LinkedIn HTTP Error 999 - Request denied - python-3.x

I am writing a simple script to get public profile visible without login on LinkedIn.
Below is my code to get the page for beautifulsoup. I am using public proxies as well.
import urllib.request, urllib.error
from bs4 import BeautifulSoup
url = "https://www.linkedin.com/company/amazon"
proxy = urllib.request.ProxyHandler({'https': proxy, })
opener = urllib.request.build_opener(proxy)
urllib.request.install_opener(opener)
hdr = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3218.0 Safari/537.36',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3',
'Accept-Encoding': 'gzip, deflate, br',
'Accept-Language': 'en-US,en;q=0.9,hi;q=0.8',
'Connection': 'keep-alive'}
req = urllib.request.Request(url, headers=hdr)
page = urllib.request.urlopen(req, timeout=20)
self.soup = BeautifulSoup(page.read(), "lxml")
But it is raising "HTTPError 999 - request Denied" error. This is only for testing purpose till I am getting access via partnership program.
What am I doing wrong? Please help.

You did not do anything wrong, LinkedIn blacklist cloud servers ip addresses to prevent "stealing" their data. Questionable practice but this is how it is.

Related

Scraping kenpom data in 2023

I have been scouring across the web to figure out how to use beautifulsoup and pandas to scrape kenpom.com college basketball data. I do not have an account to his website, hence why I am not using the kenpompy library. I have seen some past examples to scrape it from years past, including using the pracpred library (though I have zero experience on it, I'll admit) or using the curlconverter to grab the headers, cookies, and parameters during the requests.get, but now the website seems stingier in terms of grabbing the main table these days. I have used the following code so far:
import requests
from bs4 import BeautifulSoup
url ='https://kenpom.com/index.php?y=2023'
import requests
import requests
cookies = {
'PHPSESSID': 'f04463ec42584dbd1bf7a480098947d1',
'_ga': 'GA1.2.120164513.1673124870',
'_gid': 'GA1.2.622021765.1673496414',
'__stripe_mid': '71a4117b-cbef-4d3c-b31b-9d18e5c99a33183485',
'__stripe_sid': '99b77b80-1222-4f7a-b2a8-acf5cf19c7d18a637f',
'kenpomtry': 'https%3A%2F%2Fkenpom.com%2Fsummary.php%3Fs%3DRankAPL_Off%26y%3D2021',
'_gat_gtag_UA_11558853_1': '1',
}
headers = {
'authority': 'kenpom.com',
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9',
'accept-language': 'en-US,en;q=0.9',
# 'cookie': 'PHPSESSID=f04463ec42584dbd1bf7a480098947d1; _ga=GA1.2.120164513.1673124870; _gid=GA1.2.622021765.1673496414; __stripe_mid=71a4117b-cbef-4d3c-b31b-9d18e5c99a33183485; __stripe_sid=99b77b80-1222-4f7a-b2a8-acf5cf19c7d18a637f; kenpomtry=https%3A%2F%2Fkenpom.com%2Fsummary.php%3Fs%3DRankAPL_Off%26y%3D2021; _gat_gtag_UA_11558853_1=1',
'sec-ch-ua': '"Not?A_Brand";v="8", "Chromium";v="108", "Google Chrome";v="108"',
'sec-ch-ua-mobile': '?0',
'sec-ch-ua-platform': '"Windows"',
'sec-fetch-dest': 'document',
'sec-fetch-mode': 'navigate',
'sec-fetch-site': 'none',
'sec-fetch-user': '?1',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/108.0.0.0 Safari/537.36',
}
params = {
'y': '2023',
}
response = requests.get('https://kenpom.com/index.php', params=params, cookies=cookies, headers=headers)
soup = BeautifulSoup(response.text, 'html.parser')
soup
# table = soup.find('table',{'id':'ratings-table'}).tbody
Any suggestions beyond this would be truly appreciated.
Using requests and adding UserAgent as headers (It's pretty messy with multiple hierarchal indexes so will need further parsing to clean completely):
import pandas as pd
import requests
from bs4 import BeautifulSoup
headers = {
"User-Agent":
"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.5112.79 Safari/537.36"
}
url = "https://kenpom.com/index.php?y=2023"
with requests.Session() as request:
response = request.get(url, timeout=30, headers=headers)
if response.status_code != 200:
print(response.raise_for_status())
soup = BeautifulSoup(response.text, "html.parser")
df = pd.concat(pd.read_html(str(soup)))

Scraping values from View Source using Requests Python 3

So this code below is working fine but when i change the url to another site it doesn't work
import requests
import re
url = "https://www.autotrader.ca/a/ram/1500/hamilton/ontario/19_12052335_/?showcpo=ShowCpo&ncse=no&ursrc=pl&urp=2&urm=8&sprx=-2"
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/62.0.3202.94 Safari/537.36'}
response = requests.get(url, headers=headers)
phone_number = re.findall('"phoneNumber":"([\d-]+)"', response.text)
print(phone_number)
['905-870-7127']
This code below doesn't work it gives the output [] Please tell me what am i doing wrong
import requests
import re
urls = "https://www.kijijiautos.ca/vip/22686710/","https://www.kijijiautos.ca/vip/22686710/"
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/62.0.3202.94 Safari/537.36'}
for url in urls:
response = requests.get(url, headers=headers)
number = re.findall('"number":"([\d-]+)"', response.text)
print(number)
[]
I think you are not getting The HTTP 200 OK success status as a response.for that cause you are unable to get the exptected ouptput. To get the HTTP 200 OK success status, I have changed the headers from inspecting http requests.
please try this
import requests
import re
import requests
headers = {
'authority': 'www.kijijiautos.ca',
'sec-ch-ua': '"Chromium";v="94", "Google Chrome";v="94", ";Not A Brand";v="99"',
'pragma': 'no-cache',
'accept-language': 'en-CA',
'sec-ch-ua-mobile': '?0',
'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/94.0.4606.81 Safari/537.36',
'content-type': 'application/json',
'accept': 'application/json',
'cache-control': 'no-cache',
'x-client-id': 'c89e7ff8-1d5a-4c2b-a095-c08dc08ccd3b',
'x-client': 'ca.move.web.app',
'sec-ch-ua-platform': '"Linux"',
'sec-fetch-site': 'same-origin',
'sec-fetch-mode': 'cors',
'sec-fetch-dest': 'empty',
'referer': 'https://www.kijijiautos.ca/cars/hyundai/sonata/used/',
'cookie': 'mvcid=c89e7ff8-1d5a-4c2b-a095-c08dc08ccd3b; locale=en-CA; trty=e; _gcl_au=1.1.1363596757.1633936124; _ga=GA1.2.1193080228.1633936126; _gid=GA1.2.71842091.1633936126; AAMC_kijiji_0=REGION%7C3; aam_uuid=43389576784435124231935699643302941454; _fbp=fb.1.1633936286669.1508597061; __gads=ID=bb71a6fc168c1c33:T=1633936286:S=ALNI_MZk3lgy-9xgSGLPnfrkBET60uS6fA; GCLB=COyIgrWs-PWPsQE; lux_uid=163402080128473094; cto_bundle=zxCnjF95NFglMkZrTG5EZ2dzNHFSdjJ6QSUyQkJvM1BUbk5WTkpjTms0aWdZb3RxZUR3Qk1nd1BmcSUyQjZaZVFUdFdSelpua3pKQjFhTFk0U2ViTHVZbVg5ODVBNGJkZ2NqUGg1cHZJN3V0MWlwRkQwb1htcm5nNDlqJTJGUUN3bmt6ZFkzU1J0bjMzMyUyRkt5aGVqWTJ5RVJCa2ZJQUwxcFJnJTNEJTNE; _td=7f855061-c320-4570-b2d2-73c94bd22b13; rbzid=54THgSkyCRKwhVBqy+iHmjb1RG+uE6uH1XjpsXIazO5nO45GtpIXHGYii/PbJcdG3ahjIgKaBrjh0Yx2J6YCOLHEv3QYL559oz3jQaVrssH2/1Ui9buvIpuCwBOGG2xXGWW2qvcU5807PGsdubQDUvLkxmy4sor+4EzCI1OoUHMOG2asQwsgChqwzJixVvrE21E/NJdRfDLlejb5WeGEgU4B3dOYH95yYf5h+7fxV6H/XLhqbNa8e41DM3scfyeYWeqWCWmOH2VWZ7i3oQ0OXW1SkobLy0D6G+V9J5QMxb0=; rbzsessionid=ca53a07d3404ca93b3f8bc879291dc83; _uetsid=131a47702a6211ecba407d9ff6588dde; _uetvid=131b13602a6211ecacd0b56b0815e9b2',
}
response = requests.get('https://www.kijijiautos.ca/consumer/svc/a/22686710', headers=headers)
if response.status_code == 200:
# print(response.text)
numbers = re.findall(r'"number":"\+\d+"', response.text) # number one or more
print(numbers[0])
else:
print('status code is ', response.status_code)
output
# "number":"+17169905088"

How to prevent beautifulsoap from extracting the information as strange symbols?

I am trying to extract an information with beautifulsoap, however when I do it it extracts it with very rare symbols. But when I enter directly to the page everything looks good and the page has the label <meta charset="utf-8">
my code is:
HEADERS = {
'user-agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.87 Safari/537.36',
'referrer': 'https://google.com',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Encoding': 'gzip, deflate, br',
'Accept-Language': 'en-US,en;q=0.9',
'Pragma': 'no-cache',
}
urls = 'https://www.jcchouinard.com/web-scraping-with-python-and-requests-html/'
r = requests.get(urls, headers=HEADERS)
soup = bs4.BeautifulSoup(r.text, "html.parser")
print (soup)
Nevertheless, the result I get is this:
J{$%X Àà’8}±ŸÅ
I guess it's something with the encoding, however I don't understand why since the page is utf-8.
It is worth clarifying that this only happens in some cases, since with others I manage to extract the information without problems.
Edit: updated with a sample url.
Edit2: added the headers dictionary, which is the one that generates the problem.
The problem is Accept-Encoding HTTP header. There you have br specified, which means brotli compression method. requests module cannot handle that. Remove br and the server responds without this compression method.
import requests
from bs4 import BeautifulSoup
HEADERS = {
'user-agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/56.0.2924.87 Safari/537.36',
'referrer': 'https://google.com',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'Accept-Encoding': 'gzip, deflate', # <-- remove br
'Accept-Language': 'en-US,en;q=0.9',
'Pragma': 'no-cache',
}
urls = 'https://www.jcchouinard.com/web-scraping-with-python-and-requests-html/'
r = requests.get(urls, headers=HEADERS)
soup = BeautifulSoup(r.text, "html.parser")
print (soup)
Prints:
<!DOCTYPE html>
<html lang="fr-FR">
<head><style>img.lazy{min-height:1px}</style><link as="script" href="https://www.jcchouinard.com/wp-content/plugins/w3-total-cache/pub/js/lazyload.min.js?x73818" rel="preload"/>
...and so on.
import requests
from bs4 import BeautifulSoup
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:79.0) Gecko/20100101 Firefox/79.0'
}
def main(url):
r = requests.get(url, headers=headers)
soup = BeautifulSoup(r.content, 'html.parser')
print(soup.prettify())
main("https://www.jcchouinard.com/web-scraping-with-python-and-requests-html/")
You've just to add headers

How to show the hidden contents under "View More" when using Selenium - Python

driver = webdriver.Chrome(r'XXXX\chromedriver.exe')
FB_bloomberg_URL = 'https://www.bloomberg.com/quote/FB:US'
driver.get(FB_bloomberg_URL)
board_members = driver.find_elements_by_xpath('//* [#id="root"]/div/div/section[3]/div[10]/div[1]/div[2]/div/div[2]')[0]
board=board_members.text
board.split('\n')
I wrote the coding above to scrape the board information from Bloomberg for FaceBook. But I have trouble to extract all board members because others are hidden behind the "View More". How can I extract all names?
Thanks for the help.
You can do whole thing with requests and grab the appropriate cookie to pass to API from prior GET. The API can be found in the network tab when clicking the view more link and inspecting the web traffic.
import requests
headers = {
'dnt': '1',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.9',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36',
'accept': '*/*',
'referer': 'https://www.bloomberg.com/quote/FB:US',
'authority': 'www.bloomberg.com',
'cookie':''
}
with requests.Session() as s:
r = s.get('https://www.bloomberg.com/quote/FB:US')
headers['cookie'] = s.cookies.get_dict()['_pxhd']
r = s.get('https://www.bloomberg.com/markets2/api/peopleForCompany/11092218', headers = headers).json()
board_members = [item['name'] for item in r['boardMembers']]
print(board_members)

Unable to read requests HTML response from a URL

I am using python requests library for making http requests. For this website : https://www.epi.org/resources/budget/ i am unable to read the HTML response as it is not human readable , looks like its protected by cloudfare ddos protection . Here is my simple code below.
import requests
headers = {'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.9,pt;q=0.8',
'cache-control': 'max-age=0',
'user-agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.110 Safari/537.36',
'upgrade-insecure-requests': '1'}
s = requests.Session()
a = s.get('https://www.epi.org/resources/budget/',headers=headers)
print (a.text)
The response HTML looks like this : https://justpaste.it/6ie73
The reason why got unreadable content is Accept-Encoding. Differ from browser, if Python got gzip response we have to unpack it by ourselves. Also br need to do so but with different module brotl . So you should set 'Accept-Encoding': 'default'. Btw, if you need full content that rendering is necessary.

Resources