Leaflet.Draw color while drawing - leaflet.draw

I'm using a color picker to choose the color of an object to draw it with Leaflet.Draw but cannot find where.
$("#txtAPColor").on('change', function(){
colorSelectPoi=$("#txtAPColor").value;
});
var circle_options = {
stroke: true,
color: colorSelectPoi,
weight: 4,
opacity: 0.5,
fill: true,
fillColor: null, //same as color by default
fillOpacity: 0.2,
clickable: true
};
new L.Draw.Circle(map, circle_options).enable();

I have solved the problem with the following code:
var optionColorSelected = '#000'
map.on(L.Draw.Event.CREATED, function (event) {
event.layer.options.color = optionColorSelected;
var layer = event.layer;
drawnItems.addLayer(layer);
});
You just have to update the variable optionColorSelected with the color you choose.
I hope I can help you.

Related

Can I let the color of the GPX track be determined by values associated with each track point, e.g. elevation or speed?

My gpx file already contains elevation information for each trkpt and I can augment this with a speed for each trkpt. I would like to represent the elevation or the speed at each trkpt by varying the color of the track. For instance: slow is blue, fast is red.
How can I do this?
And this probably means: Which files and functions in Openlayers do I have to change to do this?
You can try the ol/style/FlowLine of ol-ext to achieve this.
Using this style, you can change the with/color of the feature along the line using a function. This example show how to: http://viglino.github.io/ol-ext/examples/style/map.style.flowline2.html.
You just have to calculate the width (or color) along the feature geometry varying according the speed or altitude:
const flowStyle = new ol.style.FlowLine({
width: function(f, step) {
// calculate the with of the feature f at the given step
// step is the curvilinear abscissa between 0,1
// (0: first coordinate, 1: last one)
const width = ...
return width;
}
});
#+
You should go with a stylefunction for the vector layer:
https://openlayers.org/en/v4.6.5/apidoc/ol.html#.StyleFunction
This function is checked for each feature to be displayed on the vector layer and the related style can be set/returned programmatically. For example:
function gpxStyle(feature) {
var style = null;
if (feature.get("speed")>="100") {
style = new ol.style.Style({
image: new ol.style.Circle({
radius: 6,
stroke: new ol.style.Stroke({
color: 'red',
width: 2
}),
fill: new ol.style.Fill({
color: 'red'
})
})
});
}
else {
style = new ol.style.Style({
image: new ol.style.Circle({
radius: 6,
stroke: new ol.style.Stroke({
color: 'blue',
width: 2
}),
fill: new ol.style.Fill({
color: 'blue'
})
})
});
}
return [style];
}
var gpxLayer = new ol.layer.Vector({
source: new ol.source.Vector(),
style: gpxStyle
});

canvas background turns black after rerender fabric.js

I have the following situation: I draw the canvas with a background image and this works:
var canvasSection = new fabric.Canvas('buildSection', {
selectionColor: 'rgba(94,213,94,0.2)',
width: widthS,
height: heightS,
hoverCursor: 'pointer',
backgroundColor: ({
source: 'image/bordenconfigurator/background/background1.png',
repeat: 'repeat'
})
});
But then I need to clear canvas and to redraw it. at this point when I try to set background, instead of an image I see a black screen. In console I can see that the background image is set however. This is the code I'm trying:
$('#cForm').on('change', function() {
if ($(this).val() == 'rectLandsc') {
widthS = 600;
heightS = 400;
} else if ($(this).val() == 'rectPortr') {
....
}
canvasSection.clear();
canvasSection.set({
fill: 'rgba(0,0,0,0)',
// backgroundColor: ({source: 'image/bordenconfigurator/background/background1.png', repeat: 'repeat'})
});
//canvasSection.backgroundColor({source: 'image/bordenconfigurator/background/background.png', repeat:'repeat'});
canvasSection.setBackgroundColor({
source: 'image/bordenconfigurator/background/background.png'
}),
canvasSection.renderAll.bind(canvas);
drawBaseForm();
canvasSection.renderAll();
console.log(canvasSection);
});
Is it a kind of a bug? Or am I doing something wrong? Could anyone help me out here?
canvas.setBackgroundColor({
source: 'image/bordenconfigurator/background/background1.png',
repeat: 'repeat'
}, canvas.renderAll.bind(canvas));
setBackgroundColor first parameter is color/pattern and second parameter is callback function.
DEMO
var canvas = new fabric.Canvas('c');
canvas.setBackgroundColor({
source: 'http://fabricjs.com/assets/pug_small.jpg'
}, canvas.renderAll.bind(canvas));
function clearCanvas(){
var background = canvas.backgroundColor;
canvas.clear();
setTimeout(function(){
canvas.setBackgroundColor(background,canvas.renderAll.bind(canvas));
},2000)
}
canvas{
border: 2px dotted black;
}
<script src="https://rawgithub.com/kangax/fabric.js/master/dist/fabric.js"></script>
<button onclick='clearCanvas()'>clear</button>
<canvas id="c" width="500" height="500"></canvas>

Graph search for element by element's name in jointJS

I have a problem in Rappid/jointJS
I have in stencil.js 4 shapes(2 basic.Circle and 2 basic.Rect) with names START(basic.Circle), END(basic.Circle), Activity(basic.Rect) and Workitem( basic.Rect) and I want in my main.js from all my graph to get the basic shape with name(I mean with attrs text ) "Activity".
This is the Stencil description for "Activity" :
new joint.shapes.basic.Rect({ size: { width: 5, height: 3 },
attrs: {
rect: {
rx: 2, ry: 2, width: 50, height: 30,
fill: '#0000FF'
},
text: { text: 'Activity', fill: '#ffffff', 'font-size': 10,
stroke: '#000000', 'stroke-width': 0 }
}
}),
How wil I get it? The only way I can search in my graph so far is if a cell has type basic.Circle(use of get('type') === 'basic.Circle')). but with type Circle I have two items:Activity and Workitem.
Is it so difficult to search for the graph element with name : "Activity"?
Thank you in advance
You can obtain all the elements (except for links) from following method
var allElement = graph.getElements()
Next if you want to obtain elements with 'Activity' do as follows
var activityElements = [];
allElement.forEach(elem => {
var textVal = elem.attributes.attrs.text.text;
if(textVal !== undefined && textVal === 'Activity') {
activityElements.push(elem);
}
});
Now the activityElements array will contain all the elements you require.
I solved my problem by taking element data in JSON format:
_.each(this.graph.getElements(), function(element) {
if(element.attributes.attrs["text"]["text"] == "Activity"){
//alert("YEAHHHHHH");
}
});
you could use the api on element as well, element.attr('text') returns the text object from the shape: { text: 'Activity', fill: '#ffffff', 'font-size': 10,
stroke: '#000000', 'stroke-width': 0 }
You could also set an "id" attribute to your shape and use graph.getCell('id_name_goes_here'); which would be much simpler if you didn't mind adding an id field to each shape.

Fabricjs How to scale object but keep the border (stroke) width fixed

I'm developing a diagram tool based on fabricjs. Our tool has our own collection of shape, which is svg based. My problem is when I scale the object, the border (stroke) scale as well. My question is: How can I scale the object but keep the stroke width fixed. Please check the attachments.
Thank you very much!
Here is an easy example where on scale of an object we keep a reference to the original stroke and calculate a new stroke based on the scale.
var canvas = new fabric.Canvas('c', { selection: false, preserveObjectStacking:true });
window.canvas = canvas;
canvas.add(new fabric.Rect({
left: 100,
top: 100,
width: 50,
height: 50,
fill: '#faa',
originX: 'left',
originY: 'top',
stroke: "#000",
strokeWidth: 1,
centeredRotation: true
}));
canvas.on('object:scaling', (e) => {
var o = e.target;
if (!o.strokeWidthUnscaled && o.strokeWidth) {
o.strokeWidthUnscaled = o.strokeWidth;
}
if (o.strokeWidthUnscaled) {
o.strokeWidth = o.strokeWidthUnscaled / o.scaleX;
}
})
canvas {
border: 1px solid #ccc;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/fabric.js/1.6.4/fabric.min.js"></script>
<canvas id="c" width="600" height="600"></canvas>
There is a property called: strokeUniform
Use it like this
shape.set({stroke: '#f55b76', strokeWidth:2, strokeUniform: true })
I have found what feels like an even better solution, works really well with SVG paths.
You can override fabricjs' _renderStroke method and add ctx.scale(1 / this.scaleX, 1 / this.scaleY); before ctx.stroke(); as shown below.
fabric.Object.prototype._renderStroke = function(ctx) {
if (!this.stroke || this.strokeWidth === 0) {
return;
}
if (this.shadow && !this.shadow.affectStroke) {
this._removeShadow(ctx);
}
ctx.save();
ctx.scale(1 / this.scaleX, 1 / this.scaleY);
this._setLineDash(ctx, this.strokeDashArray, this._renderDashedStroke);
this._applyPatternGradientTransform(ctx, this.stroke);
ctx.stroke();
ctx.restore();
};
You may also need to override fabric.Object.prototype._getTransformedDimensions to adjust the bounding box to account for the difference in size.
Also a more complete implementation would probably add a fabric object property to conditionally control this change for both overridden methods.
Another way is to draw a new object on scaled and remove the scaled one.
object.on({
scaled: function()
{
// store new widht and height
var new_width = this.getScaledWidth();
var new_height = this.getScaledHeight();
// remove object from canvas
canvas.remove(this);
// add new object with same size and original options like strokeWidth
canvas.add(new ...);
}
});
Works perfect for me.

Pattern not applying on line object fabricjs

I am facing as issue using fabricjs as pattern is not applying on line object. It fills the object property with pattern images but is not showing pattern on line. jsfiddle ins attached.
var line = new fabric.Line([10, 25, 300, 25], {
stroke: 'red',
strokeWidth: 5,
selectable: true,
left: 0,
top: 0
});
canvas.add(line);
fabric.util.loadImage('http://fabricjs.com/assets/escheresque_ste.png', function (img) {
line.setPatternFill({
source: img,
repeat: 'repeat'
});
canvas.renderAll();
});
console.log(line);
Because Fabric js setPatternFill only apply pattern to the fill property of object.But line object not have a fill property,only have a stroke so we apply pattern differently like new fabric.Pattern
var canvas = new fabric.Canvas("c")
var line = new fabric.Line([10, 25, 300, 25], {
stroke: 'red',
fill:"red",
strokeWidth: 10,
selectable: true,
left: 0,
top: 0
});
canvas.add(line);
fabric.util.loadImage('http://fabricjs.com/assets/escheresque_ste.png', function (img) {
line.stroke = new fabric.Pattern({
source: img,
repeat: 'repeat'
});
canvas.renderAll();
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/fabric.js/1.5.0/fabric.min.js"></script>
<canvas id="c"></canvas>

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