Hoping to sort (below left) by sector but distribute evenly (below right):
Name
Sector.
Name.
Sector
A
1
A
1
B
1
E
2
C
1
H
3
D
4
D
4
E
2
B
1
F
2
F
2
G
2
J
3
H
3
I
4
I
4
C
1
J
3
G
2
Real data is 70+ rows with 4 sectors.
I've worked around it manually but would love to figure out how to do it with a formula in excel.
Here's a more complete (and hopefully more accurate) idea - the carouselOrder is the column I'd like to generate via a formula.
guestID
guestSector
carouselOrder
1
1
1
2
1
5
3
1
9
4
1
13
5
2
2
6
2
6
7
2
10
8
2
14
9
3
3
10
3
7
11
3
11
12
2
18
13
1
17
14
1
20
15
1
23
16
2
21
17
2
24
18
2
27
19
1
26
20
1
29
21
1
30
22
1
31
23
3
15
24
3
19
25
3
22
26
3
25
27
3
28
28
1
32
29
4
4
30
4
8
31
4
12
32
4
16
When using Office 365 you can use the following in D2: =MOD(SEQUENCE(COUNTA(A2:A11),,0),4)+1
This create the repetitive counter of the sectors 1 to 4 to the total count of rows in your data.
In C2 use the following:
=BYROW(D2#,LAMBDA(x,
INDEX(
FILTER($A$2:$A$11,$B$2:$B$11=x),
SUM(--(D$2:x=x)))))
This filters the Names that equal the sector of mentioned row and indexes it to show only the result where the row in the filter result equals the count of the same sector (D2#) up to current row.
Let's try the following approach that doesn't require to create a helper column. I would like to explain first the logic to build the recurrence, then the excel formula that builds such recurrence.
If we sort the input data Name and Sector. by Sector. in ascending order, the new positions of the Name values (letters) can be calculated as follow (Table 1):
Name
Sector.Sorted
Position
A
1
1+4*0=1
B
1
1+4*1=5
C
1
1+4*2=9
E
2
2+4*0=2
F
2
2+4*1=6
G
2
2*4*2=10
H
3
3+4*0=3
J
3
3+4*1=7
D
4
4+4*0=4
I
4
4+4*1=8
The new positions of Name (letters) follows this pattern (Formula 1):
position = Sector.Sorted + groupSize * factor
where groupSize is 4 in our case and factor counts how many times the same Sector.Sorted value is repeated, starting from 0. Think about Sector.Sorted as groups, where each set of repeated values represents a group: 1,2,3 and 4.
If we are able to build the Position values we can sort Name, based on the new positions via SORTBY(array, by_array1) function. Check SORTBY documentation for more information how this function works.
Here is the formula to get the Name sorted in cell E2:
=LET(groupSize, 4, sorted, SORT(A2:B11,2), sName,
INDEX(sorted,,1),sSector, INDEX(sorted,,2),
seq0, SEQUENCE(ROWS(sSector),,0), mapResult,
MAP(sSector, seq0, LAMBDA(a,b, IF(b=0, "SAME",
IF(a=INDEX(sSector,b), "SAME", "NEW")))), factor,
SCAN(-1,mapResult, LAMBDA(aa,c,IF(c="SAME", aa+1,0))),
pos,MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n)),
SORTBY(sName,pos)
)
Here is the output:
Explanation
The name sorted represents the input data sorted by Sector. in ascending order, i.e.: SORT(A2:B11,2). The names sName and sSector represent each column of sorted.
To identify each group we need the following sequence (seq0) starting from 0, i.e. SEQUENCE(ROWS(sSector),,0).
Now we need to identify when a new group starts. We use MAP function for that and the result is represented by the name mapResult:
MAP(sSector, seq0, LAMBDA(a,b, IF(b=0, "SAME",
IF(a=INDEX(sSector,b), "SAME", "NEW"))))
The logic is the following: If we are at the beginning of the sequence (first value of seq0), then returns SAME otherwise we check current value of sSector (a) against the previous one represented by INDEX(sSector,b) if they are the same, then we are in the same group, otherwise a new group started.
The intermediate result of mapResult is:
Name
Sector Sorted
mapResult
A
1
SAME
B
1
SAME
C
1
SAME
E
2
NEW
F
2
SAME
G
2
SAME
H
3
NEW
J
3
SAME
D
4
NEW
I
4
SAME
The first two columns are shown just for illustrative purpose, but mapResult only returns the last column.
Now we just need to create the counter based on every time we find NEW. In order to do that we use SCAN function and the result is stored under the name factor. This value represents the factor we use to multiply by 4 within each group (see Table 1):
SCAN(-1,mapResult, LAMBDA(aa,c,IF(c="SAME", aa+1,0)))
The accumulator starts in -1, because the counter starts with 0. Every time we find SAME, it increments by 1 the previous value. When it finds NEW (not equal to SAME), the accumulator is reset to 0.
Here is the intermediate result of factor:
Name
Sector Sorted
mapResult
factor
A
1
SAME
0
B
1
SAME
1
C
1
SAME
2
E
2
NEW
0
F
2
SAME
1
G
2
SAME
2
H
3
NEW
0
J
3
SAME
1
D
4
NEW
0
I
4
SAME
1
The first three columns are shown for illustrative purpose.
Now we have all the elements to build our pattern for the new positions represented with the name pos:
MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n))
where m represents each element of Sector.Sorted and factor the previous calculated values. As you can see the formula in Excel represents the generic formula (Formula 1 see above). The intermediate result will be:
Name
Sector Sorted
mapResult
factor
pos
A
1
SAME
0
1
B
1
SAME
1
5
C
1
SAME
2
9
E
2
NEW
0
2
F
2
SAME
1
6
G
2
SAME
2
10
H
3
NEW
0
3
J
3
SAME
1
7
D
4
NEW
0
4
I
4
SAME
1
8
The previous columns are shown just for illustrative purpose. Now we have the new positions, so we are ready to sort based on the new positions for Name via:
SORTBY(sName,pos)
Update
The first MAP can be removed creating an array as input for SCAN that has the information of sSector and the index position to be used for finding the previous element. SCAN only allows a single array as input argument, so we can combine both information in a new array. This is the formula can be used instead:
=LET(groupSize, 4, sorted, SORT(A2:B11,2), sName,
INDEX(sorted,,1),sSector, INDEX(sorted,,2),
factor, SCAN(-1,sSector&"-"&SEQUENCE(ROWS(sSector),,0),
LAMBDA(aa,b, LET(s, TEXTSPLIT(b,"-"),item, INDEX(s,,1),
idx, INDEX(s,,2), IF(aa=-1, 0, IF(1*item=INDEX(sSector, idx), aa+1,0))))),
pos,MAP(sSector, factor, LAMBDA(m,n, m + groupSize*n)),
SORTBY(sName,pos)
)
We use inside of SCAN a LET function to calculate all required elements for doing the comparison as part of the calculation of the corresponding LAMBDA function. We extract the item and the idx position used to find previous element of sSector via:
1*item=INDEX(sSector, idx)
we are able to compare each element of sSector with previous one, starting from the second element of sSector. We multiply item by 1, because TEXTSPLIT converts the result to text, otherwise the comparison will fail.
I have SET 1
CLASS
Student
TEST
SCORE
A
1
1
46
A
1
2
50
A
1
3
45
A
2
1
45
A
2
2
47
A
2
3
31
A
3
1
34
A
3
2
45
B
1
1
36
B
2
1
31
B
2
2
41
B
3
1
50
C
1
1
42
C
3
1
31
and SET 2
CLASS
SIZE
YEARS
A
39
7
B
20
12
C
31
6
and wish to COMBINE to make SET 3
CLASS
STUDENT
TEST
SCORE
SIZE
YEARS
A
1
1
46
39
7
A
1
2
50
39
7
A
1
3
45
39
7
A
2
1
45
39
7
A
2
2
47
39
7
A
2
3
31
39
7
A
3
1
34
39
7
A
3
2
45
39
7
B
1
1
36
20
12
B
2
1
31
20
12
B
2
2
41
20
12
B
3
1
50
20
12
C
1
1
42
31
6
C
3
1
31
31
6
so basically add the SIZE and YEARS columns from SET 2 and merge on CLASS onto SET 1. In excel how you can do this? I need to match on CLASS
Define both sets as tables and “left join” in PowerQuery. There you can choose the columns of the resulting table.
https://learn.microsoft.com/en-us/power-query/merge-queries-left-outer
If you have Set 1 on the top left of a worksheet "Set1" and Set 2 on the top left of a worksheet "Set2", then you can use the formula
=VLOOKUP(A2;'Set2'!$A$2:$C$4;2;FALSE), where $A$2:$C$4 is the range of Set2, and A2 is the class value from Set1, which is what is used to do the lookup in Set2. The next argument, 2, means to take the second row from Set2, and the FALSE at the end means that you only want exact matches on the CLASS. You can do auto-fill with this formula, and do similar steps for the years. If you look up the help for VLOOKUP within Excel, that should help you to understand how it works.
Your first set of data is essentially your primary set of data that you just want to add attribute columns to. I built this example on Google Sheets which should help explain. Using spill formulas, only a few cells are needed with their own formulas. You can see them as they are highlighted in yellow. When you use in Excel, obviously make sure you change the column references, but this would get you the answer.
Note you have to have SpillRange in Excel for this to work. To test, see if you have the formula =unique()
This solution may work for you if both sets start in the same column. As example in my image, both of them start at column A. You can get all data with a single VLOOKUP formula:
Formula in cell E2 is:
=VLOOKUP($A2;$A$22:$R$25;COLUMN($B22);FALSE)
Notice the mixed references at first and third argument and absolute references in the second one. Third argument is critical, because is the relational position between both sets, that's the reason it's easier if both sets start at same column. If not, you'll need to adjust this argument substracting or adding, depending on the case.
Anyways, with a single formula, you can get any number of columns. The only disavantage of this formula is that you need to manually drag to right until you got all the columns (10, 30 or whatever). You'll notice you are done because the formula will raise an error:
This error means you are trying to get a referenced outside of your column area.
Im trying to have a formula, that gets the first result of entry, for every line.
An Example Table would be like this:
Column A Column B Column C Excepted Output from Formula
3 99 P 18 P 4
4 88 P 144 P 1
2 77 P 2
2 77 P 2
1 88 P 1 P 1
1 99 P 4 P 4
2 44 P 5
3 22 P 7
1 88 P 99 P 1
Now, on Column D it should always show the first time it finds Coulmn A = 1, and Column B the same value as the own row (99 for the first row, 88 for the second, 77 for the 3rd...), and Display the Column C of it.
I tried it with the following Formula:
=CALCULATE(
FIRSTNONBLANK('Table'[Column C]; TRUE());
FILTER('Table';'Table'[Column A]=1);
FILTER('Table';'Table'[Column B]='Table'[Column B])
)
Which doesnt work. No errors, but it ignores the second filter.
If i now replace the "='Table'[Column B]" with a number that it should take (99,88,77...) it shows the correct result. But since its now a static number, it shows the same Result in every line, instead of calc it always new.
Can someone help?
Try this:
= CALCULATE(FIRSTNONBLANK('Table'[Column C], TRUE()),
FILTER(FILTER('Table','Table'[Column A]=1),'Table'[Column B] = earlier('Table'[Column B])))
I have data in an Excel sheet as:
Column A Column B
1 1
5 5
6 6
50 50
.. 51
.. 52
.. 53
1 1
5 2
6 6
50 50
.. 51
.. 52
.. 53
very long list
I want to fill Column B corresponding to Column A as shown above that if cell A is not blank then cell B will have same value as A ..and if Cell A has value 50, then next blank rows in column B will have subsequent values after 50 ..
I tried to make formula
=IF(A2="",IF(A2=50,50,VALUE(A1)+1),A2)
and pasted in Cell B2 and dragged but it is giving me wrong results:
5
6
50
51
1
1
..
Can anyone please suggest? Thanks in advance.
This assumes your data starts in row 2. Paste in B2 and fill down.
=IFERROR(IF(A2<>"",A2,IF(OR(AND(A2=50,A3=""),B1>=50),1+B1,"")),"")
This works on your use case, but it's all kinds of kludgy so might not extend well to other cases.
You can simply paste in B2
=IF(ISBLANK(A2),B1+1,A2)
and then copy the formula by dragging it down
Outcome:
A B
---------
1 1
5 5
6 6
50 50
51
52
53
1 1
5 5
6 6
50 50
51
52
53
Note: it won't work for B1. You have to have enter a value in this cell manually.