Regressive call in promise - node.js

Question

Is there any easy way to do recursive call using promise. Here is my sample.
function getData() {
var result=[];
var deferred = Q.defer();
(function fetchData(pageno){
var options = {
method : 'GET',
url : 'example.com/test',
qs:{
pageNo: pageno
}
}
request(options, function (error, response, body) {
if (error)throw new Error(error);
if (body.hasMorePage == true) { //checking is there next page
result.push(body)
fetchData(++body.pageno); // getting next page data
} else {
deferred.resolve(result); // promise resolve when there is no more page
}
});
})(0);
return deferred.promise;
}
getData().then(function(data){
console.log(data)
});
Let's consider API is giving more data in consecutive calls. in order to collect all the data, I need to use some parameter (EX:hasMorePage) from previous call response. I need to go regressive call only for obtaining this scenario, but I would like to know a better(Promise) way.
Most welcome.

Answer 1

async function request(options, callback) {
// simulate server response of example.com/test with 1 second delay
const totalNumberOfPages = 3;
const pageNo = options.qs.pageNo;
await new Promise(resolve => setTimeout(resolve, 1000));
const hasMorePages = pageNo < totalNumberOfPages;
const body = { hasMorePages };
callback(void 0, { body }, body);
}
function getPage(pageNo) {
const options = {
method: 'GET',
url: 'example.com/test',
qs: { pageNo }
};
return new Promise(resolve => request(options, (error, response, body) => {
console.log('response received', response);
if(error) {
throw new Error(error);
}
resolve(body);
}));
}
async function getData() {
const result = [];
for(let i = 1, hasMorePages = true; hasMorePages; i++) {
const body = await getPage(i);
result.push(body);
hasMorePages = body.hasMorePages;
}
return result;
}
getData().then(data => console.log('RESULT', data));