Calculating Median Using Aggregate - excel

If have the following function that is used to calculate SMALL:
=IFERROR(AGGREGATE(15; 6; Table5[Salary]/(Table5[Letter]="F") /(Table5[Level]=B2) /(Table5[[Title ]]=A2); 1); "-")
Which works perfectly fine when the first parameter is 15 (SMALL) or 14 (Large). But if I try to calculate the median ( replacing 15 with 12 ) the error value "-" is returned. Any ideas?

The median does not accept an array entry, it must be 14 or higher in the AGGREGATE to accept array entry.
You will need to use MEDIAN(IF()) as an array formula:
=IFERROR(MEDIAN(IF((Table5[Letter]="F")*(Table5[Level]=B2)*(Table5[[Title ]]=A2);Table5[Salary]));"-")
Being an array formula it needs to be confirmed with Ctrl-
Shift-Enter instead of Enter when exiting edit mode. If done correctly Excel will put {} around the formula.

Related

Sum the number of products in excel

I've got the table whereby:
The left number of * contains the count of something, the right is the value of it.
I'm trying to figure out the sum of all the counts, irrespective of value. The result that I'm trying to work towards is under the "result" header.
Raw
Result
1*2+2*3+3*4+3*5+5*6
14
882*1
882
321*2+112*128
433
Trying out using names within excel for to evaluate it, but I'm unsure if you can iterate and get each position of the numbers on the left of the " * ".
Assuming the only operations are addition and multiplication, for Office 365:
=BYROW(A1:A3,LAMBDA(ζ,SUM(INDEX(0+TEXTSPLIT(ζ,"*","+"),,1))))

How do I get offset function working with max function?

Many thanks for taking the time to read this.
I've got a function to return the closest value that is less than a given value:
=MAX(IF(O80:O85<Y80,O80:O85))
This works well and I now want to multiply it by the value on the right of the value that was found so I am trying to use the offset function:
=MAX(IF(O80:O85<Y80,O80:O85))*(1+OFFSET(MAX(IF(O80:O85<Y80,O80:O85)),0,1))
But this isn't working. I've done a similar thing with another function and the offset works perfectly Does anybody know why it's not the case here?
I am using Ctrl + Shift + Enter
Many thanks
The offset function first needs a reference, but the max function just gives a value.
This would be a solution based on your first function
=(MAX(if(O80:O85<Y80,O80:O85)),O80:O85,0))* (1+INDEX(P80:P85,MATCH(MAX(if(O80:O85<Y80,O80:O85)),O80:O85,0)))
ARRAY Formula: CTRL + SHIFT + ENTER
IMO, the best pseudo-MAXIFS if you don't have Office 365 with the new MAXIFS is AGGREGATE as a standard non-array formula.
=aggregate(14, 7, O80:O85/(O80:O85<Y80), 1)
Multiply that result against the matching value in P80:P85.
=aggregate(14, 7, O80:O85/(O80:O85<Y80), 1)*index(P80:P85, match(aggregate(14, 7, O80:O85/(O80:O85<Y80), 1), O80:O85, 0))
You can use INDEX-MATCH to make easily what you need:
=INDEX(where-is-your-data,MATCH(what-is-the-target,where-is-your-data,Less-than-option))
In your case:
=INDEX(O80:O85,MATCH(Y80,O80:O85,1))
It's important to class your data in ascending order because the formula will give the closest value by checking your data one after one and stop without checking further the closest.
For the second part, if you need to multiply by an offset to the value on the right of the selected value, just make this:
=INDEX(O80:O85,MATCH(Y80,O80:O85,1))*OFFSET(INDEX(O80:O85,MATCH(Y80,O80:O85,1)),0,1)

Average not working with indirect formula and blank values

I have this formula:
=IFERROR(
(
(
IFERROR(INDIRECT($A6&"!$E$15");"")
+IFERROR(INDIRECT($A6&"!$E$29");"")
+IFERROR(INDIRECT($A6&"!$E$43");"")
+IFERROR(INDIRECT($A6&"!$E$57");"")
+IFERROR(INDIRECT($A6&"!$E$71");"")
+IFERROR(INDIRECT($A6&"!$E$84");"")
)
/6);"")
When any of these IDIRECTS return a blank value, I get an #VALUE! error (without the first IFERROR). Each individual line works just fine, and when putting them in cells individually, I can average them fine. If I remove the /6 part of this formula however, and wrap the lines with an AVERAGE-formula, I get the #VALUE! error also.
How can I proceed?
EDIT, SOLUTION FOUND (Thanks Mrig):
=IFERROR(
(
(
IF(ISNUMBER(INDIRECT($A7&"!$E$15"));INDIRECT($A7&"!$E$15");0)
+IF(ISNUMBER(INDIRECT($A7&"!$E$29"));INDIRECT($A7&"!$E$29");0)
+IF(ISNUMBER(INDIRECT($A7&"!$E$43"));INDIRECT($A7&"!$E$43");0)
+IF(ISNUMBER(INDIRECT($A7&"!$E$57"));INDIRECT($A7&"!$E$57");0)
+IF(ISNUMBER(INDIRECT($A7&"!$E$71"));INDIRECT($A7&"!$E$71");0)
+IF(ISNUMBER(INDIRECT($A7&"!$E$84"));INDIRECT($A7&"!$E$84");0)
)/
(
COUNTIF(INDIRECT($A7&"!$E$15");">=0")
+COUNTIF(INDIRECT($A7&"!$E$29");">=0")
+COUNTIF(INDIRECT($A7&"!$E$43");">=0")
+COUNTIF(INDIRECT($A7&"!$E$57");">=0")
+COUNTIF(INDIRECT($A7&"!$E$71");">=0")
+COUNTIF(INDIRECT($A7&"!$E$82");">=0")
)
);"")
The COUNTIF's bascially replaces the number "6" in the original code, and checks which of the INSNUMER's (instead of IFERROR's) that isn't blanks, so anything that's 0% or higher (actual value) will be counted, to get to the true average.
Using the suggestions above in the comments, you can use IF(ISNUMBER()) instead of IFERROR()
=IFERROR(
(
(
IF(ISNUMBER(INDIRECT($A6&"!$E$15"));INDIRECT($A6&"!$E$15");0)
+IF(ISNUMBER(INDIRECT($A6&"!$E$29"));INDIRECT($A6&"!$E$29");0)
+IF(ISNUMBER(INDIRECT($A6&"!$E$43"));INDIRECT($A6&"!$E$43");0)
+IF(ISNUMBER(INDIRECT($A6&"!$E$57"));INDIRECT($A6&"!$E$57");0)
+IF(ISNUMBER(INDIRECT($A6&"!$E$71"));INDIRECT($A6&"!$E$71");0)
+IF(ISNUMBER(INDIRECT($A6&"!$E$84"));INDIRECT($A6&"!$E$84");0)
)/6);"")
I started off thinking that your 'stagger' was 14 rows so I went with this array formula:
=AVERAGE(IF(MOD(ROW(E15:E84), 14)=1, IF(ISNUMBER(INDIRECT($A6&"!E15:E84")), INDIRECT($A6&"!E15:E84"))))
... but your 'stagger' is not a consistent 14 rows; the last gap is 13 rows so I modified it to this:
=AVERAGE(IF(ROW(15:84)={15,29,43,57,71,84}, IF(ISNUMBER(INDIRECT($A6&"!E15:E84")), INDIRECT($A6&"!E15:E84"))))
That produces a true average without zero substitution on blank cells while discarding text values.

How to exclude 0 from MIN formula Excel

i need to know how can i exclude 0 from rows and get the MIN Value.
But also i need to exlude the F1 Cell.
Ex:
A B C D E F
1 0 18 20 0 150 = 18
but if i do this In excel with =MIN(A1,B1,C1,D1,E1) return 0.
Any help is appreciated.
Try this formula
=SMALL((A1,C1,E1),INDEX(FREQUENCY((A1,C1,E1),0),1)+1)
Both SMALL and FREQUENCY functions accept "unions" as arguments, i.e. single cell references separated by commas and enclosed in brackets like (A1,C1,E1).
So the formula uses FREQUENCY and INDEX to find the number of zeroes in a range and if you add 1 to that you get the k value such that the kth smallest is always the minimum value excluding zero.
I'm assuming you don't have negative numbers.....
Enter the following into the result cell and then press Ctrl & Shift while pushing ENTER:
=MIN(If(A1:E1>0,A1:E1))
Not entirely sure what you want here, but if you want to discount blank cells in the range and pass over zeros then this would do it; if a little contrived:
=MIN(IF(A1:E1=0,MAX(A1:E1),A1:E1))
With Ctrl+Shift+Enter as an array.
What I'm doing here is replacing zeros with the maximum value in the list.
if all your value are positive, you can do -max(-n)
Solutions listed did not exactly work for me. The closest was Chief Wiggum - I wanted to add a comment on his answer but lack the reputation to do so. So I post as separate answer:
=MIN(IF(A1:E1>0;A1:E1))
Then instead of pressing ENTER, press CTRL+SHIFT+ENTER and watch Excel add { and } to respectively the beginning and the end of the formula (to activate the formula on array).
The comma "," and "If" statement as proposed by Chief Wiggum did not work on Excel Home and Student 2013. Need a semicolon ";" as well as full cap "IF" did the trick. Small syntax difference but took me 1.5 hour to figure out why I was getting an error and #VALUE.
Throwing my hat in the ring:
1) First we execute the NOT function on a set of integers,
evaluating non-zeros to 0 and zeros to 1
2) Then we search for the MAX in our original set of integers
3) Then we multiply each number in the set generated in step 1 by the MAX found in step 2, setting ones as 0 and zeros as MAX
4) Then we add the set generated in step 3 to our original set
5) Lastly we look for the MIN in the set generated in step 4
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
If you know the rough range of numbers, you can replace the MAX(RANGE) with a constant. This speeds things up slightly, still not enough to compete with the faster functions.
Also did a quick test run on data set of 5000 integers with formula being executed 5000 times.
{=SMALL(A1:A5000,COUNTIF(A1:A5000,0)+1)}
1.700859 Seconds Elapsed |
5,301,902 Ticks Elapsed
{=SMALL(A1:A5000,INDEX(FREQUENCY(A1:A5000,0),1)+1)}
1.935807 Seconds Elapsed |
6,034,279 Ticks Elapsed
{=MIN((NOT(A1:A5000)* MAX(A1:A5000))+ A1:A5000)}
3.127774 Seconds Elapsed |
9,749,865 Ticks Elapsed
{=MIN(If(A1:A5000>0,A1:A5000))}
3.287850 Seconds Elapsed |
10,248,852 Ticks Elapsed
{"=MIN(((A1:A5000=0)* MAX(A1:A5000))+ A1:A5000)"}
3.328824 Seconds Elapsed |
10,376,576 Ticks Elapsed
{=MIN(IF(A1:A5000=0,MAX(A1:A5000),A1:A5000))}
3.394730 Seconds Elapsed |
10,582,017 Ticks Elapsed
min() fuction exlude BOOLEAN and STRING values.
if you replace your zeroes with "" (empty string) - min() function will do its job as you like!
In Microsoft 365 you can use the new function MINIFS
=MINIFS(A1:E1;A1:E1;">0")
gives 1
=MINIFS(A1:E1;A1:E1;">1")
gives 18
*replace ; with , if using english version
All you have to do is to delete the "0" in the cells that contain just that and try again. That should work.

Case Function Equivalent in Excel

I have an interesting challenge - I need to run a check on the following data in Excel:
| A - B - C - D |
|------|------|------|------|
| 36 | 0 | 0 | x |
| 0 | 600 | 700 | x |
|___________________________|
You'll have to excuse my wonderfully bad ASCII art. So I need the D column (x) to run a check against the adjacent cells, then convert the values if necessary. Here's the criteria:
If column B is greater than 0, everything works great and I can get coffee. If it doesn't meet that requirement, then I need to convert A1 according to a table - for example, 32 = 1420 and place into D. Unfortunately, there is no relationship between A and what it needs to convert to, so creating a calculation is out of the question.
A case or switch statement would be perfect in this scenario, but I don't think it is a native function in Excel. I also think it would be kind of crazy to chain a bunch of =IF() statements together, which I did about four times before deciding it was a bad idea (story of my life).
Sounds like a job for VLOOKUP!
You can put your 32 -> 1420 type mappings in a couple of columns somewhere, then use the VLOOKUP function to perform the lookup.
Without reference to the original problem (which I suspect is long since solved), I very recently discovered a neat trick that makes the Choose function work exactly like a select case statement without any need to modify data. There's only one catch: only one of your choose conditions can be true at any one time.
The syntax is as follows:
CHOOSE(
(1 * (CONDITION_1)) + (2 * (CONDITION_2)) + ... + (N * (CONDITION_N)),
RESULT_1, RESULT_2, ... , RESULT_N
)
On the assumption that only one of the conditions 1 to N will be true, everything else is 0, meaning the numeric value will correspond to the appropriate result.
If you are not 100% certain that all conditions are mutually exclusive, you might prefer something like:
CHOOSE(
(1 * TEST1) + (2 * TEST2) + (4 * TEST3) + (8 * TEST4) ... (2^N * TESTN)
OUT1, OUT2, , OUT3, , , , OUT4 , , <LOTS OF COMMAS> , OUT5
)
That said, if Excel has an upper limit on the number of arguments a function can take, you'd hit it pretty quickly.
Honestly, can't believe it's taken me years to work it out, but I haven't seen it before, so figured I'd leave it here to help others.
EDIT: Per comment below from #aTrusty:
Silly numbers of commas can be eliminated (and as a result, the choose statement would work for up to 254 cases) by using a formula of the following form:
CHOOSE(
1 + LOG(1 + (2*TEST1) + (4*TEST2) + (8*TEST3) + (16*TEST4),2),
OTHERWISE, RESULT1, RESULT2, RESULT3, RESULT4
)
Note the second argument to the LOG clause, which puts it in base 2 and makes the whole thing work.
Edit: Per David's answer, there's now an actual switch statement if you're lucky enough to be working on office 2016. Aside from difficulty in reading, this also means you get the efficiency of switch, not just the behaviour!
The Switch function is now available, in Excel 2016 / Office 365
SWITCH(expression, value1, result1, [default or value2, result2],…[default or value3, result3])
example:
=SWITCH(A1,0,"FALSE",-1,"TRUE","Maybe")
Microsoft -Office Support
Note: MS has updated that page to only document the behavior of Excel 2019. Eventually, they will probably remove references to 2019 as well... To see what the page looked like in 2016, use the wayback machine:
https://web.archive.org/web/20161010180642/https://support.office.com/en-us/article/SWITCH-function-47ab33c0-28ce-4530-8a45-d532ec4aa25e
Try this;
=IF(B1>=0, B1, OFFSET($X$1, MATCH(B1, $X:$X, Z) - 1, Y)
WHERE
X = The columns you are indexing into
Y = The number of columns to the left (-Y) or right (Y) of the indexed column to get the value you are looking for
Z = 0 if exact-match (if you want to handle errors)
I used this solution to convert single letter color codes into their descriptions:
=CHOOSE(FIND(H5,"GYR"),"Good","OK","Bad")
You basically look up the element you're trying to decode in the array, then use CHOOSE() to pick the associated item. It's a little more compact than building a table for VLOOKUP().
I know it a little late to answer but I think this short video will help you a lot.
http://www.xlninja.com/2012/07/25/excel-choose-function-explained/
Essentially it is using the choose function. He explains it very well in the video so I'll let do it instead of typing 20 pages.
Another video of his explains how to use data validation to populate a drop down which you can select from a limited range.
http://www.xlninja.com/2012/08/13/excel-data-validation-using-dependent-lists/
You could combine the two and use the value in the drop down as your index to the choose function. While he did not show how to combine them, I'm sure you could figure it out as his videos are good. If you have trouble, let me know and I'll update my answer to show you.
I understand that this is a response to an old post-
I like the If() function combined with Index()/Match():
=IF(B2>0,"x",INDEX($H$2:$I$9,MATCH(A2,$H$2:$H$9,0),2))
The if function compare what is in column b and if it is greater than 0, it returns x, if not it uses the array (table of information) identified by the Index() function and selected by Match() to return the value that a corresponds to.
The Index array has the absolute location set $H$2:$I$9 (the dollar signs) so that the place it points to will not change as the formula is copied. The row with the value that you want returned is identified by the Match() function. Match() has the added value of not needing a sorted list to look through that Vlookup() requires. Match() can find the value with a value: 1 less than, 0 exact, -1 greater than. I put a zero in after the absolute Match() array $H$2:$H$9 to find the exact match. For the column that value of the Index() array that one would like returned is entered. I entered a 2 because in my array the return value was in the second column. Below my index array looked like this:
32 1420
36 1650
40 1790
44 1860
55 2010
The value in your 'a' column to search for in the list is in the first column in my example and the corresponding value that is to be return is to the right. The look up/reference table can be on any tab in the work book - or even in another file. -Book2 is the file name, and Sheet2 is the 'other tab' name.
=IF(B2>0,"x",INDEX([Book2]Sheet2!$A$1:$B$8,MATCH(A2,[Book2]Sheet2!$A$1:$A$8,0),2))
If you do not want x return when the value of b is greater than zero delete the x for a 'blank'/null equivalent or maybe put a 0 - not sure what you would want there.
Below is beginning of the function with the x deleted.
=IF(B2>0,"",INDEX...
If you don't have a SWITCH statement in your Excel version (pre-Excel-2016), here's a VBA implementation for it:
Public Function SWITCH(ParamArray args() As Variant) As Variant
Dim i As Integer
Dim val As Variant
Dim tmp As Variant
If ((UBound(args) - LBound(args)) = 0) Or (((UBound(args) - LBound(args)) Mod 2 = 0)) Then
Error 450 'Invalid arguments
Else
val = args(LBound(args))
i = LBound(args) + 1
tmp = args(UBound(args))
While (i < UBound(args))
If val = args(i) Then
tmp = args(i + 1)
End If
i = i + 2
Wend
End If
SWITCH = tmp
End Function
It works exactly like expected, a drop-in replacement for example for Google Spreadsheet's SWITCH function.
Syntax:
=SWITCH(selector; [keyN; valueN;] ... defaultvalue)
where
selector is any expression that is compared to keys
key1, key2, ... are expressions that are compared to the selector
value1, value2, ... are values that are selected if the selector equals to the corresponding key (only)
defaultvalue is used if no key matches the selector
Examples:
=SWITCH("a";"?") returns "?"
=SWITCH("a";"a";"1";"?") returns "1"
=SWITCH("x";"a";"1";"?") returns "?"
=SWITCH("b";"a";"1";"b";TRUE;"?") returns TRUE
=SWITCH(7;7;1;7;2;0) returns 2
=SWITCH("a";"a";"1") returns #VALUE!
To use it, open your Excel, go to Develpment tools tab, click Visual Basic, rightclick on ThisWorkbook, choose Insert, then Module, finally copy the code into the editor. You have to save as a macro-friendly Excel workbook (xlsm).
Even if old, this seems to be a popular questions, so I'll post another solution, which I think is very elegant:
http://fiveminutelessons.com/learn-microsoft-excel/using-multiple-if-statements-excel
It's elegant because it uses just the IF function. Basically, it boils down to this:
if(condition, choose/use a value from the table, if(condition, choose/use another value from the table...
And so on
Works beautifully, even better than HLOOKUP or VLOOOKUP
but... Be warned - there is a limit to the number of nested if statements excel can handle.
Microsoft replace SWITCH, IFS and IFVALUES with CHOOSE only function.
=CHOOSE($L$1,"index_1","Index_2","Index_3")
Recently I unfortunately had to work with Excel 2010 again for a while and I missed the SWITCH function a lot. I came up with the following to try to minimize my pain:
=CHOOSE(SUM((A1={"a";"b";"c"})*ROW(INDIRECT(1&":"&3))),1,2,3)
CTRL+SHIFT+ENTER
where A1 is where your condition lies (it could be a formula, whatever). The good thing is that we just have to provide the condition once (just like SWITCH) and the cases (in this example: a,b,c) and results (in this example: 1,2,3) are ordered, which makes it easy to reason about.
Here is how it works:
Cond={"c1";"c2";...;"cn"} returns a N-vector of TRUE or FALSE (with behaves like 1s and 0s)
ROW(INDIRECT(1&":"&n)) returns a N-vector of ordered numbers: 1;2;3;...;n
The multiplication of both vectors will return lots of zeros and a number (position) where the condition was matched
SUM just transforms this vector with zeros and a position into just a single number, which CHOOSE then can use
If you want to add another condition, just remember to increment the last number inside INDIRECT
If you want an ELSE case, just wrap it inside an IFERROR formula
The formula will not behave properly if you provide the same condition more than once, but I guess nobody would want to do that anyway
If your using Office 2016 or later, or Office 365, there is a new function that acts similarly to a CASE function called IFS. Here's the description of the function from Microsoft's documentation:
The IFS function checks whether one or more conditions are met, and returns a value that corresponds to the first TRUE condition. IFS can take the place of multiple nested IF statements, and is much easier to read with multiple conditions.
An example of usage follows:
=IFS(A2>89,"A",A2>79,"B",A2>69,"C",A2>59,"D",TRUE,"F")
You can even specify a default result:
To specify a default result, enter TRUE for your final logical_test argument. If none of the other conditions are met, the corresponding value will be returned.
The default result feature is included in the example shown above.
You can read more about it on Microsoft's Support Documentation

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