SteamBot_Csgo_Bot\settings\Configuration
i have a js file in configuration folder and want to call a file in the steamBot_Csgo_Bot folder
i understand that ../ goes back one how do i go back 2 directories
You can go 2 directories back with the following
../../
Use ../ twice.
../../jsfile.js
Related
I was using path.resolve but this command created a monster folder that can't be deleted called lib..
path.resolve(__dirname + "../assets/pic/" + `${fileName}.png`)
Question 1
What is the propper usage to create a folder 1 level up from the current path?
Question 2
How to remove the lib../assets/pic folder? Deleting the entire project or using git reset --hard, git stash doesn't work because Windows 10 says the folder doesn't exist.
Answer to Question 1:
tl;dr
const fs = require('fs')
const folderName1DirUp = '../SomeFolder'
try {
if (!fs.existsSync(folderName1DirUp)){
fs.mkdirSync(folderName1DirUp)
}
} catch (err) {
console.error(err)
}
The back story:
Two ways to reference the current folder in a Node.js script. You can use ./ or __dirname. Note in addition to ./ you can also use ../ which points to the parent folder.
The difference between the two.
__dirname in a Node script will return the path of the folder where the current JavaScript file resides.
./ will give you the current working directory (and ../ the parent). For ./ a call to process.cwd(). returns the same thing.
Initially the current working directory is the path of the folder where you ran the node command, but during the execution of your script it can change by calling process.chdir(...).
There is one place where ./ refers to the current file path which is in a require(...) call. There the ./, for convenience, refers to the JavaScript file path which lets you import other modules based on the folder structure.
Thus the call to fs.mkdirSync('../SomeFolder') with the given folder name makes a folder one level up from the current working directory.
Answer to Question 2:
From a PowerShell prompt Remove-Item './../Folder1UpToDelete' -Force The ./ is for the current folder. The ../ is for one folder up from the current. Finally the Folder1UpToDelete is the one folder up from the current that you want to delete. The -Force makes sure to delete all sub-folders/files under the folder you want deleted including hidden and/or read-only files.
To answer the first question, to create a path 1 level up, you can use path.join():
path.join(__dirname, "../assets/pics", `${fileName}.png`);
For the second question, if deleting it through the explorer doesn't work, you can try:
fs.rmdirSync("E:/path/to/broken/folder..");
Using Git Bash and running
cd /c/path/to/broken/
rmdir folder..
I have this Nodejs lambda function where some files are in a subfolder, like this:
- index.js
- connectors/
- affil.js
I have a Cannot find module error when trying to require the affil.js file. Trying to read it with fs.readFile returns an access denied error.
When I move the file to the root folder, it is accessible. Is there a requirement that Lambda functions files must all be at the root directory? How can I fix that?
Mostly it is because of the way zipping the files making the problem. Instead of zipping the root folder you have to select all files and zip it like below,
Please upload all files and subfolders like below. Please include node_modules folder as well in the zip.
As pointed by #Vijayanath Viswanathan, the issue is with how the zip file is created rather than Lambda.
I used to feed gulp-zip with this:
var src = gulp.src('src/**/*')
The correct way is to prevent folders from being included:
var src = gulp.src('src/**/*.js')
or (if you need to include file with other file extensions)
var src = gulp.src('src/**/*', {nodir: true})
I already have the relative path: /home/Folder1/Folder2 which its original absolute path is /home/user1/Folder1/Folder2. And I have several scripts that are using /home/Folder1/Folder2. Now, I need to delete user1 so I created user2 with the same structure of user1 so now I have a new path which is /home/user2/Folder1/Folder2. If I delete user1, my scripts will then fail because they are using the relative path /home/Folder1/Folder2 which its original absolute path is /home/user1/Folder1/Folder2. So I want my new path /home/user2/Folder1/Folder2 to point to /home/Folder1/Folder2 so that my scripts won't fail and I don't want to go through the trouble of opening each script and change the relative path to my new created path. Any idea how I can do this?
I guess, you got confused between soft links and absolute/relative path.
I assume you have a soft link created from "/home/Folder1/Folder2" pointing to "/home/user1/Folder1/Folder2" and you want to delete user1 directory and create user2 directory with same structure. If my assumption is right, recreate the softlink "/home/Folder1/Folder2" to point to "/home/user2/Folder1/Folder2". Your existing scripts will work seamlessly.
I am working on this Yeoman project, and I am copying some files from a template to my new app directory.
This line is doing the job well:
this.fs.copyTpl(this.templatePath(''),
this.destinationPath(this.project_name_slugified+'/'));
Everything comes from the template folder and goes to the root folder of the project.
But when someone adds a flag '--nr' I want to exclude one subfolder that has been copied. So yo my-gen my_app_name --rf should copy EVERYTHING unless this subfolder.
I tried the !-glob notation, but it's not working. I did something like as first parameter:
[this.templatePath('**'),this.templatePath('!subfolder/subfolder_to_be_excluded')]
So second parameter was set to exclude the subfolder that is not necessary
I also tried deleting (delete method), but it seems that the file is not available immediately.
It's not working anyway. Any ideas? Promisifying the copyTpl would work?
By calling this.templatePath('!subfolder/subfolder_to_be_excluded'), you end up generating a broken path: /absolute/path/!subfolder/etc.
Use it without this.templatePath given you don't need the absolute path to apply the filtering.
this.fs.copyTpl(
[
this.templatePath('**'),
'!subfolder/subfolder_to_be_excluded'
],
this.destinationPath(this.project_name_slugified + '/'),
templateContext
);
In my file system i have two directories containing subdirectories:
directory1
directory1_1
directory2
directory2_1
I want to serve both root directories (directory1, directory2) under the path /resources.
I tried to achieve this using serve-index (https://www.npmjs.com/package/serve-index):
app.use("/resources", serveIndex("/directory1", {icons:true}));
app.use("/resources", serveIndex("/directory2", {icons:true}));
The problem is, only the structure of directory1 is shown - directory2 is ignored.
I am looking for a way to serve the merged content of multiple directories.
Any ideas?
Thanks, Thomas
As i did not find a module, i implemented my own local module and took serve-index as a starting point.
The API now looks like this:
app.use("/resources", serveMergedIndex([ "directory1", "directory2" ]));
2 hours of work but works pretty well.
Thanks, Thomas