how to hide index 0 of PANDAS and Jupyter - python-3.x

Question

i want to hide de index 0 (rows) from my jupyter notebook:
display(df.style.set_properties(**{'text-align': 'left'})
the method i use is style in order to get it as an html and left align,
where df is a simple PANDAS dataframe.
THANK YOU!

Answer 1

It is very unclear what you want. So I'm going to take a guess.
Consider the dataframe df
df = pd.DataFrame([[1, 2], [3, 4], [5, 6]], list('ABC'), list('XY'))
Since simply "hiding" the first row is super easy as #chtonicdaemon pointed out:
df.iloc[1:]
X Y
B 3 4
C 5 6
I'm going to assume you wanted something different. What I've seen asked before is how do I not display the index? I'll first point at a previous answer of mine ColorChange
This is the function I'll use to apply my own css
def HTML_with_style(df, style=None, random_id=None):
from IPython.display import HTML
import numpy as np
import re
df_html = df.to_html()
if random_id is None:
random_id = 'id%d' % np.random.choice(np.arange(1000000))
if style is None:
style = """
<style>
table#{random_id} {{color: blue}}
</style>
""".format(random_id=random_id)
else:
new_style = []
s = re.sub(r'</?style>', '', style).strip()
for line in s.split('\n'):
line = line.strip()
if not re.match(r'^table', line):
line = re.sub(r'^', 'table ', line)
new_style.append(line)
new_style = ['<style>'] + new_style + ['</style>']
style = re.sub(r'table(#\S+)?', 'table#%s' % random_id, '\n'.join(new_style))
df_html = re.sub(r'<table', r'<table id=%s ' % random_id, df_html)
return HTML(style + df_html)
And I'll call it with my own css to suppress the index
style = """
<style>
table tr :first-child{display: none;}
</style>
"""
HTML_with_style(df, style)
This doesn't work for print(df)