i have the following string "USB SERIAL PORT (COM6)" i want to get COM6 out of this.
This is the code i am trying to use
string.substring(3, string.length - 1)
something of that sort. Havent been able to get anything.
You'd be better off using the last occurrence of ( as an index, in case one day your string changes format, or com6 is longer (com10):
Dim lastBra as Integer = myString.LastIndexOf("("c)
Dim lastKet as Integer = myString.LastIndexOf(")"c)
Dim subs as String = myString.Substring(lastBra + 1, lastKet - lastBra - 1)
It's lastBra+1 because we want the character after the open bracket as a start. The length to substring is the bracket indexes, less one because we don't want the last bracket to be included:
Related
I have the following strings from which I need to extract 6 digit numbers. Since these strings are generated by another software, they occur interchangeably and I cannot control it. Is there any one method that would extract both 6-digit numbers from each of these strings?
Branch '100235 to 100236 Ckt 1' specified in table 'East Contingency' for record with primary key = 21733 was not found in branch or transformer data.
Loadflow branch ID '256574_701027_1' defined in supplemental branch table was not found in branch or transformer input.
Transmission element from bus number 135415 to bus number 157062 circuit ID = 1 defined for corridor 'IESO-NYISO' was not found in input data
I don't know VBA, but I can learn it if it means I can get the 6 digit numbers using a single method.
thanks
I have been using LEFT(), RIGHT() & MID() previously, but it means manually applying the appropriate formula for individual string.
If you have Microsoft 365, you can use this formula:
=LET(arr,TEXTSPLIT(SUBSTITUTE(SUBSTITUTE(A1,"'"," "),"_"," ")," "),
FILTER(arr,ISNUMBER(-arr)*(LEN(arr)=6)))
Thanks to #TomSharpe for this shorter version, using an array constant within TEXTSPLIT to add on possible delimiters.
=LET(arr,TEXTSPLIT(A1,{"_"," ",","," ","'"}),FILTER(arr,(LEN(arr)=6)*ISNUMBER(-arr)))
Data
Output
An alternative is:
=LET(ζ,MID(A1,SEQUENCE(,LEN(A1)-5),6),ξ,MID(ζ,SEQUENCE(6),1),FILTER(ζ,MMULT(SEQUENCE(,6,,0),1-ISERR(0+ξ))=6))
A couple more suggestions (if you need them):
(1) Replacing all non-digit characters with a space then splitting the resulting string:
=LET(numbers,TEXTSPLIT(TRIM(REDUCE("",MID(A1,SEQUENCE(1,LEN(A1)),1),LAMBDA(a,c,IF(is.digit(c),a&c,a&" "))))," "),FILTER(numbers,LEN(numbers)=6))
Here I've defined a function is.digit as
=LAMBDA(c, IF(c = "", FALSE, AND(CODE(c) > 47, CODE(c) < 58)))
(tl;dr I quite like doing it this way because it hides the implementation details of is.digit and creates a rudimentary form of encapsulation)
(2) A UDF - based on the example here and called as
=RegexTest(A1)
Option Explicit
Function RegexTest(s As String) As Double()
Dim regexOne As Object
Dim theNumbers As Object
Dim Number As Object
Dim result() As Double
Dim i As Integer
Set regexOne = New RegExp
' Not sure how you would extract numbers of length 6 only, so extract all numbers...
regexOne.Pattern = "\d+"
regexOne.Global = True
regexOne.IgnoreCase = True
Set theNumbers = regexOne.Execute(s)
i = 1
For Each Number In theNumbers
'...Check the length of each number here
If Len(Number) = 6 Then
ReDim Preserve result(1 To i)
result(i) = CDbl(Number)
i = i + 1
End If
Next
RegexTest = result
End Function
Note - if you wanted to preserve leading zeroes you would need to omit the Cdbl() and return the numbers as strings. Returns an error if no 6-digit numbers are found.
This question already has answers here:
Extracting digits from a cell with varying char length
(4 answers)
Closed 2 years ago.
I need to be able to remove all alphabetical characters from a string, leaving just the numbers behind.
I don't need to worry about any other characters like ,.?# and so on, just the letters of the alphabet a-z, regardless of case.
The closest I could get to a solution was the exact opposite, the below VBA is able to remove the numbers from a string.
Function removenumbers(ByVal input1 As String) As String
Dim x
Dim tmp As String
tmp = input1
For x = a To Z
tmp = Replace(tmp, x, "")
Next
removenumbers = tmp
End Function
Is there any modification I can make to remove the letters rather than numbers to the above, or am I going at this completely wrong.
The letters could fall anywhere in the string, and there is no pattern to the strings.
Failing this I will use CTRL + H to remove all letters one by one, but may need to repeat this again each week so UDF would be much quicker.
I'm using Office 365 on Excel 16
Option Explicit
dim mystring as String
dim regex as new RegExp
Private Function rgclean(ByVal mystring As String) As String
'function that find and replace string if contains regex pattern
'returns str
With regex
.Global = True ' return all matches found in string
.Pattern = "[A-Z]" ' add [A-Za-z] if you want lower case as well the regex pattern will pick all letters from A-Z and
End With
rgclean = regex.Replace(mystring, "") '.. and replaces everything else with ""
End Function
Try using regular expression.
Make sure you enable regular expression on: Tools > References > checkbox: "Microsoft VBScript Regular Expressions 5.5"
The function will remove anything from [A-Z], if you want to include lower case add [A-Za-z] into the regex.pattern values. ( .Pattern = "[A-Za-z]")
You just pass the string into the function, and the function will use regular expression to remove any words from in a string
Thanks
I have Excel 2007. I am trying to find the largest number in a cell that contains something like the following:
[[ E:\DATA\SQL\SY0\ , 19198 ],[ E:\ , 18872 ],[ E:\DATA\SQL\ST0\ , 26211 ],[ E:\DATA\SQL\ST1\ , 26211 ],[ E:\DATA\SQL\SD0\ , 9861 ],[ E:\DATA\SQL\SD1\ , 11220 ],[ E:\DATA\SQL\SL0\ , 3377 ],[ E:\DATA\SQL\SL1\ , 1707 ],[ E:\DATA\SQL_Support\SS0\ , 14375 ],[ E:\DATA\SQL_Support\SS1\ , 30711 ]]
I am not a coder but I can get by with some basic instructions. If there is a formula that can do this, great! If the best way to do this is some sort of backend code, just let me know. Thank you for your time.
I do have the following formula that almost gets me there:
=SUMPRODUCT(MID(0&A2,LARGE(INDEX(ISNUMBER(--MID(A2,ROW(INDIRECT("1:"&LEN($A$2))),1))*ROW(INDIRECT("1:"&LEN($A$2))),0),ROW(INDIRECT("1:"&LEN($A$2))))+1,1)*10^ROW(INDIRECT("1:"&LEN($A$2)))/10)
With a cell that contains a string like above, it will work. However, with a string that contains something like:
[[ E:\DATA\SQL\SY0\ , 19198.934678 ],[ E:\ , 18872.2567 ]]
I would end up with the value of 19198934678 as the largest value.
You can use this UDF:
Function MaxInString(rng As String) As Double
Dim splt() As String
Dim i&
splt = Split(rng)
For i = LBound(splt) To UBound(splt)
If IsNumeric(splt(i)) Then
If splt(i) > MaxInString Then
MaxInString = splt(i)
End If
End If
Next i
End Function
Put this in a module attached to the workbook. NOT in the worksheet or ThisWorkbook code.
Then you can call it like any other formula:
=MaxInString(A1)
If there is always a space before and after, you can use this formula. The formula is an array formula and must be confirmed by holding down ctrl + shift while hitting enter
With your string in A1:
=MAX(IFERROR(--TRIM(MID(SUBSTITUTE(A1," ",REPT(" ",99)),IF(seq=1,1,(seq-1)*99),99)),0))
seq is a defined name that refers to:
=ROW(INDEX(Sheet1!$1:$65536,1,1):INDEX(Sheet1!$1:$65536,255,1))
If a VBA UDF is preferable, I suggest the following. The Regex will match anything that might be a number. The number is expected to be in the format of iiii.dddd The integer part and the decimal point are both optional.
Option Explicit
Function LargestNumberFromString(S As String) As Double
Dim RE As Object, MC As Object, M As Object
Dim D As Double
Set RE = CreateObject("vbscript.regexp")
With RE
.Global = True
.Pattern = "\b[0-9]*\.?[0-9]+\b"
If RE.test(S) = True Then
For Each M In MC
D = IIf(D > CDbl(M), D, CDbl(M))
Next M
End If
End With
End Function
This is going to be a rather complex answer for someone with no programming background, so be prepared to spend a lot of time covering and researching this topic if you really wish to achieve a function that finds the largest number in a string in excel.
The solution, requires the use of VBA and Regular expressions
VBA is used in excel when there is a need for more complex functionality that just can't be achieved with the use of built in spreadsheet functions.
Regular expressions are a language used to tell programs how to extract useful information from texts, in this case we can extract all the numbers in your text. with the following regular expression.
(\d+.?\d*)/g
Which roughly means: Match one or more digits with an optional period and subsequent optional digits.
The program that will interpret this will do the following: Look for digits, if you see one, then that's a match, grab all contiguous digits and add them to the match. Once you find a character that is not a digit, start looking for new matches. if at any point you find a dot, add it to the match, but just once, and keep on looking for digits. Rinse and repeat until the end of the text.
You can test it here. In this case, the regex matches 19 numbers.
http://www.regextester.com/
Once you have a collection with the 19 matches (See link to regular expressions), all you would need to do is to loop over each of the matches to find out which of the numbers is the highest:
for each number in matches
if number > highestNumber then
highestNumber = number
end if
next
And highestNumber will be the the result! In order to have this code run in a simple custom function, you can follow this microsoft tutorial ( https://support.office.com/en-us/article/Create-Custom-Functions-in-Excel-2007-2f06c10b-3622-40d6-a1b2-b6748ae8231f?ui=en-US&rs=en-US&ad=US&fromAR=1 )
Where c is your string to find max from
Dim qwe() As String
qwe = Split(c, ", ")
maxed = 0
For x = LBound(qwe) To UBound(qwe)
qwe(x) = Left(qwe(x), InStr(1, qwe(x), " ", vbBinaryCompare))
On Error Resume Next
If CLng(qwe(x)) > maxed Then maxed = CLng(qwe(x))
Next x
MsgBox maxed
The error line is there to ignore when qwe(x) cannot be converted to a LONG number.
I must say this is very specific to your string format, for a more comprehensive doodad you'd want to have the split delimiter as a variable and possibly use the "IsNumeric" function to scan the entire string.
Most people ask how to get the characters from a string, which can be done by Mid(). I am trying to assign a string character by character in VBA code. The characters to be assigned depend on some calculated results.
I do not want to use string concatenation to form the string.
I have searched the web, but the posted solution, strName.Chars(i) (e.g., at MS development network), is not recognized in my 2007 Access VBA.
Thanks
You can use Mid to set values, too.
Sub showMidExample()
Dim s As String
s = "aaaaa"
Dim i As Integer
For i = 1 To Len(s)
Mid(s, i) = "n"
Debug.Print s
Next i
End Sub
This prints out
naaaa
nnaaa
nnnaa
nnnna
nnnnn
Which is what you are looking for.
Since no working answer is posted. I assume that cannot be done in VBA and I have to use concatenation to form the string although that is cumbersome in my case.
I cannot find a solution as how to chop off part of a string(filepath) and use what's left to get another string.
For example: if I have filepath: Q:\2456_blah_blah\file.txt and I want to put this entire filepath into an array and delete from left characters 0 through 8 (which is consistent for my application) so I'd have 'blah_blah\file.txt' left for my array.
(The blah_blah portion is going to be a dynamic length, but it will always be letters.)
So then I'd like to take the 'blah_blah\file.txt' and pull just from that beginning up to the next '\' symbol, getting "blah_blah" as a string. I'm not too savy with VB strings at this point, so any help would be much appreciated. This is just my thinking how it could be done, if there's a simpler solution, I'm all ears.
Thanks,
Two Substring calls should do it.
Dim str As String = "Q:\2456_blah_blah\file.txt"
str = str.Substring(8, str.Length - 8)
Dim blah As String = str.Substring(0, str.IndexOf("\"))
Are you looking for something like this. Not knowing all the details makes it difficult to create something that fits your needs but I'll give it a shot. This will return back the blah_blah portion of your strings no matter how large "blah_blah" is, no matter how long the filename is, no matter how long the first portion of your string is and no matter how deep the path goes.
Dim test As String = "c:\34242_blah_blah\test.txt"
Dim startPos As Integer = test.IndexOf("_") + 1
Dim endPos As Integer = test.IndexOf("\", startPos)
Dim result As String = test.Substring(startPos, endPos - startPos)