how tcan i get block tag with beautifulsoup python 3 - python-3.x

I have to scrap ap page and have this in the HTML code
<div id="agentPhone" class="displayNone text large padding bck light_grey"></div>
</div>
in the elenent DOM page I have this
<div id="agentPhone" class="displayNone text large padding bck light_grey" style="display: block;"><span>τηλ:</span> <span class="text color bold ">6908511284</span></div>
</div>
I am trying to get 6908... but I can't manage it.
Is there a way to do?

It's not because the block style, your problem is because the number show with post request after you click on button, You can not have the number with bs but with selenium.

Related

How can I get texts with certain criteria in python with selenium? (texts with certain siblings)

It's really tricky one for me so I'll describe the question as detail as possible.
First, let me show you some example of html.
....
....
<div class="lawcon">
<p>
<span class="b1">
<label> No.1 </label>
</span>
</p>
<p>
"I Want to get 'No.1' label in span if the div[#class='lawcon'] has a certain <a> tags with "bb" title, and with a string of 'Law' in the text of it."
<a title="bb" class="link" onclick="javascript:blabla('12345')" href="javascript:;">Law Power</a>
</p>
</div>
<div class="lawcon">
<p>
<span class="b1">
<label> No.2 </label>
</p>
<p>
"But I don't want to get No.2 label because, although it has <a> tag with "bb" title, but it doesn't have a text of law in it"
<a title="bb" class="link" onclick="javascript:blabla('12345')" href="javascript:;">Just Power</a>
</p>
</div>
<div class="lawcon">
<p>
<span class="b1">
<label> No.3 </label>
</p>
<p>
"If there are multiple <a> tags with the right criteria in a single div, I want to get span(No.3) for each of those" <a>
<a title="bb" class="link" onclick="javascript:blabla('12345')" href="javascript:;">Lawyer</a>
<a title="bb" class="link" onclick="javascript:blabla('12345')" href="javascript:;">By the Law</a>
<a title="bb" class="link" onclick="javascript:blabla('12345')" href="javascript:;">But not this one</a>
...
...
...
So, here is the thing. I want to extract the text of (e.g. No.1) in div[#class='lawcon'] only if the div has a tag with "bb" title, with a string of 'Law' in it.
If inside of the div, if there isn't any tag with "bb" title, or string of "Law" in it, the span should not be collected.
What I tried was
div_list = [div.text for div in driver.find_elements_by_xpath('//span[following-sibling::a[#title="bb"]]')]
But the problem is, when it has multiple tag with right criteria in a single div, it only return just one div.
What I want to have is a location(: span numbers) list(or tuple) of those text of tags
So it should be like
[[No.1 - Law Power], [No.3 - Lawyer], [No.3 - By the Law]]
I'm not sure I have explained enough. Thank you for your interests and hopefully, enlighten me with your knowledge! I really appreciate it in advance.
Here is the simple python script to get your desired output.
links = driver.find_elements_by_xpath("//a[#title='bb' and contains(.,'Law')]")
linkData = []
for link in links:
currentList = []
currentList.append(link.find_element_by_xpath("./ancestor::div[#class='lawcon']//label").text + '-' + link.text)
linkData.append(currentList)
print(linkData)
Output:
[['No.1-Law Power'], ['No.3-Lawyer'], ['No.3-By the Law']]
I am not sure why you want the output in that format. I would prefer the below approach, so that you will get to know how many divs have the matching links and then you can access the links from the output based on the divs. Just a thought.
divs = driver.find_elements_by_xpath("//a[#title='bb' and contains(.,'Law')]//ancestor::div[#class='lawcon']")
linkData = []
for div in divs:
currentList = []
for link in div.find_elements_by_xpath(".//a[#title='bb' and contains(.,'Law')]"):
currentList.append(div.find_element_by_xpath(".//label").text + '-' + link.text)
linkData.append(currentList)
print(linkData)
Output:
[['No.1-Law Power'], ['No.3-Lawyer', 'No.3-By the Law']]
As your requirement is to extract the texts No.1 and so on, which are within a <label> tag, you have to induce WebDriverWait for the visibility_of_all_elements_located() and you will have only 2 matches (against your expectation of 3) and you can use the following Locator Strategy:
Using XPATH:
print([my_elem.get_attribute("innerHTML") for my_elem in WebDriverWait(driver, 5).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[#class='lawcon']//a[#title='bb' and contains(.,'Law')]//preceding::label[1]")))])

Why does attribute splitting happen in BeautifulSoup?

I try to get the attribute of the parent element:
<div class="detailMS__incidentRow incidentRow--away odd">
<div class="time-box">45'</div>
<div class="icon-box soccer-ball-own"><span class="icon soccer-ball-own"> </span></div>
<span class=" note-name">(Autogoal)</span><span class="participant-name">
Reynaldo
</span>
</div>
span_autogoal = soup.find('span', class_='note-name')
print(span_autogoal)
print(span_autogoal.find_parent('div')['class'])
# print(span_autogoal.find_parent('div').get('class')
Output:
<span class="note-name">(Autogoal)</span>
['detailMS__incidentRow', 'incidentRow--away', 'odd']
I know i can do something like this:
print(' '.join(span_autogoal.find_parent('div')['class']))
But i want to know why this is happening and is it possible to do this more correctly?
Above answer is correct however if you want get mutli attribute value return as string try use xml parser after get the parent element.
from bs4 import BeautifulSoup
data='''<div class="detailMS__incidentRow incidentRow--away odd">
<div class="time-box">45'</div>
<div class="icon-box soccer-ball-own"><span class="icon soccer-ball-own"> </span></div>
<span class=" note-name">(Autogoal)</span><span class="participant-name">
Reynaldo
</span>
</div>'''
soup=BeautifulSoup(data,'lxml')
span_autogoal = soup.find('span', class_='note-name')
print(span_autogoal)
parentdiv=span_autogoal.find_parent('div')
data=str(parentdiv)
soup=BeautifulSoup(data,'xml')
print(soup.div['class'])
Output on console:
<span class="note-name">(Autogoal)</span>
detailMS__incidentRow incidentRow--away odd
According to the BeautifulSoup documentation:
HTML 4 defines a few attributes that can have multiple values. HTML 5
removes a couple of them, but defines a few more. The most common
multi-valued attribute is class (that is, a tag can have more than one
CSS class). Others include rel, rev, accept-charset, headers, and
accesskey. Beautiful Soup presents the value(s) of a multi-valued
attribute as a list:
css_soup = BeautifulSoup('<p class="body"></p>') css_soup.p['class']
# ["body"]
css_soup = BeautifulSoup('<p class="body strikeout"></p>')
css_soup.p['class']
# ["body", "strikeout"]
So in your case in <div class="detailMS__incidentRow incidentRow--away odd"> a class attribute is multi-valued.
That's why span_autogoal.find_parent('div')['class'] gives you list as an output.

Scrape a span text from multiple span elements of same name within a p tag in a website

I want to scrape the text from the span tag within multiple span tags with similar names. Using python, beautifulsoup to parse the website.
Just cannot uniquely identify that specific gross-amount span element.
The span tag has name=nv and a data value but the other one has that too. I just wanna extract the gross numerical dollar figure in millions.
Please advise.
this is the structure :
<p class="sort-num_votes-visible">
<span class="text-muted">Votes:</span>
<span name="nv" data-value="93122">93,122</span>
<span class="ghost">|</span>
<span class="text-muted">Gross:</span>
<span name="nv" data-value="69,645,701">$69.65M</span>
</p>
Want the text from second span under span class= text muted Gross.
What you can do is find the <span> tag that has the text 'Gross:'. Then, once it finds that tag, tell it to go find the next <span> tag (which is the value amount), and get that text.
from bs4 import BeautifulSoup as BS
html = '''<p class="sort-num_votes-visible">
<span class="text-muted">Votes:</span>
<span name="nv" data-value="93122">93,122</span>
<span class="ghost">|</span>
<span class="text-muted">Gross:</span>
<span name="nv" data-value="69,645,701">$69.65M</span>
</p>'''
soup = BS(html, 'html.parser')
gross_value = soup.find('span', text='Gross:').find_next('span').text
Output:
print (gross_value)
$69.65M
or if you want to get the data-value, change that last line to:
gross_value = soup.find('span', text='Gross:').find_next('span')['data-value']
Output:
print (gross_value)
69,645,701
And finally, if you need those values as an integer instead of a string, so you can aggregate in some way later:
gross_value = int(soup.find('span', text='Gross:').find_next('span')['data-value'].replace(',', ''))
Output:
print (gross_value)
69645701

Scraping multiple similar lines with python

Using a simple request I'm trying to get from this html page some information stored in "alt". The problem is that, within each instance, the information is separated in multiple lines that start with "img", and when I try to access it, I can only read the first instance of "img" and not the rest, but I'm not sure how to do it. Here's the HTML text:
<div class="archetype-tile-description-wrapper">
<div class="archetype-tile-description">
<h2>
<span class="deck-price-online">
Golgari Midrange
</span>
<span class="deck-price-paper">
Golgari Midrange
</span>
</h2>
<div class="manacost-container">
<span class="manacost">
<img alt="b" class="common-manaCost-manaSymbol sprite-mana_symbols_b" src="//assets1.mtggoldfish.com/assets/s-d69cbc552cfe8de4931deb191dd349a881ff4448ed3251571e0bacd0257519b1.gif" />
<img alt="g" class="common-manaCost-manaSymbol sprite-mana_symbols_g" src="//assets1.mtggoldfish.com/assets/s-d69cbc552cfe8de4931deb191dd349a881ff4448ed3251571e0bacd0257519b1.gif" />
</span>
</div>
<ul>
<li>Jadelight Ranger</li>
<li>Merfolk Branchwalker</li>
<li>Vraska's Contempt</li>
</ul>
</div>
</div>
Having said that, what I'm looking to get from this is both "b" and "g" and store them in a single variable.
You can probably grab those <img> elements with the class "common-manaCost-manaSymbol" like this:
imgs = soup.find_all("img",{"class":"common-manaCost-manaSymbol"})
and then you can iterate over each <img> and grab the alt property of it.
alts = []
for i in imgs:
alts.append(i['alt'])
or with a list comprehension
alts = [i['alt'] for i in imgs]

How to extract value from href in python?

Hi developer. I am facing a problem in extracting a href value in python.
I have a button there after clicking on "view Answer" it take me a next link I want to extract that data which is present in that link.
<div class="col-md-11 col-xs-12">
<a href="https://www.marham.pk/forum/thread/4471/i-need-a-good-orthopedic- dr">
<div class="hover-div">
<h2 itemprop="name">i need a good Orthopedic dr</h2>
</div>
</a>
<div class="thread-details">
<a href="https://www.marham.pk/forum/thread/4471/i-need-a-good-orthopedic-dr">
<p class="pull-left"><span class="glyphicon glyphicon-comment"></span> View Answers (<span itemprop="answerCount">1</span>) </p>
</a>
</div>
</div>
I need to extract this href tag.
You Can Use Data Scraping In Python.
Beautiful Soup is a Python library for pulling data out of HTML and XML files.
import bs4 as bs
import urllib.request
sauce = urllib.request.urlopen("Your URL WILL GO HERE").read()
soup = bs.BeautifulSoup(sauce,'html5lib')
print(soup)

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