Excel invisible question mark - excel

I have an extracted information from a system into an Excel file.
The names "Leone" seem the same but Excel recognize it differently.
Leone
​Leone
The length of the string is not the same, and if I check the value with VBA an invisible ? is the first character.
Could you help me how to get rid of the invisible characters?

To get rid of all invisible ? you may try this.
Sub CleanUnicode()
Dim n As Long, strClean As String, strChr As String
Dim ws As Worksheet
Set ws = ThisWorkbook.Sheets("Sheet3") 'change Sheet3 to data sheet
For Each cel In ws.Range("A1:A10") 'change A1:A10 to working range
strClean = cel.Value
For n = Len(strClean) To 1 Step -1
strChr = Mid(strClean, n, 1)
If AscW(strChr) = 8203 Then '? is unicode character 8203
strClean = Replace(strClean, strChr, "")
End If
Next
cel.Value = WorksheetFunction.Trim(strClean)
Next cel
End Sub
Instead of If AscW(strChr) = 8203 Then you can also use If AscW(strChr) > 255 Then.
EDIT 1 : As per the suggestion of #YowE3K. Assuming you only have Unicode 8203 in cells to be replaced.
Sub CleanUnicode()
Dim n As Long, strClean As String, strChr As String
Dim ws As Worksheet
Set ws = ThisWorkbook.Sheets("Sheet3") 'change Sheet3 to data sheet
For Each cel In ws.Range("A1:A10") 'change A1:A10 to working range
cel.Value = Replace(cel.Value, ChrW(8203), "")
Next cel
End Sub
Got this from here.

In general this is strange - this is how chrome renders the HTML from the question:
This is a workaround, that checks the characters of the string and builds a new one if one of them is equal to 63. Pretty much like a simple replace function:
Public Function removeInvisible(rngRange As Range) As String
Dim cnt As Long
For cnt = 1 To Len(rngRange)
If AscW(Mid(rngRange, cnt, 1)) <> 8203 Then
removeInvisible = removeInvisible & Mid(rngRange, cnt, 1)
End If
Next cnt
End Function

If the text has come from a copy/paste it might have taken in some other non printable characters.
These might be displayed in the VBA editor as ? which is often the way that unicode characters are rendered when the font does not support them.
I would try the formula
=CODE(LEFT(A3,1)) in one of the cells to see what the Unicode code point of the invisible character was.
If it turns out to be a non ascii chat then you could write a macro to strip out the characters that are problematic based on their code values.

To remove multiple occurrences of non-ascii characters from all cells of your range you can use this.
Option Explicit
Sub test()
Dim regEx As Object
Dim temparray() As String
Dim myrange As Range
Dim lrow As Long
Dim lcol As Long
Dim counter As Long
Dim i As Long
Dim j As Long
Set regEx = CreateObject("vbscript.regexp")
With regEx
.Pattern = "[^\u0000-\u007F]"
.MultiLine = False
.Global = True
.IgnoreCase = False
End With
'set your last row and column
lrow = 5
lcol = 5
ReDim temparray(1 To lrow, 1 To lcol)
Set myrange = Sheets("Sheet1").Range(Cells(1, 1), Cells(lrow, lcol))
Application.ScreenUpdating = False
counter = 0
For i = 1 To lrow
For j = 1 To lcol
temparray(i, j) = regEx.Replace(myrange.Cells(i, j).Value, "")
counter = counter + 1
Next j
Next i
myrange.Value = temparray
Application.ScreenUpdating = True
End Sub

Related

Replace any letter [A-Z] in a range with vba

I have a free text field that contains both text and numbers of varying lengths. I need to replace any letter in the column with "x". I have had success with replacing specific text using 'rng.replace' but need to include any letter [A-Z]
Dim rng as Range, lastRow As Long
lastRow = ActiveSheet.Range("A" & Rows.Count).Emd(xlUp).Row
Set rng = ActiveSheet.Range("E2:E" & lastRow)
rng.replace What:=[A-Z], Replacement:="x", MatchCase:=False
I cannot get the correct syntax for "What" to match any and all letters A-Z
Any help would be appreciated. I have a loop that works, however, it is very slow and stalling my overall process too much. I have worked the above rng.replace into speeding up the process for everything except this "text" replace.
Plenty of ways to skin a cat it seems.
Dim Number As Long
Dim Letter As String
Set Rng = Range("A1")
For Number = 1 To 28
Letter = Split(Cells(1, Number).Address, "$")(1)
Rng.Replace What:=(Letter), Replacement:="x", MatchCase:=False
Number = Range(Letter & 1).Column
Next
If performance is an issue, it's usually faster to do this by checking the byte values of the string array. Something like this:
Public Function ReplaceAlphas(txt As String) As String
Dim i As Long, a As Long
Dim b() As Byte
b = txt
For i = 0 To UBound(b) Step 2
a = b(i)
If (a >= 65 And a <= 90) Or (a >= 97 And a <= 122) Then
b(i) = 120
End If
Next
ReplaceAlphas = b
End Function
Try the next function, please:
Function removeLetters(strX As String) As String
With CreateObject("vbscript.regexp")
.Pattern = "[^0-9]" 'pattern to replace everything except numbers
.Global = True
removeLetters = .Replace(strX, "X")
End With
End Function
To use it for a range, please try the next code:
Sub testRngRemoveLetters()
Dim sh As Worksheet, rng As Range, C As Range, usedCol As Long, lastRow As Long
Set sh = ActiveSheet ' use here your sheet
usedCol = 2 'column B:B. Use the column number you need
lastRow = sh.cells(Rows.count, usedCol).End(xlUp).Row 'last row on the chosen column
'building the range to be processed:
Set rng = sh.Range(sh.cells(2, usedCol), sh.cells(lastRow, usedCol))
'Use the above function to replace everything else then numbers:
For Each C In rng
C.value = removeLetters(C.value)
Next
End Sub
Please, test it and send some feedback...

Unable to search and replace the values using column headers

I'm trying to create a vba script that will search for the _ in all the cells fallen under Crude Items column. However, when it finds one, it will split the values from _ and place the rest in corresponding cells fallen under Refined Ones column.
I've tried with the following which is doing the job flawlessly but I wish to search and replace the values using column headers:
Sub CopyAndReplace()
Dim cel As Range
For Each cel In Range("A2:A" & Cells(Rows.Count, 1).End(xlUp).row)
If cel.value <> "" Then
Sheets("Sheet1").Range(cel(1, 3).Address) = Split(cel, "_")(1)
End If
Next cel
End Sub
To let you visualize how the sheet might look like:
How can I search and replace the values using column headers?
I am not sure this is what you are after, but a few important mentions...
Try to always use at least a worksheet qualifier when writing your code. How else is your program going to know explicitly where you would like it to operate?
I have changed your process slightly, but again, not sure if this is exactly what you are after. See below code.
Sub SplitByHeader()
Dim i As Long
Dim crudeHeader As Range, refinedHeader As Range
Dim ws As Worksheet
'set ws
Set ws = ThisWorkbook.Sheets("Sheet1")
'set header ranges
Set crudeHeader = ws.Rows(1).Find(What:="Crude Items", LookAt:=xlWhole)
Set refinedHeader = ws.Rows(1).Find(What:="Refined Ones", LookAt:=xlWhole)
'simple error handler
If crudeHeader Is Nothing Or refinedHeader Is Nothing Then Exit Sub
For i = 2 To ws.Cells(ws.Rows.Count, crudeHeader.Column).End(xlUp).Row
If ws.Cells(i, crudeHeader.Column).Value <> "" Then
ws.Cells(i, refinedHeader.Column).Value = Split(ws.Cells(i, crudeHeader.Column).Value, "_")(1)
End If
Next i
End Sub
I have just tried this one with the code below:
It is a good idea to add additional check to the condition, like this - If myCell.Value <> "" And InStr(1, myCell, "_") Then to avoid starting from A2.
The idea is that the LocateValueCol locates the column of the first row, which has the string, passed to it. Knowing this, it works ok.
Option Explicit
Sub CopyAndReplace()
Dim searchColumn As Long
searchColumn = LocateValueCol("SearchCol", Worksheets(1))
Dim replaceColumn As Long
replaceColumn = LocateValueCol("ReplaceCol", Worksheets(1))
Dim myCell As Range
Dim lastCell As Long
With Worksheets(1)
lastCell = .Cells(.Rows.Count, searchColumn).End(xlUp).Row
For Each myCell In .Range(.Cells(1, searchColumn), .Cells(lastCell, searchColumn))
If myCell.Value <> "" And InStr(1, myCell, "_") Then
.Cells(myCell.Row, replaceColumn) = Split(myCell, "_")(1)
End If
Next
End With
End Sub
This is the function, locating the columns. (If you have ideas for improvement, feel free to make a PR here):
Public Function LocateValueCol(ByVal textTarget As String, _
ByRef wksTarget As Worksheet, _
Optional rowNeeded As Long = 1, _
Optional moreValuesFound As Long = 1, _
Optional lookForPart = False, _
Optional lookUpToBottom = True) As Long
Dim valuesFound As Long
Dim localRange As Range
Dim myCell As Range
LocateValueCol = -999
valuesFound = moreValuesFound
Set localRange = wksTarget.Range(wksTarget.Cells(rowNeeded, 1), wksTarget.Cells(rowNeeded, Columns.Count))
For Each myCell In localRange
If lookForPart Then
If textTarget = Left(myCell, Len(textTarget)) Then
If valuesFound = 1 Then
LocateValueCol = myCell.Column
If lookUpToBottom Then Exit Function
Else
Decrement valuesFound
End If
End If
Else
If textTarget = Trim(myCell) Then
If valuesFound = 1 Then
LocateValueCol = myCell.Column
If lookUpToBottom Then Exit Function
Else
Decrement valuesFound
End If
End If
End If
Next myCell
End Function
Private Sub Increment(ByRef valueToIncrement As Variant, Optional incrementWith As Double = 1)
valueToIncrement = valueToIncrement + incrementWith
End Sub
Private Sub Decrement(ByRef valueToDecrement As Variant, Optional decrementWith As Double = 1)
valueToDecrement = valueToDecrement - decrementWith
End Sub
For fun using regex and dynamically finding header columns. You can swop out the regex based function for your own and still have the dynamic column finding.
Option Explicit
Public Sub test()
Dim i As Long, inputs(), re As Object, ws As Worksheet
Dim inputColumn As Range, outputColumn As Range, inputColumnNumber As Long, outputColumnNumber As Long
Const SEARCH_ROW As Long = 1
Const INPUT_HEADER As String = "Crude items"
Const OUTPUT_HEADER As String = "Refined Ones"
Const START_ROW = 2
Set re = CreateObject("VBScript.RegExp")
Set ws = ThisWorkbook.Worksheets("Sheet1")
Set inputColumn = GetColumnByHeader(ws, SEARCH_ROW, INPUT_HEADER)
Set outputColumn = GetColumnByHeader(ws, SEARCH_ROW, OUTPUT_HEADER)
If inputColumn Is Nothing Or outputColumn Is Nothing Then Exit Sub
inputColumnNumber = inputColumn.Column
outputColumnNumber = outputColumn.Column
With ws
inputs = Application.Transpose(.Range(.Cells(START_ROW, inputColumnNumber), .Cells(.Cells(.Rows.Count, inputColumnNumber).End(xlUp).Row, inputColumnNumber)).Value)
For i = LBound(inputs) To UBound(inputs)
inputs(i) = GetMatch(re, inputs(i))
Next
.Cells(START_ROW, outputColumnNumber).Resize(UBound(inputs), 1) = Application.Transpose(inputs)
End With
End Sub
Public Function GetColumnByHeader(ByVal ws As Worksheet, ByVal SEARCH_ROW As Long, ByVal columnName As String) As Range
Set GetColumnByHeader = ws.Rows(SEARCH_ROW).Find(columnName)
End Function
Public Function GetMatch(ByVal re As Object, ByVal inputString As String) As String
With re
.Global = True
.MultiLine = True
.Pattern = "_(.*)"
If .test(inputString) Then
GetMatch = .Execute(inputString)(0).SubMatches(0)
Else
GetMatch = inputString 'or =vbNullString if want to return nothing
End If
End With
End Function
If you are working through an actual table things will become quite easy:
Sub Test()
Dim arr(), x As Long
With ThisWorkbook.Sheets("Sheet1") 'Change accordingly
For Each cl In .Range("Table1[Crude Items]") 'Change Table1 accordingly
ReDim Preserve arr(x)
If InStr(cl, "_") > 0 Then
arr(x) = Split(cl, "_")(1)
Else
arr(x) = ""
End If
x = x + 1
Next cl
.Range("Table1[Refined Ones]").Value = Application.Transpose(arr)
End With
End Sub
There is a check for "_". If not there, the cell will be kept empty.
You can also consider to use formula to do it.
I am not clear about what you want to replace "_" character with. For example, iff you replace the following line of your script:
Sheets("Sheet1").Range(cel(1, 3).Address) = Split(cel, "_")(1)
with this one:
Sheets("Sheet1").Range(cel(1, 3).Address) = WorksheetFunction.Substitute(cel, "_", "")
The above line should replace the "_" character with nothing from the cells in the Crude_Items column
And as Lee said, you can also consider using formula in the worksheet if you do not have significant amount of data

How to highlight substring using LIKE operator in Excel VBA

I have strings that look like this:
DTTGGRKDVVNHCGKKYKDK
RKDVVNHCGKKYKDKSKRAR
What I want to do is to highlight the region with bold and red font.
Resulting this:
I tried the following code using LIKE operator in Excel VBA but it breaks
at this line Set MC = .Execute(C.Text)
Option Explicit
Sub boldSubString()
Dim R As Range, C As Range
Dim MC As Object
Set R = Range(Cells(2, 1), Cells(Rows.Count, 1).End(xlUp))
For Each C In R
C.Font.Bold = False
If C.Text Like "KK*K" Or C.Text Like "KR*R" Then
Set MC = .Execute(C.Text)
C.Characters(MC(0).firstindex + 1, MC(0).Length).Font.Bold = True
End If
Next C
End Sub
What's the right way to do it?
I'm using Mac Excel Version 15.31
Without Regular Expressions, you can try the following. I've not tested it extensively but it does seem to work even with multiple matching substrings within the same string.
Examine VBA HELP for the functions that are being used, so you understand how this works, and also how to construct proper patterns to be used with the Like operator, in case you need to expand the list of possible patterns.
Option Explicit
Sub boldSS()
Dim WS As Worksheet
Dim R As Range, C As Range
Dim sPatterns(1) As String
Dim I As Long, J As Long
sPatterns(0) = "KR?R"
sPatterns(1) = "KK?K"
Set WS = Worksheets("sheet1")
With WS
Set R = .Range(.Cells(1, 1), .Cells(.Rows.Count, 1).End(xlUp))
End With
For Each C In R
'Reset to default
With C.Font
.Bold = False
.Color = vbBlack
End With
For I = 0 To UBound(sPatterns)
If C Like "*" & sPatterns(I) & "*" Then
For J = 1 To Len(C) - Len(sPatterns(I)) + 1
If Mid(C, J, Len(sPatterns(I))) Like sPatterns(I) Then
With C.Characters(J, Len(sPatterns(I))).Font
.Bold = True
.Color = vbRed
End With
If J < Len(C) - 3 Then
J = J + 3
Else
Exit For
End If
End If
Next J
End If
Next I
Next C
End Sub
Using your regex pattern equivalent instead for the Like operator, you can rewrite the above as below. Note that your Regex pattern will also match KKAR, and KRAK (as does the macro below, but not the one above).
Option Explicit
Sub boldSS()
Dim WS As Worksheet
Dim R As Range, C As Range
Dim sPattern As String
Dim I As Long
sPattern = "K[KR]?[KR]"
Set WS = Worksheets("sheet1")
With WS
Set R = .Range(.Cells(1, 1), .Cells(.Rows.Count, 1).End(xlUp))
End With
For Each C In R
With C.Font
.Bold = False
.Color = vbBlack
End With
If C Like "*" & sPattern & "*" Then
For I = 1 To Len(C) - 4 + 1
If Mid(C, I, 4) Like sPattern Then
With C.Characters(I, 4).Font
.Bold = True
.Color = vbRed
End With
If I < Len(C) - 3 Then
I = I + 3
Else
Exit For
End If
End If
Next I
End If
Next C
End Sub
SubString problems could be complicated, once one drills a bit in them. E.g., in the OP example, the substring KKYKDKSK also is a correct substring of KK*K, thus, it probably could be color coded as well.
In general, with some limitations the task, like searching for non-overlapping substrings and considering that the substring is present once per string, this is possible:
With some hardcoding of the variables and checking only for KK*K, this is how the main method looks like:
Option Explicit
Sub TestMe()
Dim myRange As Range: Set myRange = Worksheets(1).Range("A1:A2")
Dim myCell As Range
For Each myCell In myRange
myCell.Font.Bold = False
Dim subString As String
subString = findTheSubString(myCell.Value2, "KK*K")
Debug.Print myCell.text, subString
ChangeTheFont subString, myCell, vbBlue
Next myCell
End Sub
The function findTheSubString() takes the 2 strings and returns the substring, which is to be color-coded later:
Public Function findTheSubString(wholeString As String, subString As String) As String
Dim regEx As Object
Dim inputMatches As Object
Dim regExString As String
Set regEx = CreateObject("VBScript.RegExp")
With regEx
.Pattern = Split(subString, "*")(0) & "[\s\S]*" & Split(subString, "*")(1)
.IgnoreCase = True
.Global = True
Set inputMatches = .Execute(wholeString)
If regEx.test(wholeString) Then
findTheSubString = inputMatches(0)
Else
findTheSubString = "Not Found!"
End If
End With
End Function
The last part is to change the font of a specific substring in Excel range, thus the arguments are a string and a range:
Sub ChangeTheFont(lookFor As String, currentRange As Range, myColor As Long)
Dim startPosition As Long: startPosition = InStr(1, currentRange.Value2, lookFor)
Dim endPosition As Long: endPosition = startPosition + Len(currentRange.Value2)
With currentRange.Characters(startPosition, Len(lookFor)).Font
.Color = myColor
.Bold = True
End With
End Sub

Shortening words based on database in Excel VBA

I am currently trying to replace words in a cell with shorter versions in mass. I have a dictionary of words to make shorter and will have a column of cells that need to have one or more of the words shortened.
I am very new to VBA and I'm not sure how I would go about this. I tried searching and found some that would be changing text in a word doc but nothing from Excel to excel, at least with my search terms.
I have added a picture here of the Idea, the Text to be shortened is in column A, the words that can be shortened are in column C and the shortened versions are in column D.
Sample
Here's a full sub version if that works better for you
Sub ReplaceViaList()
Dim ws As Worksheet
Dim repRng As Range
Dim x As Long, lastRow As Long
Dim repCol As Long, oldCol As Long, newCol As Long
Dim oldStr As String, newStr As String
'screenupdating/calc
Application.Calculation = xlCalculationManual
Application.ScreenUpdating = False
'define worksheet
Set ws = ActiveSheet
'define columns to work with
repCol = 1 'col A
oldCol = 3 'col C
newCol = 4 'col D
'find last row of replacement terms
lastRow = ws.Cells(ws.Rows.Count, repCol).End(xlUp).Row
'set range of items to be replaced
Set repRng = ws.Range( _
ws.Cells(2, repCol), _
ws.Cells(lastRow, repCol) _
)
'loop through cells in replacement terms
For x = 2 To ws.Cells(ws.Rows.Count, oldCol).End(xlUp).Row
'define replacement terms
oldStr = ws.Cells(x, oldCol).Value
newStr = ws.Cells(x, newCol).Value
'replace
repRng.Replace What:=oldStr, Replacement:=newStr
Next x
'screenupdating/calc
Application.Calculation = xlCalculationAutomatic
Application.ScreenUpdating = True
End Sub
You can use this UDF.
Function SubstituteMultiple(text As String, old_text As Range, new_text As Range)
Dim i As Single
For i = 1 To old_text.Cells.Count
Result = Replace(LCase(text), LCase(old_text.Cells(i)), LCase(new_text.Cells(i)))
text = Result
Next i
SubstituteMultiple = Result
End Function
Place this code in your regular module. then write this formula =SubstituteMultiple(A2,$C$2:$C$11,$D$2:$D$11) in cell B2 and drag it to the bottom.
Perhaps simple replace in VBA would do it,
Sub test()
Dim searchval As Variant
Dim replaceval As Variant
searchval = Range("C1:C10")
replaceval = Range("D1:D10")
For i = 1 To 10
Columns("A:A").Replace What:=searchval(i, 1), Replacement:=replaceval(i, 1), LookAt:=xlPart
Next i
End Sub

Excel VBA word match count fix

I have this bit of code below that is very close to what I am looking to do. How it works is you press the “List Word Issue” button in the excel spreadsheet and it scans all the text, cell by cell and row by row in column A, against a separate worksheet containing a list of words. If there is a match (between what’s in each individual cell in column 1) then it puts the word(s) that match into the adjacent row in column b.
Here (http://mintywhite.com/more/software-more/microsoft-excel-analyze-free-text-surveys-feedback-complaints-part-2) is a link to the article that I found the code on and a link (http://mintywhite.com/wp-content/uploads/2011/02/wordcount2.xls) to download the entire .xls spreadsheet.
What I am looking for is a simple change so there will not be a “match” unless the word appears at least 5 times in each cell/row in column A of the first worksheet.
Sub WordCount()
Dim vArray, WordIssue, ElementCounter As Variant
Dim lngLoop, lngLastRow As Long
Dim rngCell, rngStoplist As Range
ElementCounter = 2 'setting a default value for the counter
Worksheets(1).Activate
For Each rngCell In Worksheets("Word").Range("A3", Cells(Rows.Count, "A").End(xlUp))
vArray = Split(rngCell.Value, " ") 'spliting the value when there is a space
vrWordIssue = ""
ElementCounter = ElementCounter + 1 'increases the counter every loop
For lngLoop = LBound(vArray) To UBound(vArray)
If Application.WorksheetFunction.CountIf(Sheets("Issue").Range("A2:A" & Sheets("Issue").UsedRange.Rows.Count), vArray(lngLoop)) > 0 Then 'this is to test if the word exist in the Issue Sheet.
If vrWordIssue = "" Then
vrWordIssue = vArray(lngLoop) 'assigning the word
Else
If InStr(1, vrWordIssue, vArray(lngLoop)) = 0 Then 'a binary of comparison
vrWordIssue = vrWordIssue & ", " & vArray(lngLoop) 'this will concatinate words issue that exist in Issue Sheet
End If
End If
End If
Next lngLoop
Worksheets("Word").Range("B" & ElementCounter).Value = vrWordIssue 'entering the final word issue list into cell.
Next rngCell
End Sub
Quick comment about some of the code, if you're interested:
Dim lngLoop, lngLastRow As Long
lngLoop is actually Variant, not a long. Unfortunately, you cannot declare data types like this as you can in, say, C++.
You need to do this instead:
Dim lngLoop As Long, lngLastRow As Long
Also, WordIssue is never used. It is supposed to be vrWordIssue.
In fact, I would almost never use Variant for anything in VBA. I don't believe this author of that website knows a good amount of VBA. (at least, not when they wrote that)
That said, the first thing I would fix are the variables:
From:
Dim vArray, WordIssue, ElementCounter As Variant
Dim lngLoop, lngLastRow As Long
Dim rngCell, rngStoplist As Range
To:
Dim vArray As Variant
Dim vrWordIssue As String
Dim ElementCounter As Long
Dim lngLoop As Long, lngLastRow As Long
Dim rngCell As Range, rngStoplist As Range
And add Option Explicit to the top of the module. This will help with debugging.
...And you don't almost never have to use Activate for anything...
....you know what? I would just use a different approach entirely. I don't like this code to be honest.
I know it's not encouraged to provide a full-blown solution, but I don't like not-so-good code being spread around like that (from the website that Douglas linked, not necessarily that Douglas wrote this).
Here's what I would do. This checks against issue words with case-sensitivity, by the way.
Option Explicit
Public Type Issues
Issue As String
Count As Long
End Type
Const countTolerance As Long = 5
Public Sub WordIssues()
' Main Sub Procedure - calls other subs/functions
Dim sh As Excel.Worksheet
Dim iLastRow As Long, i As Long
Dim theIssues() As Issues
Set sh = ThisWorkbook.Worksheets("Word")
theIssues = getIssuesList()
iLastRow = sh.Cells(sh.Rows.Count, 1).End(xlUp).Row
' loop through worksheet Word
For i = 3 To iLastRow
Call evaluateIssues(sh.Cells(i, 1), theIssues)
Call clearIssuesCount(theIssues)
Next i
End Sub
Private Function getIssuesList() As Issues()
' returns a list of the issues as an array
Dim sh As Excel.Worksheet
Dim i As Long, iLastRow As Long
Dim theIssues() As Issues
Set sh = ThisWorkbook.Sheets("Issue")
iLastRow = sh.Cells(sh.Rows.Count, 1).End(xlUp).Row
ReDim theIssues(iLastRow - 2)
For i = 2 To iLastRow
theIssues(i - 2).Issue = sh.Cells(i, 1).Value
Next i
getIssuesList = theIssues
End Function
Private Sub clearIssuesCount(ByRef theIssues() As Issues)
Dim i As Long
For i = 0 To UBound(theIssues)
theIssues(i).Count = 0
Next i
End Sub
Private Sub evaluateIssues(ByRef r As Excel.Range, ByRef theIssues() As Issues)
Dim vArray As Variant
Dim i As Long, k As Long
Dim sIssues As String
vArray = Split(r.Value, " ")
' loop through words in cell, checking for issue words
For i = 0 To UBound(vArray)
For k = 0 To UBound(theIssues)
If (InStr(1, vArray(i), theIssues(k).Issue, vbBinaryCompare) > 0) Then
'increase the count of issue word
theIssues(k).Count = theIssues(k).Count + 1
End If
Next k
Next i
' loop through issue words and see if it meets tolerance
' if it does, add to the Word Issue cell to the right
For k = 0 To UBound(theIssues)
If (theIssues(k).Count >= countTolerance) Then
If (sIssues = vbNullString) Then
sIssues = theIssues(k).Issue
Else
sIssues = sIssues & ", " & theIssues(k).Issue
End If
End If
Next k
r.Offset(0, 1).Value = sIssues
End Sub

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