I wanted to do some regex search on strings and remove that part of the string that matches.
Eg. I have following strings
xyz-v1.0.0#
abc-v2.0.0#
def-v1.1.0#
So, for such cases, I wanted to remove -v1.0.0#, -v2.0.0# and -v1.1.0# from these strings.
So, for this what regex can I use and how can I remove them in Node JS?
You can do this
.replace(/-.*$/, '') will check for -{anything} at the end of the string and replace with nothing.
const strs = [
'xyz-v1.0.0#',
'abc-v2.0.0#',
'def-v1.1.0#'
];
const newStrs = strs.map(str => str.replace(/-.*$/, ''));
console.log(newStrs);
Related
So in my node code postgres query is returning double quotes when it's returning its values.
As opposed to the query at pgAdmin.
I already tried to solve it using regex but this attempt was innefective. So if anyone had a problem like this and could help me, I would be glad.
Thanks in advance
There are neither quotes nor extra back slashes in the string. They are part of the string representation as literal.
Try console.log(value) - or even directly console.log('/\\w/g') - and you'll see the output is /\w/g as expected.
To answer my own question, after a lot of reading and researching, I managed to discover that because a backslash character is a special character it will create some problems around its implementation in regex, because it is not permitted to have a lone backslash stored in a variable for example.
This would never work stored inside a variable because the backslash have to be escaped.
/\w+/ig
Javascript will transform it automatically to be able to perform.
/\w+/ig
When reading
RegExp - Javascript documentation, I came across an interesting statement, the RegExp function will recognize and use a double slash regex, thankfully!
So I just adapted my regex to split it's statement from it's flags and mount it again using RegExp.
Below is the code that I used to solve this problem
// Getting values from postgres
const values = (await pgConn.admRead.query(clientQuery)).rows[0].value || [];
// Splitting regex ( values: /\w/g )
const valuesSplit = values.split('/'); // RESULT -> ['', w, g]
// Removing first array item when it's empty
if (valuesSplit[0].length === 0) {
valuesSplit.shift();
}
// Creating regex from splitted array
const regexOperation = new RegExp(valuesSplit[0], valuesSplit[1]);
// Executing replace function
const messageMasked = message.replace(regexOperation, '*');
return messageMasked;
I'm trying to read any message sent on a discord server and send a reply if a certain string is within the message ignoring all spaces and capitals. I'm very new to javascript and this is the first code I'm making just for fun.
This is the current main part of the code.
if(msg.content.toLowerCase().includes('string'))
{
msg.channel.send(emoji("480351478930866179"));
}
You can remove whitespace with replace() and shift the string to lowercase using toLowerCase() to achieve the desired result.
const original = 'Hello there.';
const str = original.replace(/\s/g, '').toLowerCase();
if (str.includes('hello')) console.log('Hi.');
You could use the string.replace method or you could use split then join. To ignore case just use toLowerCase();
Thank's, that solved my problem.
const original = 'Hello there.';
const str = original.replace(/\s/g, '').toLowerCase();
if (str.includes('hello')) console.log('Hi.');
Spaces are useful to indent urls, sql queries to make it more readable.
Is there a way to remove characters from a const string at compile time in golang ?
ex: (runtime version)
const url = `https://example.com/path?
attr1=test
&attr2=test
`
// this is the code to be replaced
urlTrim := strings.Replace(
strings.Replace(url, "\n", "", -1)
)
Constant expressions cannot contain function calls (except a few built-in functions). So what you want cannot be done using a raw string literal.
If your goal with using multiple lines is just for readability, simply use multiple literals and concatenate them:
const url = "https://example.com/path?" +
"attr1=test" +
"&attr2=test"
Try it on the Go Playground.
See related question: Initialize const variable
i am fighting with a string splitting. I want to split string by wildcards into a slice, but this slice should contain this wildcards as well.
For example: /applications/{name}/tokens/{name} should be split into [/applications/ {name} /tokens/ {name}] etc.
Here is a sample code i wrote, but it is not working correctly, and i don't feel good about it either.
https://play.golang.org/p/VMOsJeaI4l
There are some example routes to be tested. Method splitPath split path into parts and display both: before and after.
Here is a solution:
var validPathRe = regexp.MustCompile("^(/{[[:alpha:]]+}|/[-_.[:alnum:]]+)+$")
var splitPathRe = regexp.MustCompile("({[[:alpha:]]+}|[-_.[:alnum:]]+)")
func splitPath(path string) parts{
var retPaths parts
if !validPathRe.MatchString(path) {
return retPaths
}
retPaths = splitPathRe.FindAllString(path, -1)
return retPaths
}
I made this by creating two regular expressions, one to check if the path was valid or not, the other to extract the various parts of the path and return them. If the path is not valid it will return an empty list. The return of this will look like this:
splitPath("/path/{to}/your/file.txt")
["path" "{to}" "your" "file.txt"]
This doesn't include the '/' character because you already know that all strings in the return but the last string is a directory and the last string is the file name. Because of the validity check you can assume this.
I am currently working on a project that dynamically displays DB content into table.
To edit the table contents i am want to use the dynamically created "string"+id value.
Is there any way to retrieve the appended int value from the whole string in javaScript?
Any suggestions would be appreciative...
Thanks!!!
If you know that the string part is only going to consist of letters or non-numeric characters, you could use a regular expression:
var str = "something123"
var id = str.replace(/^[^\d]+/i, "");
If it can consist of numbers as well, then things get complicated unless you can ensure that string always ends with a non-numeric character. In which case, you can do something like this:
var str = "something123"
var id = str.match(/\d+$/) ? str.match(/\d+$/)[0] : "";
(''+string.match(/\d+/) || '')
Explanation: match all digits in the variable string, and make a string from it (''+).
If there is no match, it would return null, but thanks to || '', it will always be a string.
You might try using the regex:
/\d+$/
to retrieve the appended number