I have a folder, which consists of many folders and many tar files. (this many is around 1000)
I want to write a script to copy all folders with their contents to another directory, but I do not want to copy tar files.
I already know by writing
cp -a /source/ /path/
I can copy a directory with its contents to another, but for this case, I do not know how to do it.
As the number of directories are alot, I am not able to each time copy one directory.
I appreciate if someone can help me on this.
I think this might be what you're looking for.
You want to use the rsync command and in the --exclude flag you want to put *.tar
So your answer will look something like this:
rsync -r --exclude='*.tar' [source] [destination]
This is also a helpful little tutorial on how to use rsync.
You can combine cp in find to exclude *.tar files:
dest='/path/'
mkdir "$dest" &&
find /source -mindepth 1 -not -name '*.tar' -exec cp -a {} "$dest" \;
Related
Lets say i have a folder named Pictures and I want to move or copy all files out of this folder.
However I also want to move and harvest all of the files who are in sub folders so:
Pictures/1.png
Pictures/yolo/2.png
Pictures/yolo/swag/sand/3.png
Pictures/extra/fire/4.png
I want to move or copy all these files to another folder like results so I get:
results/1.png
results/2.png
results/3.png
results/4.png
Only I have no idea in advance what sub folders will be in the Pictures folder.
How can I accomplish this in bash/shell scripts ?
I also appreciate making it file type neutral so any files are harvested from their directories (not only .png like in my example) and I have no idea what the file name will be (I only used 1...4 because i did not have any idea how to name them).
You can do it like this:
find /absolute/path/to/Pictures -type f -name '*.png' -exec mv -i {} /absolute/path/to/results \;
Another option is to use xargs
find /absolute/path/to/Pictures -name '*.png' | xargs -I files mv files /absolute/path/to/results
You can simply copy all files and subdirectories along with their contents using cp's recursive option:
cp -pr <source_path>/* <destination_path>/
But, moving them recursively is a bit tricky, you will need to create tar files of the subdirectories and move them and then untar the tar files in destination path. As this is a complex process, as a workaround, you can copy the files/directories recursively and then delete the files from original path.
cp -pr <source_path>/* <destination_path>/ && rm -rf <source_path>/*
I'm still new to linux scripting, so this might be a bit trivial.
As part of my script, I am trying to copy all the modified files (relative to the original backup I have made) to another folder while keeping the file structure.
I have found this method:
find /SourceFolder/ -newer /BackupFOlder/ -exec cp --parents \{\} /Destination
However the above command does not work, giving me the error:
find: missing argument to 'exec'
Why doesn't this work?
I also found this:
Copy files preserving folder structure
But I want to use cp command only.
Would really appreciate some help.
The -exec option requires a ; argument to tell it where the command ends, because you could have additional find options after it.
find /SourceFolder/ -newer /BackupFOlder/ -exec cp --parents {} /Destination \;
However, a better solution would be to use rsync:
rsync -a /SourceFolder /BackupFolder
Try
tar cf - . | (cd <some other dir>; tar xfv -)
I'm trying to write a script that copy all the files of one dir (with subdirs) to the root of another dir.
So Imagine I have this file structure:
/
pic.JPG
PIC5.JPG
FOLDER
pic2.JPG
pic3.JPG
FOLDER2
pic4.JPG
I want all the .JPG files from that directory and copy them over to another destination. But I don't want the directory structure, just the files.
This is what I've got:
"sudo rsync -aq --include '*/' --include '*.JPG' --exclude '*\' /source/picturesRoot/ /destination/flatView/
But it also copies the directories :(
I found this link on stackoverflow:
rsync : Recursively sync all files while ignoring the directory structure
I looked at the solution and didn't see much difference with my command, apart from the * and . in the path. I tried it but it didn't work.
I hope somebody can help me, thanks.
This answer cannot work for you because your pictures are not at the same level in directories. There is no option in rsync to skip the creation of directory structure. In the link you gave, it's working because the user explicitly select source files with *.
You can try something with find and rsync. Find will find files and rsync copy them.
Here is a solution :
find /source/picturesRoot -type f -name "*.JPG" -exec rsync -a {} /destination/flatView/ \;
Be careful, if two files have the same name just one will be in destination directory.
I'm making a bash script that should backup all files and dir structure to another dir.
I made the following code to do that:
find . -type f -exec cp {} $HOME/$bdir \; -o -type d -exec mkdir -p {} $HOME/$bdir \; ;
The problem is, is that this only copies the files and not the dir structure.
NOTE: I may not use cp -r, cp -R or something like it because this code is part of an assignment.
I hope somebody can put me in the right direction. ;)
Joeri
EDIT:
I changed it to:
find . -type d -exec mkdir -p $HOME/$bdir/{} \; ;
find . -type f -exec cp {} $HOME/$bdir/{} \; ;
And it works! Ty guys ;)
This sounds like a job for rsync.
You mention that this is an assignment. What are your restrictions? Are you limited to only using find? Does it have to be a single command?
One way to do this is to do it in two find calls. The first call only looks for directories. When a directory is found, mkdir the corresponding directory in the destination hierarchy. The second find call would look for files, and would use a cp command like you currently have.
You can also take each filename, transform the path manually, and use that with the cp command. Here's an example of how to generate the destination filename:
> find . -type f | sed -e "s|^\./|/new/dir/|"
/new/dir/file1.txt
/new/dir/file2.txt
/new/dir/dir1/file1_1.txt
/new/dir/dir1/file1_2.txt
For your purposes, you could write a short bash script that take the source file as input, uses sed to generate the destination filename, and then passes those two paths to cp. The dirname command will return the directory portion of a filename, so mkdir -p $(dirname $destination_path) will ensure that the destination directory exists before you call cp. Armed with a script like that, you can simply have find execute the script for every file it finds.
cd olddir; tar c . | (cd newdir; tar xp)
Can you do your find with "-type d" and exec a "mkdir -p" first, followed by your find that copies the files rather than having it all in one command? It should probably also be mkdir -p $HOME/$bdir/{}.
I have a bunch of zip files, and I'm trying to make a bash script to automate the unzipping of certain files from it.
Things is, although I know the name of the file I want, I don't know the name of the folder it's in; it is one folder depth in
How can I extract these files, preferably discarding the folder?
Here's how to unzip any given file at any depth and junk the folder paths on the way out:
unzip -j somezip.zip *somefile.txt
The -j junks any folder structure in the zip file and the asterisk gives a wildcard to match along any path.
if you're in:
some_directory/
and the zip files are in any number of subdirectories, say:
some_directory/foo
find ./ -name myfile.zip -exec unzip {} -d /directory \;
Edit: As for the second part, removing the directory that contained the zip file I assume?
find ./ -name myfile.zip -exec unzip {} -d /directory \; -exec echo rm -rf `dirname {}` \;
Notice the "echo." That's a sanity check. I always echo first when executing something destructive like rm -rf in a loop/iterative sequence like this. Good luck!
Have you tried unzip somefile.zip "*/blah.txt"?
You can use find to find the file that you need to unzip, and xargs to call unzip:
find /path/to/root/ -name 'zipname.zip' -print0 | xargs -0 unzip
print0 enables the command to work with files or paths that have white space in them. -0 is the option to xargs that makes it work with print0.