I'm calculating the difference between 2 columns of data and calculating the numeric difference and % increase. I wanted to combine these two values in one cell using the text function.
The problem: I have successfully done this in excel but have a formatting problem. I have separated the numeric and percent difference by the delimiter "|". Sometimes the % difference value is two digits and some times its 1 digit. I'd like to have a placeholder for the tens digit so all of the delimiters align in the column. Is there any way to do this using the function?
For example, you could solve this problem by adding "000" in the format_text argument for the second text function, but I don't want any leading zeros in my display cell.
Thank you,
You can use ? to add leading or trailing space:
= H70-F70 & Text(H70/F70-1, " | ??%")
You can also use Monospaced font like Courier New for better alignment.
Related
For example I have this line right here:
-2.7769,-5.6967,5.9179,0.37671,1
When I convert text to column using as delimiter comma in preview I see the result just right:
-2.7769 -5.6967 5.9179 0.37671 1
But when I press confirm I get this:
-27.769 -56.967 59.179 0.37671 1
How can I stop it from doing that and get the desired outcome?
I tried to make a line separated with commas into columns using the text to column feature from excel but I didn't get the result I was hoping for.
I don't know the entire solution, but I clearly see that you are mixing up decimal delimiter and thousand delimiter:
I guess that you mean "-2.7769" meaning "minus two, followed by a decimal separator, followed by .7769 (a number between zero and one)", but what your computer understand is: "minus twenty-seven thousand, seven hundred and sixty-nine, but the user has put the thousand separator at the wrong place. I will correct this."
In order to check whether or not your Excel is using a thousand separator, you can ask a random cell's formatting (right-click, choose "Format cells"): the "Use 1000 Separator (,)" checkbox in the "Number" chapter should be unchecked, as in this screenshot:
I'm trying to combine several cells of data. My problem is in placing spaces between data and, more importantly NOT putting a space when there's no data so I don't get double spaces. Here's a sample:
=TRIM(M12)&IF(N12<>M12;"-"&TRIM(N12);"")&" "&TRIM(G12)&" "&TRIM(H12)&IF(LEN(I12>0);" "&TRIM(I12)&" ")&TRIM(J12)
The data is start year (M), end year (N), make (G), model (H), body style (I), driveline (J).
For some the values in start year and end year are the same.
&IF(N12<>M12;"-"&TRIM(N12);"")
This works perfectly. If the end year is the same as the start year it does not add a - or space after.
For many rows there is no value in body style.
&IF(LEN(I12>0);" "&TRIM(I12)&" ")
This will print the body style if it's present but it always adds a double space if there is no value in body style.
When I change that reference to:
&IF(LEN(I12>0);"-"&TRIM(I12)&"+")
both the - and + print regardless of what's in I12
I've tried many variations. None work, some throw errors. Probably obviously, I do not know what I'm doing in Excel but I'm thinking there must be a better way of checking the cell I12? I tried >1 with no luck but I'm not sure what to check besides the length of the data within.
The TRIM function not only removes leading and trailing spaces, but also reduces any internal multiple space sequences to a single space. By wrapping the whole formula in TRIM(..) you can ignore the possibility of creating double spaces.
Regarding
When I change that reference to:
&IF(LEN(I12>0);"-"&TRIM(I12)&"+")
both the - and + print regardless of what's in I12
This suggests that I12 actually has one or more spaces. Fix that by using LEN(TRIM(I12))>0
Or better, just go ahead and concatenate I12 and let TRIM clean up the spaces.
Note: I'm assuming the IF(LEN(I12>0);"-"&TRIM(I12)&"+") version was just to test that bit of code, so haven't delt with adding - and +.
So, your whole formula can become
=TRIM(M17&IF(M17<>N17;"-"&TRIM(N17);"")&" "&G17&" "&H17&" "&I17&" "&J17)
If you have a version of Excel that supports TEXTJOIN then you can use
=TRIM(M16&IF(M16<>N16,"-"&TRIM(N16),"")&" "&TEXTJOIN(" ",TRUE,G16:J16))
I'm trying to write an Excel macro using VBA that will return only the first 5 numbers in a cell when the length of that cell exceeds 20. The field normally returns 15-digit alphanumeric results (which I need to leave alone) but in certain exceptions will return a 5-digit number with a multitude of zeroes following it (1234500000000000000000000...) which Excel converts into scientific notation (1.2345E+160). I am able to convert the cells to numbers instead of scientific notation and view the whole number.
I've tried to use code such as =IF(LEN(A1)>20,LEFT(A1,5),A1) and it just returns 1.2345E+160. Even though the whole number is displaying, Excel still thinks the cell length is 11 and won't display the first 5 digits.
I've also tried lines such as =IF(A1="E",LEFT(A1,6),A1) thinking it would detect the E, return 1.2345, and I could just remove the decimal points, but that didn't work either (it just returns the original 1.2345E+160).
I got the same results whether the cell was formatted as number or text. Is there a way around this?
Thank you for your time!
You are trying to use string manipulation on a number. Instead use math:
=A1/1E+160
If you do actually want to treat this thing as text, understand that the underlying value being stored is your 12345000000000000... and there is no decimal point in that thing. So you'll have to convert to text and add the decimal:
=LEFT(TEXT(A1,"0"), 1) & "." & MID(TEXT(A1,"0"), 2, 4)
But that's pretty ugly. I would just stick with math.
On a daily basis I need to load data to one of our systems. However Excel deletes the previous zeros in front of the contractor IDs. So i have to add THREE zeros manually. I normally use the CONCATENATE function however now the IDs are coming differently so some IDs now only need to have TWO zeros added.
example:
ID
911111
I use concatenate to make it look like:
000911111
I came up with the IF formula that detects if the ID starts with a number NINE, to concatenate TWO zeros and if not, then to add THREE zeros.
example:
=IF(LEFT(A32,1)="9",CONCATENATE("00",A32),CONCATENATE("000",A32))
Now I want to create this formula as a custom defined so I do not have to write down the formula ever time I work on the data every day.
Any suggestions I will really appreciate.
In addition to the formatting responses provided in the comments, you could use the RIGHT function to cut off the leading zeroes to the appropriate amount.
For example, assuming A1 holds a string of numbers, between 0 & 9 digits long. We can create text representing a 9 digit string, with as many leading zeroes as necessary, as follows:
=RIGHT(REPT("0",9) & A1,9)
REPT("0",9) tells Excel to repeat the character "0" 9 times. It then tacks on whatever text is in A1. Then it takes only the rightmost 9 characters of the concatenation.
I generally would recommend the Formatting options noted in those comments, unless you need the text to be 9 characters for other formula purposes.
In MS Excel, I would like to format a number in order to show only thousands and with 'K' in from of it,
so the number 123000 will be displayed in the cell as 123K
It is easy to format to show only thousands (123), but I'd like to add the K symbol in case the number is > 1000.
so one cell with number 123 will display 123
one cell with 123000 will show 123K
Any idea how the format Cell -> custom filters can be used?
Thanks!
Custom format
[>=1000]#,##0,"K";0
will give you:
Note the comma between the zero and the "K". To display millions or billions, use two or three commas instead.
Non-Americans take note! If you use Excel with "." as 1000 separator, you need to replace the "," with a "." in the formula, such as:
[>=1000]€ #.##0." K";[<=-1000]-€ #.##0." K";0
The code above will display € 62.123 as "€ 62 K".
[>=1000]#,##0,"K";[<=-1000]-#,##0,"K";0
teylyn's answer is great. This just adds negatives beyond -1000 following the same format.
Enter this in the custom number format field:
[>=1000]#,##0,"K€";0"€"
What that means is that if the number is greater than 1,000, display at least one digit (indicated by the zero), but no digits after the thousands place, indicated by nothing coming after the comma. Then you follow the whole thing with the string "K".
Edited to add comma and euro.
The examples above use a 'K' an uppercase k used to represent kilo or 1000. According to wiki, kilo or 1000's should be represented in lower case. So, rather than £300K, use £300k or in a code example :-
[>=1000]£#,##0,"k";[red][<=-1000]-£#,##0,"k";0
I've found the following combination that works fine for positive and negative numbers (43787200020 is transformed to 43.787.200,02 K)
[>=1000] #.##0,#0. "K";#.##0,#0. "K"