -X stuff "node discordBot/NEWNEWNEWN\n"
Here is also the crontab:
0 0 * * * /bin/bash /home/admin/discordBot/script.sh
Is it possible to have crontab run a screen session? And if so how?
Previously I tried putting the screen command stright into cron but now I have it in a bash script instead.
If I run the script in the terminal it works perfectly, it’s just cron where it fails. Also replacing "screen" with the full path "/usr/bin/screen" does not change anything.
So the best way of doing it, without investigating the underlying problem would be to create a systemd service and putting a restart command into cron.
/etc/systemd/system/mydiscordbot.service:
[Unit]
Description=A very simple discord bot
[Service]
Type=simple
ExecStart=node /path/to/my/discordBot.js
[Install]
WantedBy=multi-user.target
Now you can run your bot with systemctl start mydiscordbot and can view your logs with journalctl --follow -u mydiscord bot
Now you only need to put
45 2 * * * systemctl restart discordbot
into root's crontab and you should be good to go.
You probably should also write the logs into a logfile, maybe /var/log/mydiscordbot.log, but how and if you do that is up to you.
OLD/WRONG ANSWER:
cron is run with a minimal environment, and depending on your os, /usr/bin/ is probably not in the $PATH var. screen is mostlikely located at /usr/bin/screen, so cron can't run it because it can't find the screen binary. try replacing screen in your script with /usr/bin/screen
But the other question here is: Why does your discord bot need to be restarted every day. I run multiple bots with 100k+ users, and they don't need to be restarted at all. Maybe you should open a new question with the error and some code snippets.
I don't know what os your rpi is running, but I had a similar issue earlier today trying to get vms on a server to launch a terminal and run a python script with crontab. I found a very easily solution to automatically restart it on crashes, and to run something simply in the background. Don't rely on crontab or an init service. If your rpi as an x server running, or anything that can be launched on session start, there is a simple shell solution. Make a bash script like
while :; do
/my/script/to/keep/running/here -foo -bar -baz >> /var/log/myscriptlog 2>&1
done
and then you would start it on .xprofile or some similar startup operation like
/path/to/launcher.sh &
to have it run the background. It will restart automatically everytime it closes if started in something like .xprofile, .xinitrc, or anything ran at startup.
Then maybe make a cronjob to restart the raspberry pi or whatever system is running the script but this script wil restart the service whenever it's closed anyway. Maybe you can put that cronjob on a script but I don't think it would launch the GUI.
Some other things you can do to launch a GUI terminal in my research with cronjob that you can try, though they didn't work for my situation on these custom linux vms, and that I read was a security risk to do this from a cronjob, is you can specify the display.
* * * * * DISPLAY=:0 /your/gui/stuff/here
but you would would need to make sure the user has the right permissions and it's considered an unsafe hack to even do this as far as I have read.
for my issue, I had to launch a terminal that stayed open, and then changed to the directory of a python script and ran the script, so that the local files in directory would be called in the python script. here is a rough example of the "launcher.sh" I called from the startup method this strange linux distro used lol.
#!/bin/sh
while :; do
/usr/bin/urxvt -e /bin/bash -c "cd /path/to/project && python loader.py"
done
Also check this source for process management
https://mywiki.wooledge.org/ProcessManagement
I'm running Arch-based Manjaro Linux and wrote myself a little update program, that starts every 7 hours and runs completely in the background. This update program is started by systemd.
What I wanna know is: How can I prevent any system shutdown/reboot during the time this program runs no matter if the user just wants to turn it off or any program wants to do so.
The best would be, if any shutdown/reboot action wouldn't be cancelled but delayed instead, so when the update program has finished its run, the shutdown/reboot continues.
My systemd parts are:
uupgrades.timer
[Unit]
Description=UU Upgrades Timer
[Timer]
OnBootSec=23min
OnUnitActiveSec=7h
Unit=uupgrades.target
[Install]
WantedBy=basic.target
uupgrades.target
[Unit]
Description=UU Upgrades Timer Target
StopWhenUnneeded=yes
and in the folder uupgrades.target.wants
uupgrades.service
[Unit]
Description=UU Update Program
[Service]
Nice=19
IOSchedulingClass=2
IOSchedulingPriority=7
ExecStart=/usr/bin/uupgrades
How can I achieve this?
If a user with sufficient permissions to reboot the server or manipulate processes wants to stop or reboot the machine you cant stop them. That's just how linux works. You should set up permissions and accounts such that no other users have root permissions or permissions sufficient to manipulate the process or user that the process is running as.
When I want to block myself from rebooting or shutdown, I alias my usual shutdown and reboot aliases to beep;beep;beep;.
In multiuser environments you could move the reboot, shutdown etc. binaries and move them back, when shutdown should be allowed again.
You could also temporarily move an executable shell script outputting information about the postponed shutdown possibility in place of the corresponding binaries. This script could set a flag, if a shutdown was requested.
Q&D example script:
#!/usr/bin/env bash
echo "preventing reboot"
BACKUPBINARY_REBOOT=$(mktemp);
mv /bin/reboot $BACKUPBINARY_REBOOT;
FLAGFILE=$(mktemp);
echo '#!/usr/bin/env bash' > /bin/reboot;
echo '# original reboot binary was moved to'"$BACKUPBINARY_REBOOT" >> /bin/reboot;
echo 'echo request-reboot > '"$FLAGFILE" >> /bin/reboot;
echo 'echo reboot is prevented, your request will trigger later' >> /bin/reboot;
chmod 666 "$FLAGFILE";
chmod +x /bin/reboot;
echo "postponed reboot - press enter to allow it again and make up for requested reboot";
read;
mv "$BACKUPBINARY_REBOOT" /bin/reboot;
if grep -q request-reboot "$FLAGFILE"; then
rm $FLAGFILE;
/bin/reboot;
fi
You can add another systemd service at /usr/lib/systemd/system-shutdown/ which will be run at shutdown, and have it check if your update script is running, and if so, cancel or delay the shutdown.
I have set a specific cronjob (crontab -e), but it doesn't works like I thought. I don't get what's wrong.
Here is what I do (root cron):
#reboot /path/to/my_script.sh start
25 18 * * * halt
The first line as expected is running my_script.sh, but when time comes for the server to shutdown, nothing happen. Is the #reboot option made to work alone?
There is no option in cron to run at shutdown. #reboot is meant to run the script on start
If you want to run a script at shutdown, you need to write an initd script and register it for the shutdown run level. The standard runlevel for halt is 0, the run level for restart is 6. I've verified this for Debian, Gentoo and Redhat systems but it seems to be true across *NIX systems. Check this for more info.
I have a node.js script which need to start at boot and run under the www-data user. During development I always started the script with:
su www-data -c 'node /var/www/php-jobs/manager.js
I saw exactly what happened, the manager.js works now great. Searching SO I found I had to place this in my /etc/rc.local. Also, I learned to point the output to a log file and to append the 2>&1 to "redirect stderr to stdout" and it should be a daemon so the last character is a &.
Finally, my /etc/rc.local looks like this:
#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.
su www-data -c 'node /var/www/php-jobs/manager.js >> /var/log/php-jobs.log 2>&1 &'
exit 0
If I run this myself (sudo /etc/rc.local): yes, it works! However, if I perform a reboot no node process is running, the /var/log/php-jobs.log does not exist and thus, the manager.js does not work. What is happening?
In this example of a rc.local script I use io redirection at the very first line of execution to my own log file:
#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.
exec 1>/tmp/rc.local.log 2>&1 # send stdout and stderr from rc.local to a log file
set -x # tell sh to display commands before execution
/opt/stuff/somefancy.error.script.sh
exit 0
On some linux's (Centos & RH, e.g.), /etc/rc.local is initially just a symbolic link to /etc/rc.d/rc.local. On those systems, if the symbolic link is broken, and /etc/rc.local is a separate file, then changes to /etc/rc.local won't get seen at bootup -- the boot process will run the version in /etc/rc.d. (They'll work if one runs /etc/rc.local manually, but won't be run at bootup.)
Sounds like on dimadima's system, they are separate files, but /etc/rc.d/rc.local calls /etc/rc.local
The symbolic link from /etc/rc.local to the 'real' one in /etc/rc.d can get lost if one moves rc.local to a backup directory and copies it back or creates it from scratch, not realizing the original one in /etc was just a symbolic link.
I ended up with upstart, which works fine.
In Ubuntu I noticed there are 2 files. The real one is /etc/init.d/rc.local; it seems the other /etc/rc.local is bogus?
Once I modified the correct one (/etc/init.d/rc.local) it did execute just as expected.
You might also have made it work by specifying the full path to node. Furthermore, when you want to run a shell command as a daemon you should close stdin by adding 1<&- before the &.
I had the same problem (on CentOS 7) and I fixed it by giving execute permissions to /etc/local:
chmod +x /etc/rc.local
if you are using linux on cloud, then usually you don't have chance to touch the real hardware using your hands. so you don't see the configuration interface when booting for the first time, and of course cannot configure it. As a result, the firstboot service will always be in the way to rc.local. The solution is to disable firstboot by doing:
sudo chkconfig firstboot off
if you are not sure why your rc.local does not run, you can always check from /etc/rc.d/rc file because this file will always run and call other subsystems (e.g. rc.local).
I got my script to work by editing /etc/rc.local then issuing the following 3 commands.
sudo mv /filename /etc/init.d/
sudo chmod +x /etc/init.d/filename
sudo update-rc.d filename defaults
Now the script works at boot.
I am using CentOS 7.
$ cd /etc/profile.d
$ vim yourstuffs.sh
Type the following into the yourstuffs.sh script.
type whatever you want here to execute
export LD_LIBRARY_PATH=/usr/local/cuda-7.0/lib64:$LD_LIBRARY_PATH
Save and reboot the OS.
I have used rc.local in the past. But I have learned from my experience that the most reliable way to run your script at the system boot time is is to use #reboot command in crontab. For example:
#reboot path_to_the_start_up_script.sh
This is most probably caused by a missing or incomplete PATH environment variable.
If you provide full absolute paths to your executables (su and node) it will work.
It is my understanding that if you place your script in a certain RUN Level, you should use ln -s to link the script to the level you want it to work in.
first make the script executable using
sudo chmod 755 /path/of/the/file.sh
now add the script in the rc.local
sh /path/of/the/file.sh
before exit 0
in the rc.local,
next make the rc.local to executable with
sudo chmod 755 /etc/rc.local
next to initialize the rc.local use
sudo /etc/init.d/rc.local start
this will initiate the rc.local
now reboot the system.
Done..
I found that because I was using a network-oriented command in my rc.local, sometimes it would fail. I fixed this by putting sleep 3 at the top of my script. I don't know why but it seems when the script is run the network interfaces aren't properly configured or something, and this just allows some time for the DHCP server or something. I don't fully understand but I suppose you could give it a try.
I had exactly same issue, the script was running fine locally but when I reboot/power-on it was not.
I resolved the issue by changing the file path. Basically need to give the complete path in the script. While running locally, file can be accessed but when running on reboot, local path will not be understood.
1 Do not recommend using root to run the apps such as node app.
Well you can do it but may catch more exceptions.
2 The rc.local normally runs as root user.
So if the your script should runs as another user such as www U should make sure the PATH and other environment is ok.
3 I find a easy way to run a service as a user:
sudo -u www -i /the/path/of/your/script
Please prefer the sudo manual~
-i [command]
The -i (simulate initial login) option runs the shell specified by the password database entry of the target user as a loginshell...
rc.local only runs on startup. If you reboot and want the script to execute, it needs to go into the rc.0 file starting with the K99 prefix.
I'm trying to ensure a script remains running on a development server. It collates stats and provides a web service so it's supposed to persist, yet a few times a day, it dies off for unknown reasons. When we notice we just launch it again, but it's a pain in the rear and some users don't have permission (or the knowhow) to launch it up.
The programmer in me wants to spend a few hours getting to the bottom of the problem but the busy person in me thinks there must be an easy way to detect if an app is not running, and launch it again.
I know I could cron-script ps through grep:
ps -A | grep appname
But again, that's another hour of my life wasted on doing something that must already exist... Is there not a pre-made app that I can pass an executable (optionally with arguments) and that will keep a process running indefinitely?
In case it makes any difference, it's Ubuntu.
I have used a simple script with cron to make sure that the program is running. If it is not, then it will start it up. This may not be the perfect solution you are looking for, but it is simple and works rather well.
#!/bin/bash
#make-run.sh
#make sure a process is always running.
export DISPLAY=:0 #needed if you are running a simple gui app.
process=YourProcessName
makerun="/usr/bin/program"
if ps ax | grep -v grep | grep $process > /dev/null
then
exit
else
$makerun &
fi
exit
Then add a cron job every minute, or every 5 minutes.
Monit is perfect for this :)
You can write simple config files which tell monit to watch e.g. a TCP port, a PID file etc
monit will run a command you specify when the process it is monitoring is unavailable/using too much memory/is pegging the CPU for too long/etc. It will also pop out an email alert telling you what happened and whether it could do anything about it.
We use it to keep a load of our websites running while giving us early warning when something's going wrong.
-- Your faithful employee, Monit
Notice: Upstart is in maintenance mode and was abandoned by Ubuntu which uses systemd. One should check the systemd' manual for details how to write service definition.
Since you're using Ubuntu, you may be interested in Upstart, which has replaced the traditional sysV init. One key feature is that it can restart a service if it dies unexpectedly. Fedora has moved to upstart, and Debian is in experimental, so it may be worth looking into.
This may be overkill for this situation though, as a cron script will take 2 minutes to implement.
#!/bin/bash
if [[ ! `pidof -s yourapp` ]]; then
invoke-rc.d yourapp start
fi
If you are using a systemd-based distro such as Fedora and recent Ubuntu releases, you can use systemd's "Restart" capability for services. It can be setup as a system service or as a user service if it needs to be managed by, and run as, a particular user, which is more likely the case in OP's particular situation.
The Restart option takes one of no, on-success, on-failure, on-abnormal, on-watchdog, on-abort, or always.
To run it as a user, simply place a file like the following into ~/.config/systemd/user/something.service:
[Unit]
Description=Something
[Service]
ExecStart=/path/to/something
Restart=on-failure
[Install]
WantedBy=graphical.target
then:
systemctl --user daemon-reload
systemctl --user [status|start|stop|restart] something
No root privilege / modification of system files needed, no cron jobs needed, nothing to install, flexible as hell (see all the related service options in the documentation).
See also https://wiki.archlinux.org/index.php/Systemd/User for more information about using the per-user systemd instance.
I have used from cron "killall -0 programname || /etc/init.d/programname start". kill will error if the process doesn't exist. If it does exist, it'll deliver a null signal to the process (which the kernel will ignore and not bother passing on.)
This idiom is simple to remember (IMHO). Generally I use this while I'm still trying to discover why the service itself is failing. IMHO a program shouldn't just disappear unexpectedly :)
Put your run in a loop- so when it exits, it runs again... while(true){ run my app.. }
I couldn't get Chris Wendt solution to work for some reason, and it was hard to debug. This one is pretty much the same but easier to debug, excludes bash from the pattern matching. To debug just run: bash ./root/makerun-mysql.sh. In the following example with mysql-server just replace the value of the variables for process and makerun for your process.
Create a BASH-script like this (nano /root/makerun-mysql.sh):
#!/bin/bash
process="mysql"
makerun="/etc/init.d/mysql restart"
if ps ax | grep -v grep | grep -v bash | grep --quiet $process
then
printf "Process '%s' is running.\n" "$process"
exit
else
printf "Starting process '%s' with command '%s'.\n" "$process" "$makerun"
$makerun
fi
exit
Make sure it's executable by adding proper file permissions (i.e. chmod 700 /root/makerun-mysql.sh)
Then add this to your crontab (crontab -e):
# Keep processes running every 5 minutes
*/5 * * * * bash /root/makerun-mysql.sh
The supervise tool from daemontools would be my preference - but then everything Dan J Bernstein writes is my preference :)
http://cr.yp.to/daemontools/supervise.html
You have to create a particular directory structure for your application startup script, but it's very simple to use.
first of all, how do you start this app? Does it fork itself to the background? Is it started with nohup .. & etc? If it's the latter, check why it died in nohup.out, if it's the first, build logging.
As for your main question: you could cron it, or run another process on the background (not the best choice) and use pidof in a bashscript, easy enough:
if [ `pidof -s app` -eq 0 ]; then
nohup app &
fi
You could make it a service launched from inittab (although some Linuxes have moved on to something newer in /etc/event.d). These built in systems make sure your service keeps running without writing your own scripts or installing something new.
It's a job for a DMD (daemon monitoring daemon). there are a few around; but I usually just write a script that checks if the daemon is running, and run if not, and put it in cron to run every minute.
Check out 'nanny' referenced in Chapter 9 (p197 or thereabouts) of "Unix Hater's Handbook" (one of several sources for the book in PDF).
A nice, simple way to do this is as follows:
Write your server to die if it can't listen on the port it expects
Set a cronjob to try to launch your server every minute
If it isn't running it'll start, and if it is running it won't. In any case, your server will always be up.
I think a better solution is if you test the function, too. For example, if you had to test an apache, it is not enough only to test, if "apache" processes on the systems exist.
If you want to test if apache OK is, then try to download a simple web page, and test if your unique code is in the output.
If not, kill the apache with -9 and then do a restart. And send a mail to the root (which is a forwarded mail address to the roots of the company/server/project).
It's even simplier:
#!/bin/bash
export DISPLAY=:0
process=processname
makerun="/usr/bin/processname"
if ! pgrep $process > /dev/null
then
$makerun &
fi
You have to remember though to make sure processname is unique.
One can install minutely monitoring cronjob like this:
crontab -l > crontab;echo -e '* * * * * export DISPLAY=":0.0" && for
app in "eiskaltdcpp-qt" "transmission-gtk" "nicotine";do ps aux|grep
-v grep|grep "$app";done||"$app" &' >> crontab;crontab crontab
disadvantage is that the app names you enter have to be found in ps aux|grep "appname" output and at same time being able to be launched using that name: "appname" &
also you can use the pm2 library.
sudo apt-get pm2
And if its a node app can install.
Sudo npm install pm2 -g
them can run the service.
linux service:
sudo pm2 start [service_name]
npm service app:
pm2 start index.js