I got output from command like below. Need to extract group names.
dsAttrTypeNative:memberOf: CN=Grupa_test,OU=Groups,DC=yellow,DC=com CN=Firefox_Install,OU=Groups,DC=yellow,DC=com CN=Network_Admin,OU=Groups,DC=yellow,DC=com
So I would like to have something like:
Grupa_test
Firefox_Install
Network_Admin
Amount of groups will be different each time so I'm not sure how to achieve that.
$ awk -v RS=' ' -F'[=,]' 'NR>1{print $2}' file
Grupa_test
Firefox_Install
Network_Admin
The above will work with any awk.
You can do it with GNU grep:
grep -oP '(?<=CN=)[^,]*' file
try with following awk too once.
awk -v RS='[ ,]' -v FS="=" '/CN=/{print $2}' Input_file
$ awk -v FPAT="CN=[^,]+" '{for(i=1;i<=NF;i++)print substr($i,4)}' Input_file
Treat every matched CN=[^,]+ case as a field. And for each matched field, use substr($i,4) to filter out CN=, to print the desired string.
Related
I am trying to capture the string between 2 specific letters/words using sed/awk. This is what I am trying to do:
The input is a file test.log containing
Owner: CN=abc.samplecerrt.com,o=IN,DC=com
Owner: CN=abc1.samplecerrt.com,o=IN,DC=com
I want to extract only "CN=abc.samplecerrt.com"
I tried
sed 's/.*CN=\(.*\),.*/\1/p' test.log >> result.log
But this returns "abc.samplecerrt.com,o=IN,DC=com"
How do I go about this?
test file:
$ cat logs.txt
CN=abc.samplecerrt.com,o=IN,DC=com Owner: CN=abc1.samplecerrt.com,o=IN,DC=com
command and output:
$ grep -oP 'CN=(?:(?!CN=).)*?.com' logs.txt
CN=abc.samplecerrt.com
CN=abc1.samplecerrt.com
This might work for you (GNU sed):
sed -n 's/.*\(CN=[^,]*\).*/\1/p' file
Or:
sed 's/.*\(CN=[^,]*\).*/\1/p;d' file
The first turns off implicit printing -n so as to act like grep.
Matches and captures the string CN= followed by zero or more non-comma characters and prints the captured group \1 if a match is made.
The second solution is much the same except it deletes all lines and only prints the captured group as above.
With awk you can get the field where is the string you need. For it, you can set FS=:|, Now if you run
awk -v FS=":|," '{print $2}' file
CN=abc.samplecerrt.com
CN=abc1.samplecerrt.com
you get the field. But you only want one, so
awk -v FS=":|," '$2 !~ /abc1/ {print $2}' file
CN=abc.samplecerrt.com
I need to grep some pattern and further i need to print some output within that. Currently I am using the below command which is working fine. But I like to eliminate using multiple pipe and want to use single awk command to achieve the same output. Is there a way to do it using awk?
root#Server1 # cat file
Jenny:Mon,Tue,Wed:Morning
David:Thu,Fri,Sat:Evening
root#Server1 # awk '/Jenny/ {print $0}' file | awk -F ":" '{ print $2 }' | awk -F "," '{ print $1 }'
Mon
I want to get this output using single awk command. Any help?
You can try something like:
awk -F: '/Jenny/ {split($2,a,","); print a[1]}' file
Try this
awk -F'[:,]+' '/Jenny/{print $2}' file.txt
It is using muliple -F value inside the [ ]
The + means one or more since it is treated as a regex.
For this particular job, I find grep to be slightly more robust.
Unless your company has a policy not to hire people named Eve.
(Try it out if you don't understand.)
grep -oP '^[^:]*Jenny[^:]*:\K[^,:]+' file
Or to do a whole-word match:
grep -oP '^[^:]*\bJenny\b[^:]*:\K[^,:]+' file
Or when you are confident that "Jenny" is the full name:
grep -oP '^Jenny:\K[^,:]+' file
Output:
Mon
Explanation:
The stuff up until \K speaks for itself: it selects the line(s) with the desired name.
[^,:]+ captures the day of week (in this case Mon).
\K cuts off everything preceding Mon.
-o cuts off anything following Mon.
I have CSV columns that I'm working with:
info,example-string,super-example-string,otherinfo
I would like to get:
example-string super example string
Right now, I'm running the following command:
awk -F ',' '{print $3}' | sed "s/-//g"
But, then I have to paste the lines together to combine $2 and $3.
Is there anyway to do something like this?
awk -F ',' '{print $2" "$3}' | sed "s/-//g"
Except, where the sed command is only performed on $3 and $2 stays in place? I'm just concerned later on if the lines don't match up, the data could be misaligned.
Please note: I need to keep the pipe for the SED command. I just used a simple example but I end up running a lot of commands after that as well.
Try:
$ awk -F, '{gsub(/-/," ",$3); print $2,$3}' file
example-string super example string
How it works
-F,
This tells awk to use a comma as the field separator.
gsub(/-/," ",$3)
This replaces all - in field 3 with spaces.
print $2,$3
This prints fields 2 and 3.
Examples using pipelines
$ echo 'info,example-string,super-example-string,otherinfo' | awk -F, '{gsub(/-/," ",$3); print $2,$3}'
example-string super example string
In a pipeline with sed:
$ echo 'info,example-string,super-example-string,otherinfo' | awk -F, '{gsub(/-/," ",$3); print $2,$3}' | sed 's/string/String/g'
example-String super example String
Though best solution will be either use a single sed or use single awk. Since you have requested to use awk and sed solution so providing this. Also considering your actual data will be same as shown sample Input_file.
awk -F, '{print $2,$3}' Input_file | sed 's/\([^ ]*\)\([^-]*\)-\([^-]*\)-\([^-]*\)/\1 \2 \3 \4/'
Output will be as follows.
example-string super example string
I was given this question during an interview. I said I could do it with java or python like xreadlines() function to traverse the whole file and fetch the column, but the interviewer wanted me to just use linux cmd. How can I achieve that?
You can use the command awk. Below is an example of printing out the second column of a file:
awk -F, '{print $2}' file.txt
And to store it, you redirect it into a file:
awk -F, '{print $2}' file.txt > output.txt
You can use cut:
cut -d, -f2 /path/to/csv/file
I'd add to Andreas answer, but can't comment yet.
With csv, you have to give awk a field seperator argument, or it will define fields bound by whitespace instead of commas. (Obviously, csv that uses a different field seperator will need a different character to be declared.)
awk -F, '{print $2}' file.txt
I'd like to know how cat passwd | awk -F':' '{printf $1}' works. cat /etc/passwd is a list of users with ID and folders from root to the current user (I don't know if it has something to do with cat passwd). -F is some kind of input file and {printf $1} is printing the first column. That's what I've search so far but seems confusing to me.
Can anyone help me or explain to me if it's right or wrong, please?
This is equivalent to awk -F: '{print $1}' passwd. The cat command is superfluous as all it does is read a file.
The -F option determines the field separator for awk. The quotes around the colon are also superfluous since colon is not special to the shell in this context. The print invocation tells awk to print the first field using $1. You are not passing a format string, so you probably mean print instead of printf.