I essentially have two list containing strings:
com = ['746365', '6365']
dec = ['6d955s2359d757bb40d0cf36bd7a35662d8b3']
I take the length of the first element in list a '746365' and cut list b into the same length as the first element, (len('746365') = 6) and the result of b is '6d955s'. I now wish to move along the element in b by one place until i reach the end ('62d8b3').
I currently have:
count = 0
for a in com:
for b in dec:
print(com.index(a), a)
length_of = len(a)
print(b[0 + count:length_of + count])
count = count + 1
This doesn't work. However if I remove the count parts and leave whats displayed beneath it works but I can't get it to move along by one
for a in com:
for b in dec:
print(com.index(a), a)
length_of = len(a)
print(b[0:length_of])
how can I adjust this code so that I print then move along by one and print the next?
The initial result should be:
6d955s d955s2 955s23 etc etc..
once the end of dec has been reached, it'll move onto the next value in com.
Thanks.
Try this:
for a in com:
for b in dec:
for i in range(0,len(b)-len(a)+1):
clipped_str = b[i:i+len(a)]
print(clipped_str)
Try this code:
start = 0
for c_element in com:
current_length = len(c_element)
end = start + current_length
for d_element in dec:
for _ in range(len(d_element) - current_length + 1):
print(d_element[start:end])
start += 1
end += 1
else:
start = 0
Related
records = [["chi", 20.0],["beta", 50.0],["alpha", 50.0]]
a = len(records)
i = 0
b = []
while i < a:
print(records[i][1])
b.append(records[i][1])
i = i + 1
print(b)
c = len(b)
#from previous question
unique_list = []
for el in b:
if el not in unique_list:
unique_list.append(el)
else:
print ("Element already in the list")
print(unique_list)
second_lowest_score = unique_list[1]
print(second_lowest_score)
names_list = []
g = 0
while g < a:
if records[g][1] == second_lowest_score:
names_list.append(records[g][0])
g = g + 1
print(names_list)
What I want to do is to append the names of records which have the second lowest score (50) to the names_list. However, the while loop gives me no result. There is no syntax error so I am not sure why my code is wrong. However, when I use the previous while loop for appending the numbers, it seems to work fine. Is it not possible to use an if statement in a while loop?
This is a pretty simple problem. The g variable is not getting incremented if the if statement does not run, so the loop will endlessly continue on the same value of g.
The fix for this is to move the increment of g outside of the if statement (but still in the while loop). That way it will continue past values even if they do not match the if condition.
if records[g][1] == second_lowest_score:
names_list.append(records[g][0])
g = g + 1
Hello I have to reorder a string, I am banned from using other types and str methods
So my problem is that I could not figure out how to end my code to get it work with any string
I tried to compare the results with sorted() to check and I am stuck at the first exchange
My code:
i = 0
s1 = "hello"
s2 = sorted(s1)
while (i<len(s1)):
j=i+1
while (j<=len(s1)-1):
if (s1[i] > s1[j]):
s1 = s1[0:i] + s1[j] + s1[i]
j+=1
i+=1
print(s1)
print(s2)
I tried to add + s1[len(s1):] at the end of the operation but
I only had found the result for a single string(that I was testing) adding thisI am really stuck, how can I make it work for all the strings with different lenghts??
Thanks
You're not reconstructing the string correctly when doing s1 = s1[0:i] + s1[j] + s1[i] as you're replacing one character for the other but you omit to actually interchange the two and to add the remains of the splitted string to the end of the new string.
Given what your code looks like, I would do it like this:
i = 0
s1 = "hello"
s2 = sorted(s1)
while i < len(s1):
j = i + 1
while j <= len(s1)-1:
if s1[i] > s1[j]:
s1 = s1[0:i] + s1[j] + s1[i+1:j] + s1[i] + s1[j+1:len(s1)]
j += 1
i += 1
print("".join(s2))
# > 'ehllo'
print(s1)
# > 'ehllo'
Please tell me if anything is unclear!
I am banned from using other types and str methods
Based upon your criteria, your request is impossible. Just accessing the elements of a string requires string methods.
The technique that you are using is very convoluted, hard to read and is difficult to debug. Try running your code in a debugger.
Now given that you are allowed to convert a string to a list (which requires string methods), redesign your code to use simple, easy to understand statements.
The following code first converts the string into a list. Then loops thru the list starting at the beginning and compares each following character to the end. If any character is less then the current character, swap. As you step thru the string, the character swaps will result in a sorted list. At the end convert the list back to a string using join().
msg = 'hello'
s = list(msg)
for i in range(len(s) - 1):
for j in range(i + 1, len(s)):
if s[i] <= s[j]:
continue
# swap characters
s[i], s[j] = s[j], s[i]
print(msg)
print(''.join(s))
The program requires input of positive numbers, and counts each even number using a loop function that doesn't count odds and ends if a O is input.
I'm not sure how to go about creating a loop or if I can use an if function within the loop.
Dim Count = 0
While (number mod 2 = 0) do
Count + 1 = Count
I actually didn't understand the question very well but as far as concerned, if you dont want odd numbers to be included I suggest on count add 2 not one , since the count variable starts with zero do:
Dim Count+2
Btw when do you want the count to stop? At 2 And goes back to 0?
If so then use the if statement
var Dim_count = 0;
if(Dim_count == 0){Dim_count+2}
else if(Dim_count ==2){Dim_Count =0;}
It would help if you provide a sample input so we can work with actual code and guide you to the right solution.
If you receive the input as, let's say, array of numbers, you can simply loop trough it using for or foreach and add additional condition to check for 0 if you want to preliminary exit:
For Each number As Integer In numbers
If (number mod 2 = 0) Then
Count = Count + 1
End If
If (number = 0) Then
Exit For
End If
Next
If you have existing code in which somehow number is reinitialized/redefined on each iteration already, then what you have is pretty close to what you need:
While (number <> 0)
If (number mod 2 = 0) Then
Count = Count + 1
End If
End While
Function counts even numbers:
REM function gets input, exits at 0 and adds positive even numbers.
DO
INPUT X
IF X = 0 THEN PRINT Y; " even numbers": END
IF X > 0 THEN
IF X / 2 = X \ 2 THEN Y = Y + 1
END IF
LOOP
I am completely unsure about this. just a guess...
Dim j as Integer
Dim i As integer
j = 0
i = 2
For i = 1 to 100
j = j+i
Print j
Loop
End Sub
Assuming you are getting numbers from some input, this is how you can do it. Have an infinite loop with While True, then for every number given from your input, check if its even using number mod 2 = 0. This will go on forever so you need to add some condition (another if statement) for it to stop the while loop. More information about while loops here: https://learn.microsoft.com/en-us/dotnet/visual-basic/language-reference/statements/while-end-while-statement
Dim Count = 0
While True do
If (number mod 2 = 0) Then
Count + 1 = Count
End If
End While
I am using the following code to assign a value to a given letter (A = +1, B= -1)
letList = []
let1 = ['A','A','B']
count = 0
for l in let1:
if l == "A":
count = count + 1
else:
count = count - 1
print(letList.append(count)) #doesnt work
Goal: I want to create a list of counts with the final output that looks something like this: letList = [1,2,1]
Problem: But when I try to append using letList.append(count) I get a none output
Suggestions?
You are trying to print the append function and the append needs to be in your loop to do what you want. Below is an example that prints [1,2,1] using append.
letList = []
let1 = ['A','A','B']
count = 0
for l in let1:
if l == "A":
count = count + 1
else:
count = count - 1
letList.append(count)
print(letList)
What im trying to do is get the longest substring in s in which the letters occur in alphabetical order.
For some reason alphasub has no string in it at the end and I don't know why
start = 0
sub = 1
maxsub = 0
current = 0
s = 'azcbobobegghakl'
leng = len(s)
for i in range(leng):
if i != leng - 1:
if s[i] <= s[i+1]:
current = i
sub = 1
while current < (leng-1):
if s[current] <=s [current+1]:
sub += 1
current += 1
else:
break
if(sub>maxsub):
maxsub = sub
start = i
alphasub = s[start:maxsub]
print("longest substring is: " + alphasub)
String slicing takes starting and end position.
https://docs.python.org/2/tutorial/introduction.html
Change alphasub=s[start:maxsub] to alphasub=s[start:start+maxsub]. You should see the expected output.
It's good practice to use print's to check your code.
I've added some prints at the end of your code like so:
print(s)
print(start)
print(maxsub)
alphasub=s[start:maxsub]
print ("longest substring is: " + alphasub)
Which outputs:
azcbobobegghakl
7
5
longest substring is:
It is starting at 7, and ending at 5, which obviously doesn't work.