Hoping to sort (below left) by sector but distribute evenly (below right):
Name
Sector.
Name.
Sector
A
1
A
1
B
1
E
2
C
1
H
3
D
4
D
4
E
2
B
1
F
2
F
2
G
2
J
3
H
3
I
4
I
4
C
1
J
3
G
2
Real data is 70+ rows with 4 sectors.
I've worked around it manually but would love to figure out how to do it with a formula in excel.
Here's a more complete (and hopefully more accurate) idea - the carouselOrder is the column I'd like to generate via a formula.
guestID
guestSector
carouselOrder
1
1
1
2
1
5
3
1
9
4
1
13
5
2
2
6
2
6
7
2
10
8
2
14
9
3
3
10
3
7
11
3
11
12
2
18
13
1
17
14
1
20
15
1
23
16
2
21
17
2
24
18
2
27
19
1
26
20
1
29
21
1
30
22
1
31
23
3
15
24
3
19
25
3
22
26
3
25
27
3
28
28
1
32
29
4
4
30
4
8
31
4
12
32
4
16
When using Office 365 you can use the following in D2: =MOD(SEQUENCE(COUNTA(A2:A11),,0),4)+1
This create the repetitive counter of the sectors 1 to 4 to the total count of rows in your data.
In C2 use the following:
=BYROW(D2#,LAMBDA(x,
INDEX(
FILTER($A$2:$A$11,$B$2:$B$11=x),
SUM(--(D$2:x=x)))))
This filters the Names that equal the sector of mentioned row and indexes it to show only the result where the row in the filter result equals the count of the same sector (D2#) up to current row.
Let's try the following approach that doesn't require to create a helper column. I would like to explain first the logic to build the recurrence, then the excel formula that builds such recurrence.
If we sort the input data Name and Sector. by Sector. in ascending order, the new positions of the Name values (letters) can be calculated as follow (Table 1):
Name
Sector.Sorted
Position
A
1
1+4*0=1
B
1
1+4*1=5
C
1
1+4*2=9
E
2
2+4*0=2
F
2
2+4*1=6
G
2
2*4*2=10
H
3
3+4*0=3
J
3
3+4*1=7
D
4
4+4*0=4
I
4
4+4*1=8
The new positions of Name (letters) follows this pattern (Formula 1):
position = Sector.Sorted + groupSize * factor
where groupSize is 4 in our case and factor counts how many times the same Sector.Sorted value is repeated, starting from 0. Think about Sector.Sorted as groups, where each set of repeated values represents a group: 1,2,3 and 4.
If we are able to build the Position values we can sort Name, based on the new positions via SORTBY(array, by_array1) function. Check SORTBY documentation for more information how this function works.
Here is the formula to get the Name sorted in cell E2:
=LET(groupSize, 4, sorted, SORT(A2:B11,2), sName,
INDEX(sorted,,1),sSector, INDEX(sorted,,2),
seq0, SEQUENCE(ROWS(sSector),,0), mapResult,
MAP(sSector, seq0, LAMBDA(a,b, IF(b=0, "SAME",
IF(a=INDEX(sSector,b), "SAME", "NEW")))), factor,
SCAN(-1,mapResult, LAMBDA(aa,c,IF(c="SAME", aa+1,0))),
pos,MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n)),
SORTBY(sName,pos)
)
Here is the output:
Explanation
The name sorted represents the input data sorted by Sector. in ascending order, i.e.: SORT(A2:B11,2). The names sName and sSector represent each column of sorted.
To identify each group we need the following sequence (seq0) starting from 0, i.e. SEQUENCE(ROWS(sSector),,0).
Now we need to identify when a new group starts. We use MAP function for that and the result is represented by the name mapResult:
MAP(sSector, seq0, LAMBDA(a,b, IF(b=0, "SAME",
IF(a=INDEX(sSector,b), "SAME", "NEW"))))
The logic is the following: If we are at the beginning of the sequence (first value of seq0), then returns SAME otherwise we check current value of sSector (a) against the previous one represented by INDEX(sSector,b) if they are the same, then we are in the same group, otherwise a new group started.
The intermediate result of mapResult is:
Name
Sector Sorted
mapResult
A
1
SAME
B
1
SAME
C
1
SAME
E
2
NEW
F
2
SAME
G
2
SAME
H
3
NEW
J
3
SAME
D
4
NEW
I
4
SAME
The first two columns are shown just for illustrative purpose, but mapResult only returns the last column.
Now we just need to create the counter based on every time we find NEW. In order to do that we use SCAN function and the result is stored under the name factor. This value represents the factor we use to multiply by 4 within each group (see Table 1):
SCAN(-1,mapResult, LAMBDA(aa,c,IF(c="SAME", aa+1,0)))
The accumulator starts in -1, because the counter starts with 0. Every time we find SAME, it increments by 1 the previous value. When it finds NEW (not equal to SAME), the accumulator is reset to 0.
Here is the intermediate result of factor:
Name
Sector Sorted
mapResult
factor
A
1
SAME
0
B
1
SAME
1
C
1
SAME
2
E
2
NEW
0
F
2
SAME
1
G
2
SAME
2
H
3
NEW
0
J
3
SAME
1
D
4
NEW
0
I
4
SAME
1
The first three columns are shown for illustrative purpose.
Now we have all the elements to build our pattern for the new positions represented with the name pos:
MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n))
where m represents each element of Sector.Sorted and factor the previous calculated values. As you can see the formula in Excel represents the generic formula (Formula 1 see above). The intermediate result will be:
Name
Sector Sorted
mapResult
factor
pos
A
1
SAME
0
1
B
1
SAME
1
5
C
1
SAME
2
9
E
2
NEW
0
2
F
2
SAME
1
6
G
2
SAME
2
10
H
3
NEW
0
3
J
3
SAME
1
7
D
4
NEW
0
4
I
4
SAME
1
8
The previous columns are shown just for illustrative purpose. Now we have the new positions, so we are ready to sort based on the new positions for Name via:
SORTBY(sName,pos)
Update
The first MAP can be removed creating an array as input for SCAN that has the information of sSector and the index position to be used for finding the previous element. SCAN only allows a single array as input argument, so we can combine both information in a new array. This is the formula can be used instead:
=LET(groupSize, 4, sorted, SORT(A2:B11,2), sName,
INDEX(sorted,,1),sSector, INDEX(sorted,,2),
factor, SCAN(-1,sSector&"-"&SEQUENCE(ROWS(sSector),,0),
LAMBDA(aa,b, LET(s, TEXTSPLIT(b,"-"),item, INDEX(s,,1),
idx, INDEX(s,,2), IF(aa=-1, 0, IF(1*item=INDEX(sSector, idx), aa+1,0))))),
pos,MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n)),
SORTBY(sName,pos)
)
We use inside of SCAN a LET function to calculate all required elements for doing the comparison as part of the calculation of the corresponding LAMBDA function. We extract the item and the idx position used to find previous element of sSector via:
1*item=INDEX(sSector, idx)
we are able to compare each element of sSector with previous one, starting from the second element of sSector. We multiply item by 1, because TEXTSPLIT converts the result to text, otherwise the comparison will fail.
Im trying to write a program that displays the FIBONACCI NUMBERS, however, the numbers don't print out correctly and are always one number too high for what the Fibonacci number is meant to be, can anyone understand why?
This is the code i have:
a, b = 0, 1
while b < 1000:
print(b, '', end='')
a, b = b, a + b
(have to use those 4 lines of code)
And this is the output I get
1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597
and this is the output im looking for
0
1
2
4
7
12
20
33
54
the program should also start at 0 not 1
Try printing a instead of b. a and b are the first two terms of the sequence, so if you want to print the first term you have to print a.
To get your desired output, instead of the usual fibbonacci sequence, you'll also need to increase b by one, every iteration:
a, b = b, (a + b + 1)
Printing 'a' instead of 'b' will solve your problem.
Try this code this would solve your problem.
a, b = 0, 1
while b < 1000:
print(a, '', end='')
a, b = b, a + b
while i traced your code i got,
1st iter : a=0,b=1
2nd iter : a=1,b=1
3rd iter : a=1,b=2
4th iter : a=2,b=3
5th iter : a=3,b=5
and continues..
I have a excel document where I have something like this
A B C
1 1 45 a
2 2 32 b
3 3 34 H
4 3 37
5 4 49 i
5 5 76 H
Note that 3c is combined but 3b isn't.
I need to do a macro to change the content of B with the content of C but only those that don't have a letter H. so the document would look like this
A B C
1 1 a a
2 2 b b
3 3 34 H
4 3 37
5 4 i i
5 5 76 H
Here a image
Just use this simple formula in column C,
=IF(B1="H",A1,B1)
and drag it throughout the range. Once done, copy paste all of the data in column C to A (paste special)
Trying to get a simple VLOOKUP to work but only getting first value.
Sample Data
TABA
V
1
2 1
3 X
X = =SUM(VLOOKUP(V2,TABB!$K:$M,3,FALSE))
TABB
K L M
1 1 Hello 45
2 8 Hello 30
3 1 Hello 20
4 6 Hello 60
5 1 Hello 90
6 3 Hello 10
7 1 Hello 80
8 1 Hello 75
Current Output
=SUM(VLOOKUP(V2,TABB!$K:$M,3,FALSE))
Is returning 45 (the first value).
Expected Output
=SUM(VLOOKUP(V2,TABB!$K:$M,3,FALSE))
I want it to return 310 (the SUM of values that match 1).
Vlookup can only return the first value.
In your TABB Sheet. Create another column in Column N
e.g in N1 with
=SUMIF($K$1:$K$8,$K1,$M$1:$M$8)
Drag the formula down
Then do
Vlookup(V2,TABB!$K:$N,4,FALSE)
If this works can you please vote up. :)
All the best
I am looking for help to solve this excel problem.
Essentially I want to create a formula for cells in column F which does a multiple search on 3 criteria (on cells in columns A,B,C) and want to access the corresponding column D values where all these (multiple) matches occur, and sum this in column F. I'd also like a count of the amount of matches found to calculate the value in column F; placed alongside in column G.
e.g.
IF col_A_value (anywhere in whole A column) = current_col_A_value +/- 1
AND col_B_value (anywhere in whole B column) = current_col_B_value +/- 1
AND col_C_value (anywhere in whole C column) = current_col_C_value - 1
THEN (output in column F) the sum of all values from row D where this criteria is met
(also, as a seperate but related cell formula, output in column G) the total Count of times this occurs.
Note: the values in columns A,B,C are all integars and the +/- above means to search for any values which are either +1, 0, or -1 different in value. (i.e. this includes the value itself).
e.g. If the value in cell A1 = 10, B1 = 45, C1 = 881, then the first search criteria would look for all other rows with values of 9, 10 or 11 in column A. Then based on these rows, the second search criteria would refine the search to only those rows which also include either a 44, 45 or 46 in column B, and the third search criteria would refine the search again to only include those rows where the column C value is 880.
Next, the values in the column D cells from all of these 'filtered' rows would be summed and the result placed in the column F cell. (The count of these results rows would be put in column G. (seperate formula required))
Since these are all unique entries (think of columns A,B,C creating unique vector coordinates in space), there should be a maximum of 9 entries found and summed. A +/-1: 3 variations, B +/-1: 3 variations and C -1 only: 1 variation. In total: 3x3x1 = 9 unique rows maximum (and potentially none as a minimum, as in the below example).
(If no match is found a value of 0 is good.)
Example with A,B,C,D and E as given values, and column F values calculated (together with the count shown in col G):
A B C D E F G
1 1 1 90 8 0 0
1 2 1 80 6 0 0
1 3 1 70 1 0 0
1 4 1 60 6 0 0
2 1 1 50 1 0 0
2 2 1 40 8 0 0
2 3 1 30 6 0 0
2 4 1 20 8 0 0
3 1 1 10 8 0 0
3 2 1 11 6 0 0
3 3 1 12 1 0 0
3 4 1 13 1 0 0
1 1 2 99 8 260 4
1 2 2 89 6 360 6
1 3 2 79 1 300 6
1 4 2 69 6 180 4
2 1 2 59 1 281 6
2 2 2 49 8 393 9
etc
To illustrate how column F values are calculated here is the working:
260 = 90+80+50+40
360 = 90+80+70+50+40+30
300 = 80+70+60+40+30+20
180 = 70+60+30+20
281 = 90+80+50+40+10+11
393 = 90+80+70+50+40+30+10+11+12
Thanks a lot for any help with this!
These formulas should do what you desire:
F1: =SUMIFS(D:D,A:A,"<="&A1+1,A:A,">="&A1-1,B:B,"<="&B1+1,B:B,">="&B1-1,C:C,C1-1)
G1: =COUNTIFS(A:A,"<="&A1+1,A:A,">="&A1-1,B:B,"<="&B1+1,B:B,">="&B1-1,C:C,C1-1)
The formulas can simply be copied down as you need them...
(Still I don't know what col E is for)