getting the projected 2D "frame" of a SCNNode - io

I'm building a paged scrollview for SceneKit, where i have a bunch of nodes under a main contentNode as seen below.
My problem is trying to figure out the width of the node - in 2D coordinates - so i can calculate the amount of padding as seen below.
Current (failed) plan
projecting one of the nodes' boundingBox. Got an unreasonably large value there for width.
calculate amount of horizontal padding by subtracting the width of my SCNSceneView by the width of one of the nodes. All nodes are the same width and height.
Use half of that value so the objects to the left and right "peek" in a bit.
Unproject that value so i can apply the spacing.
So i'm stumped at the crazy values for the bounding box if anyone understands my error.

Related

How do I obtain the left, right, upper and lower shifts in coordinates between a cropped image and its original in Python?

I have the following original image:
and the cropped image:
I will like to obtain the left (a), right (c), upper (b) and lower shifts (d) from the original image to obtain the crop:
As of now, I can only think of matching the pixel array values (row and column-wise) and then subtracting the the overlapping pixel arrays coordinates from the original image's coordinates to get the shifts. However this approach seems computationally expensive and a search on 4 sides will have to be undertaken. Also if it helps, I do not have the transformations that led to the cropped image, and I'm assuming that there are no pixel value changes between the original and cropped image on regions of overlap.
Is there a more efficient approach for this? I'm not sure if there are existing built-in functions in OpenCV or other imaging libraries that can do this, so some insights on this will be deeply appreciated.

Is there a simple algorithm that can find the envelope of several circles?

Given a number of points on a 2d surface and radiuses for these points I can easily paint circles for them. What I need is an algorithm that only paints the envelope (right word for what I am looking for?) or outer bound of these combined circles. Additionally a second set of circles can 'encroach' on these circles, resulting in a kind of 'border'.
Image of what I am looking for
A quick way to draw the outline of the union of the disks is to
fill all disks in yellow, then
fill all disks in white with a smaller radius.
This can be adapted to the "encroached" circles, provided you only fill the remaining portions of the disks. Unfortunately, in a general setting finding the remaining portions can be an uneasy geometric problem.
There is an alternative approach which can work in all cases:
fill an image with zeroes, then for all disks fill every pixel with the value of the distance to the circumference (maximum at the center), but only keep the highest value so far.
while you do this, fill a second image with the color of the disk that achieved that highest value. (Initialize the image with the background color.)
At the end of this process, the first image will represent a "terrain" made of intersecting cones; and for every point of the terrain, you will know the color.
finally, color the pixels that have a height smaller than the desired stroke width, using the color map.
You can do the drawing in two steps.
1) Draw the outline using the following method: For each point, draw a circle using your favorite circle-drawing method, but before drawing a pixel, ensure that it is not contained inside any other circle. Do this for every point and you will get your outline.
2) Draw the borders between different sets using the following method: For each pair of points from different sets, calculate the two intersection points of the circles. If there is an intersection, the border can be drawn as a segment joining these two points. However, you have to make two lines, one for circle A, and another for circle B. To draw the line for circle A, slightly offset the segment towards point A. Then, use your favorite line-drawing method, but before drawing a pixel, ensure that it is closer to point A that any other point of the opposite set. After drawing the line, repeat the process for circle B. Note that both segment are not guaranteed to be the same length since the asymmetry of the points of the different sets. It will, however, always form a closed shape when all outlines and borders are drawn.

How to calculate what percentage of a pixel is within the bounds of a shape

I have a 2d grid where pixel centers are at the intersection of two half-grid lines, as shown below.
I also have a shape that is drawn on this grid. In my case the shape is a glyph, and is described by segments. Each segment has a start point, end point and a number of off-curve points. These segments can be quadratic curves or lines. What's important is that I can know the points and functions that make up the outline of the shape.
The rule for deciding which pixels should be turned on is simple: if the center of the pixel falls within the shape outline, turn that pixel on. The following image shows an example of applying this rule.
Now the problem I'm facing has to do with anti aliasing. What I'd like to do is to calculate what percentage of the area of a given pixel falls within the outline. As an example, in the image above, I've drawn a red square around a pixel that would be about 15% inside the shape.
The purpose of this would be so that I can then turn that pixel on only by 15% and thus get some cleaner edges for the final raster image.
While I was able to find algorithms for determining if a given point falls within a polygon (ray casting), I wasn't able to find anything about this type of problem.
Can someone can point me toward some algorithms to achieve this? Also let me know if I'm going about this problem in the wrong way!
This sounds like an X, Y problem.
You are asking for a way to calculate the perecentage of pixel coverage, but based on your question, it sounds that what you want to do is anti alias a polygon.
If you are working only with single color 2D shapes (i.e red, blue, magenta... squares, lines, curves...) A very simple solution is to create your image and blur the result afterwards.
This will automatically give you a smooth outline and is simple to implement in many languages.

Get Object distributed with a specific pixels distance in photoshop.!

There are 5 objects in a row which i want to distribute in a line
but i want 15 pixels distance between edges of objects in photoshop
what I am getting is Distribution Object by center, but not same distance between objects, How can i get it?
Here's what i want (case 2) & what i get (case 1).
Thanks in Advance!!!!
What you want to do is zoom in to the pictures to the point of where you can literally count each pixel. And start adjusting each picture with the arrow keys.
Or draw a square that measures 15 pixels wide and duplicate it. Once you are done with adjustment you can delete the square.

How to find line segments intersecting a 2D viewport

In an infinite 2D space there are a set of lines, each line having a start and end point, and a time of creation: Line(p0, p1, t).
I want to find the lines that should be rendered in a top-down view of this 2D space (higher values of t show up closer to the viewport, not that it should be relevant.)
The intuitive answer is "check if either point is within the viewport coordinates," but this falls down when the points are further apart than the viewport area covers.
The other idea I had was using something like geohash, this would limit precision i.e. maximum zoom level of the viewport. The idea is enumerating the hashes of the cells intersected and storing them. This way querying is a matter of asking the right question.
Are there any ideal solutions? Has this been solved before?
I think you need to check two conditions: one that the rectangle of viewport overlaps the rectangle with corners (p0,p1) and the second that some corners of viewport rectangle are on the different sides of the whole line which contains line segment (p0,p1).
The task of finding rectangle overlap can be solved very effectively for very large number of rectangles using R-trees (http://en.wikipedia.org/wiki/R-tree).
The second task can be reduced to checking signs of the cross product of (p1-p0) x (corner_coordinate-p0)
(all three quantities taken as 3-d vectors with third coordinate equal to zero, the result will be vector along the perpendicular direction). There should be corners with the opposite sign of this cross product.

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